Tüm alıştırma soruları

612 soru

Soru 541Soru

For an acute angle xx measured in degrees, sin(x)sin(90x)=15\sin(x) - \sin(90^\circ - x) = \frac{1}{5}. What is the value of 12(tan(x)+tan(90x))12(\tan(x) + \tan(90^\circ - x))?

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Cevap: 25

Cevap

The value of the expression is 25.
Applying the co-function identity sin(90x)=cos(x)\sin(90^\circ - x) = \cos(x) allows the given equation to be written as sin(x)cos(x)=15\sin(x) - \cos(x) = \frac{1}{5}. Squaring both sides of this equation yields sin2(x)2sin(x)cos(x)+cos2(x)=125\sin^2(x) - 2\sin(x)\cos(x) + \cos^2(x) = \frac{1}{25}. Applying the Pythagorean identity sin2(x)+cos2(x)=1\sin^2(x) + \cos^2(x) = 1 simplifies this to 12sin(x)cos(x)=1251 - 2\sin(x)\cos(x) = \frac{1}{25}, which gives sin(x)cos(x)=1225\sin(x)\cos(x) = \frac{12}{25}. The expression to be evaluated is 12(tan(x)+tan(90x))12(\tan(x) + \tan(90^\circ - x)). Using the identity tan(90x)=cot(x)\tan(90^\circ - x) = \cot(x), this expression can be rewritten as 12(sin(x)cos(x)+cos(x)sin(x))=12(sin2(x)+cos2(x)sin(x)cos(x))=12(1sin(x)cos(x))12\left(\frac{\sin(x)}{\cos(x)} + \frac{\cos(x)}{\sin(x)}\right) = 12\left(\frac{\sin^2(x) + \cos^2(x)}{\sin(x)\cos(x)}\right) = 12\left(\frac{1}{\sin(x)\cos(x)}\right). Substituting the value of sin(x)cos(x)\sin(x)\cos(x) gives 12×2512=2512 \times \frac{25}{12} = 25.

Adım Adım Çözüm

1
Apply the co-function identity to rewrite the equation.
sin(x)cos(x)=15\sin(x) - \cos(x) = \frac{1}{5}
Since sin(90x)=cos(x)\sin(90^\circ - x) = \cos(x) for any angle xx, we can substitute cos(x)\cos(x) into the given equation.
2
Square both sides of the rewritten equation.
sin2(x)2sin(x)cos(x)+cos2(x)=125\sin^2(x) - 2\sin(x)\cos(x) + \cos^2(x) = \frac{1}{25}
Squaring both sides allows us to use the Pythagorean trigonometric identity to find the product of sine and cosine.
3
Substitute the Pythagorean identity and solve for sin(x)cos(x)\sin(x)\cos(x).
sin(x)cos(x)=1225\sin(x)\cos(x) = \frac{12}{25}
Substituting sin2(x)+cos2(x)=1\sin^2(x) + \cos^2(x) = 1 yields 12sin(x)cos(x)=1251 - 2\sin(x)\cos(x) = \frac{1}{25}, which simplifies to sin(x)cos(x)=1225\sin(x)\cos(x) = \frac{12}{25}.
4
Rewrite the target expression in terms of sine and cosine.
tan(x)+tan(90x)=1sin(x)cos(x)\tan(x) + \tan(90^\circ - x) = \frac{1}{\sin(x)\cos(x)}
Using the co-function identity tan(90x)=cot(x)\tan(90^\circ - x) = \cot(x) and expressing the tangent and cotangent functions as ratios of sine and cosine yields sin(x)cos(x)+cos(x)sin(x)=sin2(x)+cos2(x)sin(x)cos(x)=1sin(x)cos(x)\frac{\sin(x)}{\cos(x)} + \frac{\cos(x)}{\sin(x)} = \frac{\sin^2(x) + \cos^2(x)}{\sin(x)\cos(x)} = \frac{1}{\sin(x)\cos(x)}.
5
Substitute the value of sin(x)cos(x)\sin(x)\cos(x) and multiply by 12.
25
Substituting sin(x)cos(x)=1225\sin(x)\cos(x) = \frac{12}{25} into 12(tan(x)+tan(90x))12(\tan(x) + \tan(90^\circ - x)) gives 12×2512=2512 \times \frac{25}{12} = 25.

Anahtar Kavram

Applying co-function identities, the Pythagorean identity, and fundamental trigonometric relations to simplify expressions.
Tahmini Süre:2m 0s
Soru 542Soru

A circle has a radius of 1010. A shaded sector of the circle has an area of 10π10\pi. What is the measure, in degrees, of the central angle of the shaded sector?

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Cevap: 36

Cevap

The measure of the central angle of the shaded sector is 36 degrees.
The total area of the circle is A=π(10)2=100πA = \pi (10)^2 = 100\pi. The shaded sector's area is 10π10\pi, which represents 10π100π=110\frac{10\pi}{100\pi} = \frac{1}{10} of the total area of the circle. Since a circle consists of 360360^\circ, the central angle of the sector is 110×360=36\frac{1}{10} \times 360^\circ = 36^\circ.

Adım Adım Çözüm

1
Calculate the total area of the circle.
Total area = 100π100\pi
The area of a circle is calculated using the formula A=πr2A = \pi r^2 where the radius r=10r = 10.
2
Determine the proportion of the circle covered by the shaded sector.
Proportion = 110\frac{1}{10}
Dividing the sector's area of 10π10\pi by the total area of 100π100\pi gives the fraction of the circle represented by the sector.
3
Find the central angle in degrees.
Central angle = 36
Since a full circle has a central angle of 360360^\circ, multiplying the proportion 110\frac{1}{10} by 360360^\circ yields the central angle of the sector.

Anahtar Kavram

The ratio of the area of a sector to the total area of a circle is equal to the ratio of the sector's central angle measure to the total degree measure of a circle (360360^\circ).
Tahmini Süre:45s
Soru 543Soru

A municipal utility department wants to estimate the number of residential water service lines that contain lead in a community with 3,6003,600 homes. The department selects a random sample of 120120 homes and inspects their water service lines. The inspection reveals that 99 of the sampled homes have lead service lines. Based on the results of this sample, what is the estimated number of homes in the entire community that have lead service lines?

