Heredity and Variation

159 soru

Soru 1Soru

In pea plants (Pisum sativumPisum\ sativum), seed shape and seed color inherit independently according to Mendel's Second Law. If two plants heterozygous for both round seeds (RR) and yellow seeds (YY) are crossed (RrYy×RrYyRrYy \times RrYy), what is the expected phenotypic ratio among the F2F_2 offspring?

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Cevap: 9:3:3:19 : 3 : 3 : 1 (Round Yellow : Round Green : Wrinkled Yellow : Wrinkled Green)

Cevap

The expected phenotypic ratio in the F2F_2 generation of a dihybrid cross (RrYy×RrYyRrYy \times RrYy) is 9:3:3:19 : 3 : 3 : 1.
According to Mendel's Law of Independent Assortment, two pairs of traits segregate independently of each other during gamete formation. Crossing two dihybrids (RrYy×RrYyRrYy \times RrYy) yields 16 total fertilization outcomes. Phenotypically, these break down into 9 dominant-dominant (Round Yellow), 3 dominant-recessive (Round Green), 3 recessive-dominant (Wrinkled Yellow), and 1 recessive-recessive (Wrinkled Green), giving the standard 9:3:3:19 : 3 : 3 : 1 ratio.

Adım Adım Çözüm

1
Determine the gametes produced by each heterozygous parent (RrYyRrYy).
Each parent produces four distinct types of gametes in equal proportions: RYRY, RyRy, rYrY, and ryry.
Mendel's Law of Independent Assortment states that allele pairs separate independently during gamete formation.
2
Combine the gametes in a 4×44 \times 4 Punnett square to find the phenotypic combinations.
Out of 16 total offspring combinations: 9 express both dominant traits (Round Yellow), 3 express dominant seed shape and recessive seed color (Round Green), 3 express recessive seed shape and dominant seed color (Wrinkled Yellow), and 1 expresses both recessive traits (Wrinkled Green).
Dominant alleles (RR and YY) mask the expression of recessive alleles (rr and yy) when present.
3
Write the resulting phenotypic ratio.
The final phenotypic ratio is 9:3:3:19 : 3 : 3 : 1.
Combining independent monohybrid ratios (3:1)×(3:1)(3:1) \times (3:1) yields the classic 9:3:3:19:3:3:1 dihybrid ratio.

Anahtar Kavram

Mendel's Law of Independent Assortment and Dihybrid Phenotypic Ratio
Soru 2Soru

In a diploid cell analyzed during interphase, a specific sequence of nucleotides that governs seed coat structure is situated at a precise, fixed position along a pair of morphologically matching chromosomes. An individual organism carries two different functional variants of this sequence at that position, resulting in different protein products. Which of the following correctly identifies the genetic terms for the matching chromosomes, the specific position, and the alternative sequence variants?

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Cevap: The matching chromosomes are homologous chromosomes, the fixed position is the locus, and the alternative sequence variants are alleles.

Cevap

The matching chromosomes are homologous chromosomes, the fixed position is the locus, and the alternative sequence variants are alleles.
In diploid genetics terminology, matching maternal and paternal chromosome pairs are termed homologous chromosomes. The physical coordinate or position of a gene along the chromosome is called the locus, and the alternative versions of the DNA sequence at that locus are called alleles.

Adım Adım Çözüm

1
Identify the relationship between morphologically matching chromosome pairs in a diploid organism.
Morphologically matching pairs carrying genes for identical traits (one inherited from each parent) are defined as homologous chromosomes.
Diploid organisms inherit one chromosome set from each parent, forming homologous pairs.
2
Determine the term for the fixed physical location of a gene on a chromosome.
The specific physical position occupied by a gene on a chromosome is its locus (plural: loci).
Locus specifically designates physical mapping location on chromosomal DNA.
3
Determine the term for non-identical nucleotide variants of the gene situated at that location.
Alternative forms or variants of a gene occupying the same locus are defined as alleles.
Alleles account for genetic variations in traits.

Anahtar Kavram

Basic Genetics Terminology: Homologous Chromosomes, Locus, and Alleles
Tahmini Süre:1m 30s
Soru 3Soru

A Rhesus-negative woman (rrrr) who did not receive anti-Rh immunoglobulin therapy after giving birth to her first Rhesus-positive child is expecting a second child. The father is Rhesus-positive (RR-), but his mother was Rhesus-negative (rrrr). What is the probability that this second child will suffer from erythroblastosis fetalis, and what physiological mechanism triggers this medical condition?

