Tüm alıştırma soruları

2789 soru

Soru 1441Soru

Each of the pioneering female photojournalists who documented the rapid industrialization of the American Midwest in the early twentieth century sought to capture the human cost of labor in ______ work. By emphasizing the grueling conditions of factory worker families, these photographers challenged the era's idealized narratives of technological progress.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Cevap: her

Cevap

her
The singular possessive pronoun 'her' is correct because the antecedent of the pronoun is 'Each', which is a singular indefinite pronoun. Because the photojournalists are specified as female, the singular feminine possessive pronoun 'her' is appropriate to show possession of the noun 'work'.

Adım Adım Çözüm

1
Identify the antecedent of the pronoun needed in the blank.
The antecedent is the indefinite pronoun 'Each'.
The pronoun must agree in number with its antecedent.
2
Determine the grammatical number of the antecedent.
'Each' is a singular indefinite pronoun.
Although 'photojournalists' is plural, it is the object of the prepositional phrase 'of the pioneering female photojournalists' and does not function as the antecedent.
3
Select the correct pronoun case and number to fit the context.
The blank modifies the noun 'work', so a possessive pronoun is needed. Since the photojournalists are female, the singular possessive pronoun 'her' is the correct choice.
A singular possessive pronoun is required to show possession and maintain agreement with 'Each'.

Anahtar Kavram

Pronoun-antecedent agreement in number requires that a pronoun match its antecedent (singular or plural), regardless of any intervening prepositional phrases or relative clauses.
Tahmini Süre:1m 0s
Soru 1442Soru

A circle in the xyxy-plane is defined by the equation (xh)2+(yk)2=16(x - h)^2 + (y - k)^2 = 16, where hh and kk are constants. The center (h,k)(h, k) of the circle lies on the line y=xy = x. A second line, which passes through the origin and has a slope of 34-\frac{3}{4}, is tangent to the circle at exactly one point (x,y)(x, y). If this point of tangency lies in a quadrant where x>0x > 0 and y<0y < 0, what is the value of hh?

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Cevap: 207\frac{20}{7}

Cevap

207\frac{20}{7}
The correct option is 207\frac{20}{7}. By setting the center of the circle to (h,h)(h, h) and the equation of the line to 3x+4y=03x + 4y = 0, we find that the distance from the center to the line is 7h5\frac{|7h|}{5}. Since the line is tangent to the circle, this distance must equal the radius, which is 44. This gives h=±207h = \pm\frac{20}{7}. Finding the point of tangency shows that x=425hx = \frac{4}{25}h and y=325hy = -\frac{3}{25}h. For the point of tangency to lie in Quadrant IV (x>0x > 0 and y<0y < 0), hh must be positive, which yields h=207h = \frac{20}{7}.

Adım Adım Çözüm

1
Express the center of the circle and the equation of the tangent line in terms of the given parameters.
Since the center (h,k)(h, k) lies on the line y=xy = x, we have k=hk = h. The circle has radius R=16=4R = \sqrt{16} = 4 and is centered at (h,h)(h, h). The tangent line passes through the origin with slope 34-\frac{3}{4}, so its equation is y=34xy = -\frac{3}{4}x, which simplifies to 3x+4y=03x + 4y = 0.
Setting up the algebraic expressions for both geometric entities is necessary to relate them using coordinate geometry formulas.
2
Apply the tangency condition using the point-to-line distance formula.
The distance from the center (h,h)(h, h) to the line 3x+4y=03x + 4y = 0 must equal the radius 44. Thus: 3h+4h32+42=4    7h5=4    7h=20\frac{|3h + 4h|}{\sqrt{3^2 + 4^2}} = 4 \implies \frac{|7h|}{5} = 4 \implies |7h| = 20.
A line is tangent to a circle if and only if the perpendicular distance from the center of the circle to the line equals the radius.
3
Solve for the possible values of hh.
h=±207h = \pm\frac{20}{7}.
Solving the absolute value equation yields two symmetric possibilities for the x-coordinate of the circle's center.
4
Determine the relationship between the center hh and the coordinates of the point of tangency (x,y)(x, y) to apply the quadrant constraint.
The radius connecting the center (h,h)(h, h) to the point of tangency (x,y)(x, y) is perpendicular to the tangent line. Since the tangent line has a slope of 34-\frac{3}{4}, the perpendicular radius line has a slope of 43\frac{4}{3}. Its equation is: yh=43(xh)    y=43x13hy - h = \frac{4}{3}(x - h) \implies y = \frac{4}{3}x - \frac{1}{3}h.
The intersection of the perpendicular radius line and the tangent line will locate the exact point of tangency.
5
Solve the system of equations for the point of tangency (x,y)(x, y) in terms of hh.
Equating the tangent line and the perpendicular line: 34x=43x13h    912x=1612x412h    2512x=412h    x=425h-\frac{3}{4}x = \frac{4}{3}x - \frac{1}{3}h \implies -\frac{9}{12}x = \frac{16}{12}x - \frac{4}{12}h \implies -\frac{25}{12}x = -\frac{4}{12}h \implies x = \frac{4}{25}h. Substituting back: y=34(425h)=325hy = -\frac{3}{4}\left(\frac{4}{25}h\right) = -\frac{3}{25}h.
This yields the coordinates of the tangency point as a function of the parameter hh.
6
Apply the quadrant constraint (x>0x > 0 and y<0y < 0) to choose the correct sign of hh.
We require x=425h>0x = \frac{4}{25}h > 0 and y=325h<0y = -\frac{3}{25}h < 0. Both inequalities are satisfied if and only if h>0h > 0. Therefore, h=207h = \frac{20}{7}.
This filters out the extraneous geometric solution that lies in Quadrant II.

