Tüm alıştırma soruları

13931 soru

Soru 4161Soru

If xx, yy, and zz are non-zero real numbers satisfying the exponential equation 2x=5y=100z2^x = 5^y = 100^z, what is the numerical value of the expression z(2x+2y)z \left( \frac{2}{x} + \frac{2}{y} \right)?

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Cevap: 1

Cevap

The numerical value of z(2x+2y)z \left( \frac{2}{x} + \frac{2}{y} \right) is 11.
By setting 2x=5y=100z=k2^x = 5^y = 100^z = k, we can write 2=k1/x2 = k^{1/x}, 5=k1/y5 = k^{1/y}, and 100=k1/z100 = k^{1/z}. Factoring 100=22×52100 = 2^2 \times 5^2 gives k1/z=(k1/x)2×(k1/y)2=k2/x+2/yk^{1/z} = (k^{1/x})^2 \times (k^{1/y})^2 = k^{2/x + 2/y}. Equating exponents gives 1z=2x+2y\frac{1}{z} = \frac{2}{x} + \frac{2}{y}, which upon multiplying by zz yields 11.

Adım Adım Çözüm

1
Equate the given exponential expressions to a common constant kk.
2x=5y=100z=k2^x = 5^y = 100^z = k
Introducing a common variable allows isolating each base exponent combination.
2
Express bases 22, 55, and 100100 in terms of kk using fractional indices.
2=k1x2 = k^{\frac{1}{x}}, 5=k1y5 = k^{\frac{1}{y}}, 100=k1z100 = k^{\frac{1}{z}}
Applying the power law (am)1m=a(a^m)^{\frac{1}{m}} = a isolates each base.
3
Express 100100 using prime factorization of the other bases.
100=22×52100 = 2^2 \times 5^2
Establishing a numerical relationship between 100100, 22, and 55 links the exponential variables.
4
Substitute the kk-expressions into 100=22×52100 = 2^2 \times 5^2 and apply index multiplication laws.
k1z=(k1x)2×(k1y)2=k2x×k2y=k2x+2yk^{\frac{1}{z}} = \left(k^{\frac{1}{x}}\right)^2 \times \left(k^{\frac{1}{y}}\right)^2 = k^{\frac{2}{x}} \times k^{\frac{2}{y}} = k^{\frac{2}{x} + \frac{2}{y}}
Multiplying powers with the same base requires adding the exponents: aman=am+na^m \cdot a^n = a^{m+n}.
5
Equate exponents of identical bases.
1z=2x+2y\frac{1}{z} = \frac{2}{x} + \frac{2}{y}
If ka=kbk^a = k^b for k>1k > 1, then a=ba = b.
6
Multiply both sides of the equation by zz.
z(2x+2y)=1z \left( \frac{2}{x} + \frac{2}{y} \right) = 1
Rearranging the equation yields the exact numerical value of the requested expression.

Anahtar Kavram

Equating Exponents of Common Bases and Fractional Indices
Soru 4162Soru

A binary operation \ast on the set of real numbers is defined by ab=a+b2aba \ast b = a + b - 2ab. If (x3)2=38(x \ast 3) \ast 2 = 38, find the value of xx.

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Cevap: 3

Cevap

The value of xx is 3.
Applying the binary operation definition sequentially yields x3=35xx \ast 3 = 3 - 5x for the inner expression, and (35x)2=15x7(3 - 5x) \ast 2 = 15x - 7 for the composite expression. Equating 15x7=3815x - 7 = 38 leads to 15x=4515x = 45, giving x=3x = 3.

Adım Adım Çözüm

1
Evaluate the inner binary operation expression x3x \ast 3
x3=35xx \ast 3 = 3 - 5x
Apply the definition ab=a+b2aba \ast b = a + b - 2ab with a=xa = x and b=3b = 3.
2
Evaluate the outer binary operation (35x)2(3 - 5x) \ast 2
(35x)2=15x7(3 - 5x) \ast 2 = 15x - 7
Substitute the result from step 1 into the outer operation definition with a=35xa = 3 - 5x and b=2b = 2.
3
Set the resulting expression equal to 38 and solve the linear equation
x=3x = 3
Solve 15x7=3815x - 7 = 38 by adding 7 to both sides to get 15x=4515x = 45, then dividing by 15.

