Equivalent Algebraic Expressions Alıştırma Soruları — SAT — Sayfa 2

For all positive values of $x$ , which of the following expressions is equivalent to $(8x^6)^{\frac{1}{3}}$ ?

2x^3

\frac{8}{3}x^2

2x^2

8x^2

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Cevap: $2x^2$

Cevap

The expression

2x^2

To find an equivalent expression, apply the exponent of

\frac{1}{3}

to each factor inside the parentheses. The expression

(8x^6)^{\frac{1}{3}}

becomes

8^{\frac{1}{3}} \cdot (x^6)^{\frac{1}{3}}

. Since

8^{\frac{1}{3}} = \sqrt[3]{8} = 2

, and

(x^6)^{\frac{1}{3}} = x^{6 \cdot \frac{1}{3}} = x^2

, the simplified expression is

2x^2

.

Adım Adım Çözüm

1

Apply the power of a product rule,

(ab)^n = a^n b^n

, to distribute the exponent of

\frac{1}{3}

to both the coefficient and the variable term.

(8x^6)^{\frac{1}{3}} = 8^{\frac{1}{3}} \cdot (x^6)^{\frac{1}{3}}

This separates the numerical coefficient and the variable part to simplify them individually.

2

Simplify the numerical coefficient by evaluating the cube root of

8

.

8^{\frac{1}{3}} = 2

The exponent of

\frac{1}{3}

represents the cube root, and

2^3 = 8

.

3

Simplify the variable term using the power of a power rule,

(x^a)^b = x^{a \cdot b}

.

(x^6)^{\frac{1}{3}} = x^{6 \cdot \frac{1}{3}} = x^2

Multiplying the exponents simplifies the expression.

4

Multiply the simplified coefficient and variable term together.

2x^2

This gives the final simplified equivalent expression.

Anahtar Kavram

Simplifying algebraic expressions with fractional exponents using exponent rules.

Soru 22Soru →

For all real numbers $x$ and $y$ , the expression $(4x^3y^2)^2(2x^2y)$ is equivalent to which of the following?

8x^8y^5

32x^{12}y^4

32x^8y^5

32x^7y^5

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Cevap: $32x^8y^5$

Cevap

The correct equivalent expression is

32x^8y^5

.

To find the equivalent expression, we first apply the power of a product rule to the first term:

(4x^3y^2)^2 = 4^2(x^3)^2(y^2)^2 = 16x^6y^4

. Next, we multiply this result by the second term:

(16x^6y^4)(2x^2y)

. Multiplying the coefficients gives

16 \times 2 = 32

. Adding the exponents of the same base variables gives

x^{6+2} = x^8

and

y^{4+1} = y^5

. This results in

32x^8y^5

.

Adım Adım Çözüm

1

Apply the power of a product rule to square the first expression:

(4x^3y^2)^2

.

16x^6y^4

When raising a product to a power, raise each factor to that power:

4^2 = 16

,

(x^3)^2 = x^{3 \times 2} = x^6

, and

(y^2)^2 = y^{2 \times 2} = y^4

.

2

Multiply the simplified first expression by the second expression:

(16x^6y^4)(2x^2y)

.

32x^8y^5

Multiply the numerical coefficients (

16 \times 2 = 32

) and add the exponents of variables with matching bases (

x^{6+2} = x^8

and

y^{4+1} = y^5

).

Anahtar Kavram

Simplifying equivalent algebraic expressions using rules of exponents

Tahmini Süre:45s

Soru 23Soru →

If the expression $\frac{2x + 1}{x - 3} - \frac{x - 2}{x + 1}$ is rewritten in the equivalent form $a + \frac{bx + c}{x^2 - 2x - 3}$ for all $x > 3$ , where $a$ , $b$ , and $c$ are constants, what is the value of $a + b + c$ ?

-1

11

9

19

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Cevap: 9

Cevap

9

The correct answer is 9. Finding a common denominator yields the combined numerator

(2x + 1)(x + 1) - (x - 2)(x - 3)

. Expanding these terms gives

(2x^2 + 3x + 1) - (x^2 - 5x + 6) = x^2 + 8x - 5

. Dividing

x^2 + 8x - 5

by

x^2 - 2x - 3

results in a quotient of

1

and a remainder of

10x - 2

. Thus, the expression is equivalent to

1 + \frac{10x - 2}{x^2 - 2x - 3}

, which gives

a = 1

,

b = 10

, and

c = -2

. The sum

a + b + c = 1 + 10 - 2 = 9

.

Adım Adım Çözüm

1

Find a common denominator for the two rational expressions.

The common denominator is

(x - 3)(x + 1) = x^2 - 2x - 3

. The combined expression is

\frac{(2x + 1)(x + 1) - (x - 2)(x - 3)}{x^2 - 2x - 3}

.

To combine the fractions, we need to express them with a common denominator.

2

Expand and simplify the numerator.

(2x + 1)(x + 1) = 2x^2 + 3x + 1

and

(x - 2)(x - 3) = x^2 - 5x + 6

. Subtracting them gives

(2x^2 + 3x + 1) - (x^2 - 5x + 6) = x^2 + 8x - 5

.

Simplifying the numerator allows us to express the combined fraction as a single polynomial over the denominator.

3

Perform polynomial division or rewrite the numerator to match the form

a + \frac{bx + c}{x^2 - 2x - 3}

.