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Cevap: 50%, because maternal anti-Rh IgG antibodies produced after sensitization during the first delivery cross the placenta and destroy red blood cells if the second fetus inherits the Rhesus-positive allele (RrRr).

Cevap

The probability is 50%, occurring because maternal anti-Rh IgG antibodies cross the placenta and agglutinate fetal red cells if the fetus inherits the Rhesus-positive allele.
The father is heterozygous (RrRr) because his mother was Rhesus-negative (rrrr). A cross between a Rhesus-negative mother (rrrr) and a heterozygous father (RrRr) gives a 50% chance of producing a Rhesus-positive (RrRr) child. Because the mother was sensitized during her first pregnancy with a Rhesus-positive child, her immune system contains anti-Rh IgG antibodies. In a second Rhesus-positive pregnancy, these IgG antibodies cross the placenta and lyse fetal red blood cells, causing erythroblastosis fetalis.

Adım Adım Çözüm

1
Determine parental genotypes for the Rhesus factor.
Mother is Rhesus-negative (rrrr). Father is Rhesus-positive, but since his mother was Rhesus-negative (rrrr), he must be heterozygous (RrRr).
An individual receiving a recessive allele from one parent must carry that allele.
2
Calculate the genetic probability of the fetus inheriting the Rhesus-positive phenotype.
Cross between mother (rrrr) and father (RrRr) yields genotypes 1/2 Rr1/2\ Rr (Rhesus-positive) and 1/2 rr1/2\ rr (Rhesus-negative). Probability of Rhesus-positive fetus = 50%.
Monohybrid testcross of a heterozygote with a homozygous recessive individual.
3
Evaluate the immunological cause of erythroblastosis fetalis in sensitized mothers.
Sensitization occurred during the delivery of the first Rhesus-positive child when fetal RBCs entered maternal circulation, producing anti-Rh IgG antibodies. If the second child is Rhesus-positive (RrRr), maternal anti-Rh IgG antibodies cross the placenta, causing hemolysis.
IgG antibodies cross the placental barrier, whereas IgM antibodies (such as ABO isoagglutinins) generally do not.

Anahtar Kavram

Rhesus Factor Incompatibility and Erythroblastosis Fetalis
Tahmini Süre:2m 0s
Soru 4Soru

Match each parental monohybrid cross of pea plants with its expected offspring genotypic or phenotypic ratio according to Mendel's First Law.

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Öğeler

Homozygous dominant × Homozygous recessive (TT×ttTT \times tt)
Heterozygous × Heterozygous (Tt×TtTt \times Tt)
Heterozygous × Homozygous recessive (Tt×ttTt \times tt)

Eşleşmeler

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Cevap

Homozygous dominant × Homozygous recessive matches 100% Heterozygous (TtTt); Heterozygous × Heterozygous matches 3 : 1 Phenotypic ratio; Heterozygous × Homozygous recessive matches 1 : 1 Genotypic/Phenotypic ratio.
Crossing homozygous dominant (TTTT) with homozygous recessive (tttt) produces uniform TtTt offspring. Crossing two heterozygotes (Tt×TtTt \times Tt) yields the classic Mendelian F2 phenotypic ratio of 3 dominant to 1 recessive. Crossing a heterozygote (TtTt) with a homozygous recessive (tttt) generates equal proportions (1:1) of heterozygous dominant and homozygous recessive phenotypes.

Adım Adım Çözüm

1
Analyze gamete formation for each monohybrid cross based on Mendel's Law of Segregation.
For TT×ttTT \times tt, gametes are TT and tt, producing TtTt. For Tt×TtTt \times Tt, gametes are T,tT, t and T,tT, t, producing 1TT:2Tt:1tt1TT : 2Tt : 1tt (3 dominant : 1 recessive). For Tt×ttTt \times tt, gametes are T,tT, t and tt, producing 1Tt:1tt1Tt : 1tt.
Alleles segregate during gamete formation so that each gamete carries only one allele for a trait.

Anahtar Kavram

Mendel's First Law and Monohybrid Ratios
Soru 5Soru

Consider a diploid organism with the genotype AaBbAaBb, where genes AA and BB are located on separate homologous chromosome pairs. During meiotic prophase I, crossing over does not occur between these loci. Which of the following statements correctly accounts for the relationship between gene loci, alleles, and sister chromatids during gamete formation in this organism?

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Cevap: The alleles AA and aa occupy identical loci on homologous chromosomes, whereas identical copies of allele AA exist on sister chromatids prior to anaphase I segregation.

