If the mass defect of a nucleus is 0.030\text{ u}, what is its binding energy? (Take 1\tex… — JAMB UTME

If the mass defect of a nucleus is $0.030\text{ u}$ , what is its binding energy? (Take $1\text{ u} = 931\text{ MeV}$ )

27.93\text{ MeV}

The binding energy is calculated directly by multiplying the mass defect

\Delta m

by the conversion factor

931\text{ MeV/u}

. Thus,

E_b = 0.030 \times 931 = 27.93\text{ MeV}

Identify the given values

Mass defect

\Delta m = 0.030\text{ u}

and mass-energy equivalent

1\text{ u} = 931\text{ MeV}

To calculate the binding energy, the mass defect in atomic mass units must be converted to energy.

Apply mass-energy equivalence conversion

E_b = \Delta m \times 931\text{ MeV/u} = 0.030 \times 931 = 27.93\text{ MeV}

Binding energy is equal to mass defect multiplied by the energy equivalent per atomic mass unit.

Mass Defect and Binding Energy

Soru