Rewriting the numerator:

x^2 + 8x - 5 = 1(x^2 - 2x - 3) + 10x - 2

. Thus, the expression becomes

1 + \frac{10x - 2}{x^2 - 2x - 3}

.

This separates the rational expression into a constant integer and a proper rational fraction.

4

Identify the values of

a

,

b

, and

c

, and find their sum.

a = 1

,

b = 10

, and

c = -2

. The sum is

a + b + c = 1 + 10 + (-2) = 9

.

We compare the coefficients from our result to the given form and calculate the requested sum.

Anahtar Kavram

Combining rational expressions and rewriting them using polynomial division or algebraic manipulation.

Tahmini Süre:2m 30s

Soru 24Soru →

If the expression $5(2x - 3) - 4(x - 2)$ is equivalent to $ax + b$ for all values of $x$ , where $a$ and $b$ are constants, what is the value of $a$ ?

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Cevap: 6

Cevap

The value of the constant coefficient is 6.

Expanding the expression

5(2x - 3) - 4(x - 2)

yields

10x - 15 - 4x + 8

. Combining the like terms results in

(10x - 4x) + (-15 + 8) = 6x - 7

. Comparing this to the expression

ax + b

, the constant coefficient

a

is equal to 6.

Adım Adım Çözüm

1

Distribute the multipliers to the terms inside the parentheses.

10x - 15 - 4x + 8

To remove the parentheses and prepare the expression for simplification, multiply each term inside

(2x - 3)

by

5

and each term inside

(x - 2)

by

-4

.

2

Combine the linear terms and the constant terms.

6x - 7

Combine the variable terms (

10x - 4x = 6x

) and the constants (

-15 + 8 = -7

) to rewrite the expression in its simplest form.

3

Compare the simplified expression to the form

ax + b

to identify the value of

a

.

a = 6

The coefficient of the variable

x

in

6x - 7

corresponds directly to

a

in

ax + b

.

Anahtar Kavram

Equivalent Algebraic Expressions

Soru 25Soru →

For all positive real numbers $x$ and $y$ , the expression $\frac{(x^{3} y^{2})^{2/3} \cdot (x^{-1} y^{4})^{1/6}}{(x^2 y)^{1/2}}$ can be written in the equivalent form $x^a y^b$ , where $a$ and $b$ are constants. What is the value of $6a + 2b$ ?

Cevabı ve açıklamayı göster

Cevap: 8

Cevap

The correct answer is 8.

Applying the rules of exponents systematically yields the simplified expression

x^{5/6} y^{3/2}

. By setting

a = \frac{5}{6}

and

b = \frac{3}{2}

, the linear combination

6a + 2b

evaluates to

6\left(\frac{5}{6}\right) + 2\left(\frac{3}{2}\right) = 5 + 3 = 8

.

Adım Adım Çözüm

1

Apply the power of a power rule to the first term in the numerator.

(x^3 y^2)^{2/3} = x^{3 \cdot \frac{2}{3}} y^{2 \cdot \frac{2}{3}} = x^2 y^{4/3}

To raise a product to a power, raise each factor to that power by multiplying their exponents.

2

Apply the power of a power rule to the second term in the numerator.

(x^{-1} y^4)^{1/6} = x^{-1 \cdot \frac{1}{6}} y^{4 \cdot \frac{1}{6}} = x^{-1/6} y^{2/3}

To raise a product to a power, raise each factor to that power by multiplying their exponents.

3

Multiply the two simplified terms in the numerator.

(x^2 y^{4/3})(x^{-1/6} y^{2/3}) = x^{2 - \frac{1}{6}} y^{\frac{4}{3} + \frac{2}{3}} = x^{11/6} y^2

When multiplying expressions with the same base, add their exponents.

4

Simplify the denominator.

(x^2 y)^{1/2} = x^{2 \cdot \frac{1}{2}} y^{1 \cdot \frac{1}{2}} = x y^{1/2}

To raise a product to a power, raise each factor to that power by multiplying their exponents.

5

Divide the numerator by the denominator.

\frac{x^{11/6} y^2}{x y^{1/2}} = x^{\frac{11}{6} - 1} y^{2 - \frac{1}{2}} = x^{5/6} y^{3/2}

When dividing expressions with the same base, subtract the exponent of the denominator from the exponent of the numerator.

6

Identify the values of

a

and

b

and calculate

6a + 2b

.

a = \frac{5}{6}

,

b = \frac{3}{2}

, so

6a + 2b = 6\left(\frac{5}{6}\right) + 2\left(\frac{3}{2}\right) = 5 + 3 = 8

Matching the simplified expression

x^{5/6} y^{3/2}

to

x^a y^b

yields the values of the constants

a

and

b

, which are then used to calculate the required expression.

Anahtar Kavram

Simplifying rational expressions with fractional exponents using exponent rules.

Soru 26Soru →

If the expression $(x + 5)^2 - (x - 3)^2$ is equivalent to $ax + b$ for all values of $x$ , where $a$ and $b$ are constants, what is the value of $a$ ?

