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Zorluk: KolaySurds and Rationalization of Denominators

What is the simplified form of the expression 553\frac{\sqrt{5}}{\sqrt{5} - \sqrt{3}}?

  1. 5+152\frac{5 + \sqrt{15}}{2}Cevap
  2. B
    5\sqrt{5}
  3. C
    5+155 + \sqrt{15}
  4. D
    5152\frac{5 - \sqrt{15}}{2}

Cevap

5+152\frac{5 + \sqrt{15}}{2}
To rationalize the denominator of 553\frac{\sqrt{5}}{\sqrt{5} - \sqrt{3}}, multiply both numerator and denominator by the conjugate 5+3\sqrt{5} + \sqrt{3}. The numerator becomes 5(5+3)=5+15\sqrt{5}(\sqrt{5} + \sqrt{3}) = 5 + \sqrt{15} and the denominator becomes (5)2(3)2=53=2(\sqrt{5})^2 - (\sqrt{3})^2 = 5 - 3 = 2, yielding 5+152\frac{5 + \sqrt{15}}{2}.

Adım Adım Çözüm

1
Identify the conjugate of the denominator
The conjugate of 53\sqrt{5} - \sqrt{3} is 5+3\sqrt{5} + \sqrt{3}.
Multiplying a binomial surd by its conjugate eliminates the radical terms in the denominator using the difference of two squares identity (ab)(a+b)=a2b2(a-b)(a+b) = a^2 - b^2.
2
Multiply both the numerator and the denominator by the conjugate
5(5+3)(53)(5+3)\frac{\sqrt{5}(\sqrt{5} + \sqrt{3})}{(\sqrt{5} - \sqrt{3})(\sqrt{5} + \sqrt{3})}
Multiplying the fraction by 5+35+3\frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} + \sqrt{3}} is equivalent to multiplying by 11, preserving the value of the expression.
3
Expand the numerator and simplify the denominator
Numerator: 5×5+5×3=5+15\sqrt{5} \times \sqrt{5} + \sqrt{5} \times \sqrt{3} = 5 + \sqrt{15}. Denominator: (5)2(3)2=53=2(\sqrt{5})^2 - (\sqrt{3})^2 = 5 - 3 = 2.
Applying the distributive law to the numerator and difference of squares to the denominator simplifies both parts.
4
Combine the simplified numerator and denominator
5+152\frac{5 + \sqrt{15}}{2}
This is the simplified rationalized form.

Anahtar Kavram

Rationalization of Denominators
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