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Zorluk: OrtaTrigonometric Ratios and Identities

In right triangle XYZXYZ, the measure of angle YY is 9090^\circ. If cos(X)+sin(Z)=1.6\cos(X) + \sin(Z) = 1.6, what is the value of sin(X)\sin(X)?

Cevap: 0.6

Cevap

0.6
The two acute angles in a right triangle sum to 9090^\circ, which means they are complementary. Therefore, the co-function identity sin(Z)=cos(X)\sin(Z) = \cos(X) applies. Substituting this relationship into the equation cos(X)+sin(Z)=1.6\cos(X) + \sin(Z) = 1.6 gives 2cos(X)=1.62\cos(X) = 1.6, leading to cos(X)=0.8\cos(X) = 0.8. Finally, using the Pythagorean identity sin2(X)+cos2(X)=1\sin^2(X) + \cos^2(X) = 1, we find sin(X)=10.82=0.6\sin(X) = \sqrt{1 - 0.8^2} = 0.6.

Adım Adım Çözüm

1
Determine the relationship between angles XX and ZZ.
X+Z=90X + Z = 90^\circ
Since the sum of the angles in right triangle XYZXYZ is 180180^\circ and angle YY is 9090^\circ, the two acute angles XX and ZZ must sum to 9090^\circ, making them complementary.
2
Use the co-function identity to relate sin(Z)\sin(Z) and cos(X)\cos(X).
sin(Z)=cos(X)\sin(Z) = \cos(X)
For complementary angles, the sine of one angle is equal to the cosine of the other.
3
Substitute the identity into the given equation to solve for cos(X)\cos(X).
cos(X)=0.8\cos(X) = 0.8
Replacing sin(Z)\sin(Z) with cos(X)\cos(X) in cos(X)+sin(Z)=1.6\cos(X) + \sin(Z) = 1.6 yields 2cos(X)=1.62\cos(X) = 1.6, so cos(X)=0.8\cos(X) = 0.8.
4
Solve for sin(X)\sin(X) using the Pythagorean identity.
sin(X)=0.6\sin(X) = 0.6
Since sin2(X)+cos2(X)=1\sin^2(X) + \cos^2(X) = 1, we have sin2(X)+(0.8)2=1\sin^2(X) + (0.8)^2 = 1, which gives sin2(X)=10.64=0.36\sin^2(X) = 1 - 0.64 = 0.36. Since XX is an acute angle, its sine must be positive, so sin(X)=0.6\sin(X) = 0.6.

Anahtar Kavram

Co-function and Pythagorean trigonometric identities in right triangles
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