Tüm alıştırma soruları

2789 soru

Soru 1801Soru

In a certain company, the number of entry-level employees is 60%60\% of the total number of employees, and the remaining employees are managers. Over a year, the number of entry-level employees increases by x%x\%, and the number of managers decreases by y%y\%. As a result, the total number of employees in the company decreases by 4%4\%, and the ratio of the number of managers to the number of entry-level employees becomes 11 to 33. What is the value of xx?

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Cevap: 20

Cevap

The value of xx is 2020.
To find the value of xx, represent the initial and final quantities of entry-level employees and managers algebraically. Using the 4%4\% decrease in total employees and the final manager-to-entry-level ratio of 11 to 33, set up a system of linear equations: 2y3x=202y - 3x = 20 and 2y=100x2y = 100 - x. Solving this system for xx yields 2020.

Adım Adım Çözüm

1
Represent the initial employee counts algebraically.
Initial entry-level employees = 0.60T0.60T, initial managers = 0.40T0.40T, where TT is the initial total.
Establishing initial quantities based on the given percentages.
2
Represent the final employee counts after percent changes.
Final entry-level = 0.60T(1+0.01x)0.60T(1 + 0.01x), final managers = 0.40T(10.01y)0.40T(1 - 0.01y).
Applying the percent increase and decrease to the respective initial quantities.
3
Use the total percent change to create a linear equation.
2y3x=202y - 3x = 20
Setting the sum of the final counts equal to 0.96T0.96T and simplifying.
4
Use the final ratio of managers to entry-level employees to create a second equation.
2y=100x2y = 100 - x
Setting the ratio of final managers to final entry-level employees equal to 1/31/3 and simplifying.
5
Solve the system of equations for xx.
x=20x = 20
Substituting the second equation into the first to solve for the target variable.

Anahtar Kavram

Percents and Percent Change
Soru 1802Soru

An agricultural drone is used to spray liquid fertilizer on a field. The volume of fertilizer remaining in the drone's tank, FF, in liters, can be modeled by the equation F=1204.8tF = 120 - 4.8t, where tt is the number of minutes after the drone begins spraying. What is the best interpretation of the number 4.84.8 in this context?

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Cevap: The volume of fertilizer, in liters, that is sprayed from the drone's tank each minute.

Cevap

The volume of fertilizer, in liters, that is sprayed from the drone's tank each minute.
In the linear equation F=1204.8tF = 120 - 4.8t, the variable FF represents the remaining fertilizer in liters, and tt represents the elapsed time in minutes. The value 4.8 is the coefficient of tt, which represents the rate of change of the fertilizer in the tank. The negative sign in front of 4.8 indicates a decrease over time, meaning that the drone sprays 4.8 liters of fertilizer from the tank each minute.

Adım Adım Çözüm

1
Identify the role of the constant 4.8 in the given linear equation F=1204.8tF = 120 - 4.8t.
The coefficient of the independent variable tt is 4.8-4.8, which represents the slope of the linear relationship.
In the slope-intercept form of a linear equation, the coefficient of the variable represents the rate of change (slope).
2
Interpret the meaning of the slope in the context of the problem.
Since FF is measured in liters and tt is measured in minutes, the slope represents a change in liters per minute. The negative sign indicates that the volume of fertilizer is decreasing.
The rate of change is the change in the dependent variable (liters of fertilizer) divided by the change in the independent variable (minutes).
3
Select the option that correctly describes this rate of change.
The rate of decrease is 4.8 liters per minute, which means 4.8 liters of fertilizer are sprayed from the tank each minute.
This matches the definition of the rate at which fertilizer is leaving the tank.

Anahtar Kavram

Interpreting the slope of a linear equation in a real-world context.
Soru 1803Soru

A city's annual budget is divided into education, public safety, and other expenses. In 2025, the budget allocated for education was 1212 million dollars. For 2026, the education budget is increased by 15%15\%, and the public safety budget is decreased by 8%8\% from its 2025 value. If the public safety budget in 2026 is equal to the education budget in 2026, what was the public safety budget, in millions of dollars, in 2025?

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Cevap: 15

Cevap

The public safety budget in 2025 was 1515 million dollars.
To find the 2025 public safety budget, we first determine the 2026 education budget. A 15%15\% increase on the 2025 education budget of 1212 million yields 12×1.15=13.812 \times 1.15 = 13.8 million. Since the 2026 public safety budget is equal to this amount, it is also 13.813.8 million. Given that the 2026 public safety budget is an 8%8\% decrease from its 2025 value (PP), we set up the equation P×(10.08)=13.8P \times (1 - 0.08) = 13.8. Solving for PP gives P=13.80.92=15P = \frac{13.8}{0.92} = 15 million.

Adım Adım Çözüm

1
Calculate the education budget for 2026.
The education budget in 2026 is 13.813.8 million dollars.
The education budget in 2026 is a 15%15\% increase from the 2025 education budget of 1212 million dollars: 12×(1+0.15)=12×1.15=13.812 \times (1 + 0.15) = 12 \times 1.15 = 13.8 million dollars.
2
Express the relationship between the 2025 and 2026 public safety budgets.
0.92×P=13.80.92 \times P = 13.8, where PP is the 2025 public safety budget.
The public safety budget in 2026 is equal to the education budget in 2026 (13.813.8 million dollars) and represents an 8%8\% decrease from the 2025 public safety budget PP: P×(10.08)=13.8P \times (1 - 0.08) = 13.8.
3
Solve for the 2025 public safety budget PP.
P=15P = 15 million dollars.
Dividing both sides of the equation by 0.920.92 yields P=13.80.92=15P = \frac{13.8}{0.92} = 15 million dollars.