Anahtar Kavram

Solving systems of nonlinear equations representing circles and lines by utilizing geometric relations, distance formulas, and quadrant constraints.
Tahmini Süre:3m 0s
Soru 1443Soru

If (2x3)(x+4)=0(2x - 3)(x + 4) = 0 and x>0x > 0, what is the value of xx?

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Cevap: 32\frac{3}{2}

Cevap

The value of xx is 32\frac{3}{2}.
To find the solutions to the equation (2x3)(x+4)=0(2x - 3)(x + 4) = 0, we set each factor equal to zero. Setting 2x3=02x - 3 = 0 gives x=32x = \frac{3}{2}, and setting x+4=0x + 4 = 0 gives x=4x = -4. The problem states that x>0x > 0, meaning the value of xx must be positive. Therefore, the only valid solution is 32\frac{3}{2}.

Adım Adım Çözüm

1
Set each factor of the quadratic equation equal to zero using the zero product property.
2x3=02x - 3 = 0 or x+4=0x + 4 = 0
If the product of two factors is zero, then at least one of the individual factors must equal zero.
2
Solve each linear equation to find the possible values of xx.
x=32x = \frac{3}{2} or x=4x = -4
Isolating xx in each equation gives the roots of the quadratic equation.
3
Apply the given constraint x>0x > 0 to identify the correct solution.
x=32x = \frac{3}{2} is the only valid solution because 32>0\frac{3}{2} > 0 and 40-4 \ngtr 0.
The problem restricts the solution to values of xx that are strictly greater than zero, so the negative root must be discarded.

Anahtar Kavram

Solving factored quadratic equations with inequality constraints
Soru 1444Soru

In sociology, 'third places' refer to social surroundings separate from the two primary environments of home and work. These spaces, such as coffee shops, libraries, and parks, are essential for civil society and civic engagement ______ they foster a sense of place and facilitate regular, voluntary gatherings. Without these informal meeting grounds, communities often experience a decline in social cohesion and mutual trust.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Cevap: ; they

Cevap

The choice that uses a semicolon to link the two independent clauses ('; they') is correct.
The correct choice uses a semicolon to separate two independent clauses ('These spaces... are essential for civil society and civic engagement' and 'they foster a sense of place...'). A semicolon is a standard grammatical way to link two closely related independent clauses without a coordinating conjunction.

Adım Adım Çözüm

1
Analyze the structure of the two clauses surrounding the blank.
The first clause ('These spaces, such as coffee shops, libraries, and parks, are essential for civil society and civic engagement') and the second clause ('they foster a sense of place and facilitate regular, voluntary gatherings') are both independent clauses because they can each stand alone as complete sentences.
Identifying clause types determines how they must be punctuated and joined.
2
Determine the appropriate punctuation or conjunction to connect two independent clauses.
Two independent clauses must be separated by a period, a semicolon, a colon (if the second explains the first), or a comma followed by a coordinating conjunction.
Linking independent clauses without proper punctuation results in run-on sentences or comma splices.
3
Evaluate the logical relationship between the two clauses.
The second clause explains why third places are essential for civil society. This is a continuous/explanatory relationship, not a contrasting one.
This relationship rules out contrasting coordinators like 'but' and supports a direct link like a semicolon.

Anahtar Kavram

Clause Boundaries and Linking
Soru 1445Soru

A community food bank is preparing two types of relief packages: standard boxes and family boxes. Let xx represent the number of standard boxes and yy represent the number of family boxes. The food bank needs to prepare at least 120 boxes in total. Each standard box contains 3 cans of soup and 2 packages of grain. Each family box contains 6 cans of soup and 5 packages of grain. The food bank has a maximum of 600 cans of soup and a maximum of 450 packages of grain available. Which of the following systems of inequalities represents this situation?

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Cevap: x+y1203x+6y6002x+5y450\begin{aligned} x + y &\ge 120 \\ 3x + 6y &\le 600 \\ 2x + 5y &\le 450 \end{aligned}

Cevap

The system of inequalities with x+y120x + y \ge 120, 3x+6y6003x + 6y \le 600, and 2x+5y4502x + 5y \le 450.
The correct system of inequalities translates the constraint of preparing at least 120 boxes as x+y120x + y \ge 120. The maximum limit of 600 cans of soup translates as 3x+6y6003x + 6y \le 600, since each standard box contains 3 cans and each family box contains 6. The maximum limit of 450 packages of grain translates as 2x+5y4502x + 5y \le 450, since each standard box contains 2 packages and each family box contains 5.

Adım Adım Çözüm

1
Translate the total package constraint.
x+y120x + y \ge 120
The phrase 'at least 120 boxes in total' indicates that the sum of xx and yy must be greater than or equal to 120.
2
Translate the soup constraint.
3x+6y6003x + 6y \le 600
Since each standard box (xx) has 3 cans of soup and each family box (yy) has 6 cans of soup, the total soup used is 3x+6y3x + 6y. The food bank has 'a maximum of 600 cans,' so this total must be less than or equal to 600.
3
Translate the grain constraint.
2x+5y4502x + 5y \le 450
Since each standard box (xx) has 2 packages of grain and each family box (yy) has 5 packages of grain, the total grain used is 2x+5y2x + 5y. The food bank has 'a maximum of 450 packages,' so this total must be less than or equal to 450.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Tahmini Süre:1m 30s
Soru 1446Soru

The graphs of the equations y2x=3y - 2x = 3 and y=x2y = x^2 intersect at two points in the xyxy-plane. If (x,y)(x, y) represents an intersection point with a positive xx-coordinate, what is the value of yy?