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Cevap: 270

Cevap

The estimated number of homes in the community that have lead service lines is 270.
Based on the random sample, the proportion of homes with lead service lines is 9 out of 120, which is 0.075 (or 7.5%). Generalizing this to the entire population of 3,600 homes yields an estimate of 0.075×3,600=2700.075 \times 3,600 = 270 homes.

Adım Adım Çözüm

1
Calculate the proportion of homes in the sample with lead service lines.
9120=0.075\frac{9}{120} = 0.075
To find the sample proportion, divide the number of homes with lead service lines by the total number of homes inspected.
2
Estimate the total number of homes in the community with lead service lines.
0.075×3,600=2700.075 \times 3,600 = 270
Multiply the total number of homes in the community by the proportion found in the random sample.

Anahtar Kavram

Estimating population parameters and totals from a random sample.
Soru 544Soru

A construction project requires a specific concrete mixture made by combining cement, sand, and gravel in a ratio of 1:2:41 : 2 : 4 by weight. A builder needs to prepare exactly 350350 pounds of this concrete mixture. If the builder currently has 8080 pounds of sand and an unlimited supply of cement and gravel, how many additional pounds of sand must the builder purchase to make the concrete mixture?

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Cevap: 20

Cevap

The builder must purchase 20 additional pounds of sand.
The ratio of cement to sand to gravel is 1:2:41 : 2 : 4, giving a total of 1+2+4=71 + 2 + 4 = 7 parts. Therefore, sand represents 27\frac{2}{7} of the total weight of the mixture. To find the total sand required for a 350350-pound mixture, we calculate 27×350=100\frac{2}{7} \times 350 = 100 pounds. Subtracting the 8080 pounds of sand already on hand, we find that the builder must purchase 10080=20100 - 80 = 20 additional pounds of sand.

Adım Adım Çözüm

1
Determine the fraction of the concrete mixture that consists of sand using the given ratio of 1:2:41 : 2 : 4 by weight.
Sand constitutes 27\frac{2}{7} of the total weight.
The sum of the ratio parts is 1+2+4=71 + 2 + 4 = 7 parts, and sand represents 22 parts out of these 77 total parts.
2
Calculate the total weight of sand required for 350350 pounds of the concrete mixture.
100100 pounds of sand.
Multiplying the fraction of sand, 27\frac{2}{7}, by the total desired weight of the mixture, 350350 pounds, gives the required weight of sand.
3
Calculate the additional amount of sand needed by subtracting the available sand from the total required sand.
2020 pounds of sand.
Since the builder already has 8080 pounds of sand, subtracting this from the required 100100 pounds yields the weight of additional sand to purchase.

Anahtar Kavram

Part-to-whole ratios and proportion scaling
Soru 545Soru

A polynomial f(x)f(x) is defined by f(x)=2x3+hx27x6f(x) = 2x^3 + hx^2 - 7x - 6, where hh is a constant. If the graph of y=f(x)y = f(x) in the xyxy-plane passes through the point (2,0)(2, 0), what is the value of hh?

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Cevap: 1

Cevap

The value of the constant hh is 1.
Since the graph of y=f(x)y = f(x) passes through the point (2,0)(2, 0), the value of the function at x=2x = 2 must be 00. Substituting x=2x = 2 into the equation yields 2(2)3+h(2)27(2)6=02(2)^3 + h(2)^2 - 7(2) - 6 = 0. Simplifying the terms gives 2(8)+4h146=02(8) + 4h - 14 - 6 = 0, which simplifies to 16+4h20=016 + 4h - 20 = 0, or 4h4=04h - 4 = 0. Solving for hh yields h=1h = 1.

Adım Adım Çözüm

1
Apply the point condition to the polynomial function.
f(2)=0f(2) = 0
Since the point (2,0)(2, 0) lies on the graph of y=f(x)y = f(x), substituting x=2x = 2 must yield y=0y = 0.
2
Substitute x=2x = 2 into the expression for f(x)f(x).
f(2)=2(2)3+h(2)27(2)6f(2) = 2(2)^3 + h(2)^2 - 7(2) - 6
We replace each occurrence of xx with 22 to evaluate the function value.
3
Simplify the algebraic expression.
16+4h20=0    4h4=016 + 4h - 20 = 0 \implies 4h - 4 = 0
Evaluating the exponents and multiplications gives 2(8)+4h146=16+4h20=4h42(8) + 4h - 14 - 6 = 16 + 4h - 20 = 4h - 4.
4
Solve the linear equation for hh.
h=1h = 1
Adding 4 to both sides gives 4h=44h = 4, and dividing by 4 gives h=1h = 1.

Anahtar Kavram

Connecting graphical x-intercepts of a polynomial to its algebraic roots and evaluation
Soru 546Soru

In triangle PQRPQR, point SS lies on side PQPQ and point TT lies on side PRPR such that segment STST is parallel to segment QRQR. The length of segment PSPS is xx, the length of segment SQSQ is 66, the length of segment STST is x+2x + 2, and the length of segment QRQR is 2x+72x + 7. What is the length of segment QRQR?

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Cevap: 15

Cevap

The length of segment QRQR is 1515.
Since segment STST is parallel to segment QRQR, triangle PSTPST is similar to triangle PQRPQR. The ratio of their corresponding sides is equal, so PSPQ=STQR\frac{PS}{PQ} = \frac{ST}{QR}. Substituting the values gives xx+6=x+22x+7\frac{x}{x + 6} = \frac{x + 2}{2x + 7}. Cross-multiplying and simplifying yields x2x12=0x^2 - x - 12 = 0. Factoring gives (x4)(x+3)=0(x-4)(x+3)=0, so x=4x=4 because side lengths must be positive. Substituting x=4x=4 into 2x+72x+7 yields 1515.