Cevap

The alleles AA and aa occupy identical loci on homologous chromosomes, whereas identical copies of allele AA exist on sister chromatids prior to anaphase I segregation.
Homologous chromosomes contain corresponding gene loci where alternative alleles (AA and aa) reside. Following S-phase replication prior to meiosis I, each chromosome consists of two sister chromatids carrying identical copies of its allele (e.g., two copies of AA on one chromosome and two copies of aa on its homologue).

Adım Adım Çözüm

1
Analyze the relationship between homologous chromosomes and gene loci.
In diploid organisms, homologous chromosomes occur in pairs, carrying genes for the same traits at identical physical locations termed loci. Therefore, alternative forms of a gene (alleles AA and aa) are located at corresponding loci on paternal and maternal homologous chromosomes.
Establishing the physical location of alleles on homologous chromosomes is essential to distinguish homologous pairs from replicated chromatids.
2
Analyze the composition of sister chromatids following S-phase replication.
During the S phase of interphase, each chromosome replicates to form two sister chromatids joined at the centromere. Sister chromatids carry genetically identical nucleotide sequences and thus identical alleles (e.g., AA and AA).
Differentiating sister chromatids (identical duplicated strands) from homologous chromosomes (maternal and paternal counterparts) prevents confusing allele variation with chromatid duplication.
3
Evaluate independent assortment and locus position for unlinked genes AA and BB.
Genes AA and BB reside on distinct chromosome pairs. They represent separate loci rather than alleles of the same gene locus.
Alleles compete for the same locus, whereas separate genes reside at different loci across the genome.

Anahtar Kavram

Basic Genetics Terminology and Concepts
Soru 6Soru

A survey of students in a secondary school revealed varying physical traits among individuals. Height showed a wide range of values forming a normal distribution, whereas the ABO blood group fell strictly into four distinct categories. Which of the following statements correctly accounts for the genetic basis of these observed variations?

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Cevap: Height exhibits continuous variation controlled polygenically with environmental influence, whereas ABO blood group exhibits discontinuous variation controlled by a single gene.

Cevap

Height exhibits continuous variation controlled polygenically with environmental influence, whereas ABO blood group exhibits discontinuous variation controlled by a single gene.
Continuous variation traits like human height are polygenic and influenced by environmental factors, producing a gradual continuum of phenotypes. Discontinuous variation traits like blood groups are governed by single genes with distinct alleles, producing clear-cut, non-overlapping categories regardless of environmental conditions.

Adım Adım Çözüm

1
Analyze the distribution pattern of height.
Height displays a smooth range of intermediate values forming a normal bell-shaped curve.
Continuous variations show a quantitative spectrum of phenotypes controlled by many additive genes (polygenes) interacting with environmental factors such as diet.
2
Analyze the distribution pattern of ABO blood group.
Blood group phenotypes are distinct and non-overlapping (types A, B, AB, and O).
Discontinuous variations show qualitative differences determined by single gene loci (monogenic inheritance) unaffected by environment.
3
Compare the genetic mechanisms and match the correct statement.
Height is continuous and polygenic; ABO blood group is discontinuous and monogenic.
This accurately reflects phenotypic variation concepts in population genetics.

Anahtar Kavram

Continuous vs Discontinuous Variation
Soru 7Soru

Human blood groups under the ABO system represent continuous variation because they display a smooth spectrum of intermediate phenotypes influenced by environmental factors.

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Cevap: False

Cevap

The statement is false because ABO blood groups exhibit discontinuous variation, characterized by distinct non-overlapping categories controlled by a single gene with no environmental influence.
The statement is false because human ABO blood grouping is a classic example of discontinuous variation. Individuals belong to distinct, non-overlapping phenotypes (A, B, AB, or O) determined strictly by monogenic inheritance without environmental modification.

Adım Adım Çözüm

1
Analyze the nature of the phenotypic distribution of human ABO blood groups.
Individuals fall strictly into one of four distinct categories: A, B, AB, or O, with no intermediate blood types.
Traits showing discrete, non-overlapping categories represent discontinuous variation rather than a continuous spectrum.
2
Evaluate the underlying genetic mechanism and environmental impact on the trait.
ABO blood grouping is inherited monogenically via codominant and recessive alleles (IAI^A, IBI^B, ii) and cannot be altered by environmental factors.
Discontinuous traits are typically controlled by one or two major genes and are not subject to environmental modifications.
3
Determine the accuracy of the given statement.
The statement incorrectly describes ABO blood groups as continuous and environmentally influenced.
Continuous variation applies to polygenic traits like height and skin color which show a normal distribution curve, making the premise false for blood groups.