Cevabı ve açıklamayı göster

Cevap: 16

Cevap

16

Expanding

(x + 5)^2

gives

x^2 + 10x + 25

, and expanding

(x - 3)^2

gives

x^2 - 6x + 9

. Subtracting the second expression from the first requires distributing the negative sign across all terms:

x^2 + 10x + 25 - (x^2 - 6x + 9) = x^2 + 10x + 25 - x^2 + 6x - 9

. Combining like terms yields

16x + 16

. Comparing this to

ax + b

shows that the coefficient of

x

,

a

, is 16.

Adım Adım Çözüm

1

Expand the first squared binomial term

(x + 5)^2 = x^2 + 10x + 25

To express the binomial square as a trinomial using the perfect square identity

(u + v)^2 = u^2 + 2uv + v^2

.

2

Expand the second squared binomial term

(x - 3)^2 = x^2 - 6x + 9

To express the binomial square as a trinomial using the perfect square identity

(u - v)^2 = u^2 - 2uv + v^2

.

3

Subtract the expanded expressions and distribute the negative sign

x^2 + 10x + 25 - x^2 + 6x - 9

To combine the terms while correctly applying the distributive property to the subtracted expression.

4

Combine like terms to simplify the polynomial

16x + 16

To find the final simplified polynomial of the form

ax + b

.

5

Compare the simplified expression to the standard form to find the value of

a

a = 16

The constant

a

represents the coefficient of the linear term

x

, which is 16.

Anahtar Kavram

Simplifying algebraic expressions by expanding binomial products and combining like terms.

Soru 27Soru →

For all positive real numbers $a$ and $b$ such that $a \neq b$ , which of the following is equivalent to the expression $\frac{a^{3/2} - b^{3/2}}{\sqrt{a} - \sqrt{b}}$ ?

a + \sqrt{ab} + b

a + b

a - \sqrt{ab} + b

a + 2\sqrt{ab} + b

Cevabı ve açıklamayı göster

Cevap: $a + \sqrt{ab} + b$

Cevap

a + \sqrt{ab} + b

The correct answer is obtained by expressing the numerator as a difference of cubes:

(\sqrt{a})^3 - (\sqrt{b})^3

. Factoring this expression gives

(\sqrt{a} - \sqrt{b})(a + \sqrt{ab} + b)

. Since

a \neq b

, dividing by the denominator

\sqrt{a} - \sqrt{b}

simplifies the expression to

a + \sqrt{ab} + b

.

Adım Adım Çözüm

1

Rewrite the terms in the numerator using square roots to reveal a difference of cubes pattern.

a^{3/2} = (\sqrt{a})^3

and

b^{3/2} = (\sqrt{b})^3

, so the numerator is

(\sqrt{a})^3 - (\sqrt{b})^3

.

This allows us to factor the numerator using the algebraic identity for the difference of two cubes.

2

Factor the numerator using the difference of cubes formula:

u^3 - v^3 = (u - v)(u^2 + uv + v^2)

.

(\sqrt{a})^3 - (\sqrt{b})^3 = (\sqrt{a} - \sqrt{b})(a + \sqrt{ab} + b)

where

u = \sqrt{a}

and

v = \sqrt{b}

.

Factoring allows us to identify common factors shared with the denominator.

3

Substitute the factored expression back into the fraction and cancel the common factor of

\sqrt{a} - \sqrt{b}

.

\frac{(\sqrt{a} - \sqrt{b})(a + \sqrt{ab} + b)}{\sqrt{a} - \sqrt{b}} = a + \sqrt{ab} + b

.

Since

a \neq b

,

\sqrt{a} - \sqrt{b} \neq 0

, which makes it mathematically valid to divide by this term.

Anahtar Kavram

Equivalent algebraic expressions involving fractional exponents and difference of cubes factoring

Alternatif Yöntem

Let

a = 4

and

b = 1

. Substitute these values into the original expression:

\frac{4^{3/2} - 1^{3/2}}{\sqrt{4} - \sqrt{1}} = \frac{8 - 1}{2 - 1} = 7

. Now substitute these same values into each option to see which one evaluates to 7. The correct option evaluates to

4 + \sqrt{4(1)} + 1 = 7

.

Tahmini Süre:2m 0s

Soru 28Soru →

For all $x > 1$ , which of the following is equivalent to the expression $\frac{2x^2 - 5x - 3}{2x + 1} - (x - 4)$ ?

-7

2x - 7

1

7

Cevabı ve açıklamayı göster

Cevap: 1

Cevap

1

The correct answer is

1

. Factoring the numerator of the rational expression gives

2x^2 - 5x - 3 = (2x + 1)(x - 3)

. Since

x > 1

, the denominator

2x + 1

is non-zero, allowing the expression to be simplified to

x - 3

. Subtracting

(x - 4)

and distributing the negative sign to both terms inside the parentheses yields

(x - 3) - (x - 4) = x - 3 - x + 4 = 1

.

Adım Adım Çözüm

1

Factor the quadratic expression in the numerator of the rational term.

2x^2 - 5x - 3 = (2x + 1)(x - 3)

This allows for the identification of common factors that can be simplified with the denominator.

2

Simplify the rational expression by canceling the common factor in the numerator and denominator.

\frac{(2x + 1)(x - 3)}{2x + 1} = x - 3

Since

x > 1

, the term

2x + 1

is positive and non-zero, making the division valid.

3

Subtract the linear expression from the simplified rational expression, distributing the negative sign to both terms inside the parentheses.