Adım Adım Çözüm

1
Determine the similarity between the triangles
Triangle PSTPST is similar to triangle PQRPQR
Since segment STST is parallel to segment QRQR, the corresponding angles are equal, establishing similarity by Angle-Angle (AA) criterion.
2
Express the total length of side PQPQ
PQ=x+6PQ = x + 6
The length of side PQPQ is the sum of the collinear segments PSPS and SQSQ.
3
Set up the similarity ratio equation
xx+6=x+22x+7\frac{x}{x + 6} = \frac{x + 2}{2x + 7}
Corresponding side lengths of similar triangles are in proportion: PSPQ=STQR\frac{PS}{PQ} = \frac{ST}{QR}.
4
Solve the quadratic equation for xx
x=4x = 4
Cross-multiplying gives x(2x+7)=(x+2)(x+6)    2x2+7x=x2+8x+12    x2x12=0    (x4)(x+3)=0x(2x + 7) = (x + 2)(x + 6) \implies 2x^2 + 7x = x^2 + 8x + 12 \implies x^2 - x - 12 = 0 \implies (x - 4)(x + 3) = 0. Since length must be positive, x=4x = 4.
5
Calculate the length of segment QRQR
QR=15QR = 15
Substitute x=4x = 4 into the expression for QRQR, which is 2x+72x + 7, resulting in 2(4)+7=152(4) + 7 = 15.

Anahtar Kavram

Using triangle similarity and algebraic equations to find unknown segment lengths.
Soru 547Soru

For an acute angle θ\theta, the expression sin4(θ)cos4(θ)sin(θ)cos(θ)\frac{\sin^4(\theta) - \cos^4(\theta)}{\sin(\theta) - \cos(\theta)} is equal to 75\frac{7}{5}. What is the value of 25sin(θ)cos(θ)25\sin(\theta)\cos(\theta)?

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Cevap: 12

Cevap

The correct answer is 12.
The expression sin4(θ)cos4(θ)sin(θ)cos(θ)\frac{\sin^4(\theta) - \cos^4(\theta)}{\sin(\theta) - \cos(\theta)} simplifies directly to sin(θ)+cos(θ)=75\sin(\theta) + \cos(\theta) = \frac{7}{5} by applying the difference of squares identity twice and substituting the Pythagorean identity sin2(θ)+cos2(θ)=1\sin^2(\theta) + \cos^2(\theta) = 1. Squaring both sides of this simplified equation gives sin2(θ)+2sin(θ)cos(θ)+cos2(θ)=4925\sin^2(\theta) + 2\sin(\theta)\cos(\theta) + \cos^2(\theta) = \frac{49}{25}. Replacing sin2(θ)+cos2(θ)\sin^2(\theta) + \cos^2(\theta) with 1 yields 1+2sin(θ)cos(θ)=49251 + 2\sin(\theta)\cos(\theta) = \frac{49}{25}, which simplifies to sin(θ)cos(θ)=1225\sin(\theta)\cos(\theta) = \frac{12}{25}. Multiplying this result by 25 gives the final integer value of 12.

Adım Adım Çözüm

1
Factor the numerator of the expression.
sin4(θ)cos4(θ)=(sin2(θ)cos2(θ))(sin2(θ)+cos2(θ))\sin^4(\theta) - \cos^4(\theta) = (\sin^2(\theta) - \cos^2(\theta))(\sin^2(\theta) + \cos^2(\theta))
The difference of squares identity can be applied to terms with fourth powers.
2
Apply the Pythagorean identity to simplify the factored numerator.
sin4(θ)cos4(θ)=sin2(θ)cos2(θ)\sin^4(\theta) - \cos^4(\theta) = \sin^2(\theta) - \cos^2(\theta)
The Pythagorean trigonometric identity states that sin2(θ)+cos2(θ)=1\sin^2(\theta) + \cos^2(\theta) = 1.
3
Factor the remaining term in the numerator.
sin2(θ)cos2(θ)=(sin(θ)cos(θ))(sin(θ)+cos(θ))\sin^2(\theta) - \cos^2(\theta) = (\sin(\theta) - \cos(\theta))(\sin(\theta) + \cos(\theta))
This is another application of the difference of squares identity.
4
Simplify the fraction by dividing the common factor in the numerator and denominator.
sin(θ)+cos(θ)=75\sin(\theta) + \cos(\theta) = \frac{7}{5}
The term sin(θ)cos(θ)\sin(\theta) - \cos(\theta) in the numerator and denominator cancels out since θ\theta is an acute angle and sin(θ)cos(θ)\sin(\theta) \neq \cos(\theta).
5
Square both sides of the simplified equation.
sin2(θ)+2sin(θ)cos(θ)+cos2(θ)=4925\sin^2(\theta) + 2\sin(\theta)\cos(\theta) + \cos^2(\theta) = \frac{49}{25}
Squaring both sides allows us to relate the sum sin(θ)+cos(θ)\sin(\theta) + \cos(\theta) to the product sin(θ)cos(θ)\sin(\theta)\cos(\theta).
6
Substitute the Pythagorean identity and solve for the product of sine and cosine.
sin(θ)cos(θ)=1225\sin(\theta)\cos(\theta) = \frac{12}{25}
Substituting sin2(θ)+cos2(θ)=1\sin^2(\theta) + \cos^2(\theta) = 1 yields 1+2sin(θ)cos(θ)=49251 + 2\sin(\theta)\cos(\theta) = \frac{49}{25}, which simplifies to 2sin(θ)cos(θ)=24252\sin(\theta)\cos(\theta) = \frac{24}{25}.
7
Multiply the product by 25 to find the target value.
12
The question asks for the value of 25sin(θ)cos(θ)25\sin(\theta)\cos(\theta).

Anahtar Kavram

Simplifying trigonometric expressions using algebraic factorization and Pythagorean identities.

