Tüm alıştırma soruları

13931 soru

Soru 6021Soru

Sunrise Recreation Club received ₦500,000 as entrance fees during the financial year. According to the club's constitution, 60% of entrance fees are to be capitalized, with the remainder recognized as revenue income. What amount (in ₦) should be credited to the Income and Expenditure Account for the year?

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Cevap: 200000

Cevap

₦200,000 should be credited to the Income and Expenditure Account.
When a non-profit organization's policy specifies that a portion of entrance fees should be capitalized, only the remaining percentage is treated as revenue income. Subtracting the 60% capital portion leaves 40% for revenue income. 40% of ₦500,000 equals ₦200,000, which is credited to the Income and Expenditure Account.

Adım Adım Çözüm

1
Determine the proportion of entrance fees treated as revenue income
40% (since 60% is capitalized, 100% - 60% = 40%)
Only the non-capitalized portion of entrance fees is recognized as revenue income in the Income and Expenditure Account.
2
Calculate the monetary amount of the revenue portion
���200,000
40% of ₦500,000 = 0.40 × 500,000 = ₦200,000

Anahtar Kavram

Treatment of Entrance Fees in Non-Profit Organizations
Soru 6022Soru

The interior of the Earth is divided into distinct structural layers based on physical properties and chemical composition. Which semi-fluid layer, located within the upper mantle directly beneath the rigid outer shell, provides the plastic medium that enables tectonic plate movements?

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Cevap: Asthenosphere

Cevap

Asthenosphere
The asthenosphere lies directly beneath the lithosphere in the upper mantle (between approximately 100 km and 200 km below the surface). Its high temperatures and pressure render it plastic and ductile, enabling convection currents that move tectonic plates above it.

Adım Adım Çözüm

1
Identify the target structural layer described in the stem.
The stem describes a semi-fluid layer situated in the upper mantle below the solid crust.
Understanding the physical state of each layer is essential to distinguishing internal Earth structures.
2
Distinguish between the rigid lithosphere and the plastic asthenosphere.
The lithosphere floats on top of the ductile, semi-molten asthenosphere.
Convection currents within the asthenosphere drive lithospheric plate movement.

Anahtar Kavram

Internal Structure of the Earth - Asthenosphere vs Lithosphere
Soru 6023Soru

What is the ground-state electronic configuration of the iron(II) ion, Fe2+Fe^{2+}? (Atomic number of Fe=26Fe = 26)

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Cevap: 1s22s22p63s23p63d61s^2 2s^2 2p^6 3s^2 3p^6 3d^6

Cevap

The ground-state electronic configuration of Fe2+Fe^{2+} is 1s22s22p63s23p63d61s^2 2s^2 2p^6 3s^2 3p^6 3d^6 (or [Ar]3d6[Ar] 3d^6).
The correct configuration is 1s22s22p63s23p63d61s^2 2s^2 2p^6 3s^2 3p^6 3d^6. Neutral iron has 26 electrons with the configuration 1s22s22p63s23p64s23d61s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^6. Upon forming the Fe2+Fe^{2+} ion, two electrons are removed from the outermost shell (n=4n=4, the 4s4s orbital), leaving 24 electrons and a 3d63d^6 valence structure.

Adım Adım Çözüm

1
Determine the electronic configuration of the neutral iron atom (FeFe, Z=26Z = 26).
The neutral configuration is 1s22s22p63s23p64s23d61s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^6.
Electrons fill subshells in order of increasing energy according to the Aufbau principle.
2
Determine which electrons are lost when forming the Fe2+Fe^{2+} cation.
Two electrons are removed from the principal energy level with the highest quantum number (n=4n = 4), which is the 4s4s subshell.
Transition metals lose their outermost 4s4s electrons first upon ionization because 4s4s electrons experience greater shielding and are higher in energy once subshells are populated.
3
Write the resulting configuration for Fe2+Fe^{2+}.
1s22s22p63s23p63d61s^2 2s^2 2p^6 3s^2 3p^6 3d^6.
Removing two electrons from 4s24s^2 leaves an empty 4s4s orbital and retains six electrons in the 3d3d subshell.

Anahtar Kavram

Cation formation in d-block transition elements requires losing nsns electrons before (n1)d(n-1)d electrons.
Tahmini Süre:45s
Soru 6024Soru

At the end of the financial year, Adebayo Stores extracted the following balances from its financial records:

- Trade Debtors: 85,000\text{₦}85,000
- Bad debts to be written off: ��5,000\text{��}5,000

The business policy requires creating a 10%10\% Provision for Doubtful Debts and a 5%5\% Provision for Discount on Debtors. What is the correct amount to be recognized as the Provision for Discount on Debtors?

