In the xy-plane, a point (x, y) lies in the solution set of the system of inequalities bel… — SAT

In the $xy$ -plane, a point $(x, y)$ lies in the solution set of the system of inequalities below.

$y \leq -x + 8$
$y \leq 2x + 2$

What is the maximum possible value of $y$ ?

Cevap: 6

The maximum possible value of

y

is 6.

The solution set to the system of inequalities is the region in the coordinate plane that lies on or below both boundary lines,

y = -x + 8

and

y = 2x + 2

. The maximum

y

-value in this region occurs at the intersection of the two lines. Solving the system of equations by setting

-x + 8 = 2x + 2

gives

3x = 6

, which simplifies to

x = 2

. Substituting

x = 2

back into either equation yields

y = 6

. Therefore, the maximum possible value of

y

is 6.

Set the two boundary equations equal to each other to find the

x

-coordinate of the intersection point.

-x + 8 = 2x + 2 \implies 3x = 6 \implies x = 2

Since the solution region is bounded from above by both inequalities, the maximum value of

y

must occur at the intersection of the two boundary lines.

Substitute the

x

-value back into one of the equations to find the corresponding

y

-value.

y = 2(2) + 2 = 6

This determines the

y

-coordinate of the intersection point, which represents the maximum height of the shaded region.

Systems of Linear Inequalities in Two Variables

Tahmini Süre:45s

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