Alternatif Yöntem

Since θ\theta is an acute angle in a right triangle, we can test standard Pythagorean triples. A right triangle with side lengths 3, 4, and 5 has an angle θ\theta where sin(θ)=35\sin(\theta) = \frac{3}{5} and cos(θ)=45\cos(\theta) = \frac{4}{5}. Checking these values in the simplified expression gives sin(θ)+cos(θ)=35+45=75\sin(\theta) + \cos(\theta) = \frac{3}{5} + \frac{4}{5} = \frac{7}{5}, which matches the given condition. We can then directly calculate 25sin(θ)cos(θ)=25(35)(45)=1225\sin(\theta)\cos(\theta) = 25 \left(\frac{3}{5}\right)\left(\frac{4}{5}\right) = 12.
Tahmini Süre:3m 0s
Soru 548Soru

An agricultural department monitored the population of honeybee colonies in two adjacent conservation areas starting in 2018 (t=0t = 0). In Area 1, the number of colonies increases by a constant 230 colonies each year. In Area 2, the number of colonies increases by a constant 10% each year. At t=0t = 0, both areas had 2,000 colonies. If the model for Area 1 predicts LL colonies at t=3t = 3 and the model for Area 2 predicts EE colonies at t=3t = 3, what is the value of LEL - E?

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Cevap: 28

Cevap

28
To find the value of LEL - E, the populations projected by each model at t=3t = 3 must be calculated.

For Area 1, the growth is linear with an initial population of 2,000 and a constant annual increase of 230. The model is L(t)=2000+230tL(t) = 2000 + 230t. At t=3t = 3, the population is L(3)=2000+230(3)=2690L(3) = 2000 + 230(3) = 2690.

For Area 2, the growth is exponential with an initial population of 2,000 and a constant annual increase of 10%. The model is E(t)=2000(1.10)tE(t) = 2000(1.10)^t. At t=3t = 3, the population is E(3)=2000(1.10)3=2000(1.331)=2662E(3) = 2000(1.10)^3 = 2000(1.331) = 2662.

Subtracting the exponential model output from the linear model output yields LE=26902662=28L - E = 2690 - 2662 = 28.

Adım Adım Çözüm

1
Model the population growth for Area 1.
L(t)=2000+230tL(t) = 2000 + 230t. For t=3t = 3, L(3)=2000+230(3)=2000+690=2690L(3) = 2000 + 230(3) = 2000 + 690 = 2690. Thus, L=2690L = 2690.
Since Area 1 increases by a constant number of colonies (230) each year, its growth is linear. The initial population is 2,000.
2
Model the population growth for Area 2.
E(t)=2000(1.10)tE(t) = 2000(1.10)^t. For t=3t = 3, E(3)=2000(1.10)3=2000(1.331)=2662E(3) = 2000(1.10)^3 = 2000(1.331) = 2662. Thus, E=2662E = 2662.
Since Area 2 increases by a constant percentage (10%) each year, its growth is exponential with a growth factor of 1+0.10=1.101 + 0.10 = 1.10.
3
Calculate the difference LEL - E.
LE=26902662=28L - E = 2690 - 2662 = 28.
We need to find the difference between the linear model's prediction and the exponential model's prediction at t=3t = 3.

Anahtar Kavram

Linear growth increases by a constant amount per unit of time, whereas exponential growth increases by a constant percentage (or multiplies by a constant factor) per unit of time.

Alternatif Yöntem

Instead of setting up equations, the population values can be calculated step-by-step for each year.
Year 1 (t=1t = 1):
Area 1: 2000+230=22302000 + 230 = 2230
Area 2: 2000×1.10=22002000 \times 1.10 = 2200

Year 2 (t=2t = 2):
Area 1: 2230+230=24602230 + 230 = 2460
Area 2: 2200×1.10=24202200 \times 1.10 = 2420

Year 3 (t=3t = 3):
Area 1: 2460+230=26902460 + 230 = 2690
Area 2: 2420×1.10=26622420 \times 1.10 = 2662

Subtracting the two values at Year 3 gives the final result: 26902662=282690 - 2662 = 28.
Tahmini Süre:1m 30s
Soru 549Soru

In a right triangle, the two acute angles are θ\theta and ϕ\phi. If sin(θ)=725\sin(\theta) = \frac{7}{25} and cos(ϕ)=k50\cos(\phi) = \frac{k}{50}, what is the value of kk?

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Cevap: 14

Cevap

14
In any right triangle, the two acute angles, θ\theta and ϕ\phi, must sum to 9090^\circ. The cofunction trigonometric identity states that sin(θ)=cos(90θ)=cos(ϕ)\sin(\theta) = \cos(90^\circ - \theta) = \cos(\phi). Therefore, we can equate the two given values: 725=k50\frac{7}{25} = \frac{k}{50}. Solving this equation for kk gives k=7×5025=14k = \frac{7 \times 50}{25} = 14.

Adım Adım Çözüm

1
Determine the relationship between the two acute angles in a right triangle.
θ+ϕ=90\theta + \phi = 90^\circ
Since the sum of the angles in any triangle is 180180^\circ and a right triangle has one 9090^\circ angle, the sum of the other two acute angles must be 9090^\circ.
2
Apply the cofunction trigonometric identity for complementary angles.
sin(θ)=cos(ϕ)\sin(\theta) = \cos(\phi)
The sine of an acute angle is always equal to the cosine of its complement.
3
Equate the given expressions and solve for kk.
725=k50    k=14\frac{7}{25} = \frac{k}{50} \implies k = 14
Substitute the given values into the identity and multiply both sides by 5050 to isolate kk.

Anahtar Kavram

Cofunction identities for complementary angles in a right triangle
Soru 550Soru

In a circle with center OO, central angle AOBAOB has a measure of 5π6\frac{5\pi}{6} radians. If the radius of the circle is 1212, the length of arc ABAB is kπk\pi. What is the value of kk?

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Cevap: 10

Cevap

The value of kk is 1010.
The arc length ss subtended by a central angle θ\theta (in radians) in a circle of radius rr is given by s=rθs = r\theta. Substituting the radius r=12r = 12 and the angle θ=5π6\theta = \frac{5\pi}{6} yields s=12×5π6=10πs = 12 \times \frac{5\pi}{6} = 10\pi. Since the arc length is expressed as kπk\pi, the value of kk is 1010.

