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Zorluk: OrtaMeasures of Central Tendency for Ungrouped Data

The mean score of 99 students in a mathematics test was calculated as 1212. It was later discovered that a score of 55 was incorrectly recorded as 1414, and an additional student's score of 3131 was omitted entirely. What is the correct mean score of all 1010 students?

  1. 1313Cevap
  2. B
    13.913.9
  3. C
    14.414.4
  4. D
    14.814.8

Cevap

The correct mean score of all 10 students is 1313.
The original sum of 99 scores is 108108. Subtracting the incorrect value (1414) and adding the true value (55) reduces the sum of the 99 scores to 9999. Adding the 10th10^{\text{th}} score of 3131 gives a total sum of 130130. Dividing 130130 by 1010 gives the correct mean of 1313.

Adım Adım Çözüm

1
Calculate the initial total sum of the original 9 scores.
Initial sum =9×12=108= 9 \times 12 = 108.
Mean is defined as total sum divided by number of items, so total sum equals mean times count.
2
Adjust the total sum for the misread score.
Corrected sum of 9 scores =10814+5=99= 108 - 14 + 5 = 99.
Subtract the incorrect value (1414) and add the actual value (55).
3
Add the omitted 10th score to the sum.
New total sum =99+31=130= 99 + 31 = 130.
Including the omitted score increases the total score sum.
4
Divide the new total sum by the updated total number of students.
Correct mean =13010=13= \frac{130}{10} = 13.
The total number of students increased from 9 to 10.

Anahtar Kavram

Correcting the mean of ungrouped data after data entry errors or additions
Tahmini Süre:1m 30s
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