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Zorluk: ZorSystems of Linear Equations

In the system of equations below, cc is a constant.

3x2y=3c1x+3y=2c8\begin{aligned} 3x - 2y &= 3c - 1 \\ x + 3y &= 2c - 8 \end{aligned}

If the solution (x,y)(x, y) to the system satisfies x+y=2x + y = 2, what is the value of cc?

  1. 4Cevap
  2. B
    16
  3. C
    3
  4. D
    -1

Cevap

The correct value of the constant cc is 4.
To find the value of cc, the linear constraint x+y=2x + y = 2 is rearranged to x=2yx = 2 - y. Substituting this expression into the first equation yields 3(2y)2y=3c13(2 - y) - 2y = 3c - 1, which simplifies to 65y=3c16 - 5y = 3c - 1, or y=73c5y = \frac{7 - 3c}{5}. Substituting it into the second equation yields (2y)+3y=2c8(2 - y) + 3y = 2c - 8, which simplifies to 2+2y=2c82 + 2y = 2c - 8, or y=c5y = c - 5. Equating these two expressions gives c5=73c5c - 5 = \frac{7 - 3c}{5}. Multiplying both sides by 55 results in 5c25=73c5c - 25 = 7 - 3c. Adding 3c3c and 2525 to both sides yields 8c=328c = 32, which gives c=4c = 4.

Adım Adım Çözüm

1
Express xx in terms of yy using the given constraint x+y=2x + y = 2.
x=2yx = 2 - y
This allows us to substitute the relation into the system of equations and reduce the variables from two to one.
2
Substitute x=2yx = 2 - y into the first equation, 3x2y=3c13x - 2y = 3c - 1, and isolate yy.
3(2y)2y=3c165y=3c15y=73cy=73c53(2 - y) - 2y = 3c - 1 \Rightarrow 6 - 5y = 3c - 1 \Rightarrow 5y = 7 - 3c \Rightarrow y = \frac{7 - 3c}{5}
To represent yy as a function of the parameter cc.
3
Substitute x=2yx = 2 - y into the second equation, x+3y=2c8x + 3y = 2c - 8, and isolate yy.
(2y)+3y=2c82+2y=2c82y=2c10y=c5(2 - y) + 3y = 2c - 8 \Rightarrow 2 + 2y = 2c - 8 \Rightarrow 2y = 2c - 10 \Rightarrow y = c - 5
To obtain another independent expression for yy in terms of cc.
4
Equate the two expressions for yy and solve for cc.
c5=73c55(c5)=73c5c25=73c8c=32c=4c - 5 = \frac{7 - 3c}{5} \Rightarrow 5(c - 5) = 7 - 3c \Rightarrow 5c - 25 = 7 - 3c \Rightarrow 8c = 32 \Rightarrow c = 4
Since both expressions represent the same value yy, they must be equal, allowing us to determine the constant cc.

Anahtar Kavram

Solving a system of linear equations containing unknown parameters under given linear constraints.

Alternatif Yöntem

Alternatively, substitute the relationship x=2yx = 2 - y into both equations to write them as a system in terms of yy and cc: 3(2y)2y=3c15y+3c=73(2 - y) - 2y = 3c - 1 \Rightarrow 5y + 3c = 7 and (2y)+3y=2c82y2c=10(2 - y) + 3y = 2c - 8 \Rightarrow 2y - 2c = -10. This simplified system can be solved for cc by multiplying the first equation by 2 and the second equation by 5 to eliminate yy: 2(5y+3c)5(2y2c)=2(7)5(10)6c+10c=14+5016c=64c=42(5y + 3c) - 5(2y - 2c) = 2(7) - 5(-10) \Rightarrow 6c + 10c = 14 + 50 \Rightarrow 16c = 64 \Rightarrow c = 4.
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