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Cevap: 3,600\text{₦}3,600

Cevap

The provision for discount on debtors is 3,600\text{₦}3,600.
The provision for discount on debtors is computed on net good debtors. Subtracting bad debts (5,000\text{₦}5,000) gives 80,000\text{₦}80,000. Deducting the 10%10\% doubtful debts provision (8,000\text{₦}8,000) leaves 72,000\text{₦}72,000. Applying 5%5\% to 72,000\text{₦}72,000 yields 3,600\text{₦}3,600.

Adım Adım Çözüm

1
Deduct bad debts written off from gross trade debtors to obtain net trade debtors before provisions.
85,0005,000=80,000\text{₦}85,000 - \text{₦}5,000 = \text{₦}80,000
Bad debts written off represent uncollectible debts and must be removed from gross debtors prior to estimating provisions.
2
Calculate the Provision for Doubtful Debts on the adjusted trade debtors balance.
10%×80,000=8,00010\% \times \text{₦}80,000 = \text{₦}8,000
The provision for doubtful debts is calculated on the remaining recoverable debtors.
3
Deduct the provision for doubtful debts from the adjusted trade debtors balance.
80,0008,000=72,000\text{₦}80,000 - \text{₦}8,000 = \text{₦}72,000
Cash discount will only be offered to prompt-paying debtors who are not expected to default.
4
Calculate the Provision for Discount on Debtors on the net estimated good debtors balance.
5%×72,000=3,6005\% \times \text{₦}72,000 = \text{₦}3,600
Provision for discount on debtors must be computed strictly after deducting doubtful debt provisions.

Anahtar Kavram

Accounting order of adjustments for trade debtors: Bad Debts Written Off → Provision for Doubtful Debts → Provision for Discount on Debtors.
Tahmini Süre:1m 30s
Soru 6025Soru

A proposed power transmission line measures 14.4 cm14.4\text{ cm} on Map X, which is drawn to a Representative Fraction (RF) scale of 1:250,0001 : 250,000. The same power line is subsequently transferred to Map Y, where its total path is measured across two contiguous sections: a straight stretch of 8.0 cm8.0\text{ cm} and a curved section of 10.0 cm10.0\text{ cm}. What is the denominator of the Representative Fraction (RF) scale of Map Y?

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Cevap: 200000

Cevap

The denominator of the Representative Fraction (RF) scale of Map Y is 200,000 (representing a scale of 1:200,0001 : 200,000).
Because ground distance remains constant, the actual distance is 14.4 cm×250,000=3,600,000 cm14.4\text{ cm} \times 250,000 = 3,600,000\text{ cm}. On Map Y, the total route length is 8.0 cm+10.0 cm=18.0 cm8.0\text{ cm} + 10.0\text{ cm} = 18.0\text{ cm}. Dividing 3,600,000 cm3,600,000\text{ cm} by 18.0 cm18.0\text{ cm} gives a scale denominator of 200,000200,000, which corresponds to a scale of 1:200,0001 : 200,000.

Adım Adım Çözüm

1
Calculate the actual ground distance using the length on Map X and its scale
Ground distance = 14.4 cm×250,000=3,600,000 cm14.4\text{ cm} \times 250,000 = 3,600,000\text{ cm} (or 36 km36\text{ km})
Map scale defines the relationship between map distance and ground distance: Ground distance=Map distance×Scale denominator\text{Ground distance} = \text{Map distance} \times \text{Scale denominator}.
2
Determine the total measured length of the route on Map Y
Total distance on Map Y = 8.0 cm+10.0 cm=18.0 cm8.0\text{ cm} + 10.0\text{ cm} = 18.0\text{ cm}
The entire feature consists of two contiguous sections that must be added together.
3
Calculate the RF scale denominator of Map Y
RF denominator = 3,600,000 cm18.0 cm=200,000\frac{3,600,000\text{ cm}}{18.0\text{ cm}} = 200,000
The scale denominator is the ratio of ground distance to map distance when both are expressed in the same unit.

Anahtar Kavram

Ground distance conservation across maps of differing scales and multi-segment scale denominator calculation.
Tahmini Süre:2m 30s
Soru 6026Soru

The Earth's internal energy drives tectonic movements while external processes constantly reshape the lithosphere. Which of the following correctly identifies the semi-fluid internal layer that enables tectonic plate motion, alongside the external process responsible for the strictly in-situ disintegration of exposed surface rocks?

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Cevap: Asthenosphere and weathering

Cevap

Asthenosphere and weathering
The asthenosphere is the plastic, semi-fluid upper mantle region that permits lithospheric motion, while weathering is the external process responsible for the in-situ disintegration of rock material.

Adım Adım Çözüm

1
Identify the internal structural layer responsible for plate mobility
The asthenosphere is the ductile, partially molten zone of the upper mantle (extending approximately 100 to 200 km beneath the surface) that allows overlying rigid plates to move.
Convection currents within the asthenosphere provide the mechanical drive for tectonic plate displacement.
2
Identify the external process defined by in-situ rock breakdown
Weathering is the static mechanical breakdown or chemical decay of rocks at their original location.
Unlike mass wasting or erosion, weathering involves no significant displacement or transport of material.