Anahtar Kavram

Nested composition of defined binary operations
Soru 4163Soru

In a survey of 150150 subscribers of a digital media platform, 7575 prefer High-Definition Audio (HH), 7070 prefer Offline Downloads (DD), and 6565 prefer Ad-free Listening (AA). It is observed that 3535 subscribers prefer both HH and DD, 3030 prefer both DD and AA, and 2525 prefer both HH and AA. If 1515 subscribers prefer none of these three features, how many subscribers prefer exactly two of these features?

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Cevap: 45

Cevap

The number of subscribers who prefer exactly two of the features is 45.
To find the number of subscribers who prefer exactly two features, we first calculate the cardinality of the union of all three sets as 15015=135150 - 15 = 135. Applying the 3-set inclusion-exclusion formula gives the number of subscribers preferring all three features as 1515. Subtracting 1515 from each pairwise intersection gives the exclusive regions: 2020 for HH and DD only, 1515 for DD and AA only, and 1010 for HH and AA only. Summing these three exclusive regions gives 20+15+10=4520 + 15 + 10 = 45.

Adım Adım Çözüm

1
Determine the total number of subscribers who prefer at least one feature.
HDA=135|H \cup D \cup A| = 135
Subtracting the number of subscribers who prefer none of the features (1515) from the universal set size (150150) gives HDA=15015=135|H \cup D \cup A| = 150 - 15 = 135.
2
Apply the Principle of Inclusion-Exclusion for three sets to find the number of subscribers who prefer all three features.
HDA=15|H \cap D \cap A| = 15
Substitute the known cardinalities into HDA=H+D+AHDDAHA+HDA|H \cup D \cup A| = |H| + |D| + |A| - |H \cap D| - |D \cap A| - |H \cap A| + |H \cap D \cap A| to get 135=75+70+65(35+30+25)+HDA135 = 75 + 70 + 65 - (35 + 30 + 25) + |H \cap D \cap A|, which simplifies to 135=120+HDA135 = 120 + |H \cap D \cap A|, giving HDA=15|H \cap D \cap A| = 15.
3
Calculate the number of subscribers preferring exactly two features by subtracting the triple intersection from each pairwise intersection.
45 subscribers
Subscribers preferring only HH and D=3515=20D = 35 - 15 = 20, only DD and A=3015=15A = 30 - 15 = 15, and only HH and A=2515=10A = 25 - 15 = 10. Summing these exclusive regions yields 20+15+10=4520 + 15 + 10 = 45.

Anahtar Kavram

Cardinality of set operations and 3-set inclusion-exclusion principle
Soru 4164Soru

Although the regional manager was initially hesitant, he eventually became reconciled _____ the sweeping corporate reforms, especially after the board prevailed _____ him to lead the implementation committee.

Which of the following pairs of prepositions correctly completes the sentence above?

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Cevap: to / upon

Cevap

The correct prepositions are 'to / upon'.
The preposition 'to' correctly completes the expression 'reconciled to', which signifies becoming resigned to or accepting an unwelcome circumstance. The preposition 'upon' correctly completes 'prevail upon', an established idiomatic construction meaning to persuade someone to take action.

Adım Adım Çözüm

1
Analyze the first blank following 'reconciled' in the context of accepting an unwanted situation ('sweeping corporate reforms').
The correct preposition is 'to' because 'reconciled to' means coming to accept an unpleasant or undesirable state of affairs.
Using 'with' would incorrectly imply restoring personal harmony with an individual or group rather than resigning oneself to a situation.
2
Analyze the second blank following 'prevailed' in the context of influencing or persuading someone ('him to lead the implementation committee').
The correct preposition is 'upon' (or 'on') because 'prevail upon' is an idiomatic verb-preposition pair meaning to successfully persuade or induce someone to take action.
Using 'over' or 'against' would alter the meaning to defeating or gaining victory over an adversary.

Anahtar Kavram

Dependent prepositions and contextual prepositional collocations
Tahmini Süre:1m 0s
Soru 4165Soru

Find the positive value of xx that satisfies the simultaneous equations y=x+2y = x + 2 and y=x24y = x^2 - 4.

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Cevap: 3

Cevap

The positive value of xx is 3.
Equating the linear equation y=x+2y = x + 2 and the quadratic equation y=x24y = x^2 - 4 yields x2x6=0x^2 - x - 6 = 0. Factorizing this quadratic equation gives (x3)(x+2)=0(x - 3)(x + 2) = 0, which yields roots x=3x = 3 and x=2x = -2. Selecting the positive value gives 3.

