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Zorluk: ZorSystems of Linear Inequalities in Two Variables

A closed triangular region in the coordinate plane is defined by the following system of linear inequalities:

y2x4yx+8x1\begin{aligned} y &\geq 2x - 4 \\ y &\leq -x + 8 \\ x &\geq 1 \end{aligned}

What is the maximum possible value of the expression 2x+y2x + y for any point (x,y)(x, y) that lies within or on the boundary of this region?

Cevap: 12

Cevap

The maximum possible value of the expression 2x+y2x + y is 12.
To find the maximum possible value of the expression 2x+y2x + y subject to the given system of inequalities, we first identify the boundary lines and find the vertices of the bounded triangular region in the coordinate plane. The boundary lines are y=2x4y = 2x - 4, y=x+8y = -x + 8, and x=1x = 1. The intersection of y=2x4y = 2x - 4 and y=x+8y = -x + 8 occurs at x=4,y=4x = 4, y = 4, which gives vertex (4,4)(4, 4). The intersection of y=2x4y = 2x - 4 and x=1x = 1 occurs at (1,2)(1, -2). The intersection of y=x+8y = -x + 8 and x=1x = 1 occurs at (1,7)(1, 7). Evaluating the linear expression 2x+y2x + y at these three vertices gives 2(4)+4=122(4) + 4 = 12, 2(1)2=02(1) - 2 = 0, and 2(1)+7=92(1) + 7 = 9. By the corner point theorem, the maximum value of a linear function on a closed polygonal region occurs at one of the vertices. Comparing the values, the maximum possible value is 12.

Adım Adım Çözüm

1
Find the vertex formed by the intersection of the boundary lines y=2x4y = 2x - 4 and y=x+8y = -x + 8.
Vertex A(4,4)A(4, 4)
Setting the two equations equal: 2x4=x+8    3x=12    x=42x - 4 = -x + 8 \implies 3x = 12 \implies x = 4. Substituting x=4x = 4 back into either equation yields y=4y = 4.
2
Find the vertex formed by the intersection of the boundary line y=2x4y = 2x - 4 and the vertical line x=1x = 1.
Vertex B(1,2)B(1, -2)
Substituting x=1x = 1 into y=2x4y = 2x - 4 gives y=2(1)4=2y = 2(1) - 4 = -2.
3
Find the vertex formed by the intersection of the boundary line y=x+8y = -x + 8 and the vertical line x=1x = 1.
Vertex C(1,7)C(1, 7)
Substituting x=1x = 1 into y=x+8y = -x + 8 gives y=1+8=7y = -1 + 8 = 7.
4
Evaluate the expression 2x+y2x + y at each of the three vertices.
At A(4,4)A(4, 4), the value is 1212; at B(1,2)B(1, -2), the value is 00; at C(1,7)C(1, 7), the value is 99.
According to the Corner Point Theorem of linear programming, the maximum or minimum of a linear objective function on a closed bounded region must occur at one of the vertices.
5
Identify the maximum value from the evaluated points.
The maximum value is 12.
Comparing the values 12, 0, and 9 shows that 12 is the largest value.

Anahtar Kavram

Linear Programming and Systems of Inequalities
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