Anahtar Kavram

Internal mantle layers (asthenosphere) and external denudational processes (weathering)
Soru 6027Soru

A proposed pipeline route between two water reservoirs measures 18 cm18\text{ cm} on a regional map drawn to a statement scale of 5 cm to 2 km5\text{ cm to } 2\text{ km}. If this map is reduced to a Representative Fraction (RF) scale of 1:100,0001 : 100,000, what will be the length of the pipeline route on the reduced map?

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Cevap: 7.2 cm7.2\text{ cm}

Cevap

7.2 cm7.2\text{ cm}
The original statement scale of 5 cm to 2 km5\text{ cm to } 2\text{ km} means each centimeter on the map corresponds to 0.4 km0.4\text{ km} on the ground. An 18 cm18\text{ cm} line therefore represents a total ground distance of 18×0.4 km=7.2 km18 \times 0.4\text{ km} = 7.2\text{ km}. On the new map with an RF scale of 1:100,0001 : 100,000, 1 cm1\text{ cm} represents 100,000 cm100,000\text{ cm} (or 1 km1\text{ km}). Converting the 7.2 km7.2\text{ km} ground distance onto the new map gives 7.2 km1 km/cm=7.2 cm\frac{7.2\text{ km}}{1\text{ km/cm}} = 7.2\text{ cm}.

Adım Adım Çözüm

1
Determine the ground distance represented by 1 cm1\text{ cm} on the original map scale.
Since 5 cm=2 km5\text{ cm} = 2\text{ km}, 1 cm=2 km5=0.4 km1\text{ cm} = \frac{2\text{ km}}{5} = 0.4\text{ km} (or 40,000 cm40,000\text{ cm}, giving an RF scale of 1:40,0001 : 40,000).
Converting statement scale to ground distance per centimeter establishes the actual linear distance on Earth.
2
Calculate the actual ground distance of the pipeline route.
\text{Ground Distance} = 18\text{ cm} \times 0.4\text{ km/cm} = 7.2\text{ km}(or (or 720,000\text{ cm}$).
Multiplying the map measurement by the ground equivalence per centimeter yields the true distance.
3
Calculate the new map length on the reduced map of scale 1:100,0001 : 100,000.
On an RF scale of 1:100,0001 : 100,000, 1 cm=100,000 cm=1 km1\text{ cm} = 100,000\text{ cm} = 1\text{ km}. Therefore, \text{New Map Length} = \frac{7.2\text{ km}}{1\text{ km/cm}} = 7.2\text{ cm}$.
Dividing the true ground distance by the new scale factor gives the updated map distance.

Anahtar Kavram

Map scale conversion between statement scale and Representative Fraction (RF), and linear distance scaling.
Soru 6028Soru

The adjusted cash book of Kalu Traders shows a debit (favourable) balance of NGN 25,000\text{NGN } 25,000. Unpresented cheques total NGN 4,000\text{NGN } 4,000, while uncredited lodgements amount to NGN 3,000\text{NGN } 3,000. What is the balance as per the bank statement?

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Cevap: \text{NGN } 26,000

Cevap

The balance as per the bank statement is NGN 26,000\text{NGN } 26,000.
To reconcile from an adjusted cash book debit balance to the bank statement balance, unpresented cheques are added because the bank has not yet deducted these payments, while uncredited lodgements are subtracted because the bank has not yet credited these deposits. Computing NGN 25,000+NGN 4,000NGN 3,000\text{NGN } 25,000 + \text{NGN } 4,000 - \text{NGN } 3,000 gives NGN 26,000\text{NGN } 26,000.

Adım Adım Çözüm

1
Identify the starting balance and reconciling items
Adjusted Cash Book Balance = NGN 25,000\text{NGN } 25,000; Unpresented Cheques = NGN 4,000\text{NGN } 4,000; Uncredited Lodgements = NGN 3,000\text{NGN } 3,000.
These items represent timing differences between the Cash Book and the Bank Statement.
2
Add unpresented cheques to the cash book balance
NGN 25,000+NGN 4,000=NGN 29,000\text{NGN } 25,000 + \text{NGN } 4,000 = \text{NGN } 29,000.
Unpresented cheques have been credited in the cash book but not yet debited by the bank, so they increase the bank statement balance relative to the cash book.
3
Deduct uncredited lodgements from the total
NGN 29,000NGN 3,000=NGN 26,000\text{NGN } 29,000 - \text{NGN } 3,000 = \text{NGN } 26,000.
Uncredited lodgements have been debited in the cash book but not yet credited by the bank, so they must be subtracted when reconciling from the cash book to the bank statement.

