Soru

Zorluk: ZorLinear and Quadratic Inequalities

Determine the number of integer values of xx that satisfy the quadratic inequality 3x214x5<03x^2 - 14x - 5 < 0.

Cevap: 5

Cevap

The total number of integer values satisfying the inequality is 5.
Factoring 3x214x5<03x^2 - 14x - 5 < 0 gives (3x+1)(x5)<0(3x + 1)(x - 5) < 0. The critical roots are x=13x = -\frac{1}{3} and x=5x = 5. Since the parabola opens upward, the expression is negative between the roots, yielding the interval 13<x<5-\frac{1}{3} < x < 5. The integer values contained in this interval are 0,1,2,3,0, 1, 2, 3, and 44, which total 5 values.

Adım Adım Çözüm

1
Factor the quadratic expression
(3x+1)(x5)<0(3x + 1)(x - 5) < 0
Factoring identifies the critical values where the quadratic expression changes sign.
2
Determine the critical points
x=13x = -\frac{1}{3} and x=5x = 5
Setting each factor to zero gives the boundary roots of the equation.
3
Formulate the solution interval
13<x<5-\frac{1}{3} < x < 5
Since the coefficient of x2x^2 is positive, the quadratic curve is below the x-axis strictly between the two roots.
4
List and count the integer solutions
The integers are 0,1,2,3,40, 1, 2, 3, 4, yielding 5 integer solutions.
Counting integers strictly greater than 13-\frac{1}{3} and strictly less than 55.

Anahtar Kavram

Solving quadratic inequalities and finding integer solution counts
Tahmini Süre:1m 30s
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