Adım Adım Çözüm

1
Equate the linear and quadratic equations
x+2=x24x + 2 = x^2 - 4
Since both expressions are equal to yy, set them equal to each other to solve for xx.
2
Rearrange into standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0
x2x6=0x^2 - x - 6 = 0
Subtract xx and 22 from both sides of the equation.
3
Factorize the quadratic expression
(x3)(x+2)=0(x - 3)(x + 2) = 0
Find two factors of 6-6 that add up to 1-1, which are 3-3 and 22.
4
Determine the roots and select the positive value
x=3x = 3
Setting each factor to zero gives x=3x = 3 or x=2x = -2. Selecting the positive root yields 33.

Anahtar Kavram

Solving simultaneous linear and quadratic equations by substitution
Soru 4166Soru

What is the smallest non-negative integer kk that satisfies the modular congruence 799+k15(mod11)7^{99} + k \equiv -15 \pmod{11}?

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Cevap: 10

Cevap

The correct answer is 10.
Using Fermat's Little Theorem, 7101(mod11)7^{10} \equiv 1 \pmod{11}, which simplifies 799(mod11)7^{99} \pmod{11} to 798(mod11)7^9 \equiv 8 \pmod{11}. Reducing the right-hand side gives 157(mod11)-15 \equiv 7 \pmod{11}. The modular equation 8+k7(mod11)8 + k \equiv 7 \pmod{11} yields k1(mod11)k \equiv -1 \pmod{11}. Adding the modulus 1111 gives the canonical positive remainder 1010.

Adım Adım Çözüm

1
Simplify 799(mod11)7^{99} \pmod{11} using Fermat's Little Theorem.
7101(mod11)7^{10} \equiv 1 \pmod{11}, so 799=(710)9×7919×7979(mod11)7^{99} = (7^{10})^9 \times 7^9 \equiv 1^9 \times 7^9 \equiv 7^9 \pmod{11}.
Since 1111 is prime and gcd(7,11)=1\gcd(7, 11) = 1, Fermat's Little Theorem allows exponent reduction modulo 1010.
2
Compute 79(mod11)7^9 \pmod{11}.
7177^1 \equiv 7, 72=4957^2 = 49 \equiv 5, 7452=2537^4 \equiv 5^2 = 25 \equiv 3, 757×3=21107^5 \equiv 7 \times 3 = 21 \equiv 10, 79=75×7410×3=308(mod11)7^9 = 7^5 \times 7^4 \equiv 10 \times 3 = 30 \equiv 8 \pmod{11}.
Repeated squaring and modular multiplication efficiently reduces 797^9 modulo 1111.
3
Reduce the right-hand side 15(mod11)-15 \pmod{11}.
15=2(11)+77(mod11)-15 = -2(11) + 7 \equiv 7 \pmod{11}.
Converting negative numbers into the standard non-negative remainder range [0,10][0, 10].
4
Substitute remainders into the congruence and solve for kk.
8+k7    k78=1(mod11)8 + k \equiv 7 \implies k \equiv 7 - 8 = -1 \pmod{11}.
Linear algebraic rearrangement in modular arithmetic.
5
Convert the negative remainder 1-1 to canonical non-negative form.
k=1+11=10k = -1 + 11 = 10.
The standard remainder must satisfy 0k<110 \leq k < 11.

Anahtar Kavram

Modular Exponentiation & Negative Remainder Reduction
Soru 4167Soru

Which of the following sets contains all the values of xx in the interval 0x3600^\circ \le x \le 360^\circ that satisfy the trigonometric equation 2cos2x+3sinx3=02\cos^2 x + 3\sin x - 3 = 0?

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Cevap: 30,90,15030^\circ, 90^\circ, 150^\circ

Cevap

The values of xx in the interval 0x3600^\circ \le x \le 360^\circ satisfying the equation are 30,90,30^\circ, 90^\circ, and 150150^\circ.
By substituting cos2x=1sin2x\cos^2 x = 1 - \sin^2 x, the equation reduces to 2sin2x3sinx+1=02\sin^2 x - 3\sin x + 1 = 0, which factors into (2sinx1)(sinx1)=0(2\sin x - 1)(\sin x - 1) = 0. Solving sinx=1/2\sin x = 1/2 gives x=30x = 30^\circ and x=150x = 150^\circ within the specified domain. Solving sinx=1\sin x = 1 gives x=90x = 90^\circ. Combining these yields the set of solutions 30,90,15030^\circ, 90^\circ, 150^\circ.