Anahtar Kavram

Reconciliation of Adjusted Cash Book Balance to Bank Statement Balance
Tahmini Süre:45s
Soru 6029Soru

Chidi appointed Emeka as his commercial agent to sell a fleet of haulage trucks. Before Emeka could negotiate or complete any contract with prospective buyers, Chidi was formally declared bankrupt by a court of competent jurisdiction. Which of the following best describes the legal status of the agency relationship?

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Cevap: The agency is automatically terminated by operation of law upon the principal's bankruptcy.

Cevap

The agency is automatically terminated by operation of law upon the principal's bankruptcy.
Under the Law of Agency, bankruptcy of the principal automatically terminates the agency by operation of law. Because a bankrupt individual loses the legal capacity to control or alienate their property, any authority granted to an agent regarding that property ceases instantly.

Adım Adım Çözüm

1
Identify the cause of termination in the scenario
The principal was legally declared bankrupt before the transaction was executed.
Determining whether the terminating event is an act of the parties or an event operating by law is essential.
2
Apply the rules of Law of Agency regarding termination by operation of law
Bankruptcy of the principal divests the principal of ownership and legal control over their assets, placing them in the hands of a trustee.
An agent cannot possess greater legal power over property than the principal currently holds.
3
Select the option reflecting automatic legal termination
The agency relationship terminates automatically without needing personal notice or mutual agreement.
Operation of law revokes authority instantly upon the legal decree of bankruptcy.

Anahtar Kavram

Termination of Agency by Operation of Law
Tahmini Süre:1m 0s
Soru 6030Soru

A trading business records its daily credit sales and customer returns in specialized books of prime entry. Match each accounting document or transaction summary on the left with its corresponding book of original entry or ledger posting rule on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Credit note issued to a debtor for returned goods
Duplicate invoice issued to a customer for credit sales
Monthly total of the Sales Day Book
Monthly total of the Returns Inward Day Book

Eşleşmeler

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Cevap

Credit note matches with source document for the Sales Returns Journal; duplicate invoice matches with source document for the Sales Journal; monthly total of the Sales Day Book matches with credited to the Sales Account in the General Ledger; monthly total of the Returns Inward Day Book matches with debited to the Sales Returns Account in the General Ledger.
The accounting entries and source documents are properly paired based on standard double-entry bookkeeping rules: credit notes document returns inward, sales invoices document credit sales, the Sales Day Book total increases revenue via a credit to the Sales Account, and the Returns Inward Day Book total reduces revenue via a debit to the Sales Returns Account.

Adım Adım Çözüm

1
Identify the source document for returns inward
A credit note issued to a debtor is matched to the Sales Returns Journal.
Credit notes serve as written evidence for reducing a customer's debt following a return of merchandise.
2
Identify the source document for credit sales
A duplicate sales invoice issued to a customer is matched to the Sales Journal.
Outward sales invoices provide proof of goods delivered on credit and detail the amount owed by the buyer.
3
Determine general ledger double entry for total credit sales
The periodic total of the Sales Day Book is credited to the Sales Account in the General Ledger.
Individual debtors are debited in the Sales Ledger, so the total revenue generated is credited to the main Sales Account.
4
Determine general ledger double entry for total sales returns
The periodic total of the Returns Inward Day Book is debited to the Sales Returns Account in the General Ledger.
Sales returns reduce total gross sales revenue and carry a debit balance in the general ledger.

Anahtar Kavram

Books of Original Entry and General Ledger Posting Rules for Sales and Sales Returns
Tahmini Süre:1m 30s
Soru 6031Soru

In the geomorphic development of a karst landscape, groundwater percolating through well-jointed limestone dissolves calcium carbonate to form distinct subterranean and surface features. Which of the following sequences correctly orders the evolutionary stages of these landforms from initial surface solution to the most advanced stage of cavern collapse?

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Cevap: Swallow hole (gripe) → Doline → Underground cavern excavation → Polje with karst window

Cevap

The correct sequence begins with a swallow hole (gripe), followed by doline expansion, underground cavern excavation, and ultimately the formation of a polje with a karst window.
The correct answer accurately outlines the progressive development of limestone terrain under the action of underground water. Surface runoff enters enlarged joints at a swallow hole, expands surface hollows into dolines, excavates subterranean caverns through carbonation, and eventually causes roof collapses that expose underground streams via karst windows and form extensive flat-floored poljes.

Adım Adım Çözüm

1
Identify the primary chemical weathering process
Groundwater reacts with carbon dioxide to form weak carbonic acid, dissolving calcium carbonate along limestone joint planes.
Karst landforms develop predominantly through solution (carbonation) by underground water.
2
Trace the initial surface entry points of water
Surface streams disappear underground via sinkholes or swallow holes (gripes).
Joint enlargement at the surface diverts surface runoff into subterranean drainage systems.
3
Analyze intermediate subterranean and surface collapse features
Solution hollows enlarge into dolines, while continuous subterranean solution hollows out massive caverns.
Subterranean stream flow enlarges underground passages along bedding planes and vertical joints.
4
Determine the advanced/mature stage landforms
Cavern roofs collapse to expose underground rivers (karst windows) and create expansive flat-floored depressions (poljes).
Extensive structural collapse of roof rocks marks the late stage of karst landscape evolution.