Anahtar Kavram

Calculating initial values after a percentage change

Alternatif Yöntem

Instead of converting to decimals immediately, you can use fractions: 12×115100=12×2320=695=13.812 \times \frac{115}{100} = 12 \times \frac{23}{20} = \frac{69}{5} = 13.8. Let PP be the 2025 public safety budget. Then 92100P=13.8\frac{92}{100} P = 13.8, so P=13.8×10092=138092=15P = 13.8 \times \frac{100}{92} = \frac{1380}{92} = 15.
Tahmini Süre:1m 30s
Soru 1804Soru

For the function ff, it is given that f(4)=18f(4) = 18. The function gg is defined by g(x)=13f(x+2)g(x) = \frac{1}{3}f(x + 2). What is the value of g(2)g(2)?

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Cevap: 6

Cevap

The value of g(2)g(2) is 6.
To evaluate g(2)g(2), substitute x=2x = 2 into the definition g(x)=13f(x+2)g(x) = \frac{1}{3}f(x+2), which yields g(2)=13f(2+2)=13f(4)g(2) = \frac{1}{3}f(2+2) = \frac{1}{3}f(4). Since f(4)=18f(4) = 18, this simplifies to 13(18)=6\frac{1}{3}(18) = 6.

Adım Adım Çözüm

1
Substitute x=2x = 2 into the expression for g(x)g(x).
g(2)=13f(2+2)g(2) = \frac{1}{3}f(2 + 2)
To evaluate the function gg at x=2x = 2, we substitute 2 for every occurrence of xx in the function definition.
2
Simplify the input argument for the function ff.
g(2)=13f(4)g(2) = \frac{1}{3}f(4)
Adding 2 and 2 inside the parentheses simplifies the input of ff to 4.
3
Substitute the given value of f(4)f(4) into the simplified expression.
g(2)=13(18)g(2) = \frac{1}{3}(18)
The problem states that f(4)=18f(4) = 18.
4
Perform the final multiplication.
6
Multiplying 18 by 13\frac{1}{3} is equivalent to dividing 18 by 3, which yields 6.

Anahtar Kavram

Evaluating a transformed function by substituting a value into function notation.
Tahmini Süre:45s
Soru 1805Soru

In temperate forest ecosystems, subterranean mycorrhizal networks composed of vast fungal mycelia connect the root systems of geographically distant trees. Through these subterranean highways, mature canopy trees can share vital nutrients like carbon and phosphorus with struggling understory seedlings ______ this cooperative resource distribution significantly increases the health and overall survival rate of the entire forest community.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Cevap: seedlings; this

Cevap

seedlings; this
The option using a semicolon correctly links two independent clauses. The clause before the blank is independent, and the clause after the blank is also independent. A semicolon is a standard punctuation mark used to connect two closely related independent clauses without a coordinating conjunction.

Adım Adım Çözüm

1
Analyze the structure of the two clauses surrounding the blank.
The clause before the blank ('Through these subterranean highways... seedlings') is independent because it contains a subject and a verb and expresses a complete thought. The clause after the blank ('this cooperative resource distribution... community') is also independent.
Identifying the clause boundaries helps determine what punctuation or conjunction is needed to link them.
2
Evaluate how independent clauses can be joined.
Two independent clauses can be joined by a semicolon, a period, or a comma coupled with a coordinating conjunction (like 'and'). They cannot be joined with just a comma or no punctuation at all.
This narrows down the choices to grammatically correct linking methods.
3
Select the option that conforms to standard English conventions and maintains logical flow.
The option containing a semicolon correctly separates the two clauses. The option with 'but' is grammatically possible but logically incorrect because the relationship between sharing nutrients and increasing survival is supportive, not contrastive.
The correct answer must be both grammatically valid and contextually logical.

Anahtar Kavram

Clause Boundaries and Linking
Soru 1806Soru

Consider the system of equations below:

y=3x25x4y=x22x+5\begin{aligned} y &= 3x^2 - 5x - 4 \\ y &= x^2 - 2x + 5 \end{aligned}

If (x,y)(x, y) is a solution to the system of equations above and x>0x > 0, what is the value of yy?

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Cevap: 8

Cevap

The value of yy is 8.
By setting the two equations equal to each other, we obtain 3x25x4=x22x+53x^2 - 5x - 4 = x^2 - 2x + 5. Simplifying this equation by moving all terms to one side yields 2x23x9=02x^2 - 3x - 9 = 0. Factoring this quadratic equation gives (2x+3)(x3)=0(2x + 3)(x - 3) = 0, which has solutions x=1.5x = -1.5 and x=3x = 3. Since the problem specifies that x>0x > 0, we must use x=3x = 3. Substituting x=3x = 3 into the second equation, we find y=(3)22(3)+5=8y = (3)^2 - 2(3) + 5 = 8. Substituting into the first equation also yields y=3(3)25(3)4=8y = 3(3)^2 - 5(3) - 4 = 8. Therefore, the value of yy is 8.

