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Zorluk: Çok zorDefinite Integrals and Area Under Curves

Find the total area of the region bounded by the curve y=3x26xy = 3x^2 - 6x, the xx-axis, and the vertical lines x=0x = 0 and x=3x = 3.

Cevap: 8

Cevap

The total area bounded by the curve and the x-axis between x = 0 and x = 3 is 8 square units.
To find the total geometric area bounded by a curve and the x-axis, we must split the integral at any x-intercepts within the domain. For y=3x26xy = 3x^2 - 6x, the x-intercepts are x=0x = 0 and x=2x = 2. Between x=0x = 0 and x=2x = 2, the curve lies below the x-axis, giving an area magnitude of 44. Between x=2x = 2 and x=3x = 3, the curve lies above the x-axis, giving an area magnitude of 44. Summing these positive magnitudes gives a total area of 88.

Adım Adım Çözüm

1
Find the roots of the curve y=3x26xy = 3x^2 - 6x within the given interval [0,3][0, 3].
Setting 3x26x=03x^2 - 6x = 0 yields 3x(x2)=03x(x - 2) = 0, giving x=0x = 0 and x=2x = 2.
Roots inside the integration boundaries indicate where the curve crosses the x-axis, changing the sign of yy.
2
Determine the position of the curve relative to the x-axis on each sub-interval.
On [0,2][0, 2], y0y \le 0 (below the x-axis). On [2,3][2, 3], y0y \ge 0 (above the x-axis).
Geometric area must be non-negative, so regions below the x-axis require integrating y-y or taking the absolute value of the integral.
3
Evaluate the area A1A_1 for the region below the x-axis from x=0x = 0 to x=2x = 2.
A1=02(6x3x2)dx=[3x2x3]02=(3(4)8)0=4A_1 = \int_{0}^{2} (6x - 3x^2) \, dx = \left[ 3x^2 - x^3 \right]_{0}^{2} = (3(4) - 8) - 0 = 4.
Integrating y=6x3x2-y = 6x - 3x^2 yields the positive magnitude of the area below the x-axis.
4
Evaluate the area A2A_2 for the region above the x-axis from x=2x = 2 to x=3x = 3.
A2=23(3x26x)dx=[x33x2]23=(333(32))(233(22))=0(4)=4A_2 = \int_{2}^{3} (3x^2 - 6x) \, dx = \left[ x^3 - 3x^2 \right]_{2}^{3} = (3^3 - 3(3^2)) - (2^3 - 3(2^2)) = 0 - (-4) = 4.
Direct integration of yy on [2,3][2, 3] gives the area above the x-axis.
5
Combine the areas of both sub-regions.
Total Area =A1+A2=4+4=8= A_1 + A_2 = 4 + 4 = 8.
The total geometric area is the sum of the magnitudes of the areas of all separate bounded regions.

Anahtar Kavram

Calculating area under curves crossing the x-axis by splitting definite integrals at real roots
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