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Zorluk: KolayEquations of Circles in the Coordinate Plane

In the xyxy-plane, a circle with center (4,9)(4, 9) and radius 55 is defined by the equation (xh)2+(y9)2=25(x - h)^2 + (y - 9)^2 = 25, where hh is a positive constant. What is the value of hh?

Cevap: 4

Cevap

The value of the constant hh is 44.
The standard equation of a circle with center (h,k)(h, k) and radius rr is (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2. Since the center is (4,9)(4, 9) and the radius is 55, the equation of the circle is (x4)2+(y9)2=52(x - 4)^2 + (y - 9)^2 = 5^2, which simplifies to (x4)2+(y9)2=25(x - 4)^2 + (y - 9)^2 = 25. Comparing this to the given equation (xh)2+(y9)2=25(x - h)^2 + (y - 9)^2 = 25, we see that the constant hh corresponds to the xx-coordinate of the center, which is 44.

Adım Adım Çözüm

1
Identify the standard equation of a circle.
(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2
This formula represents a circle with center (h,k)(h, k) and radius rr in the coordinate plane.
2
Substitute the given center coordinates into the standard equation.
For center (4,9)(4, 9), the equation is (x4)2+(y9)2=r2(x - 4)^2 + (y - 9)^2 = r^2.
The coordinates of the center are mapped directly to hh and kk in the standard form.
3
Compare the equation template to find the value of hh.
The equation (x4)2+(y9)2=25(x - 4)^2 + (y - 9)^2 = 25 matches the format (xh)2+(y9)2=25(x - h)^2 + (y - 9)^2 = 25, indicating that h=4h = 4.
Equating the terms in both equations allows us to identify the value of the positive constant hh.

Anahtar Kavram

Extracting coordinates of the center from the standard form equation of a circle.
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