Anahtar Kavram

Discontinuous variation involves distinct, non-overlapping phenotypic categories controlled by one or a few genes with no environmental influence, whereas continuous variation presents a wide spectrum of intermediate forms controlled by polygenes and influenced by environmental factors.
Tahmini Süre:1m 0s
Soru 8Soru

The ability of an individual to roll the tongue is a physiological trait that exhibits discontinuous variation in human populations.

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Cevap: True

Cevap

The statement is True because tongue rolling is a physiological trait that divides humans into distinct categories without intermediate types.
Tongue rolling is governed by genetic inheritance and results in distinct, non-overlapping phenotypic groups (rollers and non-rollers). Because it reflects functional capability rather than external body measurements, it is correctly classified as a discontinuous physiological variation.

Adım Adım Çözüm

1
Classify the trait type (morphological vs. physiological).
Tongue rolling relates to muscle function and movement capability, making it a physiological trait.
Physiological variation relates to anatomical functioning and biochemical processes rather than general bodily measurements.
2
Determine the distribution type (continuous vs. discontinuous).
Humans are either tongue rollers or non-rollers without intermediate states, confirming a discontinuous pattern.
Discontinuous variation features distinct, clear-cut categories influenced mainly by genetics and unaffected by environment.

Anahtar Kavram

Discontinuous Physiological Variation in Humans
Soru 9Soru

During a practical biology lesson, students recorded various inherited characteristics among their classmates, including height, blood group, fingerprint patterns, and phenylthiocarbamide (PTC) tasting ability. Which of these traits is correctly classified as a physiological variation that exhibits discontinuous variation?

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Cevap: Ability to taste phenylthiocarbamide (PTC)

Cevap

Ability to taste phenylthiocarbamide (PTC)
The ability to taste phenylthiocarbamide (PTC) is a classic example of a physiological variation because it depends on specific chemical receptors on taste buds (a biochemical/functional process). It exhibits discontinuous variation because individuals inherit discrete genotypes resulting in distinct phenotypes (tasters or non-tasters) without any blending or intermediate tasting categories.

Adım Adım Çözüm

1
Distinguish between morphological and physiological variations.
Morphological variations relate to physical appearance and anatomical structure (e.g., fingerprints, height, skin color). Physiological variations relate to internal function, biochemical processes, or behavioral reactions (e.g., blood groups, PTC tasting, tongue rolling).
The question specifically asks for a physiological variation.
2
Distinguish between continuous and discontinuous variation patterns.
Discontinuous variations fall into clear, distinct categories without intermediates (e.g., PTC tasting ability, ABO blood groups), while continuous variations show a complete spectrum of intermediate forms between extremes (e.g., height, weight).
The question requires a trait that shows discontinuous distribution.
3
Combine both criteria to identify the target trait.
PTC tasting is a physiological function (tasting chemical compound) and exhibits clear discontinuous categories (tasters vs non-tasters).
This satisfies both requested conditions simultaneously.

Anahtar Kavram

Human Morphological vs Physiological Variations and Patterns of Variation
Soru 10Soru

In human populations, physical and physiological traits are inherited through different genetic mechanisms. Which of the following characteristics displays continuous variation?

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Cevap: Body mass

Cevap

Body mass
Body mass exhibits continuous variation because it varies quantitatively across a smooth spectrum with intermediate phenotypes, influenced by polygenic inheritance and environmental factors such as diet and lifestyle.

Adım Adım Çözüm

1
Distinguish between continuous and discontinuous variation.
Continuous variation features a continuous range of phenotypes between two extremes, whereas discontinuous variation presents distinct, non-overlapping categories.
Phenotypic distribution depends on whether traits form a spectrum or clear-cut groups.
2
Evaluate each given human trait.
Body mass forms a smooth continuous curve due to polygenic control and environmental interaction. Blood group, tongue rolling, and PTC tasting fall into distinct categories.
Polygenic traits influenced by environmental factors exhibit continuous variation.

Anahtar Kavram

Continuous variation features quantitative differences forming a unbroken spectrum of phenotypes, typically mediated by polygenic inheritance and environmental effects.
Tahmini Süre:45s
Soru 11Soru

Match each human genetic trait on the left with its correct classification of variation on the right.