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Cevap: 9

Cevap

9
Substituting y=x2y = x^2 into the first equation yields x22x=3x^2 - 2x = 3. Setting the quadratic equation to zero gives x22x3=0x^2 - 2x - 3 = 0, which factors as (x3)(x+1)=0(x - 3)(x + 1) = 0. This gives the solutions x=3x = 3 and x=1x = -1. Because the question specifies a positive xx-coordinate, xx must be 3. Substituting x=3x = 3 back into y=x2y = x^2 yields y=9y = 9. Thus, the correct answer is 9.

Adım Adım Çözüm

1
Substitute y=x2y = x^2 into the equation y2x=3y - 2x = 3.
x22x=3x^2 - 2x = 3
This eliminates the variable yy and creates a single quadratic equation in terms of xx to find the xx-coordinates of the intersection points.
2
Rewrite the quadratic equation in standard form.
x22x3=0x^2 - 2x - 3 = 0
Subtracting 3 from both sides sets the quadratic equation to 0, which is necessary for factoring.
3
Factor the quadratic equation to find its solutions.
(x3)(x+1)=0(x - 3)(x + 1) = 0, which gives x=3x = 3 or x=1x = -1.
Factoring allows us to find the roots, which represent the xx-coordinates of the intersection points.
4
Apply the constraint that the xx-coordinate must be positive.
x=3x = 3
The question specifies that x>0x > 0, so we discard x=1x = -1.
5
Substitute x=3x = 3 back into y=x2y = x^2 to find the corresponding value of yy.
y=32=9y = 3^2 = 9
This determines the yy-coordinate of the intersection point with the positive xx-coordinate.

Anahtar Kavram

Solving a system of a linear equation and a quadratic equation by substitution.
Soru 1447Soru

A population of bacteria doubles every 3 hours. If the initial population of the bacteria is 500, what is the population of the bacteria after 9 hours?

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Cevap: 4000

Cevap

The population of the bacteria after 9 hours is 4,000.
The final population is calculated using the formula P(t)=P0×2t/dP(t) = P_0 \times 2^{t/d}, where P0P_0 is the initial population of 500, dd is the doubling period of 3 hours, and tt is the total time of 9 hours. Evaluating this gives P(9)=500×29/3=500×23=500×8=4000P(9) = 500 \times 2^{9/3} = 500 \times 2^3 = 500 \times 8 = 4000.

Adım Adım Çözüm

1
Identify the initial population (P0P_0), doubling time (dd), and total time (tt).
P0=500P_0 = 500, d=3d = 3, and t=9t = 9.
These parameters are required to set up the exponential growth model.
2
Calculate the number of doubling periods.
The number of doubling periods is 93=3\frac{9}{3} = 3.
The population doubles once for every 3-hour interval.
3
Calculate the final population using the exponential growth formula.
500×23=500×8=4000500 \times 2^3 = 500 \times 8 = 4000.
Applying the 3 doubling cycles to the initial population of 500 yields the final population.

Anahtar Kavram

Exponential Growth Model
Tahmini Süre:1m 0s
Soru 1448Soru

In the system of equations below, kk is a positive constant.

xy=kx - y = k
x23xy+y2=5x^2 - 3xy + y^2 = 5

If the system has exactly one real solution (x,y)(x, y), what is the value of kk?

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Cevap: 2

Cevap

The value of kk is 2.
Substituting y=xky = x - k into the second equation yields x2+kx+k25=0-x^2 + kx + k^2 - 5 = 0, which can be rewritten in standard form as x2kx+(5k2)=0x^2 - kx + (5 - k^2) = 0. For this quadratic equation to have exactly one real solution, its discriminant must equal 0: b24ac=(k)24(1)(5k2)=5k220=0b^2 - 4ac = (-k)^2 - 4(1)(5 - k^2) = 5k^2 - 20 = 0. Solving 5k220=05k^2 - 20 = 0 gives k2=4k^2 = 4, and since kk must be positive, k=2k = 2.

Adım Adım Çözüm

1
Rearrange the first equation to express yy in terms of xx.
y=xky = x - k
This allows for substitution into the second equation to eliminate yy.
2
Substitute y=xky = x - k into the second equation and expand.
x23x(xk)+(xk)2=5    x2+kx+k25=0x^2 - 3x(x - k) + (x - k)^2 = 5 \implies -x^2 + kx + k^2 - 5 = 0
To create a single quadratic equation in terms of xx.
3
Multiply by 1-1 to write the quadratic equation in standard form ax2+bx+c=0ax^2 + bx + c = 0.
x2kx+(5k2)=0x^2 - kx + (5 - k^2) = 0
Standard form makes it easier to identify the coefficients a=1a = 1, b=kb = -k, and c=5k2c = 5 - k^2.
4
Set the discriminant b24acb^2 - 4ac equal to 0.
(k)24(1)(5k2)=0(-k)^2 - 4(1)(5 - k^2) = 0
A quadratic equation has exactly one real solution if and only if its discriminant is zero.
5
Simplify the discriminant equation and solve for kk.
5k220=0    k2=4    k=25k^2 - 20 = 0 \implies k^2 = 4 \implies k = 2 (since kk must be positive)
To find the positive constant kk that satisfies the condition.