Adım Adım Çözüm

1
Identify the formula for arc length in radians.
s=rθs = r\theta
The arc length ss is directly proportional to the radius rr and the central angle θ\theta in radians.
2
Substitute the given values into the formula.
s=12×5π6s = 12 \times \frac{5\pi}{6}
The radius of the circle is 1212 and the central angle is 5π6\frac{5\pi}{6} radians.
3
Calculate the arc length.
s=10πs = 10\pi
Simplifying 12×5612 \times \frac{5}{6} gives 2×5=102 \times 5 = 10, so the product is 10π10\pi.
4
Determine the value of kk.
k=10k = 10
We equate the calculated arc length 10π10\pi with the given expression kπk\pi.

Anahtar Kavram

Arc length of a circle using radian measure
Tahmini Süre:45s
Soru 551Soru

A research group conducted a survey using a random sample of 250250 residents of a town with a total population of 18,00018,000 residents. Of the residents surveyed, 64%64\% reported that they recycle regularly. The survey has a margin of error of 3%3\%. Based on the survey results, what is the difference between the maximum and minimum estimated number of residents in the town who recycle regularly?

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Cevap: 1080

Cevap

The correct answer is 1,080.
The sample proportion is 64%64\% with a margin of error of 3%3\%, which establishes an interval of 61%61\% to 67%67\% for the proportion of the population that recycles regularly. Multiplying these boundaries by the total population of 18,00018,000 yields a minimum estimate of 0.61×18,000=10,9800.61 \times 18,000 = 10,980 residents and a maximum estimate of 0.67×18,000=12,0600.67 \times 18,000 = 12,060 residents. The difference between the maximum and minimum estimated number of residents is 12,06010,980=1,08012,060 - 10,980 = 1,080. Alternatively, this difference can be found by multiplying the total width of the interval (2×0.03=0.062 \times 0.03 = 0.06) by the population size (0.06×18,000=1,0800.06 \times 18,000 = 1,080).

Adım Adım Çözüm

1
Determine the range of the proportion of residents who recycle regularly.
The proportion ranges from 61%61\% (0.610.61) to 67%67\% (0.670.67).
The margin of error of 3%3\% is subtracted from and added to the sample proportion of 64%64\%.
2
Calculate the minimum and maximum estimated number of residents who recycle regularly.
The minimum estimate is 10,98010,980 residents and the maximum estimate is 12,06012,060 residents.
Multiply the minimum and maximum proportions by the total population of 18,00018,000: 0.61×18,000=10,9800.61 \times 18,000 = 10,980 and 0.67×18,000=12,0600.67 \times 18,000 = 12,060.
3
Find the difference between the maximum and minimum estimated values.
12,06010,980=1,08012,060 - 10,980 = 1,080 (or alternatively, 2×0.03×18,000=1,0802 \times 0.03 \times 18,000 = 1,080).
Subtracting the minimum estimate from the maximum estimate yields the difference.

Anahtar Kavram

Using sample statistics and margin of error to estimate population parameters.
Soru 552Soru

For the polynomial p(x)=2x3x2kx+6p(x) = 2x^3 - x^2 - kx + 6, where kk is a constant, the remainder when p(x)p(x) is divided by 2x32x - 3 is 00. What is the value of kk?

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Cevap: 7

Cevap

The value of kk is 77.
The correct answer is 77. According to the Factor Theorem, a linear expression axbax - b is a factor of a polynomial p(x)p(x) if and only if p(ba)=0p\left(\frac{b}{a}\right) = 0. Here, the divisor is 2x32x - 3, so setting 2x3=02x - 3 = 0 gives the root x=32x = \frac{3}{2}. Substituting x=32x = \frac{3}{2} into p(x)=2x3x2kx+6p(x) = 2x^3 - x^2 - kx + 6 gives 2(32)3(32)2k(32)+6=02\left(\frac{3}{2}\right)^3 - \left(\frac{3}{2}\right)^2 - k\left(\frac{3}{2}\right) + 6 = 0. Simplifying this equation gives 2749432k+6=0\frac{27}{4} - \frac{9}{4} - \frac{3}{2}k + 6 = 0, which reduces to 9232k+6=0\frac{9}{2} - \frac{3}{2}k + 6 = 0. Combining the constant terms gives 21232k=0\frac{21}{2} - \frac{3}{2}k = 0, which simplifies to 3k=213k = 21. Solving for kk gives k=7k = 7.

Adım Adım Çözüm

1
Determine the root associated with the linear factor 2x32x - 3.
Setting 2x3=02x - 3 = 0 gives x=32x = \frac{3}{2}. By the Factor Theorem, p(32)=0p\left(\frac{3}{2}\right) = 0.
According to the Factor Theorem, a polynomial p(x)p(x) has a factor of the form axbax - b if and only if p(ba)=0p\left(\frac{b}{a}\right) = 0.
2
Substitute x=32x = \frac{3}{2} into the polynomial expression 2x3x2kx+62x^3 - x^2 - kx + 6 and set it to 00.
2(32)3(32)2k(32)+6=02\left(\frac{3}{2}\right)^3 - \left(\frac{3}{2}\right)^2 - k\left(\frac{3}{2}\right) + 6 = 0
This establishes a linear equation in terms of the unknown constant kk.
3
Simplify the numerical terms and solve for kk.
2(278)9432k+6=0    2749432k+6=0    9232k+6=0    21232k=0    3k=21    k=72\left(\frac{27}{8}\right) - \frac{9}{4} - \frac{3}{2}k + 6 = 0 \implies \frac{27}{4} - \frac{9}{4} - \frac{3}{2}k + 6 = 0 \implies \frac{9}{2} - \frac{3}{2}k + 6 = 0 \implies \frac{21}{2} - \frac{3}{2}k = 0 \implies 3k = 21 \implies k = 7.
Standard fractional arithmetic and algebraic isolation are used to find the value of kk.

