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Zorluk: OrtaSystems of Linear Equations

A local store sells two types of coffee beans: Arabica and Robusta. On Monday, the store sold 88 pounds of Arabica coffee and 55 pounds of Robusta coffee for a total of $62.00\$62.00. On Tuesday, the store sold 44 pounds of Arabica coffee and 77 pounds of Robusta coffee for a total of $58.00\$58.00. What is the cost, in dollars, of one pound of Robusta coffee?

Cevap: 6 dollars

Cevap

The cost of one pound of Robusta coffee is 6 dollars.
The correct answer is 6. By setting up the system of equations 8a+5r=628a + 5r = 62 and 4a+7r=584a + 7r = 58, we can multiply the second equation by 2 to get 8a+14r=1168a + 14r = 116. Subtracting the first equation from this yields 9r=549r = 54, which simplifies to r=6r = 6.

Adım Adım Çözüm

1
Define variables for the price per pound of Arabica coffee (aa) and Robusta coffee (rr), then set up a system of linear equations based on the given store sales information.
Equation 1: 8a+5r=628a + 5r = 62
Equation 2: 4a+7r=584a + 7r = 58
This translates the word problem context into a solvable system of mathematical equations.
2
Multiply the second equation by 22 to make the coefficients of aa equal in both equations.
8a+14r=1168a + 14r = 116
This prepares the system for solving by the elimination method.
3
Subtract the first equation (8a+5r=628a + 5r = 62) from the new equation (8a+14r=1168a + 14r = 116) to eliminate aa and solve for rr.
9r=549r = 54, which simplifies to r=6r = 6
Subtracting the equations eliminates one variable, leaving a single-variable equation that is easily solved.

Anahtar Kavram

Solving systems of two linear equations in two variables using the elimination method.
Tahmini Süre:1m 30s
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