Adım Adım Çözüm

1
Use the Pythagorean trigonometric identity cos2x=1sin2x\cos^2 x = 1 - \sin^2 x to rewrite the equation in terms of sinx\sin x.
2(1sin2x)+3sinx3=0    22sin2x+3sinx3=02(1 - \sin^2 x) + 3\sin x - 3 = 0 \implies 2 - 2\sin^2 x + 3\sin x - 3 = 0
Converting the equation to involve a single trigonometric function allows it to be solved as a quadratic equation.
2
Simplify and rearrange the equation into standard quadratic form.
2sin2x+3sinx1=0    2sin2x3sinx+1=0-2\sin^2 x + 3\sin x - 1 = 0 \implies 2\sin^2 x - 3\sin x + 1 = 0
Multiplying by 1-1 simplifies factoring.
3
Factor the quadratic equation (2sinx1)(sinx1)=0(2\sin x - 1)(\sin x - 1) = 0 to solve for sinx\sin x.
sinx=12\sin x = \frac{1}{2} or sinx=1\sin x = 1
Setting each linear factor to zero yields the possible values for sinx\sin x.
4
Determine all values of xx in the domain 0x3600^\circ \le x \le 360^\circ for each case.
For sinx=12\sin x = \frac{1}{2}, x=30x = 30^\circ and x=18030=150x = 180^\circ - 30^\circ = 150^\circ. For sinx=1\sin x = 1, x=90x = 90^\circ.
Sine is positive in the first and second quadrants, and equals 1 at 9090^\circ.

Anahtar Kavram

Solving quadratic trigonometric equations by using fundamental identities to express the equation in terms of a single trigonometric function.
Tahmini Süre:2m 0s
Soru 4168Soru

A binary operation \circ defined on the set of real numbers R{1}\mathbb{R} \setminus \{1\} is given by ab=a+baba \circ b = a + b - ab. What is the inverse of 33 under this operation?

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Cevap: 32\frac{3}{2}

Cevap

The inverse of 33 under the given operation is 32\frac{3}{2}.
To find the inverse of 33 under the operation ab=a+baba \circ b = a + b - ab, we must first determine the identity element ee. Setting ae=aa \circ e = a yields a+eae=aa + e - ae = a, which simplifies to e(1a)=0e(1 - a) = 0. For all a1a \neq 1, the identity element is e=0e = 0. Next, using the definition of inverse 3x=03 \circ x = 0, we substitute into the operational formula to obtain 3+x3x=0    32x=0    x=323 + x - 3x = 0 \implies 3 - 2x = 0 \implies x = \frac{3}{2}. Thus, the option specifying 32\frac{3}{2} is correct.

Adım Adım Çözüm

1
Find the identity element ee of the operation \circ.
e=0e = 0
By definition of identity, ae=aa \circ e = a. Substituting into the operational formula gives a+eae=a    e(1a)=0a + e - ae = a \implies e(1 - a) = 0. Since a1a \neq 1, e=0e = 0.
2
Set up the inverse equation for 33, letting xx be the inverse of 33.
3x=03 \circ x = 0
By definition of an inverse element, aa1=ea \circ a^{-1} = e.
3
Expand 3x3 \circ x using the operation rule and solve for xx.
x=32x = \frac{3}{2}
3+x3x=0    32x=0    2x=3    x=323 + x - 3x = 0 \implies 3 - 2x = 0 \implies 2x = 3 \implies x = \frac{3}{2}.

Anahtar Kavram

Identity and Inverse Elements in Binary Operations
Soru 4169Soru

Using differentiation from first principles, what is the numerical value of the derivative of the function f(x)=3x24x+1f(x) = 3x^2 - 4x + 1 at x=2x = 2?

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Cevap: 8

Cevap

The numerical value of the derivative of f(x)=3x24x+1f(x) = 3x^2 - 4x + 1 at x=2x = 2 is 8.
Using the first-principles limit definition, the increment f(2+h)f(2)f(2+h) - f(2) simplifies to 8h+3h28h + 3h^2. Dividing by hh yields 8+3h8 + 3h, which evaluates to 8 as h0h \to 0.

