Soru

Zorluk: KolaySystems of Linear Inequalities in Two Variables

An online store sells small gift boxes for 1010 dollars each and large gift boxes for 1515 dollars each. A customer wants to buy a total of at most 1010 boxes. If the customer must spend at least 120120 dollars on the boxes, what is the minimum number of large gift boxes the customer must buy?

Cevap: 4 boxes

Cevap

The minimum number of large gift boxes the customer must buy is 4.
Using the constraints from the problem, we set up the system of inequalities: x+y10x + y \leq 10 and 10x+15y12010x + 15y \geq 120. Expressing the first inequality as x10yx \leq 10 - y and substituting it into the second gives 10(10y)+15y12010(10 - y) + 15y \geq 120. Simplifying this results in 100+5y120100 + 5y \geq 120, which simplifies to 5y205y \geq 20, or y4y \geq 4. Therefore, the minimum number of large gift boxes the customer must buy is 44.

Adım Adım Çözüm

1
Define variables for the quantities of each box.
Let xx be the number of small boxes and yy be the number of large boxes.
Establishing variables is necessary to translate the word problem into algebraic inequalities.
2
Write the system of inequalities representing the constraints.
x+y10x + y \leq 10 and 10x+15y12010x + 15y \geq 120
The total number of boxes is at most 1010, and the total cost must be at least 120120 dollars.
3
Express xx in terms of yy using the first inequality.
x10yx \leq 10 - y
This allows substitution into the second inequality to solve for the target variable yy.
4
Substitute x10yx \leq 10 - y into the second inequality and simplify.
100+5y120100 + 5y \geq 120
Solving the resulting single-variable inequality will determine the possible values of yy.
5
Solve the inequality for yy.
y4y \geq 4
Subtracting 100100 and dividing by 55 isolates yy to show its minimum possible value is 44.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Bu soruyu puanla