Algebra

432 soru

Soru 101Soru

If the equations x+2y=12x + 2y = 12 and x+y=7x + y = 7 are true for the same values of xx and yy, what is the value of yy?

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Cevap: 5

Cevap

The value of yy is 5.
Subtracting the equation x+y=7x + y = 7 from x+2y=12x + 2y = 12 gives (xx)+(2yy)=127(x - x) + (2y - y) = 12 - 7, which simplifies directly to y=5y = 5.

Adım Adım Çözüm

1
Subtract the second equation from the first equation.
y=5y = 5
Subtracting x+y=7x + y = 7 from x+2y=12x + 2y = 12 eliminates the xx terms, leaving a single linear equation in terms of yy.

Anahtar Kavram

Solving systems of linear equations using elimination.
Soru 102Soru

In the xyxy-plane, the graph of the linear function ff passes through the point (6,4)(6, 4). Line gg is perpendicular to the graph of ff and has a yy-intercept of (0,12)(0, 12). The graph of ff and line gg intersect at the point P(h,k)P(h, k), where hh and kk are integers. If the slope of the graph of ff is a positive integer greater than 55, what is the value of kk?

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Cevap: 11

Cevap

The value of kk is 1111.
By equating the linear equations representing ff and gg, we find that the intersection point's xx-coordinate hh is given by h=6+8m6m2+1h = 6 + \frac{8m - 6}{m^2 + 1}. Since hh is an integer and mm is a positive integer greater than 55, the inequality m2+18m6m^2 + 1 \le 8m - 6 limits mm to the range 1m71 \le m \le 7. Testing the integers greater than 55 (which are 66 and 77) reveals that only m=7m = 7 yields an integer value for hh, resulting in h=7h = 7. Substituting these values back into the equation of either line yields k=11k = 11.

Adım Adım Çözüm

1
Write the equation of the linear function ff in terms of its slope mm.
y4=m(x6)    y=mx+46my - 4 = m(x - 6) \implies y = mx + 4 - 6m
Since the graph of ff passes through the point (6,4)(6, 4) with slope mm, we can use the point-slope form of a linear equation.
2
Write the equation of line gg in slope-intercept form.
y=1mx+12y = -\frac{1}{m}x + 12
Line gg is perpendicular to the graph of ff, so its slope is the negative reciprocal of mm, which is 1m-\frac{1}{m}. Its yy-intercept is (0,12)(0, 12).
3
Equate the two equations to find the xx-coordinate hh of the intersection point P(h,k)P(h, k) in terms of mm.
h=6m2+8mm2+1h = \frac{6m^2 + 8m}{m^2 + 1}
At the intersection point, the yy-values of both equations are equal, so we solve mx+46m=1mx+12mx + 4 - 6m = -\frac{1}{m}x + 12 for xx.
4
Analyze the expression for hh to find the integer constraints on mm.
h=6+8m6m2+1    m28m+70    1m7h = 6 + \frac{8m - 6}{m^2 + 1} \implies m^2 - 8m + 7 \le 0 \implies 1 \le m \le 7
For hh to be an integer, 8m6m2+1\frac{8m - 6}{m^2 + 1} must be an integer. Since mm is a positive integer greater than 55, the numerator is positive, meaning the denominator m2+1m^2 + 1 must be less than or equal to the numerator 8m68m - 6.
5
Test the possible integer values of mm greater than 55 to find the one that yields integer coordinates.
m=7    h=7m = 7 \implies h = 7
The only integers greater than 55 in the range [1,7][1, 7] are 66 and 77. Testing m=6m=6 gives a non-integer, while m=7m=7 gives h=7h = 7, which is an integer.
6
Calculate the yy-coordinate kk of the intersection point PP.
k=11k = 11
Substitute h=7h = 7 into the equation of line gg: k=17(7)+12=11k = -\frac{1}{7}(7) + 12 = 11.

Anahtar Kavram

Linear Functions and Graphs
Soru 103Soru

In the xyxy-plane, the graph of the linear function ff has a slope of mm and a yy-intercept of (0,b)(0, b). The graph of the linear function gg has a slope of 3m-3m and a yy-intercept of (0,b+15)(0, b + 15). If the graphs of ff and gg intersect at the point (3,5)(3, 5), what is the value of f(5)f(5)?

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Cevap: 7.5

Cevap

7.5 (or 15/2)
By writing the equations of the two lines as f(x)=mx+bf(x) = mx + b and g(x)=3mx+b+15g(x) = -3mx + b + 15, and substituting the intersection point (3,5)(3, 5), we get the system of equations 3m+b=53m + b = 5 and 9m+b=10-9m + b = -10. Subtracting these equations gives 12m=1512m = 15, which simplifies to m=1.25m = 1.25. Substituting mm back into 3m+b=53m + b = 5 yields b=1.25b = 1.25. The function is therefore f(x)=1.25x+1.25f(x) = 1.25x + 1.25. Evaluating this at x=5x = 5 gives f(5)=1.25(5)+1.25=7.5f(5) = 1.25(5) + 1.25 = 7.5.

