Algebra

432 soru

Soru 81Soru

If 3(x2)=x+143(x - 2) = -x + 14, what is the value of xx?

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Cevap: 5

Cevap

5
The correct value is 5. Distributing the 3 on the left side of the equation 3(x2)=x+143(x - 2) = -x + 14 yields 3x6=x+143x - 6 = -x + 14. Adding xx to both sides gives 4x6=144x - 6 = 14. Adding 6 to both sides gives 4x=204x = 20. Finally, dividing both sides by 4 yields x=5x = 5.

Adım Adım Çözüm

1
Distribute the 3 to the terms inside the parentheses on the left side of the equation.
3x6=x+143x - 6 = -x + 14
To simplify the equation and prepare to isolate the variable, the parentheses must be expanded.
2
Add xx to both sides of the equation to group all variable terms on the left side.
4x6=144x - 6 = 14
Grouping the variable terms helps in isolating the variable.
3
Add 6 to both sides of the equation to isolate the variable term.
4x=204x = 20
Moving the constant term to the other side isolates the variable term 4x4x.
4
Divide both sides of the equation by 4 to find the value of xx.
x=5x = 5
Dividing by the coefficient of xx gives the final value of the variable.

Anahtar Kavram

Linear Equations in One Variable
Tahmini Süre:45s
Soru 82Soru

In the xyxy-plane, line l1l_1 passes through the origin and has a positive slope mm, where m>1m > 1. Line l2l_2 is perpendicular to line l1l_1 and has a yy-intercept of (0,10)(0, 10). The two lines intersect at point PP. If the distance from point PP to the yy-axis is 44, what is the value of mm?

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Cevap: 2

Cevap

2
The equation of line l1l_1 is y=mxy = mx and the equation of line l2l_2 is y=1mx+10y = -\frac{1}{m}x + 10. Setting these equal gives the xx-coordinate of their intersection as x=10mm2+1x = \frac{10m}{m^2 + 1}. Since the distance from the intersection point to the yy-axis is 44, we have 10mm2+1=4\frac{10m}{m^2 + 1} = 4. Solving this quadratic equation yields m=2m = 2 or m=12m = \frac{1}{2}. Given that m>1m > 1, the correct value is 22.

Adım Adım Çözüm

1
Write the equations of lines l1l_1 and l2l_2.
Line l1l_1 has a slope of mm and passes through (0,0)(0,0), so its equation is y=mxy = mx. Line l2l_2 is perpendicular to l1l_1, so its slope is 1m-\frac{1}{m}. Since its yy-intercept is (0,10)(0,10), its equation is y=1mx+10y = -\frac{1}{m}x + 10.
Setting up the equations of the lines allows us to find their point of intersection.
2
Find the xx-coordinate of the intersection point PP.
Equating the two expressions for yy gives mx=1mx+10mx = -\frac{1}{m}x + 10. Multiplying both sides by mm yields m2x=x+10mm^2 x = -x + 10m, which simplifies to (m2+1)x=10m(m^2 + 1)x = 10m, or x=10mm2+1x = \frac{10m}{m^2 + 1}.
The intersection point PP must satisfy both equations simultaneously.
3
Solve for mm using the distance from PP to the yy-axis.
The distance from P(x,y)P(x,y) to the yy-axis is given by x|x|. Since m>1m > 1, xx is positive, so the distance is 10mm2+1=4\frac{10m}{m^2 + 1} = 4. This simplifies to 10m=4m2+410m = 4m^2 + 4, or 4m210m+4=04m^2 - 10m + 4 = 0. Dividing by 22 gives 2m25m+2=02m^2 - 5m + 2 = 0. Factoring the quadratic yields (2m1)(m2)=0(2m - 1)(m - 2) = 0, giving solutions of m=12m = \frac{1}{2} and m=2m = 2. Since m>1m > 1, the slope of l1l_1 must be 22.
Applying the given distance constraint and slope condition determines the unique value of mm.

Anahtar Kavram

The relationship between the equations of perpendicular lines and their point of intersection in the coordinate plane.
Soru 83Soru

The graph of the linear function ff in the xyxy-plane has a yy-intercept of (0,b)(0, b) and an xx-intercept of (a,0)(a, 0), where aa and bb are nonzero constants. If 3a=4b3a = -4b, which of the following is the slope of the graph of ff?

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Cevap: 34\frac{3}{4}

Cevap

34\frac{3}{4}
The slope of the line passing through (0,b)(0, b) and (a,0)(a, 0) is m=0ba0=bam = \frac{0 - b}{a - 0} = -\frac{b}{a}. Starting with the given equation 3a=4b3a = -4b, dividing both sides by 4a-4a isolates the slope expression: ba=34-\frac{b}{a} = \frac{3}{4}. Therefore, the slope of the graph of ff is 34\frac{3}{4}.

Adım Adım Çözüm

1
Identify the coordinates of the intercepts and write the formula for the slope of a line.
The yy-intercept is (0,b)(0, b) and the xx-intercept is (a,0)(a, 0). The slope mm is given by m=0ba0=bam = \frac{0 - b}{a - 0} = -\frac{b}{a}.
To find the slope, we express it in terms of the variables aa and bb using the standard slope formula.
2
Use the given equation to find the ratio ba-\frac{b}{a}.
Divide both sides of the equation 3a=4b3a = -4b by aa to get 3=4(ba)3 = -4\left(\frac{b}{a}\right). Then, divide both sides by 4-4 to get 34=ba-\frac{3}{4} = \frac{b}{a}, which means ba=34-\frac{b}{a} = \frac{3}{4}.
We isolate the expression for the slope, which is ba-\frac{b}{a}, using algebraic operations on the given equation.
3
Equate the slope expression to the calculated value.
Since m=bam = -\frac{b}{a} and ba=34-\frac{b}{a} = \frac{3}{4}, the slope of the line is 34\frac{3}{4}.
This yields the final value of the slope.

