Tüm alıştırma soruları

2789 soru

Soru 1581Soru

Data collected by the Cassini spacecraft revealed that Enceladus, a moon of Saturn, harbors a subsurface liquid water ocean. Hydrothermal activity on the ocean floor spews silica nanoparticles and organic compounds into the ________ materials then erupt through cracks in the icy crust, forming a towering plume of vapor.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Cevap: water; these

Cevap

water; these
The sentence contains two independent clauses: the first ends with the word 'water,' and the second begins with the word 'these.' To join two independent clauses without a coordinating conjunction (like 'and' or 'but'), a semicolon is required. The option 'water; these' correctly uses a semicolon to separate the two independent clauses.

Adım Adım Çözüm

1
Identify the clause structure of the sentence containing the blank.
The sentence consists of two independent clauses: 'Hydrothermal activity on the ocean floor spews silica nanoparticles and organic compounds into the water' and 'these materials then erupt through cracks in the icy crust, forming a towering plume of vapor.'
Understanding the boundary between independent clauses is necessary to determine the correct punctuation and conjunctions needed to link them.
2
Evaluate the choices to find the correct method of linking two independent clauses.
Two independent clauses can be separated by a period, a semicolon, or a comma paired with a coordinating conjunction (FANBOYS). The option 'water; these' correctly uses a semicolon.
A semicolon is a grammatically valid way to link two closely related independent clauses without any conjunctions.
3
Verify why the other options are grammatically incorrect.
The option 'water, these' is a comma splice. The option 'water these' is a run-on. The option 'water; since these' uses a semicolon followed by a subordinating conjunction, which incorrectly tries to link an independent clause to a dependent clause.
Eliminating grammatically incorrect choices confirms the correct option.

Anahtar Kavram

Clause Boundaries and Linking
Tahmini Süre:1m 0s
Soru 1582Soru

Which of the following is a solution to the equation x22x8=0x^2 - 2x - 8 = 0?

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Cevap: 4

Cevap

The correct solution is 4.
To find the solutions to the equation x22x8=0x^2 - 2x - 8 = 0, we factor the quadratic expression on the left side of the equation. We need two numbers that multiply to 8-8 and add to 2-2. These numbers are 4-4 and 22. Thus, the equation can be rewritten in factored form as (x4)(x+2)=0(x - 4)(x + 2) = 0. Setting each factor to zero yields the solutions x=4x = 4 and x=2x = -2. Among the given options, 44 is the only correct solution.

Adım Adım Çözüm

1
Factor the quadratic expression x22x8x^2 - 2x - 8.
The expression factors into (x4)(x+2)(x - 4)(x + 2).
We look for two numbers that multiply to the constant term 8-8 and add to the linear coefficient 2-2. These numbers are 4-4 and 22.
2
Set each factor equal to zero to solve for xx.
x4=0x - 4 = 0 or x+2=0x + 2 = 0, which gives x=4x = 4 or x=2x = -2.
By the zero product property, if the product of two factors is zero, then at least one of the factors must be zero.
3
Identify the solution that appears in the options.
x=4x = 4 is a solution.
Checking the given options, 44 is listed while 2-2 is not.

Anahtar Kavram

Solving quadratic equations by factoring
Soru 1583Soru

Which punctuation mark should be placed in the blank to ensure the sentence conforms to the conventions of Standard English?

Aşağıdaki boşlukları doldurun

During the excavation of the ancient Roman port, archaeologists uncovered artifacts from various Mediterranean regions: transport amphorae from Carthage, modern-day Tunisia glass vessels from Alexandria, Egypt; and decorative mosaics from Antioch, Turkey.
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Cevap

A semicolon (;) must be used to separate items in a list when those items already contain internal commas.
A semicolon (;) is the correct punctuation mark because the sentence presents a complex list where the items already contain internal commas. To prevent confusion and maintain parallel structure with the semicolon used later in the sentence, a semicolon must be used to separate the items.

Adım Adım Çözüm

1
Identify the structure of the sentence and the elements being listed.
The sentence lists three types of archaeological artifacts: amphorae from Carthage, glass vessels from Alexandria, and mosaics from Antioch.
Determining the parts of the list helps establish the appropriate level of punctuation required.
2
Examine the internal punctuation of each list item.
Each individual item in the list contains a comma separating the city of origin from the modern-day country (e.g., 'Carthage, modern-day Tunisia').
Since the list items contain internal punctuation, standard commas cannot be used to separate the items themselves without creating confusion.
3
Apply the rule for complex lists with internal commas.
A semicolon must be inserted in the blank to separate the first item from the second item, matching the semicolon that separates the second item from the third.
Semicolons function as 'super-commas' to clearly divide complex items in a list.

Anahtar Kavram

Semicolons in Complex Lists
Soru 1584Soru

If 272x19y+2=31327^{2x - 1} \cdot 9^{y + 2} = 3^{13} and 8xy=2y98^{x - y} = 2^{y - 9}, what is the value of x+yx + y?

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Cevap: 4

Cevap

4
To solve the system, we convert all exponential terms to their prime bases. The first equation becomes 36x332y+4=3133^{6x - 3} \cdot 3^{2y + 4} = 3^{13}, which simplifies to 36x+2y+1=3133^{6x + 2y + 1} = 3^{13}. Equating the exponents yields 6x+2y+1=136x + 2y + 1 = 13, which simplifies to 3x+y=63x + y = 6. The second equation becomes 23x3y=2y92^{3x - 3y} = 2^{y - 9}. Equating these exponents yields 3x4y=93x - 4y = -9. Solving this system of equations gives x=1x = 1 and y=3y = 3. The sum of these values is 1+3=41 + 3 = 4.