Anahtar Kavram

Determining the number of solutions to a nonlinear system by substituting and setting the discriminant of the resulting quadratic equation to zero.

Alternatif Yöntem

Alternatively, one can rewrite the second equation by grouping: x23xy+y2=(xy)2xy=5x^2 - 3xy + y^2 = (x - y)^2 - xy = 5. Since xy=kx - y = k, we have k2xy=5k^2 - xy = 5, so xy=k25xy = k^2 - 5. We now have a system of xy=kx - y = k and xy=k25xy = k^2 - 5. Substituting y=xky = x - k gives x(xk)=k25x(x - k) = k^2 - 5, leading to x2kx+(5k2)=0x^2 - kx + (5 - k^2) = 0, which can be solved using the discriminant as shown in the primary method.
Tahmini Süre:2m 30s
Soru 1449Soru

For all x>0x > 0 and y>0y > 0, the expression (x2y3)a(xy2)2\frac{(x^2y^3)^a}{(xy^2)^2} is equivalent to x6y8x^6y^8, where aa is a constant. What is the value of aa?

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Cevap: 4

Cevap

4
Applying the rules of exponents, the expression (x2y3)a(xy2)2\frac{(x^2y^3)^a}{(xy^2)^2} simplifies to x2ay3ax2y4=x2a2y3a4\frac{x^{2a}y^{3a}}{x^2y^4} = x^{2a-2}y^{3a-4}. Setting this equal to the equivalent expression x6y8x^6y^8 gives the system of equations 2a2=62a - 2 = 6 and 3a4=83a - 4 = 8. Solving either equation yields a=4a = 4.

Adım Adım Çözüm

1
Apply the power rule of exponents to the numerator and denominator.
Numerator: x2ay3ax^{2a}y^{3a}, Denominator: x2y4x^2y^4
To expand the parentheses by multiplying the outer exponent with the inner exponents.
2
Apply the quotient rule of exponents to divide the numerator by the denominator.
x2a2y3a4x^{2a-2}y^{3a-4}
To simplify the rational expression by subtracting the exponents in the denominator from the exponents in the numerator.
3
Equate the simplified exponent of xx to the exponent of xx in the given equivalent expression.
2a2=62a - 2 = 6
Equivalent expressions must have identical exponents for corresponding variable bases.
4
Solve the linear equation for aa.
a=4a = 4
To find the constant value that satisfies the equation.
5
Verify the value of aa using the exponents of yy.
3(4)4=83(4) - 4 = 8, which is true.
To ensure consistency across both variable exponents.

Anahtar Kavram

Equivalent algebraic expressions involving exponent rules
Soru 1450Soru

A parabola and a line intersect at exactly one point in the xyxy-plane. The parabola is defined by the equation y=x2+6x2y = -x^2 + 6x - 2 and the line is defined by the equation y=2x+ky = 2x + k, where kk is a constant. What is the value of kk?

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Cevap: 2

Cevap

The correct answer is 2.
To find the value of kk where the parabola and the line intersect at exactly one point, we equate the two equations: x2+6x2=2x+k-x^2 + 6x - 2 = 2x + k. Rearranging this into standard quadratic form yields x24x+(k+2)=0x^2 - 4x + (k + 2) = 0. For a quadratic equation to have exactly one real solution, its discriminant, b24acb^2 - 4ac, must be equal to zero. Substituting a=1a = 1, b=4b = -4, and c=k+2c = k + 2 into the discriminant formula gives (4)24(1)(k+2)=0(-4)^2 - 4(1)(k + 2) = 0, which simplifies to 164k8=016 - 4k - 8 = 0, or 84k=08 - 4k = 0. Solving for kk gives k=2k = 2.

Adım Adım Çözüm

1
Equate the equations of the parabola and the line to set up an equation for the x-coordinates of their intersection points.
x2+6x2=2x+k-x^2 + 6x - 2 = 2x + k
At the points of intersection, the y-values of both equations are equal.
2
Rearrange the equation into the standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.
x24x+(k+2)=0x^2 - 4x + (k + 2) = 0
This allows us to identify the coefficients a=1a = 1, b=4b = -4, and c=k+2c = k + 2 to apply the quadratic discriminant.
3
Set the discriminant b24acb^2 - 4ac equal to zero.
(4)24(1)(k+2)=0(-4)^2 - 4(1)(k + 2) = 0
A quadratic system has exactly one real solution (tangency) if and only if the discriminant of the resulting quadratic equation is zero.
4
Solve the linear equation for kk.
k=2k = 2
Simplifying the expression yields 164k8=016 - 4k - 8 = 0, which simplifies to 84k=08 - 4k = 0, giving k=2k = 2.

Anahtar Kavram

Nonlinear Systems of Equations
Soru 1451Soru

In the xyxy-plane, the system of equations below has infinitely many solutions:

12(axby)=73x2y=c\begin{aligned} \frac{1}{2}(ax - by) &= 7 \\ 3x - 2y &= c \end{aligned}

where aa, bb, and cc are constants. If the line representing the first equation passes through the point (4,1)(4, 1), what is the value of cc?