Adım Adım Çözüm

1
Calculate f(2)f(2)
f(2)=5f(2) = 5
Substitute x=2x = 2 into f(x)=3x24x+1f(x) = 3x^2 - 4x + 1.
2
Expand f(2+h)f(2+h)
f(2+h)=5+8h+3h2f(2+h) = 5 + 8h + 3h^2
Substitute x=2+hx = 2+h into f(x)f(x) and expand algebraically.
3
Simplify the difference quotient f(2+h)f(2)h\frac{f(2+h) - f(2)}{h}
8h+3h2h=8+3h\frac{8h + 3h^2}{h} = 8 + 3h
Subtract f(2)f(2) from f(2+h)f(2+h) and divide every term by hh.
4
Evaluate the limit as h0h \to 0
f(2)=8f'(2) = 8
As hh approaches 0, the term 3h3h vanishes, leaving 8.

Anahtar Kavram

Differentiation from First Principles
Tahmini Süre:1m 30s
Soru 4170Soru

Evaluate the limit limx2x24x2\lim_{x \to 2} \frac{x^2 - 4}{x - 2}. What is the numerical value of this limit?

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Cevap: 4

Cevap

The value of the limit is 44.
Direct substitution of x=2x = 2 produces the indeterminate form 00\frac{0}{0}. Factoring the numerator gives (x2)(x+2)x2\frac{(x-2)(x+2)}{x-2}. Canceling the non-zero factor (x2)(x-2) simplifies the expression to x+2x+2. Evaluating the limit as xx approaches 22 yields 2+2=42 + 2 = 4.

Adım Adım Çözüm

1
Check the form by direct substitution of x=2x = 2
Obtained the indeterminate form 00\frac{0}{0}
Direct substitution results in division by zero, requiring algebraic simplification.
2
Factor the polynomial in the numerator
x24=(x2)(x+2)x^2 - 4 = (x - 2)(x + 2)
Difference of two squares factorization allows canceling common terms.
3
Cancel the common factor (x2)(x - 2)
(x2)(x+2)x2=x+2\frac{(x - 2)(x + 2)}{x - 2} = x + 2
For x2x \neq 2, division by (x2)(x - 2) is valid.
4
Evaluate the simplified limit as x2x \to 2
2+2=42 + 2 = 4
Substitute x=2x = 2 directly into the continuous polynomial x+2x + 2.

Anahtar Kavram

Evaluating indeterminate limits of the form 00\frac{0}{0} via factorization
Soru 4171Soru

In the sentence below, what does the underlined idiomatic expression mean?

'Facing a severe revenue deficit, the chief executive officer decided to bite the bullet and implement the painful restructuring plan.'

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Cevap: face a painful or difficult situation with courage

Cevap

The expression 'bite the bullet' means to face a painful or difficult situation with courage.
The idiom 'bite the bullet' means to force oneself to undergo something difficult or unpleasant stoically. In the context of administrative decision-making during a financial crisis, it means courageously accepting the necessity of a hard decision.

Adım Adım Çözüm

1
Analyze the context of the sentence
The chief executive officer must implement an uncomfortable restructuring plan due to financial difficulty.
Contextual clues point to accepting an unpleasant but necessary action.
2
Identify the figurative meaning of 'bite the bullet'
The idiom means accepting an unavoidable, tough situation bravely.
Idiomatic expressions convey non-literal meanings established through conventional usage.

Anahtar Kavram

Contextual interpretation of idiomatic expressions
Soru 4172Soru

Three business partners share a total profit of ₦60,000 in the ratio 1:2:31 : 2 : 3. What is the share of the partner who receives the largest portion, in naira?

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Cevap: 30000

Cevap

The share of the partner receiving the largest portion is ₦30,000.
Sum the parts of the ratio (1+2+3=61 + 2 + 3 = 6). The largest share corresponds to 3 parts out of 6. Calculating 36×60,000\frac{3}{6} \times 60,000 yields 30,000 naira.

Adım Adım Çözüm

1
Calculate the sum of all ratio parts
1 + 2 + 3 = 6 parts
The total amount is divided into equal parts represented by the sum of the ratio numbers.
2
Determine the monetary value of a single part
₦60,000 / 6 = ₦10,000 per part
Dividing the total sum by the total number of parts gives the value of one unit part.
3
Calculate the largest share corresponding to 3 parts
3 × ₦10,000 = ₦30,000
The largest portion of the ratio is 3 parts.