Anahtar Kavram

Karst Geomorphology and Subterranean Landform Evolution
Tahmini Süre:1m 30s
Soru 6032Soru

Femi and Ibrahim entered into a joint venture to trade in surplus industrial machinery, maintaining a separate set of books. They agreed to share profits and losses in the ratio of 3:23:2, respectively. They opened a Joint Bank account with initial contributions of 1,200,000\text{₦}1,200,000 from Femi and 800,000\text{₦}800,000 from Ibrahim. Purchases paid directly from the Joint Bank amounted to 1,500,000\text{₦}1,500,000, while Femi supplied additional goods from his own business stock valued at 300,000\text{₦}300,000. Ibrahim paid carriage and handling expenses of 100,000\text{₦}100,000 from his personal bank account, and general venture expenses of 150,000\text{₦}150,000 were paid out of the Joint Bank. Femi was entitled to a management commission of 5%5\% on total gross sales proceeds. Total sales cash proceeds deposited into the Joint Bank were 2,400,000\text{₦}2,400,000, and the remaining unsold inventory was taken over by Ibrahim at an agreed valuation of 200,000\text{₦}200,000. What is the final amount in Naira (\text{₦}) payable to Femi from the Joint Bank Account upon final cash settlement?

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Cevap: 1878000

Cevap

The final amount payable to Femi from the Joint Bank Account upon settlement is ₦1,878,000.
To find the amount payable to Femi, compute the Net Profit of the Joint Venture Account first. Total credits are ₦2,600,000 (sales of ₦2,400,000 plus inventory taken over by Ibrahim at ₦200,000). Total debits are ₦2,170,000 (purchases ₦1,500,000 + stock supplied by Femi ₦300,000 + expenses by Ibrahim ₦100,000 + Joint Bank expenses ₦150,000 + Femi's commission of ₦120,000). The net venture profit is ₦430,000, of which Femi receives 3/5 = ₦258,000. Adding all amounts due to Femi in his personal account (Capital ₦1,200,000 + Goods ₦300,000 + Commission ₦120,000 + Profit Share ₦258,000) gives a final settlement of ₦1,878,000.

Adım Adım Çözüm

1
Calculate Femi's management commission
₦120,000
Management commission is 5% of total gross sales proceeds of ₦2,400,000.
2
Calculate total credits in the Joint Venture Account
₦2,600,000
Total revenue includes cash sales deposited into Joint Bank (₦2,400,000) plus inventory taken over by Ibrahim (₦200,000).
3
Calculate total debits in the Joint Venture Account
₦2,170,000
Sum of purchases (₦1,500,000), goods supplied by Femi (₦300,000), expenses by Ibrahim (₦100,000), Joint Bank expenses (₦150,000), and commission (₦120,000).
4
Calculate net profit of the joint venture
₦430,000
Net Profit = Total Credits (₦2,600,000) - Total Debits (₦2,170,000).
5
Determine Femi's share of net profit
₦258,000
Femi's ratio is 3/5 of ₦430,000.
6
Determine final cash payable to Femi from Femi's Personal Account
₦1,878,000
Femi's credit balance = Capital (₦1,200,000) + Stock supplied (₦300,000) + Commission (₦120,000) + Share of profit (₦258,000).

Anahtar Kavram

Final settlement calculation in Joint Venture accounting under the separate set of books method
Soru 6033Soru

Read the unseen passage below carefully:

As the final bell echoed through the empty corridors, Mr. Okon stood by his desk, neatly stacking the uncollected report cards. He lingered at Nduka's file, tracing the sharp decline in grades over the last term, right beside the note detailing the boy's recent night shifts at the timber market. Shaking his head softly, Mr. Okon placed a fresh notebook inside Nduka's locker before locking the classroom door.

From the passage above, what can be deduced about Mr. Okon's attitude toward Nduka?

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Cevap: He is compassionate and quietly supportive of Nduka despite his academic decline.

Cevap

Mr. Okon is compassionate and quietly supportive of Nduka despite his academic decline.
The correct answer reflects Mr. Okon's empathetic understanding. His soft reaction upon reading about Nduka's night shifts, coupled with leaving a gift of a fresh notebook, directly implies compassion and quiet encouragement rather than resentment or hostility.