Adım Adım Çözüm

1
Set the quadratic expressions equal to each other.
3x25x4=x22x+53x^2 - 5x - 4 = x^2 - 2x + 5
Since both equations are solved for yy, their right-hand sides must be equal at any point of intersection.
2
Rearrange the terms to set the quadratic equation to zero.
2x23x9=02x^2 - 3x - 9 = 0
Putting the equation in standard form ax2+bx+c=0ax^2 + bx + c = 0 allows us to solve it by factoring.
3
Factor the quadratic expression to find the roots.
(2x+3)(x3)=0(2x + 3)(x - 3) = 0, which yields x=1.5x = -1.5 or x=3x = 3.
Factoring shows the values of xx that satisfy the system.
4
Select the positive root and substitute it back to find yy.
y=8y = 8
The problem specifies x>0x > 0, so we use x=3x = 3. Substituting x=3x = 3 into y=x22x+5y = x^2 - 2x + 5 gives the corresponding yy-value.

Anahtar Kavram

Solving a system of nonlinear equations by setting the equations equal to each other and solving the resulting quadratic equation.
Soru 1807Soru

An environmental study monitors the populations of two different plant species in a conservation area. The population of Species A is modeled by a linear function, A(t)=120+15tA(t) = 120 + 15t, where tt represents the number of years since the start of the study. The population of Species B is modeled by an exponential function, B(t)=cdtB(t) = c \cdot d^t, where cc and dd are constants. At the start of the study (t=0t = 0), the population of Species A is 44 times the population of Species B. After 22 years, the population of Species A is equal to the population of Species B. What is the population of Species B after 44 years?

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Cevap: 750

Cevap

The population of Species B after 44 years is 750750.
To find the population of Species B after 44 years, we evaluate the models at the given points. At t=0t = 0, A(0)=120A(0) = 120. Since the population of Species A is 44 times that of Species B at t=0t = 0, the initial population of Species B is 3030, which gives c=30c = 30. At t=2t = 2, A(2)=120+15(2)=150A(2) = 120 + 15(2) = 150. Since the populations are equal at t=2t = 2, we have B(2)=30d2=150B(2) = 30 \cdot d^2 = 150, which simplifies to d2=5d^2 = 5. The population of Species B at t=4t = 4 is given by B(4)=30d4=30(d2)2=3052=750B(4) = 30 \cdot d^4 = 30 \cdot (d^2)^2 = 30 \cdot 5^2 = 750.

Adım Adım Çözüm

1
Find the population of Species A at the start of the study (t=0t = 0)
A(0)=120A(0) = 120
This establishes the baseline population of Species A to find the corresponding initial population of Species B.
2
Determine the constant cc, which represents the initial population of Species B
c=30c = 30
Since the population of Species A is 44 times that of Species B at t=0t = 0, we solve 120=4c120 = 4c.
3
Calculate the population of Species A after 22 years (t=2t = 2)
A(2)=150A(2) = 150
This value is needed because the population of Species B equals the population of Species A at t=2t = 2.
4
Solve for the growth factor term d2d^2
d2=5d^2 = 5
Using the equality B(2)=150B(2) = 150, we solve 30d2=15030 \cdot d^2 = 150.
5
Calculate the population of Species B after 44 years (t=4t = 4)
B(4)=750B(4) = 750
Using the exponential model B(t)=30dtB(t) = 30 \cdot d^t, we find B(4)=30d4=30(d2)2=3052B(4) = 30 \cdot d^4 = 30 \cdot (d^2)^2 = 30 \cdot 5^2.

Anahtar Kavram

Solving systems involving linear and exponential models using initial conditions and key points.
Soru 1808Soru

In the xyxy-plane, the graph of the quadratic function f(x)=x2+bx+cf(x) = -x^2 + bx + c, where bb and cc are constants, has its vertex at (4,9)(4, 9). What is the positive difference between the two xx-intercepts of the graph?

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Cevap: 6

Cevap

The correct answer is 6.
The quadratic function can be represented in vertex form as f(x)=(x4)2+9f(x) = -(x - 4)^2 + 9 since the leading coefficient is 1-1 and the vertex is at (4,9)(4, 9). Setting the function equal to zero to find the xx-intercepts gives (x4)2=9(x - 4)^2 = 9, which yields x=7x = 7 and x=1x = 1. The positive difference between these intercepts is 71=67 - 1 = 6.

Adım Adım Çözüm

1
Write the quadratic function in vertex form using the given vertex (4,9)(4, 9) and the leading coefficient.
f(x)=(x4)2+9f(x) = -(x - 4)^2 + 9
The vertex form of a quadratic function is f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex. Since the coefficient of x2x^2 is 1-1, we have a=1a = -1, h=4h = 4, and k=9k = 9.
2
Set f(x)=0f(x) = 0 to find the xx-intercepts.
(x4)2=9(x - 4)^2 = 9
The xx-intercepts of a graph are the points where f(x)=0f(x) = 0.
3
Solve for xx.
x=7x = 7 and x=1x = 1
Taking the square root of both sides gives x4=±3x - 4 = \pm 3, which results in x=7x = 7 and x=1x = 1.
4
Find the positive difference between the two xx-intercepts.
6
Subtract the smaller xx-intercept from the larger xx-intercept: 71=67 - 1 = 6.