Anahtar Kavram

Direct Ratio Sharing
Soru 4173Soru

Two independent events, AA and BB, have probabilities P(A)=0.4P(A) = 0.4 and P(B)=0.5P(B) = 0.5. What is the probability that both event AA and event BB occur, P(AB)P(A \cap B)?

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Cevap: 0.2

Cevap

The probability that both events occur is 0.2.
For independent events, the joint probability of both events occurring simultaneously is found by multiplying their individual probabilities: P(AB)=P(A)×P(B)=0.4×0.5=0.2P(A \cap B) = P(A) \times P(B) = 0.4 \times 0.5 = 0.2.

Adım Adım Çözüm

1
Identify event independence and the required probability operation
Events AA and BB are independent, and the question requires calculating their intersection P(AB)P(A \cap B).
The problem explicitly states that the events are independent.
2
Apply the multiplication law for independent events
P(AB)=P(A)×P(B)P(A \cap B) = P(A) \times P(B)
For any two independent events, the probability of both occurring together is the product of their individual probabilities.
3
Perform the multiplication
P(AB)=0.4×0.5=0.2P(A \cap B) = 0.4 \times 0.5 = 0.2
Multiplying 0.4 by 0.5 gives 0.2.

Anahtar Kavram

Multiplication Law of Probability for Independent Events
Soru 4174Soru

The sum of the first nn terms of an arithmetic progression is given by Sn=2n2+3nS_n = 2n^2 + 3n. What is the value of the 7th7^{\text{th}} term of the progression?

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Cevap: 29

Cevap

The 7th7^{\text{th}} term of the arithmetic progression is 2929.
For any sequence, the nn-th term is found using Tn=SnSn1T_n = S_n - S_{n-1}. Substituting n=7n = 7 gives S7=2(7)2+3(7)=119S_7 = 2(7)^2 + 3(7) = 119 and S6=2(6)2+3(6)=90S_6 = 2(6)^2 + 3(6) = 90. Thus, T7=11990=29T_7 = 119 - 90 = 29.

Adım Adım Çözüm

1
State the relationship between the nn-th term TnT_n and the sum of first nn terms SnS_n
Tn=SnSn1T_n = S_n - S_{n-1}
The sum of the first nn terms minus the sum of the first n1n-1 terms equals the nn-th term.
2
Calculate the sum of the first 7 terms (S7S_7)
S7=2(7)2+3(7)=119S_7 = 2(7)^2 + 3(7) = 119
Substitute n=7n = 7 into the sum formula Sn=2n2+3nS_n = 2n^2 + 3n.
3
Calculate the sum of the first 6 terms (S6S_6)
S6=2(6)2+3(6)=90S_6 = 2(6)^2 + 3(6) = 90
Substitute n=6n = 6 into the sum formula Sn=2n2+3nS_n = 2n^2 + 3n.
4
Compute the 7th7^{\text{th}} term (T7T_7)
T7=11990=29T_7 = 119 - 90 = 29
Subtract S6S_6 from S7S_7.

Anahtar Kavram

Relationship between the nth term and the sum of first n terms of an AP
Soru 4175Soru

A curve is defined by the equation y=x3+px2+qx+5y = x^3 + px^2 + qx + 5, where pp and qq are constants. If the curve has a stationary point with a local maximum at x=1x = -1 and a local minimum at x=3x = 3, what is the value of p+qp + q?

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Cevap: 12-12

Cevap

The value of p+qp + q is 12-12.
The derivative of y=x3+px2+qx+5y = x^3 + px^2 + qx + 5 is dydx=3x2+2px+q\frac{dy}{dx} = 3x^2 + 2px + q. Setting dydx=0\frac{dy}{dx} = 0 at the stationary points x=1x = -1 and x=3x = 3 means dydx=3(x+1)(x3)=3x26x9\frac{dy}{dx} = 3(x + 1)(x - 3) = 3x^2 - 6x - 9. Comparing coefficients gives 2p=6    p=32p = -6 \implies p = -3 and q=9q = -9. Summing these constants gives p+q=12p + q = -12. Evaluating the second derivative d2ydx2=6x+2p=6x6\frac{d^2y}{dx^2} = 6x + 2p = 6x - 6 confirms a maximum at x=1x = -1 (d2ydx2=12<0\frac{d^2y}{dx^2} = -12 < 0) and a minimum at x=3x = 3 (d2ydx2=12>0\frac{d^2y}{dx^2} = 12 > 0).