(x - 3) - (x - 4) = x - 3 - x + 4 = 1

This performs the final subtraction and simplifies the expression to its equivalent constant form.

Anahtar Kavram

Simplifying rational expressions by factoring and performing operations on equivalent expressions

Tahmini Süre:1m 15s

Soru 29Soru →

If the expression $\frac{3x^2 + 10x - 8}{x + k}$ is equivalent to $3x - 2$ for all $x \neq -k$ , where $k$ is a positive constant, what is the value of $k$ ?

Cevabı ve açıklamayı göster

Cevap: 4

Cevap

The value of the constant

k

is 4.

For the expressions to be equivalent for all values of

x

, the numerator

3x^2 + 10x - 8

must be equal to the product of the denominator

x + k

and the simplified quotient

3x - 2

. Expanding the product yields

3x^2 + (3k - 2)x - 2k

. Equating the constant terms on both sides gives

-8 = -2k

, which results in

k = 4

. Alternatively, equating the coefficients of the linear terms gives

10 = 3k - 2

, which also yields

k = 4

.

Adım Adım Çözüm

1

Multiply both sides of the equivalence by the denominator

x + k

.

3x^2 + 10x - 8 = (3x - 2)(x + k)

To eliminate the fraction and set up a polynomial identity.

2

Expand the right side of the equation.

3x^2 + 10x - 8 = 3x^2 + (3k - 2)x - 2k

To express the right side in standard quadratic form for coefficient comparison.

3

Equate the constant terms to solve for

k

.

-8 = -2k \implies k = 4

Since the expressions are equivalent for all values of

x

, their corresponding coefficients and constants must be equal.

Anahtar Kavram

Equating coefficients of equivalent polynomial expressions

Soru 30Soru →

If the expression $\frac{4x^3 - 2x^2 + 7x + 7}{2x^2 + 1}$ is equivalent to $ax + b + \frac{cx + d}{2x^2 + 1}$ for all values of $x$ , where $a$ , $b$ , $c$ , and $d$ are constants, what is the value of $a + b + c + d$ ?

Cevabı ve açıklamayı göster

Cevap: 14

Cevap

The value of

a + b + c + d

is 14.

Performing polynomial long division on

\frac{4x^3 - 2x^2 + 7x + 7}{2x^2 + 1}

yields a quotient of

2x - 1

and a remainder of

5x + 8

. Matching this to the form

ax + b + \frac{cx + d}{2x^2 + 1}

gives

a = 2

,

b = -1

,

c = 5

, and

d = 8

. Summing these values gives

2 + (-1) + 5 + 8 = 14

.

Adım Adım Çözüm

1

Divide the leading term of the numerator by the leading term of the denominator to find the first term of the quotient.

\frac{4x^3}{2x^2} = 2x

. Multiplying

2x(2x^2 + 1) = 4x^3 + 2x

. Subtracting this from the numerator yields

-2x^2 + 5x + 7

.

To initiate the polynomial division process.

2

Divide the leading term of the remaining polynomial by the leading term of the divisor to find the second term of the quotient.

\frac{-2x^2}{2x^2} = -1

. Multiplying

-1(2x^2 + 1) = -2x^2 - 1

. Subtracting this from the remaining polynomial yields

5x + 8

.

To find the next term of the quotient and determine the remainder.

3

Write the expression in the quotient-remainder form and identify the values of the constants

a

,

b

,

c

, and

d

.

The expression is equivalent to

2x - 1 + \frac{5x + 8}{2x^2 + 1}

, so

a = 2

,

b = -1

,

c = 5

, and

d = 8

.

To match the given algebraic form of the expression.

4

Calculate the sum of the constants

a + b + c + d

.

2 + (-1) + 5 + 8 = 14

.

To find the final value requested by the question.

Anahtar Kavram

Equivalent Algebraic Expressions

Soru 31Soru →

For all $x > 8$ , the expression $\frac{x^{8/3} - 8x^{5/3}}{x^{4/3} - 4x^{2/3}} \cdot \frac{x^{1/3} + 2}{x^{4/3} + 2x + 4x^{2/3}}$ is equivalent to $x^a$ , where $a$ is a constant. What is the value of $\frac{1}{a}$ ?

Cevabı ve açıklamayı göster

Cevap: 3

Cevap

The correct answer is 3.

Factoring the numerator and denominator of the first fraction yields

\frac{x^{5/3}(x^{1/3}-2)(x^{2/3}+2x^{1/3}+4)}{x^{2/3}(x^{1/3}-2)(x^{1/3}+2)}

, which simplifies to

\frac{x(x^{2/3}+2x^{1/3}+4)}{x^{1/3}+2}

. Factoring the denominator of the second fraction yields

\frac{x^{1/3}+2}{x^{2/3}(x^{2/3}+2x^{1/3}+4)}

. Multiplying these two simplified expressions cancels the common terms

(x^{1/3}+2)

and

(x^{2/3}+2x^{1/3}+4)

, leaving

\frac{x}{x^{2/3}} = x^{1/3}

. Therefore,

a = \frac{1}{3}

, and the value of the reciprocal

\frac{1}{a}

is

3

.

Adım Adım Çözüm

1

Factor the numerator and the denominator of the first fraction.

The first fraction becomes

\frac{x(x^{2/3} + 2x^{1/3} + 4)}{x^{1/3} + 2}

.