Adım Adım Çözüm

1
Formulate equations for both linear functions using slope-intercept form.
f(x)=mx+bf(x) = mx + b and g(x)=3mx+b+15g(x) = -3mx + b + 15
The equation of a line with slope MM and yy-intercept (0,B)(0, B) is given by y=Mx+By = Mx + B.
2
Substitute the coordinates of the intersection point (3,5)(3, 5) into both equations.
3m+b=53m + b = 5 and 9m+b=10-9m + b = -10
Since the intersection point lies on both lines, its coordinates must satisfy both equations.
3
Solve the system of equations for mm and bb.
m=1.25m = 1.25 and b=1.25b = 1.25
Subtracting the equations eliminates bb, giving 12m=15    m=1.2512m = 15 \implies m = 1.25. Substituting this back into the first equation gives 3(1.25)+b=5    b=1.253(1.25) + b = 5 \implies b = 1.25.
4
Evaluate f(5)f(5) using the found values.
f(5)=1.25(5)+1.25=7.5f(5) = 1.25(5) + 1.25 = 7.5
Substitute x=5x = 5 into the equation f(x)=1.25x+1.25f(x) = 1.25x + 1.25.

Anahtar Kavram

Solving systems of linear equations and evaluating linear functions from graph intersections.
Tahmini Süre:2m 0s
Soru 104Soru

In the xyxy-plane, a line passes through the origin and has a slope of 35\frac{3}{5}. If the point (k,9)(k, 9) lies on the line, what is the value of kk?

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Cevap: 15

Cevap

15
A line passing through the origin has a yy-intercept of 00. Thus, its equation in slope-intercept form is y=mxy = mx, where mm is the slope. Given the slope is 35\frac{3}{5}, the equation is y=35xy = \frac{3}{5}x. Since the point (k,9)(k, 9) lies on the line, substituting these coordinates yields 9=35k9 = \frac{3}{5}k. Multiplying both sides by 53\frac{5}{3} gives k=15k = 15.

Adım Adım Çözüm

1
Write the equation of the line in slope-intercept form.
y=35xy = \frac{3}{5}x
The line passes through the origin (0,0)(0,0), so the yy-intercept is 00, and the slope is 35\frac{3}{5}.
2
Substitute the coordinates of the point (k,9)(k, 9) into the line's equation.
9=35k9 = \frac{3}{5}k
A point lies on a line if its coordinates satisfy the equation of the line.
3
Solve the equation for kk.
k=15k = 15
Multiply both sides of the equation by 53\frac{5}{3} to isolate kk.

Anahtar Kavram

Using the slope and a point on a line to determine an unknown coordinate.
Soru 105Soru

A system of two linear equations is given below.

y=x2y = x - 2
2x3y=12x - 3y = 1

If (x,y)(x, y) is the solution to the system of equations, what is the value of xx?

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Cevap: 5

Cevap

The value of xx is 5.
To find the value of xx, substitute the expression for yy from the first equation into the second equation: 2x3(x2)=12x - 3(x - 2) = 1. Distribute the 3-3 to obtain 2x3x+6=12x - 3x + 6 = 1, which simplifies to x+6=1-x + 6 = 1. Subtracting 6 from both sides gives x=5-x = -5. Multiplying or dividing both sides by 1-1 yields x=5x = 5.

Adım Adım Çözüm

1
Substitute the expression for yy from the first equation into the second equation.
2x3(x2)=12x - 3(x - 2) = 1
Substituting the expression reduces the system of two equations to one linear equation containing only the variable xx.
2
Distribute the coefficient 3-3 to both terms inside the parentheses.
2x3x+6=12x - 3x + 6 = 1
Applying the distributive property removes the parentheses so that like terms can be combined.
3
Combine like terms and isolate xx.
x+6=1    x=5    x=5-x + 6 = 1 \implies -x = -5 \implies x = 5
Combining the xx terms and subtracting 6 from both sides isolates x-x, allowing you to find the final value of xx.

Anahtar Kavram

Solving systems of linear equations using the substitution method

Alternatif Yöntem

Alternatively, you can solve this system using elimination. First, rewrite the first equation in standard form by subtracting xx from both sides, which gives x+y=2-x + y = -2. Next, multiply this equation by 3 to align coefficients: 3x+3y=6-3x + 3y = -6. Adding this result directly to the second equation, 2x3y=12x - 3y = 1, eliminates the yy terms and leaves x=5-x = -5, which simplifies to x=5x = 5.
Tahmini Süre:45s
Soru 106Soru

In the equation below, aa is a constant.

4(x2)a(32x)=8x54(x - 2) - a(3 - 2x) = 8x - 5

If the equation has no solution for xx, what is the value of aa?

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Cevap: 2

Cevap

2
For the linear equation to have no solution, the coefficients of the xx terms on both sides of the equation must be equal, while the constant terms must be different. First, expand the left side of the equation: 4(x2)a(32x)=4x83a+2ax4(x - 2) - a(3 - 2x) = 4x - 8 - 3a + 2ax. Grouping the xx terms and constant terms gives (4+2a)x(8+3a)=8x5(4 + 2a)x - (8 + 3a) = 8x - 5. Setting the coefficient of xx on the left side equal to the coefficient of xx on the right side gives 4+2a=84 + 2a = 8. Solving for aa yields 2a=42a = 4, which simplifies to a=2a = 2. Substituting a=2a = 2 back into the equation yields 8x14=8x58x - 14 = 8x - 5, or 14=5-14 = -5, which is a false statement with no solution. Therefore, the value of aa is 22.