Adım Adım Çözüm

1
Find the derivative of the given function.
dydx=3x2+2px+q\frac{dy}{dx} = 3x^2 + 2px + q
Stationary points occur where the first derivative dydx=0\frac{dy}{dx} = 0.
2
Use the stationary points x=1x = -1 and x=3x = 3 to form a quadratic equation for the derivative.
dydx=3(x+1)(x3)=3(x22x3)=3x26x9\frac{dy}{dx} = 3(x + 1)(x - 3) = 3(x^2 - 2x - 3) = 3x^2 - 6x - 9
Since x=1x = -1 and x=3x = 3 are roots of dydx=0\frac{dy}{dx} = 0, the derivative must factor as 3(x(1))(x3)3(x - (-1))(x - 3).
3
Equate coefficients of the two derivative expressions to solve for pp and qq.
2p=6    p=32p = -6 \implies p = -3 and q=9q = -9
Matching corresponding terms gives 2p=62p = -6 and q=9q = -9.
4
Calculate the required sum p+qp + q.
p+q=3+(9)=12p + q = -3 + (-9) = -12
Summing the calculated constants yields 12-12.

Anahtar Kavram

Determining parameters of a polynomial function from given stationary points using differentiation and coefficient matching.
Soru 4176Soru

The mean mark of a student in 66 tests is 1414. When the highest and lowest marks, which differ by 1212, are excluded, the mean mark of the remaining 44 tests becomes 13.513.5. What is the highest mark?

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Cevap: 21

Cevap

The highest mark is 21.
The total sum of all 6 tests is 6×14=846 \times 14 = 84. When the highest (HH) and lowest (LL) marks are removed, the total sum of the remaining 4 tests is 4×13.5=544 \times 13.5 = 54. The sum of the excluded marks is H+L=8454=30H + L = 84 - 54 = 30. Knowing that their difference is HL=12H - L = 12, we add the two equations to get 2H=422H = 42, which gives H=21H = 21.

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1
Calculate the total sum of all 6 test marks
Sum of 6 marks = 6×14=846 \times 14 = 84
The sum of data values equals the mean multiplied by the number of items.
2
Calculate the sum of the remaining 4 test marks
Sum of 4 marks = 4×13.5=544 \times 13.5 = 54
Multiplying the new mean by 4 gives the sum of the test scores excluding the highest and lowest values.
3
Determine the combined sum of the highest (H) and lowest (L) marks
H + L = 84 - 54 = 30
Subtracting the sum of the 4 remaining marks from the total initial sum yields the sum of the two excluded marks.
4
Solve for H using the simultaneous linear equations
H = 21
Adding H + L = 30 and H - L = 12 gives 2H = 42, which solves to H = 21.

Anahtar Kavram

Mean of Ungrouped Data and Handling Excluded Values
Soru 4177Soru

The sum of the first nn terms of an arithmetic progression (A.P.) is 210210. If the first term is 33 and the last term is 3939, what is the value of nn?

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Cevap: 10

Cevap

The number of terms nn is 1010.
Using the standard sum formula Sn=n2(a+l)S_n = \frac{n}{2}(a + l) for an A.P. with known first term a=3a = 3 and last term l=39l = 39, we set 210=n2(3+39)=21n210 = \frac{n}{2}(3 + 39) = 21n. Solving for nn gives n=10n = 10.

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1
Identify the given parameters of the arithmetic progression.
First term a=3a = 3, last term l=39l = 39, and sum Sn=210S_n = 210.
These values are required to apply the sum formula for an A.P.
2
Apply the sum formula Sn=n2(a+l)S_n = \frac{n}{2}(a + l).
210=n2(3+39)=n2(42)=21n210 = \frac{n}{2}(3 + 39) = \frac{n}{2}(42) = 21n.
The sum of nn terms in an A.P. with a known first and last term is given by n2(a+l)\frac{n}{2}(a + l).
3
Solve for nn.
n=21021=10n = \frac{210}{21} = 10.
Dividing the total sum by 2121 gives the exact number of terms.

Anahtar Kavram

Sum of an Arithmetic Progression using first and last terms
Tahmini Süre:1m 30s
Soru 4178Soru

A convex polygon has 5454 diagonals. How many distinct triangles can be formed by joining any three of its vertices?