Factoring out

x^{5/3}

from the numerator gives

x^{5/3}(x-8)

, and factoring out

x^{2/3}

from the denominator gives

x^{2/3}(x^{2/3}-4)

. Using the difference of cubes

x - 8 = (x^{1/3} - 2)(x^{2/3} + 2x^{1/3} + 4)

and the difference of squares

x^{2/3} - 4 = (x^{1/3} - 2)(x^{1/3} + 2)

, we can cancel the common factor

(x^{1/3} - 2)

.

2

Factor the denominator of the second fraction.

The second fraction becomes

\frac{x^{1/3} + 2}{x^{2/3}(x^{2/3} + 2x^{1/3} + 4)}

.

Factoring out

x^{2/3}

from the expression

x^{4/3} + 2x + 4x^{2/3}

reveals a common quadratic-like term

(x^{2/3} + 2x^{1/3} + 4)

that can be used for cancellation.

3

Multiply the two rational expressions together and simplify.

x^{1/3}

Multiplying the simplified fractions allows us to cancel the common binomial term

(x^{1/3} + 2)

and the trinomial term

(x^{2/3} + 2x^{1/3} + 4)

, leaving

\frac{x}{x^{2/3}} = x^{1 - 2/3} = x^{1/3}

.

4

Find the value of

\frac{1}{a}

.

3

Since the expression is equivalent to

x^a

, we identify

a = \frac{1}{3}

. Taking the reciprocal of

a

gives

\frac{1}{1/3} = 3

.

Anahtar Kavram

Equivalent Algebraic Expressions

Soru 32Soru →

The expression $(3x^2 + 5x) - (x^2 - kx)$ , where $k$ is a constant, can be rewritten as $2x^2 + 12x$ . What is the value of $k$ ?

Cevabı ve açıklamayı göster

Cevap: 7

Cevap

The value of

k

is

7

.

To find the value of

k

, we first simplify the expression

(3x^2 + 5x) - (x^2 - kx)

by distributing the subtraction sign to both terms inside the second set of parentheses. This yields

3x^2 + 5x - x^2 + kx

. Next, we group and combine like terms to get

(3x^2 - x^2) + (5x + kx) = 2x^2 + (5+k)x

. Since this expression is equivalent to

2x^2 + 12x

for all values of

x

, the coefficients of corresponding terms must be equal. Equating the coefficients of

x

gives

5+k = 12

. Subtracting 5 from both sides yields

k = 7

.

Adım Adım Çözüm

1

Distribute the negative sign to the terms in the second parentheses.

3x^2 + 5x - x^2 + kx

To remove the parentheses and simplify the expression.

2

Combine like terms.

2x^2 + (5 + k)x

Grouping the

x^2

terms and

x

terms simplifies comparison with the target expression.

3

Equate the coefficient of the

x

term to the corresponding coefficient in the target expression.

5 + k = 12 \implies k = 7

Equivalent expressions must have equal corresponding coefficients for all values of

x

.

Anahtar Kavram

Equivalence of polynomial expressions by combining like terms and equating coefficients

Soru 33Soru →

For all $x > 1$ , which of the following is equivalent to the expression $\frac{x^2 - \sqrt{x}}{x - \sqrt{x}} - \sqrt{x}$ ?

x - 2\sqrt{x} + 1

x - \sqrt{x} - 1

x + 1

x - 1

Cevabı ve açıklamayı göster

Cevap: $x + 1$

Cevap

The expression is equivalent to

x + 1

.

The expression can be simplified by substituting

u = \sqrt{x}

, which gives

x = u^2

and

x^2 = u^4

. Substituting these into the original expression yields

\frac{u^4 - u}{u^2 - u} - u

. Factoring out

u

from the numerator and denominator gives

\frac{u(u^3 - 1)}{u(u - 1)} - u = \frac{u^3 - 1}{u - 1} - u

. Factoring the difference of cubes in the numerator as

(u - 1)(u^2 + u + 1)

and canceling the common factor of

u - 1

leaves

u^2 + u + 1 - u = u^2 + 1

. Substituting back

x = u^2

yields the equivalent expression

x + 1

.

Adım Adım Çözüm

1

Substitute

u = \sqrt{x}

into the expression, which implies

x = u^2

and

x^2 = u^4

.

The expression becomes

\frac{u^4 - u}{u^2 - u} - u

.

Using a substitution simplifies the fractional exponents and makes the polynomial structure easier to recognize.

2

Factor out

u

from both the numerator and the denominator of the fraction.

\frac{u(u^3 - 1)}{u(u - 1)} - u = \frac{u^3 - 1}{u - 1} - u

.

Since

x > 1

, we have

u > 1

, which means

u \neq 0

. Therefore, we can cancel the common factor

u

from the numerator and denominator.

3

Factor the difference of cubes in the numerator:

u^3 - 1 = (u - 1)(u^2 + u + 1)

.

\frac{(u - 1)(u^2 + u + 1)}{u - 1} - u

.

Factoring the numerator allows us to simplify the rational expression by canceling the common binomial factor in the denominator.

4

Cancel the common factor

u - 1

and simplify the remaining terms.

(u^2 + u + 1) - u = u^2 + 1

.

Since

u > 1

, we have

u - 1 \neq 0

, allowing us to divide out

u - 1

. Subtracting

u

from

u^2 + u + 1

leaves

u^2 + 1

.