Anahtar Kavram

Finding the intercepts of a quadratic function using its vertex form

Alternatif Yöntem

Alternatively, expand the vertex form f(x)=(x4)2+9f(x) = -(x - 4)^2 + 9 to get f(x)=(x28x+16)+9=x2+8x7f(x) = -(x^2 - 8x + 16) + 9 = -x^2 + 8x - 7. Factoring this expression gives f(x)=(x7)(x1)f(x) = -(x - 7)(x - 1). The roots are x=7x = 7 and x=1x = 1, and their difference is 71=67 - 1 = 6.
Tahmini Süre:1m 30s
Soru 1809Soru

A parabola in the xyxy-plane has vertex (2,11)(2, 11) and passes through the point (5,7)(5, -7). The equation of the parabola is y=ax2+bx+cy = ax^2 + bx + c, where aa, bb, and cc are constants. What is the value of a+b+ca + b + c?

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Cevap: 9

Cevap

The value of a+b+ca + b + c is 99.
The correct value of a+b+ca + b + c is 99. This is found by writing the parabola's equation in vertex form as y=2(x2)2+11y = -2(x - 2)^2 + 11 and expanding it to standard form y=2x2+8x+3y = -2x^2 + 8x + 3, which gives the coefficients a=2a = -2, b=8b = 8, and c=3c = 3. Alternatively, substituting x=1x = 1 directly into the vertex form gives f(1)=a(1)2+b(1)+c=2(12)2+11=9f(1) = a(1)^2 + b(1) + c = -2(1 - 2)^2 + 11 = 9.

Adım Adım Çözüm

1
Write the equation of the parabola in vertex form using the given vertex (2,11)(2, 11).
y=a(x2)2+11y = a(x - 2)^2 + 11
The vertex form of a quadratic function is y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
2
Substitute the coordinates of the point (5,7)(5, -7) into the vertex form equation to solve for the constant aa.
a=2a = -2
Since the point (5,7)(5, -7) lies on the parabola, substituting x=5x = 5 and y=7y = -7 allows us to solve the linear equation 7=a(52)2+11-7 = a(5 - 2)^2 + 11 for aa.
3
Expand the vertex form equation y=2(x2)2+11y = -2(x - 2)^2 + 11 into standard form y=ax2+bx+cy = ax^2 + bx + c to identify the coefficients aa, bb, and cc.
y=2x2+8x+3y = -2x^2 + 8x + 3, which gives a=2a = -2, b=8b = 8, and c=3c = 3.
Expanding the squared term and distributing the coefficient 2-2 converts the equation to standard form, making it easy to read off the coefficients.
4
Calculate the sum of the coefficients a+b+ca + b + c.
a+b+c=9a + b + c = 9
Adding the identified coefficients: 2+8+3=9-2 + 8 + 3 = 9.

Anahtar Kavram

Writing and converting quadratic functions between vertex form y=a(xh)2+ky = a(x - h)^2 + k and standard form y=ax2+bx+cy = ax^2 + bx + c.

Alternatif Yöntem

Instead of expanding the vertex form equation to find the individual coefficients aa, bb, and cc, recognize that the expression a+b+ca + b + c is equal to f(1)f(1) for the quadratic function f(x)=ax2+bx+cf(x) = ax^2 + bx + c. After finding a=2a = -2 using the vertex form f(x)=a(x2)2+11f(x) = a(x - 2)^2 + 11, directly evaluate f(1)=2(12)2+11=9f(1) = -2(1 - 2)^2 + 11 = 9.
Tahmini Süre:2m 30s
Soru 1810Soru

During a weekend sale, a store reduced the price of a bicycle by 20%20\%. If the sale price of the bicycle is $160\$160, what was the original price, in dollars, of the bicycle?

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Cevap: $200\$200

Cevap

The original price of the bicycle was $200\$200.
The correct answer is $200\$200. A discount of 20%20\% means that the sale price of $160\$160 is 80%80\% of the original price (100%20%=80%100\% - 20\% = 80\%). Setting up the equation 0.80×P=1600.80 \times P = 160, where PP is the original price, and solving for PP gives P=1600.80=200P = \frac{160}{0.80} = 200.

Adım Adım Çözüm

1
Express the relationship between the original price and the sale price using the discount percentage.
The sale price represents 80%80\% of the original price because a 20%20\% discount was applied (100%20%=80%100\% - 20\% = 80\%).
Establishing the percentage value of the sale price relative to the original price is necessary to set up the equation.
2
Set up an equation with the original price, represented by PP.
0.80×P=1600.80 \times P = 160
Since the sale price is 80%80\% of the original price, multiplying the original price by 0.800.80 must equal the sale price of $160\$160.
3
Solve for the original price, PP, by dividing both sides of the equation by 0.800.80.
P=1600.80=200P = \frac{160}{0.80} = 200
Dividing the sale price by the decimal representation of its percentage of the original price isolates the variable and calculates the original price.

Anahtar Kavram

Percents and Percent Change
Soru 1811Soru
kx5y=83x2y=12\begin{aligned} k x - 5y &= 8 \\ 3x - 2y &= 12 \end{aligned}

In the system of equations above, kk is a constant. If the system has no solution, what is the value of kk?

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Cevap: 152\frac{15}{2}

Cevap

152\frac{15}{2}
The correct answer is the value that makes the two lines parallel. Rewriting both equations in slope-intercept form gives the slopes k5\frac{k}{5} and 32\frac{3}{2}. Equating these slopes yields k5=32\frac{k}{5} = \frac{3}{2}, which simplifies to 152\frac{15}{2}. Since their yy-intercepts (85-\frac{8}{5} and 6-6) are distinct, the lines are parallel and never intersect, meaning the system has no solution.