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Cevap: 220

Cevap

220 distinct triangles
Solving the equation for the number of diagonals n(n3)2=54\frac{n(n-3)}{2} = 54 yields n=12n = 12 vertices. The number of triangles that can be formed by selecting any 3 of these 12 vertices is given by (123)=12×11×106=220\binom{12}{3} = \frac{12 \times 11 \times 10}{6} = 220.

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1
Determine the number of vertices nn of the polygon using the diagonals formula.
n=12n = 12
The number of diagonals DD in an nn-sided convex polygon is given by D=(n2)n=n(n3)2D = \binom{n}{2} - n = \frac{n(n-3)}{2}. Setting n(n3)2=54\frac{n(n-3)}{2} = 54 gives n23n108=0n^2 - 3n - 108 = 0. Factoring (n12)(n+9)=0(n - 12)(n + 9) = 0 yields n=12n = 12 since the number of vertices must be positive.
2
Calculate the number of distinct triangles formed by choosing 3 vertices from 12.
220220
Each set of 3 distinct vertices forms one unique triangle. The order in which the vertices are chosen does not matter, so we use combinations: (123)=12×11×103×2×1=220\binom{12}{3} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220.

Anahtar Kavram

Combinations applied to geometric figures and polygon properties
Tahmini Süre:2m 0s
Soru 4179Soru

Complete the statement below by identifying the correct figure of speech. Which literary device is demonstrated in the sentence?

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When the veteran described his traumatic combat experiences as merely 'a bit of an inconvenience', he was making use of .
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Cevap

The correct figure of speech to complete the sentence is 'understatement' (or 'litotes').
Understatement is a figure of speech in which a situation is intentionally presented as less important, smaller, or less severe than it really is. Describing traumatic combat as merely 'a bit of an inconvenience' deliberately downplays the severity to achieve emphasis.

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1
Analyze the expression used in the sentence
The phrase 'a bit of an inconvenience' intentionally minimizes the severity of 'traumatic combat experiences'.
Recognizing the deliberate contrast between the magnitude of the situation and the mildness of the expression.
2
Identify the literary device
Representing something as much less intense or severe than it actually is constitutes an understatement.
Matching the definition of understatement to the contextual meaning of the excerpt.

Anahtar Kavram

Understatement (and Litotes) as a figure of speech used to intentionally minimize expression for emphasis or effect.
Tahmini Süre:45s
Soru 4180Soru

Using differentiation from first principles, what is the derivative of the function f(x)=x2+3xf(x) = x^2 + 3x with respect to xx?

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Cevap: 2x+32x + 3

Cevap

2x+32x + 3
Applying the first principles limit formula limh0f(x+h)f(x)h\lim_{h \to 0} \frac{f(x+h) - f(x)}{h} gives x2+2xh+h2+3x+3h(x2+3x)h=2xh+h2+3hh=2x+h+3\frac{x^2 + 2xh + h^2 + 3x + 3h - (x^2 + 3x)}{h} = \frac{2xh + h^2 + 3h}{h} = 2x + h + 3. As h0h \to 0, this expression evaluates to 2x+32x + 3.

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1
Set up the difference quotient using the definition of differentiation from first principles
\frac{f(x+h) - f(x)}{h} = \frac{[(x+h)^2 + 3(x+h)] - [x^2 + 3x]}{h}
The definition of derivative from first principles requires finding limh0f(x+h)f(x)h\lim_{h \to 0} \frac{f(x+h) - f(x)}{h}.
2
Expand algebraic terms in the numerator
\frac{x^2 + 2xh + h^2 + 3x + 3h - x^2 - 3x}{h}
Expanding (x+h)2=x2+2xh+h2(x+h)^2 = x^2 + 2xh + h^2 and 3(x+h)=3x+3h3(x+h) = 3x + 3h allows terms to be combined.
3
Simplify the numerator by canceling like terms and dividing by hh
\frac{2xh + h^2 + 3h}{h} = 2x + h + 3
The terms x2x2=0x^2 - x^2 = 0 and 3x3x=03x - 3x = 0 cancel out, leaving terms containing hh, which can be divided by hh.
4
Evaluate the limit as h0h \to 0
\lim_{h \to 0} (2x + h + 3) = 2x + 3
Setting h=0h = 0 in the simplified quotient yields the final derivative f(x)=2x+3f'(x) = 2x + 3.

Anahtar Kavram

Differentiation from first principles
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