Soru

Zorluk: OrtaLinear Equations in Two Variables

A landscaping company uses the equation 12x+18y=24012x + 18y = 240 to model the total cost, in dollars, of renting a wood chipper for xx hours and a soil aerator for yy hours. If the wood chipper was rented for 5 more hours than the soil aerator, and the company spent a total of 240240 on these rentals, for how many hours was the soil aerator rented?

  1. A
    5
  2. 6Cevap
  3. C
    10
  4. D
    11

Cevap

The soil aerator was rented for 6 hours.
The correct answer is 6. By writing the relationship between the rental hours as x=y+5x = y + 5 and substituting this expression into the cost equation, we obtain 12(y+5)+18y=24012(y + 5) + 18y = 240. Distributing the 12 results in 12y+60+18y=24012y + 60 + 18y = 240. Combining the like terms gives 30y+60=24030y + 60 = 240. Subtracting 60 from both sides of the equation yields 30y=18030y = 180. Dividing both sides by 30 results in y=6y = 6. Therefore, the soil aerator was rented for 6 hours.

Adım Adım Çözüm

1
Express the relationship between the rental hours of the wood chipper (xx) and the soil aerator (yy) as an equation.
x=y+5x = y + 5
The wood chipper was rented for 5 more hours than the soil aerator.
2
Substitute the expression for xx into the cost equation 12x+18y=24012x + 18y = 240.
12(y+5)+18y=24012(y + 5) + 18y = 240
Substitution reduces the equation to a single variable, allowing us to solve for yy.
3
Distribute the 12 and combine like terms.
12y+60+18y=240    30y+60=24012y + 60 + 18y = 240 \implies 30y + 60 = 240
Simplification isolates the variable terms on one side.
4
Isolate yy by subtracting 60 from both sides and then dividing by 30.
30y=180    y=630y = 180 \implies y = 6
This calculation yields the rental hours for the soil aerator.

Anahtar Kavram

Solving a system of linear equations in two variables where one equation represents a budget constraint and the other relates the quantities of the two variables.
Bu soruyu puanla