Linear and Quadratic Inequalities
27 soru
Soru 21Soru →
Find the largest integer value of x that satisfies the linear inequality 32x−5≤4x+1.
Cevabı ve açıklamayı göster
Cevap: 4
Cevap
The largest integer value of x satisfying the inequality is 4.
Multiplying the entire inequality by 12 yields 4(2x - 5) <= 3(x + 1). Expanding both sides produces 8x - 20 <= 3x + 3. Subtracting 3x and adding 20 gives 5x <= 23, which simplifies to x <= 4.6. The largest integer less than or equal to 4.6 is 4.
Adım Adım Çözüm
1
Clear the denominators by multiplying both sides by 12.
4(2x - 5) \le 3(x + 1)
Multiplying by a positive number preserves the inequality direction while clearing fractions.
2
Expand both sides of the inequality using the distributive property.
8x - 20 \le 3x + 3
Multiply 4 through (2x - 5) and 3 through (x + 1).
3
Isolate the variable terms on one side and constant terms on the other.
5x \le 23 \implies x \le 4.6
Subtract 3x from both sides and add 20 to both sides, then divide by 5.
4
Determine the maximum integer value satisfying the inequality boundary.
4
Since x must be less than or equal to 4.6, the greatest whole integer satisfying this condition is 4.
Anahtar Kavram
Solving linear inequalities with fractions and finding integer bounds
Soru 22Soru →
Find the sum of all integer values of x that satisfy both the linear inequality 2x−1≥3 and the quadratic inequality x2−5x−14≤0.
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Cevap: 27
Cevap
The sum of all integer values of x satisfying both inequalities is 27.
Solving the linear inequality 2x−1≥3 yields x≥2. Solving the quadratic inequality x2−5x−14≤0 by factoring gives (x−7)(x+2)≤0, which defines the interval −2≤x≤7. Taking the intersection of x≥2 and −2≤x≤7 gives 2≤x≤7. The integer values satisfying this range are 2,3,4,5,6, and 7, and their sum is 27.
Adım Adım Çözüm
1
Solve the linear inequality
2x≥4⟹x≥2
Adding 1 to both sides and dividing by 2 isolates the variable x.
2
Factor and solve the quadratic inequality
(x−7)(x+2)≤0⟹−2≤x≤7
The roots of the quadratic equation are x=7 and x=−2. The parabola opens upward, so the expression is non-positive between the roots.
3
Determine the intersection of both solution sets
2≤x≤7
The values of x must simultaneously satisfy x≥2 and −2≤x≤7.
4
List all integer solutions within the valid interval
x∈{2,3,4,5,6,7}
These are all the whole numbers contained in the closed interval [2,7].
5
Sum the integer solutions
2+3+4+5+6+7=27
Summing the identified integer values yields the final required numerical answer.
Anahtar Kavram
Linear and Quadratic Inequalities
Tahmini Süre:1m 30s
Soru 23Soru →
Find the set of real values of x that satisfies the inequality 35−2x≥x−5.
x≥4
x≤4
x≤−4
x≥−4
Cevabı ve açıklamayı göster
Cevap: x≤4
Cevap
The set of real values satisfying the inequality is x≤4.
Multiplying through by 3 yields 5−2x≥3x−15. Rearranging terms gives −5x≥−20. Dividing both sides by −5 requires flipping the inequality sign from ≥ to ≤, giving x≤4.
Adım Adım Çözüm
1
Multiply both sides of the inequality by 3 to clear the fraction.
5−2x≥3(x−5)
Eliminating the denominator simplifies the algebraic expression.
2
Expand the right-hand side and collect terms containing x on one side and constants on the other.
5−2x≥3x−15⟹−2x−3x≥−15−5⟹−5x≥−20
Group like terms to isolate the variable x.
3
Divide both sides by −5 and reverse the inequality sign.
x≤−5−20⟹x≤4
Dividing or multiplying an inequality by a negative number reverses the direction of the inequality sign.
Anahtar Kavram
Solving linear inequalities involving negative coefficient division
Soru 24Soru →
Which of the following is the set of real values of x that satisfies the inequality 43−x≤32x+5?
x≥−1
x≤−1
x≥1
x≤1
Cevabı ve açıklamayı göster
Cevap: x≥−1
Cevap
The set of real values of x that satisfies the inequality is x≥−1.