Adım Adım Çözüm

1
Convert the bases of the first equation to a common base of 3.
Since 27=3327 = 3^3 and 9=329 = 3^2, we can rewrite the equation 272x19y+2=31327^{2x - 1} \cdot 9^{y + 2} = 3^{13} as (33)2x1(32)y+2=313(3^3)^{2x - 1} \cdot (3^2)^{y + 2} = 3^{13}. Applying the power of a power rule, this simplifies to 36x332y+4=3133^{6x - 3} \cdot 3^{2y + 4} = 3^{13}. Using the product rule of exponents, we add the exponents to get 36x+2y+1=3133^{6x + 2y + 1} = 3^{13}.
This allows us to equate the exponents and form a linear equation.
2
Set the exponents equal to each other to obtain the first linear equation.
6x+2y+1=13    6x+2y=12    3x+y=66x + 2y + 1 = 13 \implies 6x + 2y = 12 \implies 3x + y = 6.
Since the bases are identical on both sides, their exponents must be equal.
3
Convert the bases of the second equation to a common base of 2 and equate their exponents.
Since 8=238 = 2^3, rewrite 8xy=2y98^{x - y} = 2^{y - 9} as (23)xy=2y9    23x3y=2y9(2^3)^{x - y} = 2^{y - 9} \implies 2^{3x - 3y} = 2^{y - 9}. Equating the exponents gives 3x3y=y9    3x4y=93x - 3y = y - 9 \implies 3x - 4y = -9.
This gives us a second linear equation to form a system of equations.
4
Solve the system of equations for the variables.
From the first equation, we have 3x=6y3x = 6 - y. Substituting this into the second equation gives (6y)4y=9    65y=9    5y=15    y=3(6 - y) - 4y = -9 \implies 6 - 5y = -9 \implies -5y = -15 \implies y = 3. Substituting y=3y = 3 back into the first equation yields 3x+3=6    3x=3    x=13x + 3 = 6 \implies 3x = 3 \implies x = 1.
Solving the system of linear equations provides the individual values of the variables.
5
Calculate the sum of the variables.
x+y=1+3=4x + y = 1 + 3 = 4.
This answers the question asking for the sum of the variables.

Anahtar Kavram

Expressing exponential terms with a common base to form and solve a system of linear equations.
Soru 1585Soru

A certain substance decays radioactively such that the mass of the substance, in grams, remaining after tt days is modeled by the function M(t)=802t5M(t) = 80 \cdot 2^{-\frac{t}{5}}. After how many days will the mass of the substance be 1010 grams?

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Cevap: 15

Cevap

15
To find the number of days after which the mass of the substance is 1010 grams, we substitute 1010 for M(t)M(t) in the given function, yielding 10=802t510 = 80 \cdot 2^{-\frac{t}{5}}. Dividing both sides by 8080 gives 1080=2t5\frac{10}{80} = 2^{-\frac{t}{5}}, which simplifies to 18=2t5\frac{1}{8} = 2^{-\frac{t}{5}}. Since 18\frac{1}{8} can be written as 232^{-3}, the equation becomes 23=2t52^{-3} = 2^{-\frac{t}{5}}. Because the bases are the same, we equate the exponents: 3=t5-3 = -\frac{t}{5}. Multiplying both sides by 5-5 gives t=15t = 15.

Adım Adım Çözüm

1
Set the mass M(t)M(t) equal to 1010 in the given function.
10=802t510 = 80 \cdot 2^{-\frac{t}{5}}
We want to find the value of tt when the remaining mass of the substance is 1010 grams.
2
Divide both sides of the equation by 8080.
18=2t5\frac{1}{8} = 2^{-\frac{t}{5}}
To isolate the exponential expression.
3
Express both sides of the equation with a common base of 22.
23=2t52^{-3} = 2^{-\frac{t}{5}}
Since 8=238 = 2^3, the fraction 18\frac{1}{8} can be written as 232^{-3}. Having the same base on both sides allows us to equate the exponents.
4
Set the exponents equal to each other and solve for tt.
t=15t = 15
Because the bases are equal, the exponents must be equal: 3=t5-3 = -\frac{t}{5}.

Anahtar Kavram

Solving exponential equations by finding a common base.
Soru 1586Soru

An IT administrator uses the equation T=0.06r+40T = 0.06r + 40 to model the total time TT, in milliseconds, required to retrieve rr records from a cloud database. The constant term in the model represents the total setup time, which consists of network latency and database connection overhead. If the database connection overhead is 20% of the total setup time, which of the following is the best interpretation of the value 8 in this model?

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Cevap: The database connection overhead, in milliseconds, for retrieving any number of records.

Cevap

The database connection overhead, in milliseconds, for retrieving any number of records.
In the linear model T=0.06r+40T = 0.06r + 40, the constant term of 4040 represents the total setup time in milliseconds, which is independent of the number of records rr retrieved. The database connection overhead is 20%20\% of this total setup time, which equals 0.20×40=80.20 \times 40 = 8 milliseconds. Since it is part of the constant term, it represents a fixed overhead of 88 milliseconds for retrieving any number of records.