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Öğeler

ABO blood group system
Human height distribution
Fingerprint ridge pattern
Ability to taste phenylthiocarbamide (PTC)

Eşleşmeler

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Cevap

The ABO blood group system matches discontinuous physiological trait determined by multiple alleles; Human height distribution matches continuous morphological trait controlled by polygenes and environmental factors; Fingerprint ridge pattern matches discontinuous morphological trait that is distinct and unaffected by environment; Ability to taste PTC matches discontinuous physiological trait dividing individuals into distinct taster and non-taster categories.
Each trait is accurately matched according to its classification as either anatomical/structural (morphological) or biochemical/functional (physiological), alongside its pattern of inheritance (continuous spectrum vs. discrete discontinuous categories).

Adım Adım Çözüm

1
Distinguish between morphological traits (physical body structures) and physiological traits (biochemical and functional characteristics).
Height and fingerprints are morphological features; blood group and PTC tasting ability are physiological features.
Morphological traits relate to form and structure, whereas physiological traits relate to chemical function and biological mechanisms.
2
Categorize each feature as displaying continuous (gradient/range) or discontinuous (discrete non-overlapping groups) variation.
Height varies continuously across a spectrum; blood groups, fingerprints, and PTC tasting divide individuals into distinct, non-overlapping categories.
Continuous variation involves polygenic inheritance influenced by environmental factors, while discontinuous variation is typically controlled by one or a few genes with little to no environmental modification.
3
Pair each specified human feature on the left with its full description on the right.
All left items are accurately paired with their corresponding variation profile.
This confirms mastery of human morphological vs. physiological and continuous vs. discontinuous variation concepts.

Anahtar Kavram

Human Morphological vs Physiological Variations and Continuous vs Discontinuous Genetic Patterns
Tahmini Süre:1m 30s
Soru 12Soru

Match each biological trait on the left with its corresponding category of variation and genetic control on the right.

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Öğeler

Human height
ABO blood group
Fingerprint pattern

Eşleşmeler

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Cevap

Human height matches continuous variation controlled by polygenes and environmental factors; ABO blood group matches discontinuous variation controlled by a single gene locus with multiple alleles; Fingerprint pattern matches discontinuous variation exhibiting distinct qualitative categories.
Human height is a quantitative feature showing continuous variation influenced by polygenes and the environment. In contrast, ABO blood groups and fingerprint patterns are qualitative traits exhibiting discontinuous variation with distinct, clear-cut phenotypic categories.

Adım Adım Çözüm

1
Analyze human height variation.
Height displays a continuous range of phenotypes with no clear separation between types.
It is a quantitative trait controlled by polygenes and influenced by environmental conditions.
2
Analyze ABO blood group variation.
Blood groups exist in distinct classes (A, B, AB, O) without intermediate phenotypes.
It is a monogenic trait controlled by multiple alleles at a single locus.
3
Analyze fingerprint pattern variation.
Fingerprint patterns fall into distinct categories such as arches, loops, and whorls.
It exhibits clear-cut discrete categories characteristic of discontinuous variation.

Anahtar Kavram

Continuous variation presents an unbroken spectrum of intermediate phenotypes regulated by polygenes, whereas discontinuous variation exhibits distinct, non-overlapping phenotypic categories controlled by one or a few genes.
Soru 13Soru

A genetic counselor assesses a couple planning to have children. Both parents are asymptomatic carriers of the sickle-cell allele (HbAHbSHb^A Hb^S). The father has blood group ABAB (IAIBI^A I^B) and the mother has blood group OO (iiii). What is the probability that their first child will be a carrier of the sickle-cell trait and also have a blood group that can safely receive red blood cells from a type AA (IAiI^A i) donor without transfusion agglutination?

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Cevap: 14\frac{1}{4} (or 25%25\%)

Cevap

The probability that the child is both a sickle-cell carrier and compatible with type A donor blood is 14\frac{1}{4} (or 25%25\%).
Crossing two sickle-cell carriers (HbAHbS×HbAHbSHb^A Hb^S \times Hb^A Hb^S) gives a 12\frac{1}{2} probability of producing a carrier child (HbAHbSHb^A Hb^S). Crossing a parent of blood type ABAB (IAIBI^A I^B) with a parent of type OO (iiii) yields offspring with blood types AA (IAiI^A i) or BB (IBiI^B i), each with a probability of 12\frac{1}{2}. For red blood cell transfusion from a type AA donor, only type AA offspring can receive the blood safely because type BB offspring possess anti-A antibodies that would cause agglutination. Since the two gene loci assort independently, the overall combined probability is 12×12=14\frac{1}{2} \times \frac{1}{2} = \frac{1}{4} (or 25%25\%).