Adım Adım Çözüm

1
Expand and simplify the left side of the equation.
The left side expands to 4x83a+2ax4x - 8 - 3a + 2ax. Grouping the terms by the variable xx gives (4+2a)x(8+3a)(4 + 2a)x - (8 + 3a).
To find when the linear equation has no solution, we need to rewrite it in the standard form px+q=rx+spx + q = rx + s by distributing terms and grouping like terms.
2
Equate the coefficients of the xx terms from both sides of the equation.
4+2a=84 + 2a = 8
A linear equation of the form px+q=rx+spx + q = rx + s has no solution if the coefficients of the variable are equal (p=rp = r) but the constants are not (qsq \neq s).
3
Solve for the constant aa.
2a=4    a=22a = 4 \implies a = 2
Subtracting 44 from both sides of 4+2a=84 + 2a = 8 isolates the variable term, and dividing by 22 gives the value of aa.
4
Verify that the constants are different when a=2a = 2.
Substituting a=2a = 2 back into the constant terms yields a left-side constant of (8+3(2))=14-(8 + 3(2)) = -14 and a right-side constant of 5-5. Since 145-14 \neq -5, the equation has no solution.
If the constant terms were also equal, the equation would have infinitely many solutions instead of no solution.

Anahtar Kavram

Linear Equations in One Variable (No Solution Case)
Soru 107Soru

A system of equations is shown below.

y=2(x5)y = -2(x - 5)
3x+y=133x + y = 13

What is the value of xx?

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Cevap: 3

Cevap

The value of xx is 33.
Substituting the expression for yy from the first equation into the second equation gives 3x2(x5)=133x - 2(x - 5) = 13. Distributing the 2-2 yields 3x2x+10=133x - 2x + 10 = 13. Combining the xx terms gives x+10=13x + 10 = 13. Subtracting 10 from both sides of the equation yields x=3x = 3.

Adım Adım Çözüm

1
Substitute the expression for yy from the first equation into the second equation.
3x2(x5)=133x - 2(x - 5) = 13
This substitution reduces the system to a single linear equation in terms of xx.
2
Apply the distributive property to simplify the equation.
3x2x+10=133x - 2x + 10 = 13
Multiplying 2-2 by xx gives 2x-2x, and multiplying 2-2 by 5-5 gives +10+10.
3
Combine like terms and isolate xx.
x+10=13x + 10 = 13, which simplifies to x=3x = 3
Subtracting 10 from both sides gives the value of xx.

Anahtar Kavram

Solving a system of linear equations using substitution.
Tahmini Süre:1m 0s
Soru 108Soru

A line in the coordinate plane is defined by the function f(x)=px+qf(x) = px + q, where pp and qq are constants. This line contains the point (6,2)(6, 2) and intersects the vertical axis at a point with a negative yy-coordinate. If the region bounded by the line and the two coordinate axes is a right triangle with an area of 2525, what is the value of pp?

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Cevap: 2

Cevap

2
The correct answer is the option representing the value 22. Substituting the point (6,2)(6, 2) into the linear function gives q=26pq = 2 - 6p. The area of the right triangle formed by the intercepts and the origin is given by 12×base×height=q22p\frac{1}{2} \times |\text{base}| \times |\text{height}| = \frac{q^2}{2p}. Setting this equal to 2525 leads to the quadratic equation 18p237p+2=018p^2 - 37p + 2 = 0. Factoring this equation yields p=2p = 2 or p=118p = \frac{1}{18}. Checking the yy-intercept condition (q<0q < 0) shows that only p=2p = 2 yields a negative yy-intercept (q=10q = -10), whereas p=118p = \frac{1}{18} yields a positive yy-intercept (q=53q = \frac{5}{3}).

Adım Adım Çözüm

1
Use the point (6,2)(6, 2) to express qq in terms of pp.
q=26pq = 2 - 6p
Since the line contains (6,2)(6, 2), substituting x=6x = 6 and f(x)=2f(x) = 2 into the function f(x)=px+qf(x) = px + q must satisfy the equation.
2
Determine the intercepts of the line on the coordinate axes.
The vertical intercept is (0,q)(0, q) and the horizontal intercept is (qp,0)\left(-\frac{q}{p}, 0\right).
The vertical intercept is found by setting x=0x = 0, and the horizontal intercept is found by setting f(x)=0f(x) = 0.
3
Express the area of the bounded right triangle and set it equal to 2525.
q22p=25q2=50p\frac{q^2}{2p} = 25 \Rightarrow q^2 = 50p
The area of a right triangle with vertices at the origin and the intercepts is 12×base×height=12(qp)(q)=q22p\frac{1}{2} \times |\text{base}| \times |\text{height}| = \frac{1}{2} \left(-\frac{q}{p}\right)(-q) = \frac{q^2}{2p}.
4
Substitute q=26pq = 2 - 6p into q2=50pq^2 = 50p and solve the quadratic equation.
18p237p+2=0(18p1)(p2)=0p=218p^2 - 37p + 2 = 0 \Rightarrow (18p - 1)(p - 2) = 0 \Rightarrow p = 2 or p=118p = \frac{1}{18}.
Substituting the expression for qq gives a quadratic equation in terms of pp that can be factored to find its roots.
5
Verify which root satisfies the condition that the vertical intersection point has a negative yy-coordinate.
For p=2p = 2, q=10q = -10 (valid). For p=118p = \frac{1}{18}, q=53q = \frac{5}{3} (invalid). Thus, p=2p = 2.
The problem states that the vertical axis intersection (yy-intercept) must have a negative yy-coordinate (q<0q < 0).