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Cevap: 10

Cevap

10
The correct answer is 10. For a system of linear equations in two variables to have infinitely many solutions, the two equations must describe the exact same line, meaning their coefficients and constant terms are proportional. Multiplying the first equation by 22 yields axby=14ax - by = 14. Comparing this with 3x2y=c3x - 2y = c shows that a3=b2=14c\frac{a}{3} = \frac{b}{2} = \frac{14}{c}, which simplifies to b=23ab = \frac{2}{3}a and c=42ac = \frac{42}{a}. Since the first line passes through (4,1)(4, 1), we substitute x=4x = 4 and y=1y = 1 to get 4ab=144a - b = 14. Substituting b=23ab = \frac{2}{3}a gives 4a23a=144a - \frac{2}{3}a = 14, which simplifies to 103a=14\frac{10}{3}a = 14, or a=4.2a = 4.2. Finally, solving for cc gives c=424.2=10c = \frac{42}{4.2} = 10.

Adım Adım Çözüm

1
Clear the fraction in the first equation by multiplying both sides by 22.
axby=14ax - by = 14
This puts the first equation into standard form, making it easier to compare with the second equation.
2
Set up the proportionality of the coefficients for the two equations to represent the same line.
a3=b2=14c    b=23a\frac{a}{3} = \frac{-b}{-2} = \frac{14}{c} \implies b = \frac{2}{3}a and c=42ac = \frac{42}{a}
For a system of two linear equations to have infinitely many solutions, the equations must be equivalent, meaning their corresponding coefficients and constants must be proportional.
3
Substitute the given point (4,1)(4, 1) into the first equation.
a(4)b(1)=14    4ab=14a(4) - b(1) = 14 \implies 4a - b = 14
Since the line passes through the point (4,1)(4, 1), the coordinates must satisfy the equation of the line.
4
Substitute b=23ab = \frac{2}{3}a into 4ab=144a - b = 14 and solve for aa.
4a23a=14    103a=14    a=4.24a - \frac{2}{3}a = 14 \implies \frac{10}{3}a = 14 \implies a = 4.2
This reduces the equation to a single variable, allowing us to find the value of the parameter aa.
5
Substitute a=4.2a = 4.2 into the expression for cc to find its value.
c=424.2=10c = \frac{42}{4.2} = 10
This uses the coefficient proportionality relation from step 2 to determine the constant term of the second equation.

Anahtar Kavram

Systems of linear equations with infinitely many solutions require the equations to represent the same line, meaning their coefficients and constant terms are proportional.
Soru 1452Soru

An industrial oven is used in a bakery. The temperature of the oven chamber, CC, in degrees Fahrenheit (F^\circ\text{F}), tt minutes after the heating element is turned on is modeled by the linear equation:

C=18.5t+72C = 18.5t + 72

After a system upgrade, the starting temperature of the oven is 8F8^\circ\text{F} warmer, and the rate at which the oven heats up is 20%20\% faster. During a test of the upgraded oven, the heating element is turned on for 1515 minutes, after which the oven is turned off and cools down at a constant rate of 12F12^\circ\text{F} per minute. If the cooling process is also linear, which of the following functions models the temperature of the upgraded oven, UU, in degrees Fahrenheit, mm minutes after it is turned off?

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Cevap: U(m)=12m+413U(m) = -12m + 413

Cevap

The function U(m)=12m+413U(m) = -12m + 413 models the temperature of the upgraded oven, UU, in degrees Fahrenheit, mm minutes after it is turned off.
To find the temperature model during the cooling phase, we must first determine the state of the oven when the cooling begins. The upgraded oven has a starting temperature of 72+8=80F72 + 8 = 80^\circ\text{F} and a heating rate of 18.5×1.20=22.2F18.5 \times 1.20 = 22.2^\circ\text{F} per minute. After 1515 minutes of heating, the temperature reaches 22.2×15+80=413F22.2 \times 15 + 80 = 413^\circ\text{F}. When the oven is turned off at m=0m = 0 minutes, its temperature is 413F413^\circ\text{F}, which serves as the y-intercept of the cooling function. Since the temperature decreases at a constant rate of 12F12^\circ\text{F} per minute, the rate of change (slope) is 12-12. Therefore, the linear model is the function showing a rate of change of 12-12 and a starting value of 413413.

Adım Adım Çözüm

1
Determine the upgraded starting temperature and heating rate of the oven.
The upgraded starting temperature is 80F80^\circ\text{F} and the upgraded heating rate is 22.2F22.2^\circ\text{F} per minute.
The original starting temperature of 72F72^\circ\text{F} is increased by 8F8^\circ\text{F} to get 72+8=80F72 + 8 = 80^\circ\text{F}. The original heating rate (slope) of 18.5F18.5^\circ\text{F} per minute is increased by 20%20\%, which is calculated as 18.5×1.20=22.2F18.5 \times 1.20 = 22.2^\circ\text{F} per minute.
2
Calculate the temperature of the upgraded oven at the moment it is turned off.
The temperature is 413F413^\circ\text{F} at t=15t = 15 minutes.
The heating phase is modeled by the linear relationship H(t)=22.2t+80H(t) = 22.2t + 80. Substituting t=15t = 15 yields H(15)=22.2(15)+80=333+80=413FH(15) = 22.2(15) + 80 = 333 + 80 = 413^\circ\text{F}.
3
Construct the linear function for the cooling phase.
U(m)=12m+413U(m) = -12m + 413
When the oven is turned off (m=0m = 0), its temperature is 413F413^\circ\text{F}. Since it cools down at a constant rate of 12F12^\circ\text{F} per minute, the slope of the cooling function is 12-12. Thus, the linear model is U(m)=12m+413U(m) = -12m + 413.

