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Zorluk: KolayMeasures of Dispersion

A meteorologist recorded the rainfall (in millimeters) in a town over five days as 22, 55, 66, 77, and 1010. What is the mean deviation of the rainfall data?

  1. 22Cevap
  2. B
    00
  3. C
    1010
  4. D
    66

Cevap

The mean deviation of the rainfall data is 22.
To find the mean deviation, first calculate the mean of the data: (2+5+6+7+10)/5=6(2 + 5 + 6 + 7 + 10) / 5 = 6. Next, calculate the absolute difference of each value from 6, which yields 4, 1, 0, 1, and 4. The average of these absolute differences is (4+1+0+1+4)/5=10/5=2(4 + 1 + 0 + 1 + 4) / 5 = 10 / 5 = 2.

Adım Adım Çözüm

1
Calculate the arithmetic mean (xˉ\bar{x}) of the dataset.
\bar{x} = \frac{2 + 5 + 6 + 7 + 10}{5} = \frac{30}{5} = 6
The mean is required to compute the deviation of each observation from the central value.
2
Find the absolute deviation xxˉ|x - \bar{x}| for each data point.
|2 - 6| = 4, \quad |5 - 6| = 1, \quad |6 - 6| = 0, \quad |7 - 6| = 1, \quad |10 - 6| = 4
Mean deviation measures the average absolute distance of data values from the mean.
3
Sum the absolute deviations and divide by the total number of observations (N=5N = 5).
\text{Mean Deviation} = \frac{4 + 1 + 0 + 1 + 4}{5} = \frac{10}{5} = 2
Dividing the sum of absolute deviations by NN gives the mean deviation.

Anahtar Kavram

Mean Deviation
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