Adım Adım Çözüm

1
Identify the constant term in the linear model T=0.06r+40T = 0.06r + 40.
The constant term (y-intercept) is 4040, which represents the total setup time of 4040 milliseconds when r=0r = 0 records are retrieved.
In a linear relationship of the form y=mx+by = mx + b, the constant term bb represents the initial value or y-intercept.
2
Calculate the database connection overhead.
The database connection overhead is 20%20\% of the 4040 milliseconds total setup time, which is 0.20×40=80.20 \times 40 = 8 milliseconds.
The problem states that the database connection overhead is 20% of the total setup time.
3
Interpret the calculated value of 8 in the context of the model.
Since the 4040 milliseconds is a constant term that does not depend on the number of records rr, the 88 milliseconds represents a fixed database connection overhead for any number of records retrieved.
The constant term in a linear model represents a fixed value that does not scale with the independent variable.

Anahtar Kavram

Interpreting the constant term (y-intercept) and its components in a linear relationship context.
Soru 1587Soru

A community theater sold adult tickets and student tickets for its opening weekend performances. On Friday, the theater sold 2020 adult tickets and 4040 student tickets for a total of $760\$760. On Saturday, the theater sold 3535 adult tickets and 3030 student tickets for a total of $930\$930. What is the price, in dollars, of one adult ticket?

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Cevap: 18

Cevap

The price of one adult ticket is 18 dollars.
The price of one adult ticket is 1818. By setting up the system of linear equations representing the total sales on Friday (20x+40y=76020x + 40y = 760) and Saturday (35x+30y=93035x + 30y = 930), where xx is the adult ticket price and yy is the student ticket price, we can simplify them to x+2y=38x + 2y = 38 and 7x+6y=1867x + 6y = 186. Multiplying the first simplified equation by 33 gives 3x+6y=1143x + 6y = 114. Subtracting this equation from 7x+6y=1867x + 6y = 186 eliminates yy and yields 4x=724x = 72, which simplifies to x=18x = 18.

Adım Adım Çözüm

1
Define variables and write the system of linear equations based on the given information.
Let xx represent the price of an adult ticket and yy represent the price of a student ticket. The system of equations is:
20x+40y=76020x + 40y = 760
35x+30y=93035x + 30y = 930
Variables represent the unknown quantities, and the equations relate these quantities to the total sales on Friday and Saturday.
2
Simplify both equations by dividing by their greatest common divisors.
Divide the first equation by 2020:
x+2y=38x + 2y = 38
Divide the second equation by 55:
7x+6y=1867x + 6y = 186
Simplifying equations reduces the coefficient values and minimizes the chance of arithmetic errors in later steps.
3
Use the elimination method to solve for xx. Multiply the first simplified equation by 33 to align the yy-coefficients.
3(x+2y)=3(38)3x+6y=1143(x + 2y) = 3(38) \Rightarrow 3x + 6y = 114
Matching the coefficients of yy allows us to eliminate the variable yy by subtracting the equations.
4
Subtract the equation obtained in Step 3 from the second simplified equation.
(7x+6y)(3x+6y)=1861144x=72(7x + 6y) - (3x + 6y) = 186 - 114 \Rightarrow 4x = 72
Subtracting the equations eliminates yy, leaving a single linear equation in terms of xx.
5
Solve for xx by dividing both sides of the equation by 44.
x=18x = 18
Isolating xx provides the price of one adult ticket.

Anahtar Kavram

Solving a system of linear equations using substitution or elimination.

Alternatif Yöntem

Instead of using elimination on the simplified equations, you can use substitution. Express xx in terms of yy using the first simplified equation: x=382yx = 38 - 2y. Substitute this expression into the second equation: 7(382y)+6y=1867(38 - 2y) + 6y = 186. Expanding this gives 26614y+6y=186266 - 14y + 6y = 186, which simplifies to 2668y=186266 - 8y = 186. Subtracting 266266 from both sides gives 8y=80-8y = -80, which solves to y=10y = 10. Finally, substitute y=10y = 10 back into x=382yx = 38 - 2y to find x=382(10)=18x = 38 - 2(10) = 18.
Tahmini Süre:1m 30s
Soru 1588Soru

If x>0x > 0 and x23x18=0x^2 - 3x - 18 = 0, what is the value of x+2x + 2?

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Cevap: 8

Cevap

8
Factoring the quadratic equation x23x18=0x^2 - 3x - 18 = 0 yields (x6)(x+3)=0(x - 6)(x + 3) = 0. This gives two solutions: x=6x = 6 and x=3x = -3. Since the condition specifies x>0x > 0, we choose x=6x = 6. The question asks for the value of x+2x + 2, which is 6+2=86 + 2 = 8.

Adım Adım Çözüm

1
Factor the quadratic equation x23x18=0x^2 - 3x - 18 = 0 by finding two numbers that multiply to 18-18 and add to 3-3.
(x6)(x+3)=0(x - 6)(x + 3) = 0
Factoring allows us to find the individual roots of the quadratic equation.
2
Solve for the possible values of xx by setting each factor equal to zero.
x=6x = 6 or x=3x = -3
If the product of two factors is zero, then at least one of the factors must equal zero.
3
Apply the given constraint that x>0x > 0.
x=6x = 6
The problem specifies that xx must be a positive number, so the negative root x=3x = -3 must be discarded.
4
Substitute the value of xx into the expression x+2x + 2.
8
The question asks for the value of x+2x + 2, so we evaluate 6+26 + 2.