Anahtar Kavram

Using coordinate points and geometric properties of intercepts to determine parameters of linear functions
Soru 109Soru

In the xyxy-plane, the graph of a linear function ff has a negative slope and a positive yy-intercept. The graph of ff intersects the xx-axis at point AA and the yy-axis at point BB. A second line, LL, is perpendicular to the graph of ff and passes through the origin. If line LL intersects the graph of ff at point PP such that the ratio of the area of triangle OAPOAP to the area of triangle OBPOBP is 4:94:9, what is the slope of the graph of ff?

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Cevap: 32-\frac{3}{2}

Cevap

The slope of the graph of ff is 32-\frac{3}{2}.
The correct answer is 32-\frac{3}{2}. By setting up the equations of the lines f(x)=mx+bf(x) = mx + b and y=1mxy = -\frac{1}{m}x, we can express the coordinates of the intercepts AA and BB, as well as the intersection point PP, in terms of mm and bb. Calculating the areas of triangle OAPOAP and triangle OBPOBP gives Area(OAP)=12(bm)y0\text{Area}(OAP) = \frac{1}{2} \left(-\frac{b}{m}\right) y_0 and Area(OBP)=12bx0\text{Area}(OBP) = \frac{1}{2} b x_0. Since PP lies on the perpendicular line, y0=1mx0y_0 = -\frac{1}{m}x_0. Substituting this into the area ratio yields Area(OAP)Area(OBP)=1m2\frac{\text{Area}(OAP)}{\text{Area}(OBP)} = \frac{1}{m^2}. Equating this to the given ratio 49\frac{4}{9} results in m2=94m^2 = \frac{9}{4}. Given that the slope is negative, mm must be 32-\frac{3}{2}.

Adım Adım Çözüm

1
Define the linear function f(x)f(x) and the line LL perpendicular to it.
Let the function be f(x)=mx+bf(x) = mx + b, where m<0m < 0 and b>0b > 0. The line LL perpendicular to the graph of ff that passes through the origin has the equation y=1mxy = -\frac{1}{m}x.
This establishes the equations of both lines in terms of the slope mm and yy-intercept bb.
2
Determine the coordinates of the intercepts AA and BB, and the intersection point P(x0,y0)P(x_0, y_0).
The xx-intercept is A(bm,0)A\left(-\frac{b}{m}, 0\right) and the yy-intercept is B(0,b)B(0, b). The intersection point P(x0,y0)P(x_0, y_0) is the solution to mx+b=1mxmx + b = -\frac{1}{m}x, which gives x0=mbm2+1x_0 = -\frac{mb}{m^2+1} and y0=bm2+1y_0 = \frac{b}{m^2+1}.
Finding these points allows us to express the dimensions of triangles OAPOAP and OBPOBP.
3
Calculate the areas of triangles OAPOAP and OBPOBP and find their ratio in terms of mm.
The base of triangle OAPOAP along the xx-axis is OA=bmOA = -\frac{b}{m} and its height is y0y_0. Thus, Area(OAP)=12(bm)y0\text{Area}(OAP) = \frac{1}{2} \left(-\frac{b}{m}\right) y_0. The base of triangle OBPOBP along the yy-axis is OB=bOB = b and its height is x0x_0. Thus, Area(OBP)=12bx0\text{Area}(OBP) = \frac{1}{2} b x_0. The ratio of their areas is Area(OAP)Area(OBP)=bmy0bx0=y0mx0\frac{\text{Area}(OAP)}{\text{Area}(OBP)} = \frac{-\frac{b}{m} y_0}{b x_0} = -\frac{y_0}{m x_0}. Since PP lies on LL, we have y0x0=1m\frac{y_0}{x_0} = -\frac{1}{m}. Substituting this gives the ratio Area(OAP)Area(OBP)=1m(1m)=1m2\frac{\text{Area}(OAP)}{\text{Area}(OBP)} = -\frac{1}{m}\left(-\frac{1}{m}\right) = \frac{1}{m^2}.
This simplifies the geometric relationship to a direct relation between the area ratio and the slope of the function.
4
Solve for the slope mm using the given ratio of 4:94:9.
Setting 1m2=49\frac{1}{m^2} = \frac{4}{9} yields m2=94m^2 = \frac{9}{4}. Since the problem states the slope is negative, we take the negative square root to get m=32m = -\frac{3}{2}.
This identifies the correct slope value matching the given constraints.

Anahtar Kavram

Using coordinate geometry and system of linear equations to determine slopes and intersections, and relating those to geometric areas on the coordinate plane.
Soru 110Soru

A project manager uses the linear equation ax+by=cax + by = c to model the allocation of resources, where xx represents the number of hours spent on research, yy represents the number of hours spent on development, and a,b,a, b, and cc are positive constants. Initially, the project manager allocates 4040 hours for research and 3030 hours for development. To optimize the project, the manager decides to increase the research hours by 25%25\% and decrease the development hours by 20%20\% such that the total resource value, cc, remains unchanged. Which of the following equations correctly expresses aa in terms of bb?

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Cevap: a=0.6ba = 0.6b

Cevap

The equation a=0.6ba = 0.6b correctly expresses aa in terms of bb.
The correct equation is a=0.6ba = 0.6b. The initial resource allocation is represented by 40a+30b=c40a + 30b = c. Increasing 4040 by 25%25\% gives 5050, and decreasing 3030 by 20%20\% gives 2424, which yields the new equation 50a+24b=c50a + 24b = c. Equating these two expressions since cc is constant gives 40a+30b=50a+24b40a + 30b = 50a + 24b. Simplifying this equation results in 6b=10a6b = 10a, which gives a=0.6ba = 0.6b.