Adım Adım Çözüm

1
Determine the probability of inheriting the sickle-cell carrier genotype (HbAHbSHb^A Hb^S).
Crossing two carrier parents (HbAHbS×HbAHbSHb^A Hb^S \times Hb^A Hb^S) produces genotypes 1HbAHbA:2HbAHbS:1HbSHbS1\, Hb^A Hb^A : 2\, Hb^A Hb^S : 1\, Hb^S Hb^S. The probability of a carrier offspring (HbAHbSHb^A Hb^S) is 24=12\frac{2}{4} = \frac{1}{2}.
Monohybrid inheritance of autosomal recessive trait yields a 1:2:11:2:1 genotypic ratio.
2
Determine the blood group genotypes of the offspring and identify donor compatibility.
Crossing father ABAB (IAIBI^A I^B) with mother OO (iiii) yields 12\frac{1}{2} blood group AA (IAiI^A i) and 12\frac{1}{2} blood group BB (IBiI^B i). Only blood group AA recipients can safely receive type AA red blood cells without antibody-antigen agglutination.
Blood group BB recipients possess anti-A antibodies in their blood plasma, causing hemolysis/agglutination if transfused with type AA cells.
3
Calculate the combined probability of both independent genetic events.
P(Carrier AND Type A)=P(Carrier)×P(Type A)=12×12=14P(\text{Carrier AND Type A}) = P(\text{Carrier}) \times P(\text{Type A}) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} (or 25%25\%).
The hemoglobin locus and ABO locus reside on different chromosomes and assort independently according to Mendel's Second Law.

Anahtar Kavram

Application of Mendel's laws of independent assortment to human medical genetic counseling involving disease carriers and ABO blood transfusion compatibility.
Soru 14Soru

Which of the following terms describes an organism that possesses two identical alleles for a specific gene?

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Cevap: Homozygous

Cevap

Homozygous
Homozygous is the genetic term for an organism carrying two identical alleles for a given gene locus.

Adım Adım Çözüm

1
Define genetic zygosity terms.
Alleles are alternative forms of a gene located at the same locus on homologous chromosomes.
Comparing maternal and paternal alleles determines the zygosity of the gene locus.
2
Identify the term for matching alleles.
When an individual inherits identical alleles from both parents for a gene, the genetic condition is homozygous.
The prefix 'homo-' means same, indicating identical alleles.

Anahtar Kavram

Basic Genetics Terminology (Homozygous vs. Heterozygous)
Soru 15Soru

A genetic counselor evaluates a married couple who are both heterozygous carriers of the sickle-cell gene (HbAHbSHb^A Hb^S). What is the probability that their first child will be an asymptomatic carrier of the sickle-cell trait?

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Cevap: 50%

Cevap

The probability that the couple's first child will be an asymptomatic carrier of the sickle-cell trait is 50%.
When two heterozygous individuals (HbAHbSHb^A Hb^S) produce offspring, Mendelian segregation yields a genotypic ratio of 1 HbAHbAHb^A Hb^A (normal, 25%) : 2 HbAHbSHb^A Hb^S (carrier trait, 50%) : 1 HbSHbSHb^S Hb^S (sickle-cell anemia, 25%). Therefore, there is a 50% chance that any child born to them will be an asymptomatic carrier.

Adım Adım Çözüm

1
Determine parental genotypes
Both parents are heterozygous carriers with the genotype HbAHbSHb^A Hb^S.
Sickle-cell trait is an autosomal codominant condition where carriers possess one normal hemoglobin allele (HbAHb^A) and one sickle hemoglobin allele (HbSHb^S).
2
Perform a monohybrid cross between the parents (HbAHbS×HbAHbSHb^A Hb^S \times Hb^A Hb^S)
The possible offspring genotypes are 1 HbAHbAHb^A Hb^A : 2 HbAHbSHb^A Hb^S : 1 HbSHbSHb^S Hb^S.
Gametes from each parent separate independently during meiosis, giving equal likelihood for inheriting either allele.
3
Calculate the proportion corresponding to asymptomatic carriers (HbAHbSHb^A Hb^S)
Heterozygous carrier probability = 24=50%\frac{2}{4} = 50\%.
Two out of the four possible genotypic outcomes result in the carrier state (HbAHbSHb^A Hb^S).

Anahtar Kavram

Application of genetic inheritance in medical counseling for sickle-cell trait
Tahmini Süre:1m 0s
Soru 16Soru

In genetics, phenotypic variation across organisms is categorized based on distribution patterns, underlying gene architecture, and susceptibility to environmental influences. Match each biological trait on the left with its precise classification of genetic control and variation dynamics on the right.