Anahtar Kavram

Solving quadratic equations by factoring and applying constraints on roots
Tahmini Süre:1m 0s
Soru 1589Soru

For all x>1x > 1, the expression 2x2+7x4x21x12x1\frac{2x^2 + 7x - 4}{x^2 - 1} \cdot \frac{x - 1}{2x - 1} is equivalent to x+kx+1\frac{x+k}{x+1}, where kk is a constant. What is the value of kk?

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Cevap: 4

Cevap

The value of the constant kk is 4.
Factoring the numerator 2x2+7x42x^2 + 7x - 4 yields (2x1)(x+4)(2x - 1)(x + 4) and factoring the denominator x21x^2 - 1 yields (x1)(x+1)(x - 1)(x + 1). Substituting these factored forms into the given product gives (2x1)(x+4)(x1)(x+1)x12x1\frac{(2x - 1)(x + 4)}{(x - 1)(x + 1)} \cdot \frac{x - 1}{2x - 1}. Canceling the common factors (2x1)(2x - 1) and (x1)(x - 1) simplifies the expression to x+4x+1\frac{x + 4}{x + 1}. Comparing this to x+kx+1\frac{x + k}{x + 1} shows that k=4k = 4.

Adım Adım Çözüm

1
Factor the quadratic expression in the numerator: 2x2+7x42x^2 + 7x - 4.
(2x1)(x+4)(2x - 1)(x + 4)
Factoring the numerator helps identify common factors that can be simplified.
2
Factor the difference of squares in the denominator: x21x^2 - 1.
(x1)(x+1)(x - 1)(x + 1)
Factoring the denominator helps identify common factors that can be simplified.
3
Multiply the rational expressions and cancel out the common factors.
x+4x+1\frac{x + 4}{x + 1}
Since x>1x > 1, the terms (2x1)(2x - 1) and (x1)(x - 1) are not equal to zero and can be canceled.
4
Compare the resulting expression with x+kx+1\frac{x + k}{x + 1} to find the value of kk.
k=4k = 4
By matching the numerators of the equivalent expressions, x+4=x+kx + 4 = x + k, which gives k=4k = 4.

Anahtar Kavram

Factoring and simplifying products of rational expressions
Soru 1590Soru
y=3x24x5y2x=4\begin{aligned} y &= 3x^2 - 4x - 5 \\ y - 2x &= 4 \end{aligned}

If (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the solutions to the system of equations above, and y1>y2y_1 > y_2, what is the value of x1+y2x_1 + y_2?

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Cevap: 5

Cevap

5
To find the solutions to the system of equations, substitute the expression for yy from the second equation into the first equation. First, rewrite the second equation as y=2x+4y = 2x + 4. Substituting this into the first equation yields 2x+4=3x24x52x + 4 = 3x^2 - 4x - 5. Rearranging terms to set the equation to zero gives 3x26x9=03x^2 - 6x - 9 = 0. Dividing the entire equation by 3 simplifies it to x22x3=0x^2 - 2x - 3 = 0. Factoring this quadratic equation gives (x3)(x+1)=0(x - 3)(x + 1) = 0, which yields the solutions x1=3x_1 = 3 and x2=1x_2 = -1. Next, find the corresponding yy-coordinates by substituting these xx-values back into the linear equation y=2x+4y = 2x + 4. For x=3x = 3, y1=2(3)+4=10y_1 = 2(3) + 4 = 10. For x=1x = -1, y2=2(1)+4=2y_2 = 2(-1) + 4 = 2. We are given that y1>y2y_1 > y_2, which confirms that (x1,y1)=(3,10)(x_1, y_1) = (3, 10) and (x2,y2)=(1,2)(x_2, y_2) = (-1, 2). Finally, calculate x1+y2x_1 + y_2, which is 3+2=53 + 2 = 5.

Adım Adım Çözüm

1
Rewrite the linear equation to express yy in terms of xx.
y=2x+4y = 2x + 4
This allows for substitution into the quadratic equation.
2
Substitute y=2x+4y = 2x + 4 into the quadratic equation and set to zero.
3x26x9=03x^2 - 6x - 9 = 0
To find the xx-coordinates of the intersection points.
3
Simplify and factor the quadratic equation.
(x3)(x+1)=0(x - 3)(x + 1) = 0, giving x=3x = 3 and x=1x = -1.
To solve for the xx-values of the intersection points.
4
Substitute the xx-values back into the linear equation to find the corresponding yy-values.
For x=3x = 3, y=10y = 10. For x=1x = -1, y=2y = 2. The intersection points are (3,10)(3, 10) and (1,2)(-1, 2).
To find the complete coordinates of the intersection points.
5
Identify (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) using the condition y1>y2y_1 > y_2, and compute x1+y2x_1 + y_2.
Since 10>210 > 2, y1=10y_1 = 10 (with x1=3x_1 = 3) and y2=2y_2 = 2 (with x2=1x_2 = -1). Then, x1+y2=3+2=5x_1 + y_2 = 3 + 2 = 5.
To compute the required target expression.

Anahtar Kavram

Solving a nonlinear system of equations by substituting a linear expression into a quadratic equation and solving the resulting quadratic equation.
Soru 1591Soru

If 32x19y+1=27x+y3^{2x - 1} \cdot 9^{y + 1} = 27^{x + y}, which of the following equations expresses xx in terms of yy?