5

Substitute

x

back in place of

u^2

.

x + 1

.

Converting the simplified expression back to the original variable gives the final equivalent algebraic expression.

Anahtar Kavram

Simplifying rational expressions with fractional exponents by substitution and factoring.

Soru 34Soru →

For all $x > 4$ , the expression $\frac{x^2 - 4x}{x - 2\sqrt{x}} + \frac{x\sqrt{x} + 8}{\sqrt{x} + 2}$ can be written in the form $ax + b$ , where $a$ and $b$ are constants. What is the value of $a + b$ ?

Cevabı ve açıklamayı göster

Cevap: 6

Cevap

6

Factoring the numerator of the first term yields

x(\sqrt{x}-2)(\sqrt{x}+2)

and its denominator yields

\sqrt{x}(\sqrt{x}-2)

. Simplifying this term gives

x + 2\sqrt{x}

. Factoring the numerator of the second term as a sum of cubes gives

(\sqrt{x}+2)(x - 2\sqrt{x} + 4)

, which simplifies to

x - 2\sqrt{x} + 4

. Summing both simplified terms results in

2x + 4

. Matching this to the form

ax+b

gives

a=2

and

b=4

, so

a+b=6

.

Adım Adım Çözüm

1

Simplify the first term of the expression.

\frac{x^2 - 4x}{x - 2\sqrt{x}} = x + 2\sqrt{x}

Factor

x

from the numerator to get

x(x-4)

and

\sqrt{x}

from the denominator to get

\sqrt{x}(\sqrt{x}-2)

. Rewrite

x-4

as the difference of squares

(\sqrt{x}-2)(\sqrt{x}+2)

, then cancel the common factor

\sqrt{x}-2

and simplify

\frac{x}{\sqrt{x}}

to

\sqrt{x}

.

2

Simplify the second term of the expression.

\frac{x\sqrt{x} + 8}{\sqrt{x} + 2} = x - 2\sqrt{x} + 4

Recognize

x\sqrt{x} + 8

as a sum of cubes,

(\sqrt{x})^3 + 2^3

. Factor it as

(\sqrt{x}+2)(x - 2\sqrt{x} + 4)

and cancel the common factor of

\sqrt{x}+2

in the denominator.

3

Add the simplified terms together.

2x + 4

Combine

(x + 2\sqrt{x})

and

(x - 2\sqrt{x} + 4)

by grouping like terms: the

2\sqrt{x}

and

-2\sqrt{x}

cancel out, leaving

2x + 4

.

4

Identify the values of

a

and

b

and find

a+b

.

6

Comparing

2x + 4

to

ax + b

gives

a = 2

and

b = 4

. Therefore,

a + b = 2 + 4 = 6

.

Anahtar Kavram

Simplifying rational expressions involving radicals by factoring (difference of squares and sum of cubes).

Soru 35Soru →

For all $x > 1$ , which of the following is equivalent to the expression $\frac{4x^2 - 1}{2x - 1} - \frac{6x^2 + x - 2}{3x + 2}$ ?

0

2

-2

4x

Cevabı ve açıklamayı göster

Cevap: 2

Cevap

2

Factoring the numerators allows the expression to be simplified. The first term becomes

2x + 1

, and the second term becomes

2x - 1

. Subtracting the second term from the first and distributing the negative sign results in

(2x + 1) - (2x - 1) = 2x + 1 - 2x + 1 = 2

.

Adım Adım Çözüm

1

Factor the numerator of the first rational term,

4x^2 - 1

, using the difference of squares identity.

4x^2 - 1 = (2x - 1)(2x + 1)

To identify and divide out common factors between the numerator and denominator.

2

Simplify the first term by dividing the factored numerator by its denominator,

2x - 1

.

\frac{(2x - 1)(2x + 1)}{2x - 1} = 2x + 1

Since

x > 1

,

2x - 1 \neq 0

, allowing the division.

3

Factor the numerator of the second rational term,

6x^2 + x - 2

.

6x^2 + x - 2 = (2x - 1)(3x + 2)

To find common factors that can be simplified with the denominator.

4

Simplify the second term by dividing the factored numerator by its denominator,

3x + 2

.

\frac{(2x - 1)(3x + 2)}{3x + 2} = 2x - 1

Since

x > 1

,

3x + 2 \neq 0

, allowing the division.

5

Subtract the second simplified expression from the first, ensuring that the negative sign is correctly distributed to all terms.

(2x + 1) - (2x - 1) = 2x + 1 - 2x + 1 = 2

To combine the terms and find the final equivalent value of the entire expression.

Anahtar Kavram

Equivalent Algebraic Expressions

Soru 36Soru →

For all $x \neq -2.5$ , the expression $\frac{6x^2 + 17x + 8}{2x + 5}$ is equivalent to $3x + 1 + \frac{a}{2x + 5}$ , where $a$ is a constant. What is the value of $a$ ?

Cevabı ve açıklamayı göster

Cevap: 3

Cevap

The value of

a

is

3

.

Multiplying both sides of the equivalent relation by

2x + 5

yields

6x^2 + 17x + 8 = (3x + 1)(2x + 5) + a

. Expanding the right side gives

6x^2 + 17x + 5 + a

. Since the expressions are equivalent, the constant terms must be equal:

8 = 5 + a

, which simplifies to

a = 3

.