Adım Adım Çözüm

1
Write the linear equation representing the initial allocation of resources.
40a+30b=c40a + 30b = c
The initial values are 4040 hours for research (xx) and 3030 hours for development (yy).
2
Calculate the new values of xx and yy after the percentage changes are applied.
x=40×1.25=50x = 40 \times 1.25 = 50 and y=30×0.80=24y = 30 \times 0.80 = 24
Research hours increase by 25%25\% and development hours decrease by 20%20\%.
3
Write the new linear equation with the updated resource allocations.
50a+24b=c50a + 24b = c
The total resource value cc remains unchanged.
4
Equate the two expressions for cc and solve for aa in terms of bb.
40a+30b=50a+24b    6b=10a    a=0.6b40a + 30b = 50a + 24b \implies 6b = 10a \implies a = 0.6b
Since both equations equal the same constant cc, we set them equal to each other and isolate the variable aa.

Anahtar Kavram

Expressing and manipulating linear relationships in two variables with constraints.

Alternatif Yöntem

Instead of keeping cc general, we can choose a convenient value for cc, such as c=120c = 120. This gives two linear equations in terms of aa and bb: 40a+30b=12040a + 30b = 120 and 50a+24b=12050a + 24b = 120. Solving this system for the ratio of aa to bb yields a=1.33a = 1.33 and b=2.22b = 2.22, which confirms that a/b=0.6a/b = 0.6, or a=0.6ba = 0.6b.
Tahmini Süre:3m 0s
Soru 111Soru

A student tracks the remaining battery percentage, yy, of a tablet after xx hours of use. The table below shows the battery percentage at three different times:

Time (xx, hours)Battery percentage (yy)
090
375
660

Which of the following equations represents the relationship between xx and yy?

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Cevap: y=5x+90y = -5x + 90

Cevap

y = -5x + 90
The correct equation is y=5x+90y = -5x + 90. According to the table, when time x=0x = 0, the battery percentage y=90y = 90, which indicates that the y-intercept of the line is 9090. The slope can be determined using any two points from the table, such as (0,90)(0, 90) and (3,75)(3, 75): slope=759030=153=5\text{slope} = \frac{75 - 90}{3 - 0} = \frac{-15}{3} = -5. Writing this in slope-intercept form gives y=5x+90y = -5x + 90.

Adım Adım Çözüm

1
Identify the y-intercept from the table.
The y-intercept bb is 9090.
When the time x=0x = 0 hours, the battery percentage y=90y = 90. This corresponds to the y-intercept of the linear equation.
2
Calculate the slope (rate of change) using two points from the table.
The slope mm is 5-5.
Using the points (0,90)(0, 90) and (3,75)(3, 75), the slope is calculated as the change in yy divided by the change in xx: m=759030=153=5m = \frac{75 - 90}{3 - 0} = \frac{-15}{3} = -5.
3
Substitute the slope and y-intercept into the slope-intercept form equation.
y=5x+90y = -5x + 90
Plugging m=5m = -5 and b=90b = 90 into y=mx+by = mx + b yields the final equation.

Anahtar Kavram

Determining a linear equation in two variables from a table of values.
Tahmini Süre:1m 0s
Soru 112Soru

If the equation 34(8x12)56(6x18)=12(4x8)\frac{3}{4}(8x - 12) - \frac{5}{6}(6x - 18) = -\frac{1}{2}(4x - 8) is true, what is the value of xx?

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Cevap: 23-\frac{2}{3}

Cevap

23-\frac{2}{3}
The correct answer is found by distributing the coefficients across each set of parentheses, combining like terms on the left side to get x+6=2x+4x + 6 = -2x + 4, adding 2x2x to both sides to get 3x+6=43x + 6 = 4, subtracting 66 from both sides to get 3x=23x = -2, and finally dividing by 33 to obtain 23-\frac{2}{3}.

Adım Adım Çözüm

1
Distribute the coefficients to the terms inside the parentheses on both sides of the equation.
6x95x+15=2x+46x - 9 - 5x + 15 = -2x + 4
To eliminate the parentheses and prepare the equation for combining like terms.
2
Combine the constant and variable terms on the left side of the equation.
x+6=2x+4x + 6 = -2x + 4
To simplify the left side of the equation.
3
Add 2x2x to both sides of the equation.
3x+6=43x + 6 = 4
To group all terms containing the variable xx on the left side.
4
Subtract 66 from both sides, then divide by 33 to solve for xx.
3x=23x = -2, which gives x=23x = -\frac{2}{3}
To isolate xx and find its value.

Anahtar Kavram

Linear Equations in One Variable
Soru 113Soru

For the linear function ff, the value of f(0)f(0) is 33 and the value of f(5)f(5) is 1818. What is the slope of the graph of y=f(x)y = f(x) in the xyxy-plane?

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Cevap: 3

Cevap

The slope of the graph of y=f(x)y = f(x) is 33.
The slope of a linear function can be determined using any two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) on its graph with the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}. The given function values f(0)=3f(0) = 3 and f(5)=18f(5) = 18 correspond to the coordinate points (0,3)(0, 3) and (5,18)(5, 18) respectively. Substituting these coordinates into the formula gives m=18350=155=3m = \frac{18 - 3}{5 - 0} = \frac{15}{5} = 3.