Adım Adım Çözüm

1
Analyze the passage for details regarding Mr. Okon's actions and reactions.
Mr. Okon lingers over Nduka's file, reads the note explaining his night shifts at the timber market, shakes his head softly, and places a new notebook in Nduka's locker.
Inferences must be grounded directly in textual details.
2
Deduce the underlying emotional tone and character motivation from these actions.
Connecting the grade drop to heavy nighttime labor shows understanding, and leaving a learning resource (notebook) signifies subtle encouragement.
Actions in literary extracts convey unstated character dispositions and attitudes.

Anahtar Kavram

Drawing Inferences and Deductions from Unseen Passages
Tahmini Süre:1m 15s
Soru 6034Soru

The following ledger account balances were extracted from the books of Binta Traders at 31 December 2025:

- Purchases: ₦240,000
- Sales: ₦410,000
- Motor Vehicles (Cost): ₦180,000
- Provision for Depreciation on Motor Vehicles: ₦36,000
- Trade Debtors: ₦75,000
- Trade Creditors: ₦52,000
- Cash at Bank: ₦34,000
- Capital: ₦150,000
- Returns Inwards: ₦14,000
- Returns Outwards: ₦9,000
- Rent and Rates: ₦22,000
- Discount Received: ₦6,000
- Provision for Doubtful Debts: ₦4,000
- Opening Inventory: ₦45,000
- Drawings: ₦18,000

When preparing the trial balance, the bookkeeper inserted a Suspense Account balance to make the total of the debit column equal the total of the credit column. What is the value of the balance (in ��) required in the Suspense Account?

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Cevap: 39000

Cevap

The balance required in the Suspense Account to make the Trial Balance agree is ₦39,000.
The total of all credit balances (Sales ₦410,000 + Provision for Depreciation ₦36,000 + Trade Creditors ₦52,000 + Capital ₦150,000 + Returns Outwards ₦9,000 + Discount Received ₦6,000 + Provision for Doubtful Debts ₦4,000) is ₦667,000. The total of all debit balances (Purchases ₦240,000 + Motor Vehicles ₦180,000 + Trade Debtors ₦75,000 + Cash at Bank ₦34,000 + Returns Inwards ₦14,000 + Rent and Rates ₦22,000 + Opening Inventory ₦45,000 + Drawings ₦18,000) is ₦628,000. The shortfall on the debit side is ₦667,000 - ₦628,000 = ₦39,000, which is the required Suspense Account balance.

Adım Adım Çözüm

1
Classify each ledger account balance into debit or credit columns according to double-entry rules.
Debit Balances: Purchases (₦240,000), Motor Vehicles (₦180,000), Trade Debtors (₦75,000), Cash at Bank (₦34,000), Returns Inwards (₦14,000), Rent and Rates (₦22,000), Opening Inventory (₦45,000), Drawings (₦18,000). Credit Balances: Sales (₦410,000), Provision for Depreciation (₦36,000), Trade Creditors (₦52,000), Capital (₦150,000), Returns Outwards (₦9,000), Discount Received (₦6,000), Provision for Doubtful Debts (₦4,000).
Assets, expenses, drawings, and sales returns carry debit balances, whereas liabilities, capital, revenues, contra-asset provisions, purchase returns, and gains carry credit balances.
2
Sum up the debit balances and credit balances separately.
Total Debits = ₦628,000; Total Credits = ₦667,000.
Comparing both column totals determines the discrepancy in the Trial Balance.
3
Compute the missing Suspense Account balance.
Suspense Account Balance = ₦667,000 - ₦628,000 = ₦39,000.
A debit entry of ₦39,000 is required in the Suspense Account to equalize the debit side with the credit total of ₦667,000.

Anahtar Kavram

Balancing Ledger Accounts and Extracting Trial Balance
Tahmini Süre:2m 0s
Soru 6035Soru

Which of the following processes is primarily responsible for the formation of metamorphic rocks such as marble?

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Cevap: Great heat and pressure acting on existing parent rocks

Cevap

Great heat and pressure acting on existing parent rocks is responsible for the formation of metamorphic rocks.
Metamorphic rocks are created when existing rocks (such as limestone) are subjected to extreme heat and pressure beneath the Earth's crust, recrystallizing the minerals to form new textures (such as marble). Therefore, heat and pressure acting on existing parent rocks correctly describes this formation process.

Adım Adım Çözüm

1
Identify the classification of the rock mentioned
Marble is classified as a metamorphic rock derived from limestone.
Determining the rock group clarifies its mode of origin.
2
Select the geological agent responsible for metamorphism
Intense heat and extreme pressure alter the mineral alignment and texture of existing rocks without melting them.
Metamorphic processes require high temperature and pressure within the crust.

Anahtar Kavram

Metamorphic Rock Formation
Soru 6036Soru

A manufacturing enterprise transfers finished goods from its factory to the trading section at a mark-up of 25%25\% on manufacturing cost. For the financial year ended 31 December 2025, the opening inventory of finished goods at transfer price was 30,000\text{₦}30,000 with an existing provision for unrealized profit of 6,000\text{₦}6,000. The closing inventory of finished goods at transfer price was 45,000\text{₦}45,000. What is the amount of provision for unrealized profit to be debited to the Profit and Loss Account for the year?