Adım Adım Çözüm

1

Multiply both sides of the equation by

2x + 5

to clear the denominators.

6x^2 + 17x + 8 = (3x + 1)(2x + 5) + a

This clears the rational expressions so we can work with polynomials directly.

2

Expand the expression

(3x + 1)(2x + 5)

using the distributive property.

6x^2 + 17x + 8 = 6x^2 + 15x + 2x + 5 + a

To write the right side as a polynomial in standard form.

3

Combine like terms on the right side of the equation.

6x^2 + 17x + 8 = 6x^2 + 17x + (5 + a)

To group coefficients of like powers of

x

for easy comparison.

4

Equate the constant terms from both sides of the equation to solve for

a

.

8 = 5 + a

, which gives

a = 3

.

For the two polynomial expressions to be equivalent for all values of

x

, their corresponding coefficients and constants must be equal.

Anahtar Kavram

Rewriting rational expressions by clearing denominators or polynomial long division to find equivalent expressions.

Soru 37Soru →

If the expression $\frac{10x^2 + x - 3}{2x - 1}$ is equivalent to $ax + b$ for all $x \neq 0.5$ , where $a$ and $b$ are constants, what is the value of $a + b$ ?

Cevabı ve açıklamayı göster

Cevap: 8

Cevap

The value of

a + b

is 8.

To find the equivalent expression, factor the numerator:

10x^2 + x - 3 = (2x - 1)(5x + 3)

. For all

x \neq 0.5

, the denominator

2x - 1

is non-zero, so we can divide out the common factor

(2x - 1)

to get

5x + 3

. Matching

5x + 3

with

ax + b

gives

a = 5

and

b = 3

. The sum of these constants is

5 + 3 = 8

.

Adım Adım Çözüm

1

Factor the numerator of the expression

10x^2 + x - 3 = (2x - 1)(5x + 3)

Factoring the quadratic trinomial allows us to identify common factors that can be simplified.

2

Simplify the rational expression

\frac{(2x - 1)(5x + 3)}{2x - 1} = 5x + 3

(for

x \neq 0.5

)

Since

x \neq 0.5

, the term

2x - 1

is non-zero and can be canceled from both the numerator and the denominator.

3

Identify the values of

a

and

b

a = 5

and

b = 3

By comparing the simplified expression

5x + 3

to the form

ax + b

, the coefficients of corresponding terms must be equal.

4

Calculate the sum of

a

and

b

5 + 3 = 8

The question asks for the sum of the constants

a

and

b

.

Anahtar Kavram

Simplifying rational expressions by factoring and coefficient matching

Soru 38Soru →

For $x > 1$ , which of the following expressions is equivalent to $\frac{x - x^{-1}}{x^{1/2} - x^{-1/2}}$ ?

x^{1/2} - x^{-1/2}

x + 1

x^{1/2} + x^{-1/2}

x^{3/2} + x^{1/2}

Cevabı ve açıklamayı göster

Cevap: $x^{1/2} + x^{-1/2}$

Cevap

x^{1/2} + x^{-1/2}

The expression

x^{1/2} + x^{-1/2}

is correct because the numerator

x - x^{-1}

can be factored using the difference of squares identity,

a^2 - b^2 = (a - b)(a + b)

, where

a = x^{1/2}

and

b = x^{-1/2}

. This yields

x - x^{-1} = (x^{1/2} - x^{-1/2})(x^{1/2} + x^{-1/2})

. Substituting this back into the original fraction and canceling the common factor of

x^{1/2} - x^{-1/2}

in both the numerator and denominator simplifies the expression directly to

x^{1/2} + x^{-1/2}

.

Adım Adım Çözüm

1

Recognize the numerator

x - x^{-1}

as a difference of squares in terms of the base variables

x^{1/2}

and

x^{-1/2}

.

Write

x - x^{-1}

as

(x^{1/2})^2 - (x^{-1/2})^2 = (x^{1/2} - x^{-1/2})(x^{1/2} + x^{-1/2})

.

Since the denominator is

x^{1/2} - x^{-1/2}

, factoring the numerator as a difference of squares allows us to identify a common factor that can be canceled.

2

Substitute the factored numerator back into the original expression and cancel the common factor of

x^{1/2} - x^{-1/2}

from the numerator and the denominator.

\frac{(x^{1/2} - x^{-1/2})(x^{1/2} + x^{-1/2})}{x^{1/2} - x^{-1/2}} = x^{1/2} + x^{-1/2}

For all

x > 1

, the term

x^{1/2} - x^{-1/2}

is non-zero, so we can divide both the numerator and the denominator by this common term to simplify the expression.

Anahtar Kavram

Factoring algebraic expressions using the difference of squares identity with fractional exponents.

Alternatif Yöntem

Convert the fractional and negative exponents into standard algebraic fractions:

\frac{x - \frac{1}{x}}{\sqrt{x} - \frac{1}{\sqrt{x}}}

. Find common denominators for both the numerator and denominator to write the expression as

\frac{\frac{x^2 - 1}{x}}{\frac{x - 1}{\sqrt{x}}}

. Next, multiply the numerator by the reciprocal of the denominator:

\frac{(x - 1)(x + 1)}{x} \cdot \frac{\sqrt{x}}{x - 1}

. Cancel the common factor of

x - 1

to get

\frac{(x + 1)\sqrt{x}}{x}

. Distributing

\sqrt{x}

and dividing each term by

x

gives

\frac{x\sqrt{x}}{x} + \frac{\sqrt{x}}{x} = \sqrt{x} + \frac{1}{\sqrt{x}}

, which is equivalent to

x^{1/2} + x^{-1/2}

.

