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Zorluk: KolayNonlinear Systems of Equations

If (x,y)(x, y) is a solution to the system of equations below and x>0x > 0, what is the value of xx?

y=x2y = x^2
y=x+6y = x + 6

Cevap: 3

Cevap

The correct answer is 33.
Substituting y=x2y = x^2 into y=x+6y = x + 6 gives the quadratic equation x2x6=0x^2 - x - 6 = 0. Factoring this expression yields (x3)(x+2)=0(x - 3)(x + 2) = 0, which gives solutions of x=3x = 3 and x=2x = -2. Since the system requires x>0x > 0, the only valid solution is 33.

Adım Adım Çözüm

1
Substitute the expression for yy from the first equation into the second equation.
x2=x+6x^2 = x + 6
To eliminate the variable yy and solve for xx directly.
2
Subtract xx and 66 from both sides to write the quadratic equation in standard form.
x2x6=0x^2 - x - 6 = 0
Setting the quadratic expression equal to zero allows it to be factored.
3
Factor the quadratic trinomial.
(x3)(x+2)=0(x - 3)(x + 2) = 0
Finding factors whose product is 6-6 and whose sum is 1-1 helps find the roots.
4
Solve for xx and apply the constraint x>0x > 0.
x=3x = 3
The equation has solutions x=3x = 3 and x=2x = -2. Because xx must be greater than 00, we discard the negative solution.

Anahtar Kavram

Solving a system of nonlinear equations by substitution and factoring the resulting quadratic equation.
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