Anahtar Kavram

Interpreting and modifying parameters of linear models in multi-stage contextual scenarios.

Alternatif Yöntem

Instead of writing the heating function explicitly, you can calculate the total temperature increase directly: the temperature rises by 18.5×1.20=22.2F18.5 \times 1.20 = 22.2^\circ\text{F} per minute for 1515 minutes, which is a total increase of 22.2×15=333F22.2 \times 15 = 333^\circ\text{F}. Adding this increase to the upgraded starting temperature of 72+8=80F72 + 8 = 80^\circ\text{F} gives the peak temperature of 80+333=413F80 + 333 = 413^\circ\text{F}. Since the cooling phase is linear with a slope of 12-12 and a y-intercept of 413413, the function is immediately determined.
Tahmini Süre:3m 0s
Soru 1453Soru

To rent an electric scooter, a rider pays a flat unlocking fee plus a fee for each minute of the ride. The total cost CC, in dollars, for a ride of mm minutes is given by the equation C=0.15m+1.20C = 0.15m + 1.20. Which of the following is the best interpretation of the number 1.201.20 in this context?

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Cevap: The flat unlocking fee, in dollars, to rent the scooter

Cevap

The flat unlocking fee, in dollars, to rent the scooter
In the linear model C=0.15m+1.20C = 0.15m + 1.20, the constant term 1.201.20 represents the value of CC when m=0m = 0. Since mm represents the number of minutes, m=0m = 0 corresponds to the beginning of the rental. Therefore, 1.201.20 represents the initial flat unlocking fee, in dollars, to rent the scooter.

Adım Adım Çözüm

1
Identify the component of the linear equation C=0.15m+1.20C = 0.15m + 1.20 that corresponds to the number 1.201.20.
The number 1.201.20 is the constant term (y-intercept) of the equation.
A linear equation in slope-intercept form is y=mx+by = mx + b, where bb is the y-intercept (the value of yy when x=0x = 0).
2
Determine the physical meaning of m=0m = 0 in the given context.
m=0m = 0 represents a ride that lasts 00 minutes, meaning no time has elapsed yet.
Evaluating the relationship at the initial state helps identify the physical meaning of the y-intercept.
3
Substitute m=0m = 0 into the equation to find the corresponding cost.
C=0.15(0)+1.20=1.20C = 0.15(0) + 1.20 = 1.20 dollars.
This shows that the initial cost, or flat unlocking fee before starting the ride, is 1.201.20 dollars.

Anahtar Kavram

Interpreting the y-intercept of a linear relationship in context
Soru 1454Soru

During a chemical reaction, the temperature TT, in degrees Celsius, of a solution ss seconds after the reaction begins is modeled by the equation T=0.04(s150)+92T = -0.04(s - 150) + 92, where 150s900150 \le s \le 900. According to the model, how many minutes does it take for the temperature of the solution to decrease by 1212 degrees Celsius?

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Cevap: 5

Cevap

5
To find the number of minutes it takes for the temperature to decrease by 12C12^\circ\text{C}, we first determine the rate of temperature change from the linear model. The equation is given in the form T=m(ss0)+T0T = m(s - s_0) + T_0, where the slope m=0.04m = -0.04 represents the rate of change of temperature in degrees Celsius per second. Thus, the temperature decreases at a rate of 0.04C0.04^\circ\text{C} per second. To achieve a total decrease of 12C12^\circ\text{C}, the time in seconds required is 120.04=300\frac{12}{0.04} = 300 seconds. Converting 300300 seconds to minutes gives 30060=5\frac{300}{60} = 5 minutes.

Adım Adım Çözüm

1
Identify the rate of change from the linear equation.
The rate of temperature decrease is 0.04C0.04^\circ\text{C} per second.
The slope of the linear equation T=0.04(s150)+92T = -0.04(s - 150) + 92 is 0.04-0.04, which represents a change of 0.04C-0.04^\circ\text{C} for every 11 second increase in time.
2
Calculate the time in seconds for a decrease of 12C12^\circ\text{C}.
300300 seconds
Divide the target temperature change of 12C-12^\circ\text{C} by the rate of change of 0.04C-0.04^\circ\text{C} per second: 120.04=300\frac{-12}{-0.04} = 300 seconds.
3
Convert the time from seconds to minutes.
55 minutes
Since there are 6060 seconds in 11 minute, divide 300300 seconds by 6060: 30060=5\frac{300}{60} = 5 minutes.

Anahtar Kavram

Interpreting Linear Relationships in Context
Soru 1455Soru

A nutritionist is designing a meal plan containing xx grams of protein and yy grams of carbohydrates. The meal plan must satisfy the following system of inequalities:

y1.5x+153x+2y120\begin{aligned} y &\ge 1.5x + 15 \\ 3x + 2y &\le 120 \end{aligned}

What is the maximum possible number of grams of protein, xx, that can be included in the meal plan?

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Cevap: 15

Cevap

The maximum possible number of grams of protein that can be included is 15.
To find the maximum possible value of xx, we determine the region defined by the system of inequalities. The system restricts the values to the region above the line y=1.5x+15y = 1.5x + 15 and below the line 3x+2y=1203x + 2y = 120. Since the first inequality limits yy from below and the second limits yy from above, the feasible region narrows as xx increases, terminating at the intersection of the two boundary lines. Substituting y=1.5x+15y = 1.5x + 15 into 3x+2y=1203x + 2y = 120 gives 3x+2(1.5x+15)=1203x + 2(1.5x + 15) = 120. Simplifying this yields 3x+3x+30=1203x + 3x + 30 = 120, which simplifies further to 6x=906x = 90, giving x=15x = 15. Thus, the maximum value of xx is 15.

