Soru

Zorluk: OrtaSystems of Linear Equations

Given the system of equations below:

3xy=112x+3y=11\begin{aligned} 3x - y &= 11 \\ 2x + 3y &= 11 \end{aligned}

If (x,y)(x, y) is the solution to the system of equations above, what is the value of x+2yx + 2y?

  1. A
    44
  2. 66Cevap
  3. C
    88
  4. D
    99

Cevap

The value of x+2yx + 2y is 66.
To solve the system, we can isolate yy in the first equation to get y=3x11y = 3x - 11. Substituting this into the second equation gives 2x+3(3x11)=112x + 3(3x - 11) = 11, which simplifies to 11x33=1111x - 33 = 11, or 11x=4411x = 44, resulting in x=4x = 4. Substituting x=4x = 4 back into the equation for yy gives y=3(4)11=1y = 3(4) - 11 = 1. The value of the expression x+2yx + 2y is therefore 4+2(1)=64 + 2(1) = 6.

Adım Adım Çözüm

1
Isolate yy in the first equation.
y=3x11y = 3x - 11
To prepare for substitution into the second equation.
2
Substitute the expression for yy into the second equation and solve for xx.
2x+3(3x11)=11    11x33=11    11x=44    x=42x + 3(3x - 11) = 11 \implies 11x - 33 = 11 \implies 11x = 44 \implies x = 4
To find the value of xx.
3
Substitute the value of xx back into the isolated equation for yy to solve for yy.
y=3(4)11    y=1y = 3(4) - 11 \implies y = 1
To find the value of yy.
4
Evaluate the expression x+2yx + 2y using the values of xx and yy.
4+2(1)=64 + 2(1) = 6
To find the final requested value.

Anahtar Kavram

Solving a system of linear equations using substitution or elimination, and evaluating a linear combination of the variables.

Alternatif Yöntem

Alternatively, the system can be solved using the elimination method. Multiply the first equation by 33 to align the yy-coefficients: 9x3y=339x - 3y = 33. Add this equation to the second equation, 2x+3y=112x + 3y = 11, to eliminate yy, yielding 11x=4411x = 44, so x=4x = 4. Then substitute x=4x = 4 into either original equation to find y=1y = 1.
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