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Zorluk: OrtaElectric Circuits and Measuring Instruments

A cell with an electromotive force (e.m.f.) of 15.0 V15.0\text{ V} and an internal resistance of 2.0 Ω2.0\ \Omega is connected across a parallel combination of two resistors with resistances of 6.0 Ω6.0\ \Omega and 12.0 Ω12.0\ \Omega. What is the potential difference across the parallel resistor network?

  1. 10.0 V10.0\text{ V}Cevap
  2. B
    15.0 V15.0\text{ V}
  3. C
    5.0 V5.0\text{ V}
  4. D
    13.5 V13.5\text{ V}

Cevap

The potential difference across the parallel resistor network is 10.0 V10.0\text{ V}.
The parallel combination of 6.0 Ω6.0\ \Omega and 12.0 Ω12.0\ \Omega has an effective resistance of 4.0 Ω4.0\ \Omega. Adding the internal resistance of 2.0 Ω2.0\ \Omega gives a total circuit resistance of 6.0 Ω6.0\ \Omega. The circuit current is I=15.0 V6.0 Ω=2.5 AI = \frac{15.0\text{ V}}{6.0\ \Omega} = 2.5\text{ A}. The potential difference across the parallel load is therefore V=2.5 A×4.0 Ω=10.0 VV = 2.5\text{ A} \times 4.0\ \Omega = 10.0\text{ V}.

Adım Adım Çözüm

1
Calculate the equivalent resistance of the two parallel resistors (R1=6.0 ΩR_1 = 6.0\ \Omega and R2=12.0 ΩR_2 = 12.0\ \Omega).
Rp=R1R2R1+R2=6.0×12.06.0+12.0=72.018.0=4.0 ΩR_p = \frac{R_1 R_2}{R_1 + R_2} = \frac{6.0 \times 12.0}{6.0 + 12.0} = \frac{72.0}{18.0} = 4.0\ \Omega
Resistors connected in parallel combine according to the reciprocal formula.
2
Determine the total resistance of the entire circuit including the internal resistance (r=2.0 Ωr = 2.0\ \Omega).
Rtotal=Rp+r=4.0 Ω+2.0 Ω=6.0 ΩR_{\text{total}} = R_p + r = 4.0\ \Omega + 2.0\ \Omega = 6.0\ \Omega
The cell's internal resistance is in series with the external equivalent load resistance.
3
Calculate the total current supplied by the cell using Ohm's law for a complete circuit.
I=ERtotal=15.0 V6.0 Ω=2.5 AI = \frac{E}{R_{\text{total}}} = \frac{15.0\text{ V}}{6.0\ \Omega} = 2.5\text{ A}
The current depends on the total e.m.f. divided by the total circuit resistance.
4
Calculate the potential difference across the parallel combination (terminal potential difference).
V=IRp=2.5 A×4.0 Ω=10.0 VV = I R_p = 2.5\text{ A} \times 4.0\ \Omega = 10.0\text{ V}
The potential difference across the parallel network is the product of the total current flowing into the combination and its equivalent resistance.

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Terminal Potential Difference and Internal Resistance
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