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Cevap: x=1yx = 1 - y

Cevap

The equation expressing xx in terms of yy is x=1yx = 1 - y.
The correct option is x=1yx = 1 - y. To solve the equation, each term is rewritten with base 3: 32x1(32)y+1=(33)x+y3^{2x-1} \cdot (3^2)^{y+1} = (3^3)^{x+y}. Using the exponent rule (bm)n=bmn(b^m)^n = b^{mn}, this becomes 32x132y+2=33x+3y3^{2x-1} \cdot 3^{2y+2} = 3^{3x+3y}. Using the rule bmbn=bm+nb^m \cdot b^n = b^{m+n}, the left side simplifies to 32x+2y+13^{2x+2y+1}. Equating the exponents gives 2x+2y+1=3x+3y2x+2y+1 = 3x+3y. Subtracting 2x2x and 2y2y from both sides results in 1=x+y1 = x+y, which isolated for xx gives x=1yx = 1-y.

Adım Adım Çözüm

1
Rewrite all bases in the equation as powers of 3.
Since 9=329 = 3^2 and 27=3327 = 3^3, the equation becomes 32x1(32)y+1=(33)x+y3^{2x - 1} \cdot (3^2)^{y + 1} = (3^3)^{x + y}.
To apply exponent rules and combine terms, all bases must be identical.
2
Apply the power of a power rule (bm)n=bmn(b^m)^n = b^{mn} to simplify the exponents.
32x132y+2=33x+3y3^{2x - 1} \cdot 3^{2y + 2} = 3^{3x + 3y}
Multiplying the outer exponent by the inner exponent simplifies the terms on both sides.
3
Apply the product of powers rule bmbn=bm+nb^m \cdot b^n = b^{m+n} to combine the terms on the left side of the equation.
3(2x1)+(2y+2)=33x+3y3^{(2x - 1) + (2y + 2)} = 3^{3x + 3y}, which simplifies to 32x+2y+1=33x+3y3^{2x + 2y + 1} = 3^{3x + 3y}.
Adding exponents when multiplying expressions with the same base allows the left side to be represented as a single exponential term.
4
Set the exponents equal to each other and solve for xx in terms of yy.
2x+2y+1=3x+3y    1=x+y    x=1y2x + 2y + 1 = 3x + 3y \implies 1 = x + y \implies x = 1 - y
If two exponential expressions with the same positive base (other than 1) are equal, their exponents must be equal.

Anahtar Kavram

Solving exponential equations by expressing terms with a common base and applying exponent laws.
Tahmini Süre:1m 30s
Soru 1592Soru

In cognitive linguistics, the concept of 'embodied cognition' suggests that human language is shaped by our physical interactions with the environment. Abstract concepts are often conceptualized through metaphoric extensions of physical ______ we regularly use spatial terms like 'up' and 'down' to describe emotional states, linking physical orientation directly to subjective feelings.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Cevap: experience; for example,

Cevap

experience; for example,
The sentence contains two independent clauses: the first ends with 'experience' and the second begins with 'we regularly use'. To connect two independent clauses, standard English conventions require a period, a semicolon, or a coordinating conjunction with a comma. The punctuation 'experience; for example,' correctly uses a semicolon to separate the clauses and a comma after the transitional phrase 'for example'.

Adım Adım Çözüm

1
Identify the boundary between the two clauses in the sentence.
The first clause is 'Abstract concepts are often conceptualized through metaphoric extensions of physical experience' and the second clause is 'we regularly use spatial terms like 'up' and 'down' to describe emotional states, linking physical orientation directly to subjective feelings.'
Both clauses contain a subject and a verb and can stand alone as complete sentences, meaning they are independent clauses.
2
Determine the grammatical rules for linking two independent clauses.
Two independent clauses must be joined by a period, a semicolon, or a comma coupled with a coordinating conjunction.
Joining them with only a comma creates a comma splice, and joining them with no punctuation creates a run-on sentence.
3
Evaluate the logical relationship between the two clauses to select the appropriate connector.
The second clause provides a specific instance of the phenomenon described in the first clause, so a transition meaning 'for example' is logical, whereas a contrastive coordinator like 'but' is inappropriate.
A semicolon followed by the transitional phrase 'for example' and a comma correctly and logically joins the clauses.

Anahtar Kavram

Clause Boundaries and Linking
Tahmini Süre:1m 15s
Soru 1593Soru

In the xyxy-plane, a point with coordinates (x,y)(x, y) lies in the region defined by the system of inequalities below.

y+2x12y + 2x \leq 12
x2y6x - 2y \leq 6
x2x \geq 2

What is the maximum possible value of yy?

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Cevap: 8

Cevap

8
The system of inequalities bounds the solution set. The upper boundary is given by y2x+12y \leq -2x + 12. Because the slope is negative, the maximum value of yy on this boundary occurs at the smallest possible value of xx. The constraint x2x \geq 2 dictates that the minimum value of xx is 2. Substituting x=2x = 2 into the boundary equation yields y=2(2)+12=8y = -2(2) + 12 = 8. Checking this coordinate against the third inequality, 22(8)=1462 - 2(8) = -14 \leq 6, verifies that (2,8)(2, 8) is a valid solution.