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Öğeler

Total dermatoglyphic ridge count (fingerprint pattern complexity)
ABO erythrocyte surface antigen specificity
Human epidermal melanin concentration gradient
Ability to roll the lateral margins of the tongue upward

Eşleşmeler

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Cevap

The correct pairings are: Total dermatoglyphic ridge count matches continuous polygenic variation with minimal environmental change; ABO erythrocyte antigen specificity matches discontinuous single-locus variation with codominant alleles; Human epidermal melanin concentration matches continuous polygenic variation influenced by external environment; Ability to roll tongue margins matches discontinuous single-locus variation with complete dominance.
Total dermatoglyphic ridge count forms a quantitative continuous spectrum under polygenic control with high embryonic heritability and no post-natal environmental modification. ABO blood group is a discontinuous trait determined by codominant single-locus alleles (IA,IB,iI^A, I^B, i). Skin melanin concentration shows continuous polygenic distribution enhanced by UV radiation. Tongue rolling is a simple monogenic discontinuous trait controlled by complete dominance.

Adım Adım Çözüm

1
Differentiate continuous from discontinuous variation mechanisms
Continuous variation involves quantitative traits forming a smooth spectrum (bell curve) under polygenic control. Discontinuous variation involves qualitative traits forming discrete bar categories under monogenic or oligogenic control.
Establishing the genetic architecture and distribution pattern is necessary to categorize each trait accurately.
2
Analyze environmental influence versus genetic stability
Skin pigmentation is polygenic and environmental (sunlight exposure alters melanin density). Dermatoglyphics (ridge counts) are polygenic but environment-stable post-birth.
Distinguishing between environmentally susceptible polygenic traits and environmentally immune polygenic traits separates skin color from fingerprint ridge counts.
3
Analyze single-locus allele interactions
ABO blood group involves multiple codominant/recessive alleles (IA,IB,iI^A, I^B, i) generating distinct physiological groups. Tongue rolling involves simple complete dominance (RR vs rr).
Both are discontinuous, but their specific genetic mechanisms differ in codominance versus complete dominance.

Anahtar Kavram

Polygenic vs Monogenic Inherited Variation and Environmental Plasticity
Soru 17Soru

Match each application of genetics in medicine and agriculture listed on the left with its correct biological purpose or effect on the right.

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Öğeler

Genetic counseling
Hybrid vigor (Heterosis)
Anti-Rh immunoglobulin administration
Selective breeding

Eşleşmeler

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Cevap

Genetic counseling matches with evaluating hereditary disorder risks in prospective offspring; Hybrid vigor matches with producing outbred F1F_1 progeny superior to both parents; Anti-Rh immunoglobulin administration matches with preventing erythroblastosis fetalis in subsequent pregnancies; Selective breeding matches with combining desirable traits over generations by mating selected parents.
Each application correctly pairs with its defined mechanism: genetic counseling evaluates hereditary disease risks, hybrid vigor enhances phenotypic performance via crossbreeding, anti-Rh immunoglobulin prevents maternal immunization against Rh-positive fetal red cells, and selective breeding increases desirable trait frequencies across generations.

Adım Adım Çözüm

1
Identify medical applications of genetic principles.
Genetic counseling assesses hereditary disease transmission risks, whereas anti-Rh immunoglobulin therapy prevents maternal Rh-sensitization and subsequent erythroblastosis fetalis.
These procedures apply genetic knowledge to clinical prevention and family planning.
2
Identify agricultural applications of genetic principles.
Selective breeding accumulates favorable traits over successive generations, while heterosis produces high-yielding, vigorous F1F_1 hybrids by crossing diverse pure lines.
These techniques utilize genetic selection and hybridization to improve crop yields and livestock quality.

Anahtar Kavram

Applications of Genetics in Medicine and Agriculture
Soru 18Soru

In a genetic analysis of a plant species, a researcher observes that crossing a true-breeding round-seeded plant with a true-breeding wrinkled-seeded plant yields offspring that all produce round seeds. When these offspring self-pollinate, the resulting progeny exhibit both round and wrinkled seeds. Which statement correctly identifies the genetic terms for the hereditary units involved and their physiological state in the first-generation offspring?

Cevabı ve açıklamayı göster

Cevap: The hereditary units are alleles of a single gene occupying the same chromosome locus, and the first-generation offspring are heterozygous.