Adım Adım Çözüm

1
Convert the first equation to slope-intercept form (y=mx+by = mx + b).
kx5y=8    5y=kx+8    y=k5x85kx - 5y = 8 \implies -5y = -kx + 8 \implies y = \frac{k}{5}x - \frac{8}{5}
This identifies the slope (m1=k5m_1 = \frac{k}{5}) and the yy-intercept (b1=85b_1 = -\frac{8}{5}) of the first line.
2
Convert the second equation to slope-intercept form.
3x2y=12    2y=3x+12    y=32x63x - 2y = 12 \implies -2y = -3x + 12 \implies y = \frac{3}{2}x - 6
This identifies the slope (m2=32m_2 = \frac{3}{2}) and the yy-intercept (b2=6b_2 = -6) of the second line.
3
Equate the two slopes to find the value of kk that makes the lines parallel.
k5=32    k=5×32=152\frac{k}{5} = \frac{3}{2} \implies k = 5 \times \frac{3}{2} = \frac{15}{2}
A system of linear equations has no solution if the lines are parallel (equal slopes) and distinct (different yy-intercepts). Since the yy-intercepts 85-\frac{8}{5} and 6-6 are different, setting the slopes equal guarantees no solution.

Anahtar Kavram

A system of two linear equations has no solution if the lines represented by the equations have the same slope but different yy-intercepts (parallel lines).
Tahmini Süre:1m 30s
Soru 1812Soru

The polynomial function pp is defined by p(x)=x3+4x27x10p(x) = x^3 + 4x^2 - 7x - 10. If p(2)=0p(2) = 0, which of the following expressions must be a factor of p(x)p(x)?

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Cevap: x2x - 2

Cevap

The expression x2x - 2 must be a factor of p(x)p(x).
According to the Factor Theorem, if a polynomial p(x)p(x) evaluates to 00 at a certain value x=cx = c (meaning p(c)=0p(c) = 0), then (xc)(x - c) is a factor of the polynomial. Since we are given that p(2)=0p(2) = 0, the value 22 is a root of p(x)p(x), which means the expression x2x - 2 must be a factor of the polynomial.

Adım Adım Çözüm

1
Identify the given root of the polynomial.
The problem states that p(2)=0p(2) = 0, which means that x=2x = 2 is a root of the polynomial p(x)p(x).
A root is any value of xx for which the polynomial evaluates to 00.
2
Apply the Factor Theorem to write the corresponding factor.
According to the Factor Theorem, if cc is a root of a polynomial p(x)p(x), then (xc)(x - c) is a factor of p(x)p(x). Substituting c=2c = 2 gives (x2)(x - 2) as a factor.
The Factor Theorem directly relates the roots of a polynomial to its linear factors.

Anahtar Kavram

The Factor Theorem states that a polynomial p(x)p(x) has a factor (xc)(x - c) if and only if p(c)=0p(c) = 0.
Soru 1813Soru

In the dry environment of the Taklamakan Desert, ancient textiles have remained remarkably well-preserved for thousands of years. The arid conditions prevent the growth of bacteria and fungi that normally cause organic decay _______ archaeologists have been able to recover silk garments with their vibrant colors still intact.

Which choice completes the text so that it conforms to the conventions of Standard English?

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Cevap: ; as a result,

Cevap

The correct choice is '; as a result,', which uses a semicolon and a comma-delineated transition phrase to properly connect two independent clauses and establish a logical cause-and-effect relationship.
The correct option correctly joins two independent clauses using a semicolon followed by the conjunctive adverb 'as a result' and a comma. This conforms to Standard English conventions for linking independent clauses and logically reflects the cause-and-effect relationship between the prevention of decay and the recovery of preserved textiles.

Adım Adım Çözüm

1
Analyze the clauses surrounding the blank.
The clause before the blank ('The arid conditions prevent the growth of bacteria and fungi that normally cause organic decay') and the clause after the blank ('archaeologists have been able to recover silk garments with their vibrant colors still intact') are both independent clauses because they can each stand alone as complete sentences.
Identifying clause types is necessary to determine the appropriate punctuation and linking words needed to join them.
2
Identify the logical relationship between the two clauses.
The first clause describes a cause (arid conditions preventing decay) and the second clause describes the direct effect or consequence of that cause (the recovery of well-preserved garments). Therefore, a transition expressing cause-and-effect or consequence is required.
Determining the logical connection helps eliminate transition words that indicate an incorrect relationship, such as contrast.
3
Evaluate the grammar and punctuation of the choices.
To link two independent clauses, standard English conventions require a period, a semicolon, or a comma paired with a coordinating conjunction. The transition phrase 'as a result' is a conjunctive adverb, which must be preceded by a semicolon and followed by a comma when linking independent clauses.
Applying grammatical rules ensures the sentence avoids errors like comma splices, run-ons, and fragments.

Anahtar Kavram

Clause Boundaries and Linking
Soru 1814Soru

The graph of the function ff in the xyxy-plane passes through the point (5,2)(5, -2). The function gg is defined by g(x)=f(x)+6g(x) = f(x) + 6. Which of the following points must lie on the graph of gg?