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Cevap: 3,000\text{₦}3,000

Cevap

The amount to be debited to the Profit and Loss Account as provision for unrealized profit is 3,000\text{₦}3,000.
To determine the provision for unrealized profit, convert the 25%25\% mark-up on cost to a margin on transfer value: 25125=20%\frac{25}{125} = 20\% (or 15\frac{1}{5}). Applying this fraction to the closing inventory transfer value of 45,000\text{₦}45,000 yields a closing provision of 9,000\text{₦}9,000. Subtracting the existing opening provision of 6,000\text{₦}6,000 gives a net increase of 3,000\text{₦}3,000, which is debited to the Profit and Loss Account.

Adım Adım Çözüm

1
Convert mark-up on cost to profit margin on transfer price.
Margin=Mark-up100+Mark-up=25125=15 or 20%\text{Margin} = \frac{\text{Mark-up}}{100 + \text{Mark-up}} = \frac{25}{125} = \frac{1}{5} \text{ or } 20\%.
Because inventory is valued at transfer price, the profit element contained within it must be determined using the margin ratio.
2
Calculate the total provision for unrealized profit required on closing inventory.
Closing Provision=15×45,000=9,000\text{Closing Provision} = \frac{1}{5} \times \text{₦}45,000 = \text{₦}9,000.
This isolates the profit element that remains unrealized in unsold inventory at year-end.
3
Determine the net adjustment required in the Profit and Loss Account.
Increase in Provision=9,0006,000=3,000\text{Increase in Provision} = \text{₦}9,000 - \text{₦}6,000 = \text{₦}3,000.
Only the net increase in the provision from the opening balance (6,000\text{₦}6,000) is charged to the Profit and Loss Account.

Anahtar Kavram

Provision for Unrealized Profit on Closing Inventory
Soru 6037Soru

Emeka and Chidi are partners sharing profits and losses in the ratio 3:13:1. On 1st July 2025, they agree to revalue their assets and liabilities as follows: Machinery recorded at ₦150,000 is revalued to ₦180,000; Furniture recorded at ₦80,000 is revalued to ₦70,000; a provision for doubtful debts of 5%5\% is created on Debtors of ₦60,000; and an unrecorded legal expense of ₦5,000 is recognized. What is Emeka's share of the net revaluation profit or loss?

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Cevap: ₦9,000 profit

Cevap

₦9,000 profit
The net revaluation profit is calculated by subtracting all losses and provisions from the asset appreciation gains: +₦30,000 (Machinery) - ₦10,000 (Furniture) - ₦3,000 (Provision) - ₦5,000 (Legal Expense) = ₦12,000 net profit. Multiplying ₦12,000 by Emeka's share of 3/4 yields ₦9,000 profit.

Adım Adım Çözüm

1
Calculate gains and losses on asset and liability revaluation
Gain on Machinery = ₦180,000 - ₦150,000 = +₦30,000. Loss on Furniture = ₦80,000 - ₦70,000 = -₦10,000. Provision for Doubtful Debts = 5% of ₦60,000 = -₦3,000. Unrecorded Legal Expense = -₦5,000.
Increases in asset values are gains (credited), while decreases in asset values, new provisions, and unrecorded liabilities are losses (debited) in the Revaluation Account.
2
Calculate net profit or loss on revaluation
Net Revaluation Profit = ₦30,000 - ₦10,000 - ₦3,000 - ₦5,000 = ���12,000 profit.
Total gains exceed total losses by ₦12,000, creating a net credit balance in the Revaluation Account.
3
Share the net revaluation profit to Emeka using the old profit-sharing ratio
Emeka's Share = 33+1×12,000=34×12,000=9,000\frac{3}{3 + 1} \times ₦12,000 = \frac{3}{4} \times ₦12,000 = ₦9,000 profit.
Revaluation profit or loss belongs to existing partners and must be divided using their old profit-sharing ratio.

Anahtar Kavram

Revaluation Account Profit Determination and Allocation
Soru 6038Soru

Arrange the principal layers of the Earth's atmosphere in order of increasing altitude, starting from the layer closest to the Earth's surface up to the outer boundary.

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Cevap

The correct atmospheric order from the Earth's surface outward is: Troposphere, Stratosphere, Mesosphere, and Thermosphere.
Starting from the Earth's surface moving outward, the atmospheric layers are encountered in sequence based on altitude: Troposphere (0–12 km), Stratosphere (12–50 km), Mesosphere (50–85 km), and Thermosphere (85–600 km).