Adım Adım Çözüm

1
Express the first two inequalities in terms of y.
y2x+12y \leq -2x + 12 and y12x3y \geq \frac{1}{2}x - 3
This helps identify the upper and lower boundaries of the solution region.
2
Determine the boundary line that limits the maximum values of y.
The upper boundary is the line y=2x+12y = -2x + 12.
Since the inequality is y2x+12y \leq -2x + 12, any solution must lie on or below this line.
3
Find the maximum value of y on this boundary line given the constraint x2x \geq 2.
y2(2)+12=8y \leq -2(2) + 12 = 8
Since the slope of the boundary line is negative, y is maximized when x is at its minimum value, which is 2.
4
Verify that the point (2,8)(2, 8) satisfies the inequality x2y6x - 2y \leq 6.
22(8)=1462 - 2(8) = -14 \leq 6, which is true.
This confirms that the point (2,8)(2, 8) is indeed in the solution set of the system.

Anahtar Kavram

Maximizing a coordinate value subject to a system of linear inequalities in two variables

Alternatif Yöntem

Instead of graphing or checking boundaries, we can algebraically solve for the boundary. Since x2x \geq 2, multiplying by 2-2 and reversing the inequality gives 2x4-2x \leq -4. Adding 12 to both sides gives 2x+128-2x + 12 \leq 8. Since y2x+12y \leq -2x + 12, we get y8y \leq 8. Checking if y=8y = 8 and x=2x = 2 satisfies the second inequality x2y6x - 2y \leq 6 confirms that 216=1462 - 16 = -14 \leq 6 is true, meaning y=8y = 8 is indeed a valid solution and thus the maximum.
Tahmini Süre:1m 30s
Soru 1594Soru

A shipping container has a maximum weight capacity of 24,15024,150 kilograms. The container is loaded with 1212 machinery units, each weighing 1,1501,150 kilograms. The remaining space will be filled with packing crates, each weighing 180180 kilograms. A safety regulation requires that a clearance weight of at least 15%15\% of the total loaded weight (the combined weight of the machinery units and the packing crates) must be left unused. What is the maximum number of packing crates that can be loaded into the container?

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Cevap: 40

Cevap

The maximum number of packing crates that can be loaded is 40.
By setting up the inequality representing the physical constraints, we find that the number of packing crates, xx, must satisfy x40x \le 40. Since the question asks for the maximum number of packing crates, the maximum value is 40.

Adım Adım Çözüm

1
Calculate the constant weight of the machinery units.
The total weight of the 1212 machinery units is 12×1,150=13,80012 \times 1,150 = 13,800 kilograms.
This establishes the base weight that is already loaded in the container.
2
Define the variable and write the expression for the total loaded weight.
Let xx be the number of packing crates. The total loaded weight is 13,800+180x13,800 + 180x kilograms.
This represents the combined weight of the machinery and the crates in terms of the variable xx.
3
Set up the inequality representing the safety clearance requirement.
24,150(13,800+180x)0.15(13,800+180x)24,150 - (13,800 + 180x) \ge 0.15(13,800 + 180x)
The unused weight capacity (maximum capacity minus loaded weight) must be at least 15%15\% of the loaded weight.
4
Solve the inequality for xx.
24,1501.15(13,800+180x)    21,00013,800+180x    7,200180x    x4024,150 \ge 1.15(13,800 + 180x) \implies 21,000 \ge 13,800 + 180x \implies 7,200 \ge 180x \implies x \le 40.
Isolating xx gives the range of allowable values for the number of packing crates.

Anahtar Kavram

Formulating and solving linear inequalities in one variable based on real-world constraints.
Soru 1595Soru

If (x4)2=81(x - 4)^2 = 81 and x>0x > 0, what is the value of xx?

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Cevap: 13

Cevap

The value of xx is 13.
Taking the square root of both sides of (x4)2=81(x - 4)^2 = 81 yields x4=9x - 4 = 9 or x4=9x - 4 = -9. Solving these linear equations gives x=13x = 13 or x=5x = -5. Since x>0x > 0 is specified, the correct value of xx is 13.

Adım Adım Çözüm

1
Take the square root of both sides of the equation.
x4=9x - 4 = 9 or x4=9x - 4 = -9
Applying the square root property to solve the quadratic equation.
2
Solve each linear equation for xx.
x=13x = 13 or x=5x = -5
Adding 4 to both sides of each equation.
3
Apply the given constraint that x>0x > 0.
x=13x = 13
Since 5-5 is not greater than 0, the only positive solution is 13.

Anahtar Kavram

Solving quadratic equations by taking square roots
Soru 1596Soru

In the xyxy-plane, the graph of the linear function ff passes through the points (3,11)(3, 11) and (7,23)(7, 23). The function gg is defined by g(x)=f(2x)5g(x) = f(2x) - 5. What is the value of g(4)g(4)?

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Cevap: 21

Cevap

21
The correct answer is 21. First, find the slope of the linear function ff using the given points (3,11)(3, 11) and (7,23)(7, 23): m=231173=3m = \frac{23 - 11}{7 - 3} = 3. The equation of the line is f(x)11=3(x3)f(x) - 11 = 3(x - 3), which simplifies to f(x)=3x+2f(x) = 3x + 2. To find g(4)g(4), substitute x=4x = 4 into the definition of g(x)g(x): g(4)=f(24)5=f(8)5g(4) = f(2 \cdot 4) - 5 = f(8) - 5. Evaluating f(8)f(8) gives 3(8)+2=263(8) + 2 = 26. Finally, subtracting 55 gives g(4)=265=21g(4) = 26 - 5 = 21.