Adım Adım Çözüm

1
Identify the boundary lines of the system of inequalities.
The boundary lines are y=1.5x+15y = 1.5x + 15 and 3x+2y=1203x + 2y = 120.
The maximum value of xx under these linear constraints occurs at the intersection of the boundary lines of the feasible region.
2
Substitute the expression for yy from the first boundary equation into the second equation.
3x+2(1.5x+15)=1203x + 2(1.5x + 15) = 120
This allows us to solve for xx by eliminating yy.
3
Simplify the equation and solve for xx.
3x+3x+30=120    6x+30=120    6x=90    x=153x + 3x + 30 = 120 \implies 6x + 30 = 120 \implies 6x = 90 \implies x = 15.
Solving the linear equation gives the xx-coordinate of the intersection point.
4
Verify that this point lies in the feasible region and represents the maximum possible value of xx.
At x=15x=15, y=37.5y=37.5. Since y1.5x+15y \ge 1.5x + 15 restricts the region above the line and 3x+2y1203x + 2y \le 120 restricts it below the line, the region lies to the left of the intersection point (15,37.5)(15, 37.5). Thus, the maximum value of xx is 15.
Confirming the geometry of the feasible region ensures the intersection point is indeed the maximum value.

Anahtar Kavram

Solving systems of linear inequalities to find the boundaries and extreme values of a feasible region.
Soru 1456Soru
y=x25x+8y = x^2 - 5x + 8
y=2x+2y = 2x + 2

The system of equations above has two real solutions, (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2). If y1>y2y_1 > y_2, what is the value of x1x2x_1 - x_2?

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Cevap: 5

Cevap

The value of the difference between the two x-coordinates is 5.
To solve the system, substitute y=2x+2y = 2x + 2 into y=x25x+8y = x^2 - 5x + 8 to obtain 2x+2=x25x+82x + 2 = x^2 - 5x + 8. Subtracting 2x+22x + 2 from both sides gives the quadratic equation x27x+6=0x^2 - 7x + 6 = 0. Factoring this equation yields (x6)(x1)=0(x - 6)(x - 1) = 0, which gives the x-coordinates x=6x = 6 and x=1x = 1. Substituting these back into y=2x+2y = 2x + 2 gives the corresponding y-coordinates: y=14y = 14 when x=6x = 6, and y=4y = 4 when x=1x = 1. Thus, the two solutions are (6,14)(6, 14) and (1,4)(1, 4). Because y1>y2y_1 > y_2, we must have (x1,y1)=(6,14)(x_1, y_1) = (6, 14) and (x2,y2)=(1,4)(x_2, y_2) = (1, 4). The value of x1x2x_1 - x_2 is therefore 61=56 - 1 = 5.

Adım Adım Çözüm

1
Substitute the expression for yy from the second equation into the first equation.
2x+2=x25x+82x + 2 = x^2 - 5x + 8
This substitution reduces the system of two equations to a single quadratic equation in terms of xx.
2
Rearrange the quadratic equation into standard form by subtracting 2x2x and 22 from both sides.
x27x+6=0x^2 - 7x + 6 = 0
Putting the equation in standard form is necessary to factor it and find its roots.
3
Factor the quadratic equation to find the two possible values of xx.
(x6)(x1)=0(x - 6)(x - 1) = 0, which gives x=6x = 6 or x=1x = 1.
Factoring allows us to find the x-coordinates of the points where the two graphs intersect.
4
Substitute the x-values back into the linear equation y=2x+2y = 2x + 2 to find their corresponding y-values.
For x=6x = 6, y=2(6)+2=14y = 2(6) + 2 = 14. For x=1x = 1, y=2(1)+2=4y = 2(1) + 2 = 4. The two solutions are (6,14)(6, 14) and (1,4)(1, 4).
Finding the y-values helps identify which coordinate pair corresponds to (x1,y1)(x_1, y_1) and which to (x2,y2)(x_2, y_2) using the given condition.
5
Apply the condition y1>y2y_1 > y_2 to assign the variables and calculate x1x2x_1 - x_2.
Since 14>414 > 4, the solution with the larger y-value is (x1,y1)=(6,14)(x_1, y_1) = (6, 14) and the other is (x2,y2)=(1,4)(x_2, y_2) = (1, 4). Thus, x1x2=61=5x_1 - x_2 = 6 - 1 = 5.
This calculation yields the final requested value.

Anahtar Kavram

Solving a system of a linear equation and a quadratic equation by substitution.
Soru 1457Soru

Unlike other cephalopods that rely purely on camouflage, the mimic octopus (*Thaumoctopus mimicus*) employs a dynamic predator-deterrence strategy ______ by contorting its body and adjusting its swimming style, it can impersonate venomous species such as lionfish and sea snakes.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Cevap: strategy: by

Cevap

The correct punctuation is a colon followed by the preposition 'by' to introduce an explanation of the predator-deterrence strategy.
The correct option is the one that uses a colon to link the independent clauses. The clause preceding the blank is grammatically complete, and the clause following the blank explains the specific nature of the octopus's strategy. A colon is standard punctuation for introducing an explanation or illustration in this context.