Adım Adım Çözüm

1
Identify the coordinates of two points on the line using the given function values.
The function values f(0)=3f(0) = 3 and f(5)=18f(5) = 18 correspond to the points (0,3)(0, 3) and (5,18)(5, 18) on the graph of the function.
In function notation, f(x)=yf(x) = y represents a point (x,y)(x, y) on the graph of the function.
2
Calculate the slope using the slope formula.
The slope mm is calculated as 18350=3\frac{18 - 3}{5 - 0} = 3.
The slope of a line is defined as the change in yy divided by the change in xx between any two points on the line.

Anahtar Kavram

Calculating the slope of a linear function from given function values.
Soru 114Soru

If 3(2.5x4)1.5(x2)=0.8(5x+10)3(2.5x - 4) - 1.5(x - 2) = 0.8(5x + 10), what is the value of xx?

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Cevap: 8.5

Cevap

8.5
By distributing and simplifying terms, the linear equation simplifies to 2x=172x = 17, which yields x=8.5x = 8.5.

Adım Adım Çözüm

1
Distribute the constants on both sides of the equation.
7.5x121.5x+3=4x+87.5x - 12 - 1.5x + 3 = 4x + 8
To simplify the expressions.
2
Combine like terms on the left side.
6x9=4x+86x - 9 = 4x + 8
To simplify the left side of the equation.
3
Subtract 4x4x from both sides of the equation.
2x9=82x - 9 = 8
To group variable terms on one side.
4
Add 9 to both sides of the equation.
2x=172x = 17
To isolate the term with the variable.
5
Divide both sides by 2.
x=8.5x = 8.5
To find the final value of the variable.

Anahtar Kavram

Linear Equations in One Variable

Alternatif Yöntem

Multiply the entire equation by 10 to clear all decimal values: 30(2.5x4)15(x2)=8(5x+10)30(2.5x - 4) - 15(x - 2) = 8(5x + 10). Expanding this yields 75x12015x+30=40x+8075x - 120 - 15x + 30 = 40x + 80, which simplifies to 60x90=40x+8060x - 90 = 40x + 80. Subtracting 40x40x and adding 90 to both sides gives 20x=17020x = 170, resulting in x=8.5x = 8.5.
Tahmini Süre:1m 30s
Soru 115Soru

A linear function ff is defined by f(x)=mx+bf(x) = mx + b, where mm and bb are constants. The graph of ff in the xyxy-plane passes through the point (2,5)(2, 5). A second linear function gg is defined by g(x)=f(x3)+4g(x) = f(x - 3) + 4. The graph of gg has an xx-intercept of (k,0)(k, 0) and a yy-intercept of (0,k)(0, -k), where kk is a nonzero constant. What is the value of f(8)f(8)?

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Cevap: 11

Cevap

11
The correct answer is 11. By using the given point on the graph of f(x)f(x), we express its y-intercept bb in terms of its slope mm as b=52mb = 5 - 2m. Substituting this expression into the translation equation g(x)=f(x3)+4g(x) = f(x - 3) + 4 yields g(x)=mx5m+9g(x) = mx - 5m + 9. Setting the y-intercept of g(x)g(x), which is 5m+9-5m + 9, equal to k-k gives k=5m9k = 5m - 9. Evaluating g(x)g(x) at its x-intercept x=kx = k gives mk5m+9=0mk - 5m + 9 = 0. Substituting the relation 5m+9=k-5m + 9 = -k into this equation yields mkk=0mk - k = 0, or k(m1)=0k(m - 1) = 0. Since kk is nonzero, we find m=1m = 1, which in turn gives b=3b = 3. Thus, the linear function is f(x)=x+3f(x) = x + 3, and f(8)=11f(8) = 11.

Adım Adım Çözüm

1
Express the y-intercept constant bb in terms of the slope mm.
b=52mb = 5 - 2m
Since the graph of f(x)=mx+bf(x) = mx + b passes through (2,5)(2, 5), substituting x=2x = 2 and f(x)=5f(x) = 5 gives 5=2m+b5 = 2m + b.
2
Write the expression for g(x)g(x) in terms of mm.
g(x)=mx5m+9g(x) = mx - 5m + 9
By definition, g(x)=f(x3)+4=m(x3)+b+4g(x) = f(x - 3) + 4 = m(x - 3) + b + 4. Substituting b=52mb = 5 - 2m simplifies the expression to g(x)=mx5m+9g(x) = mx - 5m + 9.
3
Relate the y-intercept of g(x)g(x) to the parameter kk.
k=5m9k = 5m - 9
The y-intercept of g(x)g(x) is g(0)=5m+9g(0) = -5m + 9. Since the y-intercept is given as (0,k)(0, -k), we set k=5m+9-k = -5m + 9, which gives k=5m9k = 5m - 9.
4
Set up an equation using the x-intercept of g(x)g(x).
g(k)=mk5m+9=0g(k) = mk - 5m + 9 = 0
Since the x-intercept of g(x)g(x) is (k,0)(k, 0), substituting x=kx = k into the expression for g(x)g(x) must yield 00.
5
Solve for the slope mm.
m=1m = 1
Substituting 5m+9=k-5m + 9 = -k into the equation mk5m+9=0mk - 5m + 9 = 0 gives mkk=0mk - k = 0, which factors as k(m1)=0k(m - 1) = 0. Since kk is a nonzero constant, we divide by kk to get m1=0m - 1 = 0, so m=1m = 1.
6
Find the constant bb and write the final formula for f(x)f(x).
f(x)=x+3f(x) = x + 3
Substituting m=1m = 1 back into b=52mb = 5 - 2m yields b=3b = 3. Therefore, f(x)=x+3f(x) = x + 3.
7
Evaluate f(8)f(8).
11
Substituting x=8x = 8 into the function f(x)=x+3f(x) = x + 3 gives f(8)=8+3=11f(8) = 8 + 3 = 11.

