Complete the statements regarding the artificial nuclear transmutation of aluminium-27 by filling in the blanks with the correct numerical values.
Cevap:When aluminium-27 () is bombarded with an alpha particle (), it produces phosphorus-30 () and a neutron (). According to the law of conservation of mass number and atomic number, the mass number of the emitted neutron is 【1】 and its atomic number is 【0】.
Cevap
The mass number A is 1 and the atomic number Z is 0.
In any balanced nuclear reaction, the sum of the superscripts (mass numbers) and the sum of the subscripts (atomic numbers) must be equal on both sides of the equation. For the reactants (), the total mass number is and the total atomic number is . For the products (), setting yields , and setting yields . Thus, the emitted particle is a neutron ().
Adım Adım Çözüm
Anahtar Kavram
Conservation of mass number and atomic number in nuclear transmutation equations.
Tahmini Süre:1m 0s