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Zorluk: Çok zorFundamental and Derived Quantities

A physical quantity ZZ is defined as the ratio of the product of impulse and linear velocity to the product of electric current and electric potential difference. When ZZ is fully resolved into fundamental physical quantities, which fundamental quantity does ZZ represent?

  1. TimeCevap
  2. B
    Mass
  3. C
    Length
  4. D
    Electric current

Cevap

Time
The correct answer is Time because reducing both the numerator (energy) and denominator (electrical power) to base fundamental dimensions yields ML2T2ML2T3=T\frac{M L^2 T^{-2}}{M L^2 T^{-3}} = T, which corresponds directly to the fundamental quantity of Time.

Adım Adım Çözüm

1
Express impulse and velocity in terms of fundamental base quantities (Mass MM, Length LL, Time TT)
Impulse=Force×Time=MLT1\text{Impulse} = \text{Force} \times \text{Time} = M L T^{-1}. Velocity=LT1\text{Velocity} = L T^{-1}. Product =(MLT1)(LT1)=ML2T2= (M L T^{-1})(L T^{-1}) = M L^2 T^{-2}.
To evaluate the numerator in fundamental base dimensions.
2
Express electric current and potential difference in terms of fundamental base quantities
Current=I\text{Current} = I. Potential Difference=WorkCharge=ML2T2IT=ML2T3I1\text{Potential Difference} = \frac{\text{Work}}{\text{Charge}} = \frac{M L^2 T^{-2}}{I T} = M L^2 T^{-3} I^{-1}. Product =I×(ML2T3I1)=ML2T3= I \times (M L^2 T^{-3} I^{-1}) = M L^2 T^{-3}.
To evaluate the denominator in fundamental base dimensions.
3
Divide the numerator by the denominator to simplify quantity ZZ
Z=ML2T2ML2T3=M11L22T2(3)=T1Z = \frac{M L^2 T^{-2}}{M L^2 T^{-3}} = M^{1-1} L^{2-2} T^{-2 - (-3)} = T^1.
Determining the net fundamental quantity after all derived units cancel out.

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Fundamental and Derived Quantities
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