Anahtar Kavram

Factor and Remainder Theorems
Soru 553Soru

In the figure, lines ABAB and CDCD intersect at point OO, and ray OEOE is perpendicular to line ABAB. If the measure of EOC\angle EOC is 2727^\circ, what is the measure, in degrees, of BOD\angle BOD?

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Cevap: 63

Cevap

The measure of BOD\angle BOD is 63 degrees.
The correct answer is 63. Since ray OEOE is perpendicular to line ABAB, the angle EOA\angle EOA is a right angle measuring 9090^\circ. The adjacent angles AOC\angle AOC and EOC\angle EOC make up EOA\angle EOA, which means AOC=9027=63\angle AOC = 90^\circ - 27^\circ = 63^\circ. Finally, because lines ABAB and CDCD intersect at point OO, the angle BOD\angle BOD and the angle AOC\angle AOC are vertical angles. Vertical angles are equal in measure, so the measure of BOD\angle BOD is 6363^\circ.

Adım Adım Çözüm

1
Identify the angle formed by perpendicular lines.
The measure of EOA\angle EOA is 9090^\circ.
Since ray OEOE is perpendicular to line ABAB, the angle EOA\angle EOA is a right angle.
2
Calculate the measure of AOC\angle AOC.
The measure of AOC\angle AOC is 6363^\circ.
Angles AOC\angle AOC and EOC\angle EOC are adjacent and form the right angle EOA\angle EOA, meaning they are complementary: AOC=9027=63\angle AOC = 90^\circ - 27^\circ = 63^\circ.
3
Determine the measure of BOD\angle BOD.
The measure of BOD\angle BOD is 6363^\circ.
Lines ABAB and CDCD intersect at point OO, making BOD\angle BOD and AOC\angle AOC vertical angles. Since vertical angles are equal, the measure of BOD\angle BOD is equal to the measure of AOC\angle AOC.

Anahtar Kavram

Using properties of perpendicular lines and vertical angles to solve for unknown angle measures.
Tahmini Süre:1m 30s
Soru 554Soru

In triangle ABCABC, the measure of angle ABCABC is 9090^\circ and the measure of angle BACBAC is 3030^\circ. Segment BDBD is perpendicular to segment ACAC such that DD lies on ACAC. Segment DEDE is perpendicular to segment BCBC such that EE lies on BCBC. If the length of segment CECE is 33, what is the length of segment ACAC?

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Cevap: 24

Cevap

The correct answer is 24.
The correct answer is 24. Since the question asks for the length of segment AC, and by sequentially applying the properties of 30-60-90 right triangles we find CD = 6, BC = 12, and AC = 24.

Adım Adım Çözüm

1
Find the measure of angle ACBACB in triangle ABCABC.
ACB=60\angle ACB = 60^\circ
The sum of the angles in a triangle is 180180^\circ, so ACB=180ABCBAC=1809030=60\angle ACB = 180^\circ - \angle ABC - \angle BAC = 180^\circ - 90^\circ - 30^\circ = 60^\circ.
2
Calculate the length of segment CDCD using right triangle DECDEC.
CD=6CD = 6
In the right triangle DECDEC, DEC=90\angle DEC = 90^\circ and C=60\angle C = 60^\circ, making it a 30-60-90 triangle. The side opposite the 3030^\circ angle is CE=3CE = 3, so the hypotenuse CDCD is 2×CE=2×3=62 \times CE = 2 \times 3 = 6.
3
Calculate the length of segment BCBC using right triangle BDCBDC.
BC=12BC = 12
In the right triangle BDCBDC, BDBD is perpendicular to ACAC, so BDC=90\angle BDC = 90^\circ. With BCD=60\angle BCD = 60^\circ, this is a 30-60-90 triangle. The side opposite the 3030^\circ angle is CD=6CD = 6, so the hypotenuse BCBC is 2×CD=2×6=122 \times CD = 2 \times 6 = 12.
4
Calculate the length of the hypotenuse ACAC using right triangle ABCABC.
AC=24AC = 24
In the right triangle ABCABC, the angle BAC=30\angle BAC = 30^\circ and the side opposite to it is BC=12BC = 12. The hypotenuse ACAC is twice the length of the opposite leg, so AC=2×BC=2×12=24AC = 2 \times BC = 2 \times 12 = 24.

Anahtar Kavram

Properties of special right triangles (30-60-90 triangles) and their trigonometric ratios.
Soru 555Soru

At the beginning of 2015, Forest A had 4,000 trees and Forest B had 3,000 trees. The number of trees in Forest A increases by 150 trees each year. The number of trees in Forest B increases by 4% each year. If A(t)A(t) and B(t)B(t) represent the number of trees in Forest A and Forest B, respectively, tt years after the beginning of 2015, what is the value of A(5)B(5)A(5) - B(5), rounded to the nearest whole number?

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Cevap: 1100

Cevap

The correct value of A(5)B(5)A(5) - B(5) is 1100.
The correct value is 1100. By defining Forest A's population with the linear function A(t)=4000+150tA(t) = 4000 + 150t and Forest B's population with the exponential function B(t)=3000(1.04)tB(t) = 3000(1.04)^t, evaluating both functions at t=5t = 5 yields A(5)=4750A(5) = 4750 and B(5)3650B(5) \approx 3650. The difference is 47503650=11004750 - 3650 = 1100.

