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Zorluk: ZorSystems of Linear Equations

In the xyxy-plane, the system of equations below has infinitely many solutions:

12(axby)=73x2y=c\begin{aligned} \frac{1}{2}(ax - by) &= 7 \\ 3x - 2y &= c \end{aligned}

where aa, bb, and cc are constants. If the line representing the first equation passes through the point (4,1)(4, 1), what is the value of cc?

  1. A
    5
  2. B
    8
  3. 10Cevap
  4. D
    20

Cevap

10
The correct answer is 10. For a system of linear equations in two variables to have infinitely many solutions, the two equations must describe the exact same line, meaning their coefficients and constant terms are proportional. Multiplying the first equation by 22 yields axby=14ax - by = 14. Comparing this with 3x2y=c3x - 2y = c shows that a3=b2=14c\frac{a}{3} = \frac{b}{2} = \frac{14}{c}, which simplifies to b=23ab = \frac{2}{3}a and c=42ac = \frac{42}{a}. Since the first line passes through (4,1)(4, 1), we substitute x=4x = 4 and y=1y = 1 to get 4ab=144a - b = 14. Substituting b=23ab = \frac{2}{3}a gives 4a23a=144a - \frac{2}{3}a = 14, which simplifies to 103a=14\frac{10}{3}a = 14, or a=4.2a = 4.2. Finally, solving for cc gives c=424.2=10c = \frac{42}{4.2} = 10.

Adım Adım Çözüm

1
Clear the fraction in the first equation by multiplying both sides by 22.
axby=14ax - by = 14
This puts the first equation into standard form, making it easier to compare with the second equation.
2
Set up the proportionality of the coefficients for the two equations to represent the same line.
a3=b2=14c    b=23a\frac{a}{3} = \frac{-b}{-2} = \frac{14}{c} \implies b = \frac{2}{3}a and c=42ac = \frac{42}{a}
For a system of two linear equations to have infinitely many solutions, the equations must be equivalent, meaning their corresponding coefficients and constants must be proportional.
3
Substitute the given point (4,1)(4, 1) into the first equation.
a(4)b(1)=14    4ab=14a(4) - b(1) = 14 \implies 4a - b = 14
Since the line passes through the point (4,1)(4, 1), the coordinates must satisfy the equation of the line.
4
Substitute b=23ab = \frac{2}{3}a into 4ab=144a - b = 14 and solve for aa.
4a23a=14    103a=14    a=4.24a - \frac{2}{3}a = 14 \implies \frac{10}{3}a = 14 \implies a = 4.2
This reduces the equation to a single variable, allowing us to find the value of the parameter aa.
5
Substitute a=4.2a = 4.2 into the expression for cc to find its value.
c=424.2=10c = \frac{42}{4.2} = 10
This uses the coefficient proportionality relation from step 2 to determine the constant term of the second equation.

Anahtar Kavram

Systems of linear equations with infinitely many solutions require the equations to represent the same line, meaning their coefficients and constant terms are proportional.
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