Tahmini Süre:1m 30s

Soru 39Soru →

If the expression $\frac{4x^2 + kx - 7}{2x - 1}$ is equivalent to $2x + 5 - \frac{2}{2x - 1}$ for all $x \neq \frac{1}{2}$ , where $k$ is a constant, what is the value of $k$ ?

Cevabı ve açıklamayı göster

Cevap: 8

Cevap

8

The correct answer is 8. Combining the expression

2x + 5 - \frac{2}{2x - 1}

into a single fraction requires finding a common denominator of

2x - 1

. Multiplying the linear term

2x + 5

by

\frac{2x - 1}{2x - 1}

and subtracting 2 yields

\frac{(2x + 5)(2x - 1) - 2}{2x - 1}

. Expanding and simplifying the numerator gives

4x^2 + 8x - 7

. Equating this to the numerator of the original expression,

4x^2 + kx - 7

, shows that the coefficient of the linear term,

k

, must be equal to 8.

Adım Adım Çözüm

1

Multiply the linear expression by the denominator to prepare for combining the terms.

(2x + 5)(2x - 1) = 4x^2 + 8x - 5

To combine all terms under a single common denominator of

2x - 1

, the non-fractional terms must be multiplied by the denominator.

2

Subtract the numerator of the fractional term from the expanded product.

(4x^2 + 8x - 5) - 2 = 4x^2 + 8x - 7

This completes the subtraction of the fraction over the common denominator, resulting in a single rational expression.

3

Compare the resulting numerator to the numerator of the original expression to find the value of the constant.

k = 8

For the two rational expressions to be equivalent, their numerators must be equal for all values of

x

. Thus, the coefficient of

x

in both expressions must match.

Anahtar Kavram

Equivalence of rational expressions through finding a common denominator

Soru 40Soru →

For all $x > 0$ , which of the following expressions is equivalent to $\frac{x^2 - 8}{x^{4/3} + 2x^{2/3} + 4} + \frac{x - 4x^{1/3}}{x^{2/3} + 2x^{1/3}}$ ?

x^{2/3} + x^{1/3} + 4

x^{4/3} + x^{2/3} - 4

x^{2/3} + x^{1/3} - 4

x^{2/3} + x^{1/3} - 6

Cevabı ve açıklamayı göster

Cevap: $x^{2/3} + x^{1/3} - 4$

Cevap

The expression

x^{2/3} + x^{1/3} - 4

The correct answer shows the sum of the simplified terms, which is

x^{2/3} + x^{1/3} - 4

. First, the numerator of the first term,

x^2 - 8

, can be written as a difference of cubes:

(x^{2/3})^3 - 2^3 = (x^{2/3} - 2)(x^{4/3} + 2x^{2/3} + 4)

. Dividing by the denominator leaves

x^{2/3} - 2

. Second, the second term can be factored by extracting

x^{1/3}

from both the numerator and denominator, leaving

\frac{x^{2/3} - 4}{x^{1/3} + 2}

. Factoring the numerator as a difference of squares,

(x^{1/3} - 2)(x^{1/3} + 2)

, and dividing by the denominator leaves

x^{1/3} - 2

. Adding the two simplified parts,

(x^{2/3} - 2) + (x^{1/3} - 2)

, gives

x^{2/3} + x^{1/3} - 4

.

Adım Adım Çözüm

1

Simplify the first term,

\frac{x^2 - 8}{x^{4/3} + 2x^{2/3} + 4}

x^{2/3} - 2

Rewrite

x^2 - 8

as

(x^{2/3})^3 - 2^3

and expand using the difference of cubes identity:

a^3 - b^3 = (a - b)(a^2 + ab + b^2)

, where

a = x^{2/3}

and

b = 2

. The term

x^{4/3} + 2x^{2/3} + 4

in the numerator and denominator cancels out.

2

Simplify the second term,

\frac{x - 4x^{1/3}}{x^{2/3} + 2x^{1/3}}

x^{1/3} - 2

Factor out

x^{1/3}

from both the numerator and denominator to get

\frac{x^{2/3} - 4}{x^{1/3} + 2}

. Then rewrite

x^{2/3} - 4

as

(x^{1/3})^2 - 2^2

and expand using the difference of squares identity:

a^2 - b^2 = (a - b)(a + b)

, where

a = x^{1/3}

and

b = 2

. The term

x^{1/3} + 2

in the numerator and denominator cancels out.

3

Sum the two simplified terms

x^{2/3} + x^{1/3} - 4

Add the two simplified expressions:

(x^{2/3} - 2) + (x^{1/3} - 2) = x^{2/3} + x^{1/3} - 4

.

Anahtar Kavram

Simplification of rational expressions involving fractional exponents, difference of cubes, and difference of squares.

Tahmini Süre:2m 0s

Equivalent Algebraic Expressions

Cevap

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Anahtar Kavram

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Alternatif Yöntem

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Alternatif Yöntem

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