Adım Adım Çözüm

1
Formulate the growth model for Forest A.
A(t)=4000+150tA(t) = 4000 + 150t
Forest A grows linearly with a constant increase of 150 trees per year from an initial value of 4,000 trees.
2
Formulate the growth model for Forest B.
B(t)=3000(1.04)tB(t) = 3000(1.04)^t
Forest B grows exponentially with a constant percent increase of 4% per year (growth factor of 1+0.04=1.041 + 0.04 = 1.04) from an initial value of 3,000 trees.
3
Calculate the population of each forest after 5 years (t=5t = 5).
A(5)=4750A(5) = 4750 and B(5)3650B(5) \approx 3650
Substitute t=5t = 5 into both models: A(5)=4000+150(5)=4750A(5) = 4000 + 150(5) = 4750 and B(5)=3000(1.04)53649.96B(5) = 3000(1.04)^5 \approx 3649.96.
4
Calculate the difference A(5)B(5)A(5) - B(5) and round to the nearest whole number.
1100
Subtract: 47503649.96=1100.044750 - 3649.96 = 1100.04. Rounding 1100.04 to the nearest whole number yields 1100.

Anahtar Kavram

Linear vs. Exponential Growth Models

Alternatif Yöntem

Instead of evaluating each function separately, you can construct the difference expression directly as D(t)=(4000+150t)3000(1.04)tD(t) = (4000 + 150t) - 3000(1.04)^t and substitute t=5t = 5 into D(t)D(t) to compute D(5)=47503000(1.04)51100.04D(5) = 4750 - 3000(1.04)^5 \approx 1100.04, which rounds to 1100.
Tahmini Süre:1m 30s
Soru 556Soru

An agricultural irrigation system uses two types of sprinklers, Type A and Type B. Water flows through 33 Type A sprinklers at a combined rate of 1515 gallons per minute. Water flows through 55 Type B sprinklers at a combined rate of 1818 gallons per minute. If a farmer runs 88 Type A sprinklers and 1010 Type B sprinklers simultaneously, what is the total rate of water flow, in gallons per minute?

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Cevap: 76

Cevap

The total rate of water flow is 76 gallons per minute.
To find the total water flow rate, determine the rate of a single sprinkler of each type first. For Type A, the rate is 15 gallons per minute÷3=5 gallons per minute15 \text{ gallons per minute} \div 3 = 5 \text{ gallons per minute}. For Type B, the rate is 18 gallons per minute÷5=3.6 gallons per minute18 \text{ gallons per minute} \div 5 = 3.6 \text{ gallons per minute}. Running 88 Type A sprinklers and 1010 Type B sprinklers simultaneously yields a total rate of (8×5)+(10×3.6)=40+36=76(8 \times 5) + (10 \times 3.6) = 40 + 36 = 76 gallons per minute.

Adım Adım Çözüm

1
Find the rate of water flow for a single Type A sprinkler.
Each Type A sprinkler has a water flow rate of 55 gallons per minute.
Dividing the combined rate of 1515 gallons per minute by the 33 sprinklers gives the individual rate.
2
Find the rate of water flow for a single Type B sprinkler.
Each Type B sprinkler has a water flow rate of 3.63.6 gallons per minute.
Dividing the combined rate of 1818 gallons per minute by the 55 sprinklers gives the individual rate.
3
Calculate the total water flow rate for the combined group of active sprinklers.
The total combined flow rate is 7676 gallons per minute.
Multiplying the individual rate of each type by the respective count of active sprinklers and summing the results: (8×5)+(10×3.6)=40+36=76(8 \times 5) + (10 \times 3.6) = 40 + 36 = 76.

Anahtar Kavram

Combining rates of individual components to find a total rate.
Tahmini Süre:1m 30s
Soru 557Soru

In the xyxy-plane, an angle θ\theta in standard position has its terminal ray intersecting the unit circle at the point (22,22)\left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2}\right). The angle is rotated counterclockwise by 1515^\circ, and then its measure is doubled. The final resulting angle is coterminal with an angle of aπb\frac{a\pi}{b} radians, where 0aπb<2π0 \le \frac{a\pi}{b} < 2\pi, and aa and bb are positive integers with no common factors. What is the value of a+ba + b?

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Cevap: 5

Cevap

5
The correct answer is 5. Starting with the point (22,22)\left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2}\right) on the unit circle, the angle in standard position is 225225^\circ (or 5π4\frac{5\pi}{4} radians). Adding 1515^\circ for the counterclockwise rotation yields 240240^\circ (or 4π3\frac{4\pi}{3} radians). Doubling this measure gives 480480^\circ (or 8π3\frac{8\pi}{3} radians). Finding the coterminal angle within [0,2π)[0, 2\pi) yields 120120^\circ (or 2π3\frac{2\pi}{3} radians). In this form, a=2a=2 and b=3b=3, which are positive integers with no common factors, so a+b=5a+b = 5.

Adım Adım Çözüm

1
Determine the initial angle of the terminal ray intersecting the unit circle at (22,22)\left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2}\right).
The initial angle θ\theta is 225225^\circ (or 5π4\frac{5\pi}{4} radians).
Since both the xx- and yy-coordinates are negative and equal, the angle lies in the third quadrant and forms a 4545^\circ reference angle with the negative xx-axis, which corresponds to 225225^\circ.
2
Apply a counterclockwise rotation of 1515^\circ to the initial angle.
The new angle is 240240^\circ (or 4π3\frac{4\pi}{3} radians).
Counterclockwise rotations correspond to adding positive angle measures: 225+15=240225^\circ + 15^\circ = 240^\circ.
3
Double the measure of the rotated angle.
The doubled angle is 480480^\circ (or 8π3\frac{8\pi}{3} radians).
The prompt specifies that the angle's measure is doubled after the rotation: 240×2=480240^\circ \times 2 = 480^\circ.
4
Find the coterminal angle within the standard interval [0,2π)[0, 2\pi) radians (or [0,360)[0^\circ, 360^\circ)).
The coterminal angle is 120120^\circ (or 2π3\frac{2\pi}{3} radians).
To bring the angle back into the interval [0,360)[0^\circ, 360^\circ), subtract 360360^\circ (one full rotation): 480360=120480^\circ - 360^\circ = 120^\circ. In radians, 120×π180=2π3120^\circ \times \frac{\pi}{180^\circ} = \frac{2\pi}{3} radians.
5
Identify aa and bb and calculate their sum.
a=2a = 2, b=3b = 3, and a+b=5a + b = 5.
The coterminal angle is expressed as aπb\frac{a\pi}{b} in simplest form, so a=2a=2 and b=3b=3, which are positive integers with no common factors.