Adım Adım Çözüm

1
Determine the equation of the linear function f(x)f(x)
f(x)=3x+2f(x) = 3x + 2
First find the slope m=231173=3m = \frac{23 - 11}{7 - 3} = 3. Then, use the point-slope formula with (3,11)(3, 11) to get f(x)11=3(x3)f(x) - 11 = 3(x - 3), which simplifies to f(x)=3x+2f(x) = 3x + 2.
2
Express g(4)g(4) in terms of ff
g(4)=f(8)5g(4) = f(8) - 5
Substitute x=4x = 4 into the definition g(x)=f(2x)5g(x) = f(2x) - 5 to get g(4)=f(2(4))5g(4) = f(2(4)) - 5.
3
Calculate the value of f(8)f(8) and g(4)g(4)
g(4)=21g(4) = 21
Evaluate f(8)=3(8)+2=26f(8) = 3(8) + 2 = 26, then subtract 55 to obtain g(4)=265=21g(4) = 26 - 5 = 21.

Anahtar Kavram

Linear Functions and Graphs
Soru 1597Soru

A scientist is monitoring the population of two species of bacteria, Species A and Species B, in a controlled environment. Initially, the combined population of the two species is 12,00012,000. Over the next week, the population of Species A doubles, and the population of Species B triples. If the total combined population of both species is 29,00029,000 at the end of the week, what was the initial population of Species A?

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Cevap: 7000

Cevap

The initial population of Species A was 7000.
To find the initial population of Species A, we set up a system of linear equations representing the total initial population and the population after one week. Let xx represent the initial population of Species A and yy represent the initial population of Species B. The initial combined population is given by x+y=12,000x + y = 12,000. After one week, the population of Species A doubles (2x2x) and Species B triples (3y3y), so the new combined population is 2x+3y=29,0002x + 3y = 29,000. We can express yy in terms of xx as y=12,000xy = 12,000 - x. Substituting this expression into the second equation gives 2x+3(12,000x)=29,0002x + 3(12,000 - x) = 29,000. Distributing and simplifying yields x+36,000=29,000-x + 36,000 = 29,000, which simplifies to x=7,000x = 7,000. Therefore, the initial population of Species A was 7,000.

Adım Adım Çözüm

1
Define the variables and set up the first equation.
x+y=12,000x + y = 12,000
Let xx be the initial population of Species A and yy be the initial population of Species B. Their combined initial population is 12,00012,000.
2
Set up the second equation based on the growth after one week.
2x+3y=29,0002x + 3y = 29,000
The population of Species A doubles to 2x2x and Species B triples to 3y3y, summing to a total of 29,00029,000.
3
Solve for xx using substitution.
x=7,000x = 7,000
From the first equation, y=12,000xy = 12,000 - x. Substituting this into the second equation gives 2x+3(12,000x)=29,0002x + 3(12,000 - x) = 29,000. Distributing the 33 yields 2x+36,0003x=29,0002x + 36,000 - 3x = 29,000. Combining like terms results in x+36,000=29,000-x + 36,000 = 29,000. Subtracting 36,00036,000 from both sides gives x=7,000-x = -7,000, which simplifies to x=7,000x = 7,000.

Anahtar Kavram

Solving systems of linear equations using substitution or elimination methods
Soru 1598Öğrencilerin %0'i bunu doğru yanıtladıSoru

For all x>3x > 3, which of the following is equivalent to the expression 2x25x3x29xx+3\frac{2x^2 - 5x - 3}{x^2 - 9} - \frac{x}{x+3}?

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Cevap: x+1x+3\frac{x + 1}{x + 3}

Cevap

x+1x+3\frac{x + 1}{x + 3}
To simplify the expression, we factor the first term: 2x25x3x29=(2x+1)(x3)(x3)(x+3)\frac{2x^2 - 5x - 3}{x^2 - 9} = \frac{(2x + 1)(x - 3)}{(x - 3)(x + 3)}. Canceling the common factor of x3x - 3 leaves 2x+1x+3\frac{2x + 1}{x + 3}. Subtracting the second term gives 2x+1x+3xx+3=2x+1xx+3=x+1x+3\frac{2x + 1}{x + 3} - \frac{x}{x + 3} = \frac{2x + 1 - x}{x + 3} = \frac{x + 1}{x + 3}. This matches the correct expression.

Adım Adım Çözüm

1
Factor the numerator and denominator of the first rational expression.
The numerator 2x25x32x^2 - 5x - 3 factors into (2x+1)(x3)(2x + 1)(x - 3). The denominator x29x^2 - 9 is a difference of squares and factors into (x3)(x+3)(x - 3)(x + 3).
Factoring allows for the simplification of the rational expression by identifying common factors in the numerator and denominator.
2
Simplify the first rational expression by canceling the common factor.
(2x+1)(x3)(x3)(x+3)=2x+1x+3\frac{(2x + 1)(x - 3)}{(x - 3)(x + 3)} = \frac{2x + 1}{x + 3} for all x>3x > 3.
Since x>3x > 3, the term x3x - 3 is non-zero, allowing us to divide both the numerator and denominator by x3x - 3.
3
Subtract the second expression from the simplified first expression.
2x+1x+3xx+3=2x+1xx+3=x+1x+3\frac{2x + 1}{x + 3} - \frac{x}{x + 3} = \frac{2x + 1 - x}{x + 3} = \frac{x + 1}{x + 3}
Since both fractions now have the same denominator, x+3x + 3, we subtract their numerators.