Cevabı ve açıklamayı göster

Cevap: (5,4)(5, 4)

Cevap

The point (5,4)(5, 4)
Since the point (5,2)(5, -2) is on the graph of ff, we know that f(5)=2f(5) = -2. The function gg is defined by g(x)=f(x)+6g(x) = f(x) + 6, which represents a vertical shift upward by 66 units. Substituting x=5x = 5 into the equation for gg yields g(5)=f(5)+6=2+6=4g(5) = f(5) + 6 = -2 + 6 = 4. Therefore, the point (5,4)(5, 4) must be on the graph of gg.

Adım Adım Çözüm

1
Determine the value of f(5)f(5) using the given point on the graph of ff.
f(5)=2f(5) = -2
Since the point (5,2)(5, -2) lies on the graph of ff, the input x=5x = 5 corresponds to the output y=2y = -2.
2
Use the definition of g(x)g(x) to evaluate g(5)g(5).
g(5)=f(5)+6=2+6=4g(5) = f(5) + 6 = -2 + 6 = 4
Substitute x=5x = 5 into the definition g(x)=f(x)+6g(x) = f(x) + 6 to find the corresponding yy-value for the graph of gg.

Anahtar Kavram

Vertical translations of function graphs
Tahmini Süre:45s
Soru 1815Soru

The table below shows the remaining balance, BB, in dollars, on a transit card after a user has taken rr rides on a city bus.

Number of rides (rr)Remaining balance (BB, in dollars)
3322.5022.50
8810.0010.00
12120.000.00

Which of the following equations represents the relationship between BB and rr?

Cevabı ve açıklamayı göster

Cevap: B=30.002.50rB = 30.00 - 2.50r

Cevap

B=30.002.50rB = 30.00 - 2.50r
The correct equation has a rate of change of 2.50-2.50 dollars per ride and a starting balance of 30.0030.00 dollars. The rate of change (slope) can be calculated by finding the change in balance divided by the change in the number of rides between two points, such as (3,22.50)(3, 22.50) and (8,10.00)(8, 10.00), which gives 10.0022.5083=2.50\frac{10.00 - 22.50}{8 - 3} = -2.50. Using the slope-intercept form B=mr+B0B = mr + B_0 and the point (12,0.00)(12, 0.00), we get 0.00=2.50(12)+B00.00 = -2.50(12) + B_0, which simplifies to B0=30.00B_0 = 30.00. Therefore, the equation is B=30.002.50rB = 30.00 - 2.50r.

Adım Adım Çözüm

1
Calculate the slope (rate of change) using two points from the table, such as (3,22.50)(3, 22.50) and (8,10.00)(8, 10.00).
The slope is m=10.0022.5083=12.505=2.50m = \frac{10.00 - 22.50}{8 - 3} = \frac{-12.50}{5} = -2.50.
The slope represents the constant change in the remaining balance per ride.
2
Use the slope-intercept form B=mr+B0B = mr + B_0 and one point to find the initial balance B0B_0.
Substituting m=2.50m = -2.50 and the point (12,0.00)(12, 0.00) gives 0.00=2.50(12)+B00.00 = -2.50(12) + B_0, which simplifies to 0.00=30.00+B00.00 = -30.00 + B_0, so B0=30.00B_0 = 30.00.
The initial balance B0B_0 is the y-intercept, which is the value of BB when r=0r = 0.
3
Write the final linear equation representing the relationship.
The final equation is B=30.002.50rB = 30.00 - 2.50r.
This equation models the remaining balance on the card as a function of the number of rides taken.

Anahtar Kavram

Finding a linear equation in two variables from a table of values.
Soru 1816Soru

What is the larger solution to the equation below?

xx2+3x=2\frac{x}{x - 2} + \frac{3}{x} = 2
Cevabı ve açıklamayı göster

Cevap: 6

Cevap

The larger solution to the equation is 6.
To solve the rational equation, we clear the denominators by multiplying both sides by x(x2)x(x - 2), which yields the quadratic equation x27x+6=0x^2 - 7x + 6 = 0. Factoring this equation gives (x6)(x1)=0(x - 6)(x - 1) = 0, leading to the solutions x=6x = 6 and x=1x = 1. Both values are valid because they do not make any denominator of the original expression equal to zero. The larger of the two values is 6.

Adım Adım Çözüm

1
Multiply both sides of the equation by the common denominator x(x2)x(x - 2) to clear the fractions.
x2+3(x2)=2x(x2)x^2 + 3(x - 2) = 2x(x - 2)
Clearing denominators simplifies the rational equation into a polynomial equation.
2
Expand both sides of the equation.
x2+3x6=2x24xx^2 + 3x - 6 = 2x^2 - 4x
Distributing the multiplication allows us to combine like terms.
3
Move all terms to one side of the equation to write it in the standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.
x27x+6=0x^2 - 7x + 6 = 0
Setting the quadratic expression to zero prepares it for factoring.
4
Factor the quadratic equation.
(x6)(x1)=0(x - 6)(x - 1) = 0
Finding two numbers that multiply to 66 and sum to 7-7 gives 6-6 and 1-1.
5
Identify the values of xx that satisfy the factored equation and check for extraneous solutions.
x=6x = 6 or x=1x = 1
Neither solution makes the denominators in the original equation, x2x-2 or xx, equal to zero, so both are valid. The larger of these two solutions is 6.

Anahtar Kavram

Solving rational equations by clearing denominators to form a quadratic equation, and verifying solutions against the domain constraints.
Soru 1817Soru

A laboratory technician prepared a chemistry solution containing only liquid A and liquid B. Initially, liquid A made up 35%35\% of the total volume of the solution. After 150150 milliliters of liquid B was removed from the solution, the volume of liquid A became 42%42\% of the total volume of the remaining solution. What was the initial volume of liquid A, in milliliters?