Anahtar Kavram

Converting between radians and degrees, finding coterminal angles, and performing angle transformations.
Tahmini Süre:3m 0s
Soru 558Soru

In the xyxy-plane, the graph of the quadratic function ff has a vertex at (h,k)(h, k), where hh and kk are constants. The graph passes through the points (1,10)(1, 10) and (7,10)(7, 10). If the minimum value of the function ff is 11, what is the value of f(2)f(2)?

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Cevap: 5

Cevap

The value of f(2)f(2) is 5.
The correct answer is 5. Since the graph of the quadratic function passes through (1,10)(1, 10) and (7,10)(7, 10), the axis of symmetry is the vertical line halfway between x=1x = 1 and x=7x = 7, which is x=1+72=4x = \frac{1+7}{2} = 4. The minimum value of the function is 11, which occurs at the vertex, so the vertex is (4,1)(4, 1). In vertex form, the function is f(x)=a(x4)2+1f(x) = a(x-4)^2 + 1. Substituting the point (1,10)(1, 10) yields 10=a(14)2+110 = a(1-4)^2 + 1, which simplifies to 9=9a9 = 9a, so a=1a = 1. The function is f(x)=(x4)2+1f(x) = (x-4)^2 + 1. Evaluating this function at x=2x = 2 gives f(2)=(24)2+1=5f(2) = (2-4)^2 + 1 = 5.

Adım Adım Çözüm

1
Find the xx-coordinate of the vertex using the symmetry of the parabola.
h=4h = 4
A parabola is symmetric about its vertical axis of symmetry. Since the points (1,10)(1, 10) and (7,10)(7, 10) have the same yy-coordinate, the axis of symmetry is exactly halfway between their xx-coordinates: x=1+72=4x = \frac{1 + 7}{2} = 4.
2
Find the vertex coordinates using the minimum value of the function.
Vertex is (4,1)(4, 1)
The vertex of a quadratic function with a minimum value lies on the axis of symmetry, and its yy-coordinate is the minimum value. Thus, the vertex (h,k)(h, k) is (4,1)(4, 1).
3
Write the vertex form of the quadratic function and solve for the leading coefficient aa.
f(x)=(x4)2+1f(x) = (x - 4)^2 + 1
Using the vertex form f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, we substitute h=4h = 4 and k=1k = 1 to get f(x)=a(x4)2+1f(x) = a(x - 4)^2 + 1. Substituting the point (1,10)(1, 10) gives 10=a(14)2+1    9=9a    a=110 = a(1 - 4)^2 + 1 \implies 9 = 9a \implies a = 1.
4
Evaluate f(2)f(2) using the determined function.
f(2)=5f(2) = 5
Substitute x=2x = 2 into the equation f(x)=(x4)2+1f(x) = (x - 4)^2 + 1 to obtain f(2)=(24)2+1=4+1=5f(2) = (2 - 4)^2 + 1 = 4 + 1 = 5.

Anahtar Kavram

Using symmetry and the vertex form of a quadratic function to determine its equation and evaluate values.
Tahmini Süre:1m 30s
Soru 559Soru

A marine biologist wants to estimate the number of blue crabs in a bay that are infected with a specific parasite. The biologist captures a random sample of 250250 blue crabs from the bay, finds that 1515 of the crabs are infected, and then releases them. Based on this sample, if there is a total population of 12,00012,000 blue crabs in the bay, what is the best estimate of the total number of blue crabs infected with the parasite?

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Cevap: 720

Cevap

The best estimate of the total number of blue crabs infected with the parasite is 720.
The correct answer is found by establishing the sample proportion of infected crabs, which is 15 out of 250, or 6%. Multiplying this rate by the total estimated population of 12,000 crabs yields 720.

Adım Adım Çözüm

1
Calculate the proportion of infected crabs in the sample.
15250=0.06\frac{15}{250} = 0.06
To determine the rate of infection in the representative sample.
2
Multiply the sample proportion by the total population of blue crabs in the bay.
0.06×12,000=7200.06 \times 12,000 = 720
To generalize the sample rate to the entire population of crabs in the bay.

Anahtar Kavram

Generalizing a sample proportion to estimate a population parameter.
Soru 560Soru

In the xyxy-plane, a circle with center (4,9)(4, 9) and radius 55 is defined by the equation (xh)2+(y9)2=25(x - h)^2 + (y - 9)^2 = 25, where hh is a positive constant. What is the value of hh?

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Cevap: 4

Cevap

The value of the constant hh is 44.
The standard equation of a circle with center (h,k)(h, k) and radius rr is (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2. Since the center is (4,9)(4, 9) and the radius is 55, the equation of the circle is (x4)2+(y9)2=52(x - 4)^2 + (y - 9)^2 = 5^2, which simplifies to (x4)2+(y9)2=25(x - 4)^2 + (y - 9)^2 = 25. Comparing this to the given equation (xh)2+(y9)2=25(x - h)^2 + (y - 9)^2 = 25, we see that the constant hh corresponds to the xx-coordinate of the center, which is 44.

Adım Adım Çözüm

1
Identify the standard equation of a circle.
(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2
This formula represents a circle with center (h,k)(h, k) and radius rr in the coordinate plane.
2
Substitute the given center coordinates into the standard equation.
For center (4,9)(4, 9), the equation is (x4)2+(y9)2=r2(x - 4)^2 + (y - 9)^2 = r^2.
The coordinates of the center are mapped directly to hh and kk in the standard form.
3
Compare the equation template to find the value of hh.
The equation (x4)2+(y9)2=25(x - 4)^2 + (y - 9)^2 = 25 matches the format (xh)2+(y9)2=25(x - h)^2 + (y - 9)^2 = 25, indicating that h=4h = 4.
Equating the terms in both equations allows us to identify the value of the positive constant hh.

Anahtar Kavram

Extracting coordinates of the center from the standard form equation of a circle.
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