Anahtar Kavram

Simplifying rational expressions by factoring polynomials and performing operations on fractions with common denominators.
Tahmini Süre:1m 30s
Soru 1599Soru

A scientist models the population of a bacteria culture using the function P(t)=P0btP(t) = P_0 \cdot b^t, where P(t)P(t) is the population tt hours after the start of the experiment, P0P_0 is the initial population, and bb is a constant. The table below shows the population at two different times:

tt (hours)P(t)P(t)
221,8001,800
5548,60048,600

If the population of the bacteria culture is 1,312,2001,312,200 after kk hours, what is the value of kk?

Cevabı ve açıklamayı göster

Cevap: 8

Cevap

8
The correct value is 8. By setting up the ratio of the population at t=5t = 5 to t=2t = 2, we find that P(5)P(2)=b3=48,6001,800=27\frac{P(5)}{P(2)} = b^3 = \frac{48,600}{1,800} = 27, which yields an hourly growth factor of b=3b = 3. Using P(2)=P032=1,800P(2) = P_0 \cdot 3^2 = 1,800, we determine the initial population P0P_0 is 200. To find the hour kk when the population is 1,312,2001,312,200, we solve 2003k=1,312,200200 \cdot 3^k = 1,312,200, which simplifies to 3k=6,5613^k = 6,561. Since 38=6,5613^8 = 6,561, we find k=8k = 8. Alternatively, we can calculate P(k)P(5)=1,312,20048,600=27=33\frac{P(k)}{P(5)} = \frac{1,312,200}{48,600} = 27 = 3^3, meaning the population triples 3 more times after t=5t = 5, giving k=5+3=8k = 5 + 3 = 8.

Adım Adım Çözüm

1
Set up the ratio of the population at t=5t = 5 to the population at t=2t = 2 to find the growth factor bb.
P(5)P(2)=P0b5P0b2=b3=48,6001,800=27\frac{P(5)}{P(2)} = \frac{P_0 \cdot b^5}{P_0 \cdot b^2} = b^3 = \frac{48,600}{1,800} = 27
Dividing the function values eliminates the initial population P0P_0 and isolates the base bb.
2
Solve for the growth factor bb.
b=3b = 3
Since b3=27b^3 = 27, taking the cube root of both sides gives b=3b = 3.
3
Find the initial population P0P_0 using P(2)=1,800P(2) = 1,800 and b=3b = 3.
1,800=P0321,800=9P0P0=2001,800 = P_0 \cdot 3^2 \Rightarrow 1,800 = 9P_0 \Rightarrow P_0 = 200
Substituting the known values into the function formula allows us to solve for P0P_0.
4
Set up the equation for the population after kk hours and solve for kk.
1,312,200=2003k3k=1,312,200200=6,5611,312,200 = 200 \cdot 3^k \Rightarrow 3^k = \frac{1,312,200}{200} = 6,561
Dividing both sides by 200 isolates the exponential term 3k3^k.
5
Find the exponent kk by expressing 6,561 as a power of 3.
3k=38k=83^k = 3^8 \Rightarrow k = 8
Since 38=6,5613^8 = 6,561, the exponents must be equal, so k=8k = 8.

Anahtar Kavram

Determining parameters of an exponential growth function from given data points and using the function to solve for an unknown time variable.

Alternatif Yöntem

Instead of solving for the initial population P0P_0, we can compare the target population of 1,312,2001,312,200 to the population at t=5t = 5. Since the population triples every hour (b=3b = 3), the ratio of the population at t=kt = k to the population at t=5t = 5 is 3k53^{k-5}. We have 1,312,20048,600=27\frac{1,312,200}{48,600} = 27, which is 333^3. Therefore, 3k5=333^{k-5} = 3^3, which directly gives k5=3k - 5 = 3, or k=8k = 8.
Tahmini Süre:1m 15s
Soru 1600Soru

An artist creates xx small sculptures and yy large sculptures. Each small sculpture requires 3 hours of crafting and 2 hours of painting. Each large sculpture requires 7 hours of crafting and 3 hours of painting. The artist can spend at most 120 hours on crafting and at most 50 hours on painting. Which of the following pairs of small and large sculptures can the artist create under these constraints?

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Cevap: 10 small sculptures and 8 large sculptures

Cevap

10 small sculptures and 8 large sculptures
The option featuring 10 small sculptures and 8 large sculptures is correct because substituting x=10x = 10 and y=8y = 8 satisfies both linear inequalities representing the constraints. Specifically, the crafting time of 86 hours is less than or equal to the maximum allowed 120 hours (3(10)+7(8)=861203(10) + 7(8) = 86 \leq 120), and the painting time of 44 hours is less than or equal to the maximum allowed 50 hours (2(10)+3(8)=44502(10) + 3(8) = 44 \leq 50).

Adım Adım Çözüm

1
Set up the system of inequalities representing the constraints.
The crafting constraint is 3x+7y1203x + 7y \leq 120. The painting constraint is 2x+3y502x + 3y \leq 50. The variables must be non-negative: x0x \geq 0 and y0y \geq 0.
To model the limits on crafting hours and painting hours mathematically.
2
Substitute the values of each option into the system to verify which one satisfies both inequalities.
For the option with 10 small sculptures and 8 large sculptures (x=10,y=8x = 10, y = 8):
3(10)+7(8)=30+56=861203(10) + 7(8) = 30 + 56 = 86 \leq 120 (True)
2(10)+3(8)=20+24=44502(10) + 3(8) = 20 + 24 = 44 \leq 50 (True)
Only a coordinate pair that makes both inequality statements true is a valid solution.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
ÖncekiSayfa 80 / 140Sonraki
Tüm alıştırma soruları — SAT | Examkin