Adım Adım Çözüm

1
Identify the atmospheric layer touching the Earth's crust
The Troposphere is the lowest atmospheric layer touching the ground.
The Troposphere contains over 75% of atmospheric mass and is adjacent to the surface.
2
Identify the second layer containing the ozone region
The Stratosphere sits immediately above the tropopause.
It extends from ~12 km to 50 km above the surface.
3
Determine the middle layer
The Mesosphere lies between 50 km and 85 km altitude.
It forms the middle layer of the upper atmosphere above the stratopause.
4
Identify the outer high-temperature layer
The Thermosphere extends above 85 km.
It forms the upper structural boundary before merging into the exosphere.

Anahtar Kavram

External Structure of the Earth - Stratification of the Atmosphere
Soru 6039Soru

Geophysical studies reveal that Earth's internal layers are stratified according to their physical properties and chemical compositions. Arrange the following structural layers of the Earth in order of increasing average density, starting from the layer with the lowest density to the layer with the highest density.

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Cevap

The correct sequence from lowest to highest density is: SIAL (Continental Crust) → SIMA (Oceanic Crust) → Asthenosphere (Upper Mantle) → Lower Mantle (Mesosphere) → Barysphere (Inner Core).
Earth's internal structure is naturally arranged by density due to planetary differentiation. The least dense layer at the surface is the granitic SIAL (2.7 g/cm³), followed by the basaltic SIMA (3.0 g/cm³), the semi-plastic asthenosphere in the upper mantle (3.3–3.5 g/cm³), the solid silicate lower mantle (4.5–5.7 g/cm³), and finally the ultra-dense metallic nickel-iron barysphere (12.0–13.0 g/cm³) at the center.

Adım Adım Çözüm

1
Identify the chemical composition and density of the outermost continental crust.
SIAL has the lowest density (~2.7 g/cm³) due to lightweight granitic minerals (silica and aluminium).
Continental crust floats highest on the underlying layers.
2
Determine the relative position and density of the oceanic crust beneath or adjacent to SIAL.
SIMA has a higher density (~3.0 g/cm³) than SIAL because of basaltic composition (silica and magnesium).
Basaltic rocks are denser than granitic rocks.
3
Examine the mantle layers situated beneath the crust.
The asthenosphere (upper mantle) has a density of ~3.3–3.5 g/cm³, while the deeper lower mantle (mesosphere) ranges from ~4.5–5.7 g/cm³.
Density increases with depth in the mantle due to increasing pressure and heavy ultrabasic rock compositions.
4
Identify the innermost core layer density.
The barysphere (core) has the maximum density (~12.0–13.0 g/cm³).
Heavy metallic elements (nickel and iron) concentrated at the center under extreme gravitational pressure.

Anahtar Kavram

Density Stratification of Earth's Layers
Soru 6040Soru

On a topographical map with a scale of 1:50,0001:50,000, Point X is situated on a contour line marked 350 m350\text{ m} and Point Y is situated on a contour line marked 500 m500\text{ m}. If the measured distance between Point X and Point Y on the map is 6 cm6\text{ cm}, what is the gradient of the slope between Point X and Point Y?

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Cevap: 1 in 201\text{ in } 20

Cevap

The gradient of the slope between Point X and Point Y is 1 in 201\text{ in } 20 (or 1:201:20).
The slope gradient is calculated by dividing the Vertical Interval (difference in elevation: 500 m350 m=150 m500\text{ m} - 350\text{ m} = 150\text{ m}) by the Horizontal Equivalent (actual ground distance: 6 cm×50,000=300,000 cm=3,000 m6\text{ cm} \times 50,000 = 300,000\text{ cm} = 3,000\text{ m}). Converting both parameters into meters gives 1503000=120\frac{150}{3000} = \frac{1}{20}, which represents a slope ratio of 1 in 201\text{ in } 20.

Adım Adım Çözüm

1
Calculate the Vertical Interval (VI)
VI=500 m350 m=150 m\text{VI} = 500\text{ m} - 350\text{ m} = 150\text{ m}
The Vertical Interval is the difference in height between the two contour points.
2
Calculate the Horizontal Equivalent (HE) in ground measurement
HE=6 cm×50,000=300,000 cm=3,000 m\text{HE} = 6\text{ cm} \times 50,000 = 300,000\text{ cm} = 3,000\text{ m}
The Representative Fraction scale of 1:50,0001:50,000 means 1 cm1\text{ cm} on the map represents 50,000 cm50,000\text{ cm} (500 m500\text{ m}) on the ground.
3
Calculate the slope gradient formula Gradient=VIHE\text{Gradient} = \frac{\text{VI}}{\text{HE}}
Gradient=150 m3,000 m=120\text{Gradient} = \frac{150\text{ m}}{3,000\text{ m}} = \frac{1}{20}
Dividing the vertical height by the horizontal distance in identical units expresses the slope as a ratio.

Anahtar Kavram

Topographic Slope Gradient Calculation
Tahmini Süre:2m 0s
ÖncekiSayfa 302 / 697Sonraki
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