Cevabı ve açıklamayı göster

Cevap: 315

Cevap

315
The correct answer is 315. Let VV represent the initial total volume of the solution. Initially, liquid A's volume is 0.35V0.35V. After removing 150150 milliliters of liquid B, the total volume becomes V150V - 150. Since only liquid B was removed, the volume of liquid A remains unchanged. This volume is now 42%42\% of the new total volume, which gives the equation 0.35V=0.42(V150)0.35V = 0.42(V - 150). Expanding the right side yields 0.35V=0.42V630.35V = 0.42V - 63. Subtracting 0.35V0.35V and adding 6363 to both sides results in 0.07V=630.07V = 63, which simplifies to V=900V = 900 milliliters. To find the initial volume of liquid A, we calculate 35%35\% of 900900, which is 315315 milliliters.

Adım Adım Çözüm

1
Let VV represent the initial total volume of the solution in milliliters. Express the initial volume of liquid A in terms of VV.
The initial volume of liquid A is 0.35V0.35V milliliters.
Liquid A constitutes 35%35\% of the initial total volume VV.
2
Express the final total volume of the solution after removing 150150 milliliters of liquid B.
The final total volume is V150V - 150 milliliters.
Subtracting the volume of liquid B that was removed from the initial total volume gives the remaining total volume.
3
Set up an equation representing the volume of liquid A in the remaining solution and solve for VV.
0.35V=0.42(V150)    0.35V=0.42V63    0.07V=63    V=9000.35V = 0.42(V - 150) \implies 0.35V = 0.42V - 63 \implies 0.07V = 63 \implies V = 900 milliliters.
The volume of liquid A remains constant, but it now represents 42%42\% of the remaining total volume V150V - 150.
4
Calculate the initial volume of liquid A.
0.35×900=3150.35 \times 900 = 315 milliliters.
Substitute the value of VV back into the expression for the initial volume of liquid A.

Anahtar Kavram

Solving multi-step percent problems involving a change in the baseline total volume.
Tahmini Süre:2m 0s
Soru 1818Soru
For all real values of xx that satisfy the equation below, what is the value of x+1x + 1?
5x+393=x\sqrt{5x + 39} - 3 = x
Cevabı ve açıklamayı göster

Cevap: 66

Cevap

The correct answer is 66.
By adding 33 to both sides, we get 5x+39=x+3\sqrt{5x + 39} = x + 3. Squaring both sides yields 5x+39=x2+6x+95x + 39 = x^2 + 6x + 9. Setting this quadratic equation to zero gives x2+x30=0x^2 + x - 30 = 0, which factors as (x+6)(x5)=0(x + 6)(x - 5) = 0. The potential solutions are x=5x = 5 and x=6x = -6. Checking these values in the original equation shows that only x=5x = 5 is valid: 5(5)+393=83=5\sqrt{5(5) + 39} - 3 = 8 - 3 = 5, which satisfies the equation. The value x=6x = -6 is extraneous since 5(6)+393=33=06\sqrt{5(-6) + 39} - 3 = 3 - 3 = 0 \neq -6. Therefore, the value of x+1x + 1 is 5+1=65 + 1 = 6.

Adım Adım Çözüm

1
Isolate the radical expression on one side of the equation.
5x+39=x+3\sqrt{5x + 39} = x + 3
Isolating the radical allows us to square both sides to eliminate the square root.
2
Square both sides of the equation.
5x+39=(x+3)2    5x+39=x2+6x+95x + 39 = (x + 3)^2 \implies 5x + 39 = x^2 + 6x + 9
Squaring a square root removes the radical, allowing us to solve the resulting quadratic equation.
3
Rearrange the terms to form a standard quadratic equation of the form ax2+bx+c=0ax^2 + bx + c = 0.
x2+x30=0x^2 + x - 30 = 0
Subtracting 5x5x and 3939 from both sides sets the quadratic expression equal to zero.
4
Factor the quadratic equation to find potential solutions.
(x+6)(x5)=0    x=6 or x=5(x + 6)(x - 5) = 0 \implies x = -6 \text{ or } x = 5
Finding two numbers that multiply to 30-30 and add up to 11 gives 66 and 5-5.
5
Substitute both candidate solutions back into the original equation to check for extraneous solutions.
For x=5x = 5: 5(5)+393=83=5\sqrt{5(5) + 39} - 3 = 8 - 3 = 5 (Valid). For x=6x = -6: 5(6)+393=33=06\sqrt{5(-6) + 39} - 3 = 3 - 3 = 0 \neq -6 (Extraneous).
Squaring both sides of an equation can introduce extraneous solutions that do not satisfy the original relation.
6
Use the valid solution to calculate the requested expression.
x+1=5+1=6x + 1 = 5 + 1 = 6
The question asks for the value of x+1x + 1.

Anahtar Kavram

Solving radical equations and identifying extraneous solutions
Soru 1819Soru

If 16x+12x3=64\frac{16^{x+1}}{2^{x-3}} = 64, what is the value of xx?

