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Zorluk: ZorBasic Tools of Economic Analysis

The table below presents the distribution of daily expenditure on diesel (in ₦’000₦\text{'000}) by 4040 micro-enterprises in a commercial hub:

Daily Expenditure (₦’000₦\text{'000})Number of Enterprises (ff)
101910 - 1966
202920 - 291010
303930 - 391414
404940 - 4977
505950 - 5933

What is the median daily expenditure on diesel for these enterprises?

  1. 32.36 thousand₦32.36\text{ thousand}Cevap
  2. B
    32.86 thousand₦32.86\text{ thousand}
  3. C
    32.07 thousand₦32.07\text{ thousand}
  4. D
    34.50 thousand₦34.50\text{ thousand}

Cevap

The median daily expenditure on diesel is 32.36 thousand₦32.36\text{ thousand}.
The median of grouped data is computed using the formula Median=L+(N2Ff)c\text{Median} = L + \left(\frac{\frac{N}{2} - F}{f}\right) c. For this distribution, total frequency N=40N = 40, giving a median position of 2020. Cumulative frequency reveals that the median class is 303930 - 39. The lower boundary LL is 29.529.5, the cumulative frequency of preceding classes FF is 1616, the frequency of the median class ff is 1414, and the class width cc is 1010. Substituting these values gives 29.5+(201614)×10=32.36 thousand Naira29.5 + \left(\frac{20 - 16}{14}\right) \times 10 = 32.36\text{ thousand Naira}.

Adım Adım Çözüm

1
Determine total frequency and find the median position
Total frequency N=6+10+14+7+3=40N = 6 + 10 + 14 + 7 + 3 = 40. Median position =N2=402=20th= \frac{N}{2} = \frac{40}{2} = 20^{\text{th}} item.
The median in grouped data corresponds to the value at the half-way position of total observations.
2
Calculate cumulative frequencies to identify the median class
Cumulative frequencies are 6,16,30,37,406, 16, 30, 37, 40. The 20th20^{\text{th}} observation lies within the class 303930 - 39.
The cumulative frequency reaches 3030 in the 303930 - 39 group, which exceeds 2020.
3
Identify class parameters for the median formula
Lower class boundary L=29.5L = 29.5, preceding cumulative frequency F=16F = 16, class frequency f=14f = 14, class interval width c=39.529.5=10c = 39.5 - 29.5 = 10.
Accurate calculation requires continuous boundaries rather than discrete limits.
4
Apply the grouped median formula
Median=L+(N2Ff)×c=29.5+(201614)×10=29.5+(414)×10=29.5+2.857=32.35732.36\text{Median} = L + \left(\frac{\frac{N}{2} - F}{f}\right) \times c = 29.5 + \left(\frac{20 - 16}{14}\right) \times 10 = 29.5 + \left(\frac{4}{14}\right) \times 10 = 29.5 + 2.857 = 32.357 \approx 32.36.
Evaluates the linear interpolation within the median class interval.

Anahtar Kavram

Calculating median for grouped statistical frequency distributions using class boundaries.
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