Adım Adım Çözüm

1
Identify the grammatical structure of the clauses before and after the blank.
The clause before the blank is independent, and the clause after the blank is also independent.
Determining clause independence helps identify which punctuation marks can be used to join them.
2
Evaluate the logical relationship between the two independent clauses.
The second clause explains and elaborates on the predator-deterrence strategy mentioned in the first clause.
A colon is the appropriate punctuation mark to introduce an explanation or elaboration that follows an independent clause.

Anahtar Kavram

Using colons to link independent clauses when the second clause explains or illustrates the first.
Soru 1458Soru

If x(x9)=20x(x - 9) = -20, which of the following is a possible value of xx?

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Cevap: 5

Cevap

5
To solve the equation x(x9)=20x(x - 9) = -20, first distribute the xx to get x29x=20x^2 - 9x = -20. Next, rewrite the equation in standard form by adding 2020 to both sides, which gives x29x+20=0x^2 - 9x + 20 = 0. Factoring the quadratic expression yields (x4)(x5)=0(x - 4)(x - 5) = 0. Applying the zero product property gives two possible solutions: x=4x = 4 and x=5x = 5. Therefore, the value 55 is a possible value of xx.

Adım Adım Çözüm

1
Distribute xx on the left side of the equation.
x29x=20x^2 - 9x = -20
Expanding the product allows the quadratic equation to be rewritten in standard form.
2
Add 2020 to both sides to set the equation to standard form ax2+bx+c=0ax^2 + bx + c = 0.
x29x+20=0x^2 - 9x + 20 = 0
Setting the quadratic equation to equal zero is necessary to solve by factoring or using the quadratic formula.
3
Factor the quadratic trinomial by finding two integers that multiply to 2020 and add to 9-9.
(x4)(x5)=0(x - 4)(x - 5) = 0
The numbers 4-4 and 5-5 satisfy these conditions, allowing the expression to be factored.
4
Set each factor equal to zero to find the possible values of xx.
x=4x = 4 or x=5x = 5
According to the zero product property, if the product of two factors is zero, then at least one of the factors must be zero.

Anahtar Kavram

Solving quadratic equations by factoring
Soru 1459Soru

Consider the system of inequalities below:

3x+y>5x2y>4\begin{aligned} 3x + y &> 5 \\ x - 2y &> 4 \end{aligned}

Which of the following coordinate pairs (x,y)(x, y) is a solution to the system?

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Cevap: (4,2)(4, -2)

Cevap

(4,2)(4, -2)
The coordinate pair (4,2)(4, -2) is the correct answer because substituting these values into both inequalities of the system produces true statements: 3(4)+(2)=10>53(4) + (-2) = 10 > 5 and 42(2)=8>44 - 2(-2) = 8 > 4.

Adım Adım Çözüm

1
Substitute the coordinates of the candidate point into the first inequality, 3x+y>53x + y > 5.
For (4,2)(4, -2), we get 3(4)+(2)=122=103(4) + (-2) = 12 - 2 = 10. Since 10>510 > 5, the first inequality is satisfied.
A coordinate pair must satisfy both inequalities in the system to be a solution.
2
Substitute the coordinates of the candidate point into the second inequality, x2y>4x - 2y > 4.
For (4,2)(4, -2), we get 42(2)=4+4=84 - 2(-2) = 4 + 4 = 8. Since 8>48 > 4, the second inequality is also satisfied.
Since both inequalities are true for (4,2)(4, -2), it is a valid solution to the system.

Anahtar Kavram

A coordinate pair (x,y)(x, y) is a solution to a system of linear inequalities if and only if it makes all inequalities in the system true when substituted.
Tahmini Süre:1m 30s
Soru 1460Soru

A chemist needs to mix a 10%10\% acid solution with a 30%30\% acid solution to create a 100100-milliliter mixture. If the final mixture must be 18%18\% acid, how many milliliters of the 10%10\% acid solution should the chemist use?

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Cevap: 60

Cevap

60 milliliters
The correct answer is 60 milliliters. Defining xx as the volume of the 10%10\% solution and yy as the volume of the 30%30\% solution gives the system of equations x+y=100x + y = 100 and 0.10x+0.30y=180.10x + 0.30y = 18. Substituting y=100xy = 100 - x into the second equation yields 0.10x+300.30x=180.10x + 30 - 0.30x = 18. Simplifying this equation gives 0.20x=12-0.20x = -12, which simplifies to x=60x = 60.

Adım Adım Çözüm

1
Define variables for the volume of each solution and set up the system of equations representing the total volume and the total amount of pure acid.
Let xx be the number of milliliters of the 10%10\% acid solution, and let yy be the number of milliliters of the 30%30\% acid solution. The system is:
x+y=1000.10x+0.30y=18\begin{aligned} x + y &= 100 \\ 0.10x + 0.30y &= 18 \end{aligned}
To represent the physical relationships between the two solutions mathematically.
2
Solve the first equation for yy in terms of xx and substitute this expression into the second equation.
y=100xy = 100 - x
0.10x+0.30(100x)=180.10x + 0.30(100 - x) = 18
To reduce the system to a single linear equation in terms of xx.
3
Distribute the coefficients, combine like terms, and solve for xx.
0.10x+300.30x=180.10x + 30 - 0.30x = 18
0.20x+30=18-0.20x + 30 = 18
0.20x=12-0.20x = -12
x=60x = 60
To isolate xx and determine the volume of the 10%10\% acid solution.

Anahtar Kavram

Solving systems of linear equations in two variables using substitution or elimination.
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