Anahtar Kavram

Linear function transformations and intercept properties
Soru 116Soru

The equation 3x+4y=363x + 4y = 36 represents the relationship between the number of small boxes, xx, and large boxes, yy, that can fit in a delivery van. If the van is loaded with exactly 6 large boxes, what is the number of small boxes that can also fit in the van?

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Cevap: 4

Cevap

The number of small boxes that can also fit in the van is 4.
Substituting y=6y = 6 into the equation 3x+4y=363x + 4y = 36 gives 3x+24=363x + 24 = 36. Subtracting 24 from both sides results in 3x=123x = 12. Dividing both sides by 3 yields x=4x = 4. Thus, the number of small boxes that can fit is 4.

Adım Adım Çözüm

1
Substitute 6 for yy in the equation 3x+4y=363x + 4y = 36.
3x+4(6)=363x + 4(6) = 36
The variable yy represents the number of large boxes, which is given as 6.
2
Simplify the multiplication in the equation.
3x+24=363x + 24 = 36
To simplify the terms before solving for xx.
3
Subtract 24 from both sides of the equation.
3x=123x = 12
To isolate the variable term 3x3x on one side of the equation.
4
Divide both sides of the equation by 3.
x=4x = 4
To solve for xx, the number of small boxes.

Anahtar Kavram

Evaluating and solving a linear equation in two variables given the value of one variable.
Tahmini Süre:45s
Soru 117Soru

The graph of the linear function ff in the xyxy-plane is defined by f(x)=kx+4f(x) = kx + 4, where kk is a positive constant. The graph of the linear function gg is obtained by translating the graph of ff left by 33 units and down by 22 units. If the xx-intercept of the graph of gg is 55 times the xx-intercept of the graph of ff, what is the value of kk?

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Cevap: 6

Cevap

6
The correct answer is 6. The linear function g(x)g(x) represents the translated graph, which is expressed as g(x)=f(x+3)2g(x) = f(x+3) - 2. Substituting f(x)=kx+4f(x) = kx + 4 yields g(x)=k(x+3)+42=kx+3k+2g(x) = k(x+3) + 4 - 2 = kx + 3k + 2. The xx-intercept of a graph is the point where the function value is 00. Solving f(x)=0f(x) = 0 gives the xx-intercept of the graph of ff as x=4kx = -\frac{4}{k}. Solving g(x)=0g(x) = 0 gives the xx-intercept of the graph of gg as x=3k+2kx = -\frac{3k + 2}{k}. We are given that the xx-intercept of the graph of gg is 55 times the xx-intercept of the graph of ff, which translates to the equation 3k+2k=5(4k)-\frac{3k+2}{k} = 5 \left(-\frac{4}{k}\right). Multiplying both sides by k-k (since k>0k > 0, k0k \neq 0) yields 3k+2=203k + 2 = 20. Subtracting 22 from both sides gives 3k=183k = 18, and dividing by 33 results in k=6k = 6.

Adım Adım Çözüm

1
Determine the equation of the translated function g(x)g(x)
g(x)=kx+3k+2g(x) = kx + 3k + 2
Shifting the graph of f(x)f(x) left by 33 units and down by 22 units translates to g(x)=f(x+3)2g(x) = f(x+3) - 2.
2
Find the xx-intercept of the graph of ff
x=4kx = -\frac{4}{k}
The xx-intercept is the input value for which the output of the function is zero, so we solve f(x)=0f(x) = 0.
3
Find the xx-intercept of the graph of gg
x=3k+2kx = -\frac{3k + 2}{k}
We set the equation of g(x)g(x) to zero and solve for xx in terms of kk.
4
Set up and solve the equation relating the two xx-intercepts
k=6k = 6
Using the relation xg=5xfx_g = 5 \cdot x_f, we obtain 3k+2k=5(4k)-\frac{3k + 2}{k} = 5 \left(-\frac{4}{k}\right), which simplifies to 3k+2=203k + 2 = 20, leading to k=6k = 6.

Anahtar Kavram

Function translations and finding intercepts of linear equations
Soru 118Soru

In the xyxy-plane, a line with a positive slope mm and a yy-intercept of (0,b)(0, b) passes through the point (b,12)(b, 12), where b>0b > 0. If the area of the triangle bounded by the line, the xx-axis, and the yy-axis is 44, what is the value of mm?

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Cevap: 2

Cevap

2
The line equation is y=mx+by = mx + b. Substituting the point (b,12)(b, 12) gives 12=b(m+1)12 = b(m + 1). The xx-intercept of the line is at (bm,0)(-\frac{b}{m}, 0), which gives a base length of bm\frac{b}{m} for the right triangle, while the height is bb. The area of the triangle is b22m=4    b2=8m\frac{b^2}{2m} = 4 \implies b^2 = 8m. Substituting b=12m+1b = \frac{12}{m + 1} into this equation yields 144(m+1)2=8m    m(m+1)2=18\frac{144}{(m + 1)^2} = 8m \implies m(m + 1)^2 = 18. Solving this for positive values of mm gives the unique solution m=2m = 2.