Cevabı ve açıklamayı göster

Cevap: 13-\frac{1}{3}

Cevap

13-\frac{1}{3}
The correct answer is 13-\frac{1}{3}. By expressing all terms with base 2, the equation 16x+12x3=64\frac{16^{x+1}}{2^{x-3}} = 64 becomes 24x+42x3=26\frac{2^{4x+4}}{2^{x-3}} = 2^6. Applying exponent division rules yields 2(4x+4)(x3)=262^{(4x+4)-(x-3)} = 2^6, which simplifies to 23x+7=262^{3x+7} = 2^6. Setting the exponents equal gives 3x+7=63x + 7 = 6, which simplifies to x=13x = -\frac{1}{3}.

Adım Adım Çözüm

1
Rewrite all terms in the equation using a common base of 2.
The equation becomes (24)x+12x3=26\frac{(2^4)^{x+1}}{2^{x-3}} = 2^6.
Expressing bases 16 and 64 as powers of 2 allows us to apply exponent laws to simplify the equation.
2
Apply the power of a power rule to the numerator, then apply the quotient rule for exponents.
The left side simplifies to 24x+4(x3)=23x+72^{4x+4 - (x-3)} = 2^{3x+7}.
The expression (24)x+1(2^4)^{x+1} becomes 24x+42^{4x+4}. Using the quotient rule aman=amn\frac{a^m}{a^n} = a^{m-n}, we subtract the denominator's exponent (x3)(x-3) from the numerator's exponent (4x+4)(4x+4), distributing the negative sign to get 3x+73x+7.
3
Set the exponents equal to each other and solve the resulting linear equation.
3x+7=6    3x=1    x=133x + 7 = 6 \implies 3x = -1 \implies x = -\frac{1}{3}.
Since the bases on both sides of the equation are equal, their exponents must be equal.

Anahtar Kavram

Solving exponential equations by rewriting with a common base
Tahmini Süre:1m 30s
Soru 1820Soru

A researcher is drying a sample of wet soil in a laboratory. Initially, water makes up 40%40\% of the total weight of the sample. During the first stage of drying, 25%25\% of the water in the sample evaporates. During the second stage of drying, an additional quantity of water evaporates such that the water in the sample now makes up 20%20\% of the sample's total weight. What percent of the water that remained after the first stage evaporated during the second stage?

Cevabı ve açıklamayı göster

Cevap: 50%50\%

Cevap

50%50\%
The correct answer is the option stating 50%50\%. After the first stage of drying, the sample contains 3030 grams of water and has a total weight of 9090 grams. In the second stage, 1515 grams of water evaporates, leaving 1515 grams of water and a total weight of 7575 grams. Since 1515 is exactly 20%20\% of 7575, the final condition is met. The 1515 grams of water that evaporated in the second stage represents exactly 50%50\% of the 3030 grams of water that remained after the first stage.

Adım Adım Çözüm

1
Define the initial weights using a convenient total weight.
Let the initial total weight of the wet soil sample be 100100 grams. Since water makes up 40%40\% of this weight, the initial water weight is 4040 grams and the dry soil weight is 6060 grams.
Choosing a concrete value of 100100 grams simplifies the percent calculations.
2
Calculate the water remaining after the first stage of drying.
In the first stage, 25%25\% of the water evaporates. The evaporated water is 0.25×40=100.25 \times 40 = 10 grams. The remaining water weight is 4010=3040 - 10 = 30 grams. The total weight of the sample is now 60 (dry soil)+30 (water)=9060 \text{ (dry soil)} + 30 \text{ (water)} = 90 grams.
We must establish the new baseline amount of water and total sample weight before the second drying stage.
3
Set up an equation for the second stage of drying.
Let xx be the weight of water in grams that evaporates during the second stage. The final water weight is 30x30 - x grams, and the final total weight of the sample is 90x90 - x grams. Since the final water weight is 20%20\% of the final total weight, we write: 30x90x=0.20\frac{30 - x}{90 - x} = 0.20.
This relates the unknown quantity of water evaporated to the given final water percentage.
4
Solve the equation for the evaporated water weight xx.
Multiplying both sides by 90x90 - x gives 30x=0.20(90x)30x=180.20x30 - x = 0.20(90 - x) \Rightarrow 30 - x = 18 - 0.20x. Rearranging terms yields 12=0.80x12 = 0.80x, which gives x=15x = 15 grams.
Solving the algebraic equation finds the exact amount of water that evaporated during the second stage.
5
Calculate the percent of the remaining water that evaporated.
Divide the water evaporated in the second stage (1515 grams) by the water remaining after the first stage (3030 grams): 1530×100%=50%\frac{15}{30} \times 100\% = 50\%.
This answers the specific question asked using the correct base weight.

Anahtar Kavram

Multi-step percent change with a shifting base

Alternatif Yöntem

Instead of assuming a weight of 100100 grams, the problem can be solved using variables. Let the initial total weight of the wet soil sample be WW. The initial water weight is 0.40W0.40W and the dry soil is 0.60W0.60W. After the first stage, remaining water is 0.75×0.40W=0.30W0.75 \times 0.40W = 0.30W, and total weight is 0.90W0.90W. Let EE be the water evaporated in the second stage. The final water content is 0.30WE0.30W - E, and the final total weight is 0.90WE0.90W - E. The equation is 0.30WE=0.20(0.90WE)0.30W - E = 0.20(0.90W - E), which solves to E=0.15WE = 0.15W. The ratio of evaporated water to remaining water is 0.15W0.30W=0.50\frac{0.15W}{0.30W} = 0.50, or 50%50\%.
Tahmini Süre:3m 0s
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Tüm alıştırma soruları — SAT | Examkin