Multiplying through by 12 gives 9−3x≤8x+20. Grouping terms results in −11x≤11. Dividing by −11 requires reversing the inequality sign from ≤ to ≥, giving the solution x≥−1.
Adım Adım Çözüm
1
Clear the denominators by multiplying both sides of the inequality by the lowest common multiple, 12.
3(3−x)≤4(2x+5)
Eliminating fractions simplifies the algebraic expression.
2
Expand both sides by distributing the multipliers.
9−3x≤8x+20
Prepares terms for grouping variables on one side and constants on the other.
3
Collect all terms containing x on the left side and constant terms on the right side.
−3x−8x≤20−9⟹−11x≤11
Isolates the linear variable term.
4
Divide both sides by −11 and flip the inequality sign.
x≥−1
Dividing or multiplying an inequality by a negative number reverses the direction of the inequality sign.
Anahtar Kavram
Linear Inequalities and Reversing Inequality Sign on Division by Negative Numbers
Soru 25Soru →
Determine the smallest integer value of x that satisfies the compound inequality 3<2x−5≤11.
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Cevap: 5
Cevap
The smallest integer value of x that satisfies the inequality is 5.
Adding 5 across the compound inequality 3<2x−5≤11 gives 8<2x≤16. Dividing by 2 yields 4<x≤8. The integer values satisfying this range are 5, 6, 7, and 8. Therefore, the smallest integer solution is 5.
Adım Adım Çözüm
1
Add 5 to all parts of the compound inequality
8 < 2x <= 16
Isolates the variable term in the middle segment.
2
Divide all parts of the compound inequality by 2
4 < x <= 8
Solves for x without changing inequality signs since 2 is positive.
3
Identify integer solutions within the range (4, 8]
x in {5, 6, 7, 8}
Since the inequality at 4 is strict (<), 4 is excluded, but 8 is included (<=).
4
Find the minimum integer value in the solution set
5
5 is the smallest integer strictly greater than 4.
Anahtar Kavram
Solving Compound Linear Inequalities
Soru 26Soru →
Which of the following represents the solution set of real values of x satisfying the inequality 4(1−x)≤3(x+6)?
x≥−2
x≤−2
x≥2
x≤2
Cevabı ve açıklamayı göster
Cevap: x≥−2
Cevap
The set of real values satisfying the inequality is x≥−2.
Expanding the given inequality yields 4−4x≤3x+18. Subtracting 3x and 4 from both sides gives −7x≤14. When dividing both sides by −7, the inequality sign must reverse direction, yielding x≥−2.
Adım Adım Çözüm
1
Expand both sides of the inequality
4−4x≤3x+18
Remove brackets to group like terms.
2
Rearrange terms by moving variable terms to the left side and constant terms to the right side
−4x−3x≤18−4⟹−7x≤14
Isolate the term containing the variable x.
3
Divide both sides by −7 and reverse the inequality sign
x≥−2
Dividing or multiplying an inequality by a negative number flips the direction of the inequality symbol.
Anahtar Kavram
Solving linear inequalities involving bracket expansion and division by negative numbers
Soru 27Soru →
How many integer values of x satisfy the quadratic inequality 2x2−7x−4≤0?
Cevabı ve açıklamayı göster
Cevap: 5
Cevap
There are 5 integer values of x that satisfy the inequality.
Solving the quadratic inequality yields −21≤x≤4. The integer solutions within this interval are 0,1,2,3, and 4. Counting them gives a total of 5 valid integer values.
Adım Adım Çözüm
1
Factor the quadratic expression.
(2x+1)(x−4)≤0
Factoring allows determination of the critical boundary points.
2
Find the critical values (roots of the equation).
x=−21 and x=4
The roots divide the number line into test intervals.
3
Determine the solution set of the inequality.
−21≤x≤4
Since the quadratic coefficient is positive, the quadratic expression is non-positive between its roots.
4
List and count the integers within the range.
The integers are 0,1,2,3,4, making a total of 5 integers.
Counting only whole numbers in the closed interval [−0.5,4].
Anahtar Kavram
Quadratic Inequalities and Integer Solution Counting
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