Soru

Zorluk: KolaySimultaneous Linear and Quadratic Equations

Solve the simultaneous equations y=2x+1y = 2x + 1 and y=x22y = x^2 - 2. Which of the following represents the complete set of solution pairs (x,y)(x, y)?

  1. (3,7)(3, 7) and (1,1)(-1, -1)Cevap
  2. B
    (3,5)(-3, -5) and (1,3)(1, 3)
  3. C
    (3,5)(3, 5) and (1,3)(-1, -3)
  4. D
    (3,7)(3, 7) and (1,3)(1, 3)

Cevap

The complete set of solution pairs (x,y)(x, y) is (3,7)(3, 7) and (1,1)(-1, -1).
Equating 2x+1=x222x + 1 = x^2 - 2 yields x22x3=0x^2 - 2x - 3 = 0. Factoring gives (x3)(x+1)=0(x - 3)(x + 1) = 0, leading to x=3x = 3 or x=1x = -1. Substituting these xx-values into y=2x+1y = 2x + 1 gives y=7y = 7 for x=3x = 3, and y=1y = -1 for x=1x = -1. Thus, the solution pairs are (3,7)(3, 7) and (1,1)(-1, -1).

Adım Adım Çözüm

1
Equate the linear expression for yy to the quadratic expression for yy.
2x+1=x222x + 1 = x^2 - 2
Since both expressions equal yy, setting them equal eliminates yy.
2
Rearrange the equation into standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.
x22x3=0x^2 - 2x - 3 = 0
Subtract 2x2x and 11 from both sides.
3
Factor the quadratic equation to find the values of xx.
(x3)(x+1)=0    x=3 or x=1(x - 3)(x + 1) = 0 \implies x = 3 \text{ or } x = -1
Determine two numbers that multiply to 3-3 and add to 2-2.
4
Substitute each xx-value back into the linear equation y=2x+1y = 2x + 1 to find the corresponding yy-value.
For x=3x = 3, y=2(3)+1=7y = 2(3) + 1 = 7. For x=1x = -1, y=2(1)+1=1y = 2(-1) + 1 = -1.
Calculate the exact coordinate pairs (x,y)(x, y) that satisfy both equations.

Anahtar Kavram

Solving simultaneous linear and quadratic equations using algebraic substitution.
Bu soruyu puanla