Adım Adım Çözüm

1
Express the line equation and substitute the given point (b,12)(b, 12).
b(m+1)=12b(m + 1) = 12
Since the line has a yy-intercept of (0,b)(0, b) and a slope of mm, its equation is y=mx+by = mx + b. Substituting the point (b,12)(b, 12) yields 12=m(b)+b=b(m+1)12 = m(b) + b = b(m + 1).
2
Determine the lengths of the base and height of the triangle formed by the line and the coordinate axes.
Base =bm= \frac{b}{m}, Height =b= b
The yy-intercept is at (0,b)(0, b) and the xx-intercept is at (bm,0)(-\frac{b}{m}, 0). Since b>0b > 0 and m>0m > 0, the height is bb and the base is the absolute value of the xx-intercept, which is bm\frac{b}{m}.
3
Write the area equation of the triangle and simplify it.
b2=8mb^2 = 8m
The area of the right triangle is 12×base×height=12(bm)b=b22m\frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \left(\frac{b}{m}\right)b = \frac{b^2}{2m}. Setting this equal to the given area of 44 gives b22m=4    b2=8m\frac{b^2}{2m} = 4 \implies b^2 = 8m.
4
Solve the system of equations for mm.
m=2m = 2
Substituting b=12m+1b = \frac{12}{m + 1} into b2=8mb^2 = 8m yields (12m+1)2=8m    144(m+1)2=8m    m(m+1)2=18\left(\frac{12}{m + 1}\right)^2 = 8m \implies \frac{144}{(m + 1)^2} = 8m \implies m(m + 1)^2 = 18. Since m(m+1)2m(m + 1)^2 is strictly increasing for positive mm, testing small integers shows 2(3)2=182(3)^2 = 18, so m=2m = 2 is the unique positive real solution.

Anahtar Kavram

Formulating linear equations in slope-intercept form and solving non-linear systems of equations derived from geometric constraints.

Alternatif Yöntem

Instead of algebraically expanding the cubic equation, one can test small positive integers for mm in the equation m(m+1)2=18m(m + 1)^2 = 18. Testing m=1m = 1 yields 1(2)2=41(2)^2 = 4 (too small), and testing m=2m = 2 yields 2(3)2=182(3)^2 = 18 (correct). Because m(m+1)2m(m + 1)^2 is strictly increasing for m>0m > 0, m=2m = 2 is the only positive real root.
Tahmini Süre:3m 0s
Soru 119Soru

If 2(x5)4-2(x - 5) \geq 4, what is the maximum possible value of xx?

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Cevap: 3

Cevap

3
Distributing the 2-2 on the left side of the inequality 2(x5)4-2(x - 5) \geq 4 yields 2x+104-2x + 10 \geq 4. Subtracting 1010 from both sides gives 2x6-2x \geq -6. Dividing both sides by 2-2 and reversing the inequality sign results in x3x \leq 3. The maximum possible value is therefore 3.

Adım Adım Çözüm

1
Distribute 2-2 to the terms inside the parentheses.
2x+104-2x + 10 \geq 4
Applying the distributive property simplifies the inequality.
2
Subtract 1010 from both sides of the inequality.
2x6-2x \geq -6
This isolates the variable term on the left side.
3
Divide both sides of the inequality by 2-2 and reverse the inequality sign.
x3x \leq 3
Dividing both sides of an inequality by a negative number reverses the direction of the inequality.

Anahtar Kavram

Solving linear inequalities in one variable using the distributive property and division by negative numbers.
Soru 120Soru

A company manufactures custom travel mugs. The daily cost CC, in dollars, to manufacture nn mugs is given by the formula C=1.25n+250C = 1.25n + 250. The company sells each mug for 4.50.Tomakeaprofitofexactly4.50. To make a profit of exactly 400$ in a day, how many mugs must the company manufacture?

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Cevap: 200

Cevap

The company must manufacture 200 mugs to make a profit of exactly $400 in a day.
Subtracting the cost expression from the revenue expression gives the profit equation: 4.50n(1.25n+250)=4004.50n - (1.25n + 250) = 400. Distributing the negative sign results in 4.50n1.25n250=4004.50n - 1.25n - 250 = 400, which simplifies to 3.25n250=4003.25n - 250 = 400. Adding 250 to both sides gives 3.25n=6503.25n = 650. Dividing both sides by 3.25 yields n=200n = 200.

Adım Adım Çözüm

1
Set up the profit equation
4.50n(1.25n+250)=4004.50n - (1.25n + 250) = 400
Profit is calculated as total revenue (4.50n4.50n) minus total cost (1.25n+2501.25n + 250).
2
Distribute the negative sign and simplify the equation
3.25n250=4003.25n - 250 = 400
Subtracting the entire cost expression requires distributing the subtraction to both 1.25n1.25n and 250250, yielding 4.50n1.25n2504.50n - 1.25n - 250.
3
Isolate the variable term by adding 250 to both sides
3.25n=6503.25n = 650
Adding 250 to both sides of the equation isolates the term containing nn.
4
Solve for nn by dividing both sides by 3.25
n=200n = 200
Dividing 650 by 3.25 gives the number of mugs needed to achieve the target profit.

Anahtar Kavram

Solving linear equations in one variable derived from a real-world context.
ÖncekiSayfa 6 / 22Sonraki
Algebra Alıştırma Soruları — SAT — Sayfa 6 | Examkin