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Zorluk: KolayLinear Equations in Two Variables

A florist sells carnations for 1.501.50 each and roses for 3.003.00 each. The equation 1.50c+3.00r=45.001.50c + 3.00r = 45.00 represents the possible number of carnations, cc, and roses, rr, that a customer can buy for exactly 45.0045.00. If the customer buys 8 carnations, how many roses can they buy?

Cevap: 11

Cevap

11
To find the number of roses the customer can buy, substitute the number of carnations bought, which is 8, for cc in the given equation. This yields 1.50(8)+3.00r=45.001.50(8) + 3.00r = 45.00. Simplifying the product gives 12.00+3.00r=45.0012.00 + 3.00r = 45.00. Subtracting 12.00 from both sides of the equation gives 3.00r=33.003.00r = 33.00. Finally, dividing both sides by 3.00 yields r=11r = 11. Thus, the customer can buy 11 roses.

Adım Adım Çözüm

1
Substitute the given value for carnations, c=8c = 8, into the linear equation.
1.50(8)+3.00r=45.001.50(8) + 3.00r = 45.00
We are given that the customer buys 8 carnations, so cc is replaced by 8 to solve for the number of roses, rr.
2
Multiply 1.501.50 by 88 to simplify the term.
12.00+3.00r=45.0012.00 + 3.00r = 45.00
Simplifying the constant term on the left side of the equation.
3
Subtract 12.0012.00 from both sides of the equation to isolate the term with rr.
3.00r=33.003.00r = 33.00
To solve for rr, we must get the term 3.00r3.00r by itself on one side.
4
Divide both sides of the equation by 3.003.00 to solve for rr.
r=11r = 11
Dividing isolates the variable rr.

Anahtar Kavram

Solving a linear equation in two variables by substitution when one variable's value is known.
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