Cevap

The hereditary units are alleles of a single gene occupying the same chromosome locus, and the first-generation offspring are heterozygous.
Alternative versions of a gene located at the exact same locus on homologous chromosomes are called alleles. Crossing two true-breeding parents with contrasting phenotypes (RR×rrRR \times rr) yields F1F_1 offspring that inherit one allele from each parent (RrRr). Because these offspring possess two different alleles for the gene, their genetic condition is heterozygous, and because the round trait completely hides the wrinkled trait, it shows complete dominance.

Adım Adım Çözüm

1
Identify the genetic term for alternative forms of a gene controlling seed shape.
Alternative forms of a gene that occupy identical positions (loci) on homologous chromosomes are called alleles.
The round and wrinkled traits represent variations of a single gene sequence governing seed texture.
2
Determine the genetic state of the first-generation (F1F_1) offspring.
The F1F_1 offspring inherit one dominant allele (RR) from the round parent and one recessive allele (rr) from the wrinkled parent, forming genotype RrRr (heterozygous).
True-breeding parental lines are homozygous (RRRR and rrrr), so their offspring must receive two distinct alleles for that gene locus.
3
Evaluate the mode of gene expression displayed.
Since all F1F_1 plants express only the round seed phenotype, the round allele exhibits complete dominance over the wrinkled allele.
Complete dominance occurs when the presence of one dominant allele completely masks the physical expression of a recessive allele in a heterozygous state.

Anahtar Kavram

Basic Genetics Terminology: Alleles, Locus, Heterozygosity, and Dominance
Soru 19Soru

In human genetics, sickle-cell anaemia and Down syndrome represent two distinct types of genetic disorders. Which of the following statements correctly differentiates between the underlying genetic causes of these two conditions?

Cevabı ve açıklamayı göster

Cevap: Sickle-cell anaemia is caused by a point mutation in a single gene, whereas Down syndrome is caused by a chromosomal numerical aberration.

Cevap

Sickle-cell anaemia is caused by a point mutation in a single gene, whereas Down syndrome is caused by a chromosomal numerical aberration.
The correct response accurately distinguishes the scope of the genetic error. Sickle-cell anaemia is a classic gene mutation resulting from a single point substitution in the DNA sequence coding for beta-globin. Down syndrome is a chromosomal numerical aberration (aneuploidy/trisomy 21) resulting from the failure of chromosome pair 21 to separate during gamete formation (non-disjunction).

Adım Adım Çözüm

1
Analyze the cause of sickle-cell anaemia
Determined that sickle-cell anaemia is a gene mutation caused by a single nucleotide substitution (GAG to GUG) in the hemoglobin gene.
Gene mutations involve alterations in the molecular sequence of nucleotides within a single gene.
2
Analyze the cause of Down syndrome
Determined that Down syndrome is a chromosomal aberration involving an extra chromosome 21 (trisomy 21) caused by non-disjunction during meiosis.
Chromosomal aberrations involve changes in the number or gross structure of whole chromosomes rather than single nucleotide changes.
3
Compare the classifications
Matched sickle-cell anaemia to gene mutation and Down syndrome to chromosomal numerical aberration.
This establishes the fundamental distinction between point gene mutations and numerical chromosomal abnormalities.

Anahtar Kavram

Distinction between Gene Mutations and Chromosomal Aberrations
Tahmini Süre:1m 0s
Soru 20Soru

In human ABO blood groups, an individual carrying both the IAI^A and IBI^B alleles expresses both A and B antigens equally on the surface of red blood cells, demonstrating codominance.

Cevabı ve açıklamayı göster

Cevap: True

Cevap

The statement is true. Individuals with genotype IAIBI^A I^B produce both A and B antigens on their red blood cells, showing full expression of both alleles.
Codominance refers to an inheritance pattern where two different alleles at a locus are both fully expressed in heterozygotes. In blood group AB (genotype IAIBI^A I^B), both A and B antigens exist on the erythrocyte membrane without blending or masking.

Adım Adım Çözüm

1
Analyze the genetic relationship between the IAI^A and IBI^B alleles in human blood groups.
Both IAI^A and IBI^B alleles code for functional cell-surface enzymes that attach specific sugar antigens to red blood cells.
Understanding the allele actions determines the phenotypic outcome in heterozygotes.
2
Determine whether the inheritance pattern shown is codominance.
Because neither allele masks the other and both A and B antigens are fully expressed together in blood group AB, the pattern is codominance.
Codominance is defined by the joint and full expression of both alleles in a heterozygous organism.

Anahtar Kavram

Codominance in ABO Blood Grouping
Sayfa 1 / 8Sonraki