Anahtar Kavram

Calculating the slope of a linear function using intercepts and algebraic substitution.
Soru 84Soru

The table below shows several values of xx and their corresponding values of f(x)f(x) for the linear function ff.

xxf(x)f(x)
2277
551313
881919

What is the slope of the graph of y=f(x)y = f(x) in the xyxy-plane?

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Cevap: 2

Cevap

The slope of the graph of y=f(x)y = f(x) is 2.
The slope of a linear function represents the constant rate of change of the function values with respect to the input values. Using any two points from the table, such as (2,7)(2, 7) and (5,13)(5, 13), the slope mm can be calculated using the slope formula: m=f(x2)f(x1)x2x1=13752=63=2m = \frac{f(x_2) - f(x_1)}{x_2 - x_1} = \frac{13 - 7}{5 - 2} = \frac{6}{3} = 2. Therefore, the slope of the graph of y=f(x)y = f(x) is 22.

Adım Adım Çözüm

1
Select two points from the given table.
Two points are (2,7)(2, 7) and (5,13)(5, 13).
To find the slope of a linear function, we need to calculate the rate of change between any two points on the line.
2
Apply the slope formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}.
m=13752=63=2m = \frac{13 - 7}{5 - 2} = \frac{6}{3} = 2
Calculating the ratio of the vertical change (change in f(x)f(x)) to the horizontal change (change in xx) yields the constant slope of the linear function.

Anahtar Kavram

Calculating the slope of a linear function from a table of values.
Tahmini Süre:1m 0s
Soru 85Soru

If 3(2n+4)=423(2n + 4) = 42, what is the value of nn?

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Cevap: 5

Cevap

5
To solve the linear equation 3(2n+4)=423(2n + 4) = 42, first divide both sides of the equation by 3, which simplifies it to 2n+4=142n + 4 = 14. Next, subtract 4 from both sides of the equation to isolate the term with the variable, giving 2n=102n = 10. Finally, divide both sides of the equation by 2 to solve for the variable, which yields n=5n = 5.

Adım Adım Çözüm

1
Divide both sides of the equation by 3.
2n+4=142n + 4 = 14
To simplify the equation by eliminating the outer constant multiplier.
2
Subtract 4 from both sides of the equation.
2n=102n = 10
To isolate the variable term on one side of the equation.
3
Divide both sides of the equation by 2.
n=5n = 5
To find the value of nn.

Anahtar Kavram

Solving a linear equation in one variable using inverse operations.
Tahmini Süre:45s
Soru 86Soru

In the xyxy-plane, the graph of the linear function ff is perpendicular to the line with equation y=2x7y = 2x - 7. If the region in the first quadrant bounded by the graph of ff, the xx-axis, and the yy-axis has an area of 3636, what is the xx-intercept of the graph of ff?

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Cevap: 12

Cevap

The xx-intercept of the graph of ff is 1212.
The correct answer is 1212. Since the graph of ff is perpendicular to the line y=2x7y = 2x - 7, its slope is 12-\frac{1}{2}. The equation of the line is f(x)=12x+bf(x) = -\frac{1}{2}x + b, which has a yy-intercept of (0,b)(0, b) and an xx-intercept of (2b,0)(2b, 0). In the first quadrant, these intercepts form a right triangle with the axes, having legs of length bb and 2b2b. The area of this triangle is 12(2b)(b)=b2\frac{1}{2}(2b)(b) = b^2. Setting the area equal to 3636 gives b2=36b^2 = 36, so b=6b = 6 (since b>0b > 0). The xx-intercept is 2b=2(6)=122b = 2(6) = 12.

Adım Adım Çözüm

1
Find the slope of the perpendicular line ff.
The slope of ff is 12-\frac{1}{2}.
Perpendicular lines in the coordinate plane have slopes that are negative reciprocals of each other. The given line has a slope of 22, so the slope of ff must be 12-\frac{1}{2}.
2
Express the yy-intercept and xx-intercept of ff in terms of a single variable.
The yy-intercept is (0,b)(0, b) and the xx-intercept is (2b,0)(2b, 0), where b>0b > 0.
The equation of ff can be written as f(x)=12x+bf(x) = -\frac{1}{2}x + b. Setting x=0x = 0 gives the yy-intercept bb. Setting f(x)=0f(x) = 0 and solving for xx gives the xx-intercept 2b2b.
3
Set up the area equation for the triangle in the first quadrant.
The area is represented by b2=36b^2 = 36.
The region bounded by the graph of ff and the coordinate axes in the first quadrant forms a right triangle with perpendicular sides of lengths bb and 2b2b. The area of this triangle is 12×base×height=12×2b×b=b2\frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 2b \times b = b^2.
4
Solve for bb and calculate the xx-intercept.
The xx-intercept is 1212.
Solving b2=36b^2 = 36 with the condition b>0b > 0 yields b=6b = 6. The xx-intercept is 2b2b, which equals 2(6)=122(6) = 12.

Anahtar Kavram

Using perpendicular slopes and intercepts of linear functions to analyze geometric areas in the coordinate plane.
Tahmini Süre:2m 0s
Soru 87Soru

A commercial drone delivery service charges a flat rate of 15.5015.50 dollars per delivery plus a fuel surcharge of 1.801.80 dollars per mile. During a promotional event, the service offers a 20%20\% discount off the fuel surcharge only. If the total cost for a specific delivery during this promotion was 27.0227.02 dollars, how many miles did the drone travel for this delivery?

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Cevap: 8

Cevap

8
The correct answer is 8. The promotional fuel surcharge is reduced by 20%20\% from the normal 1.801.80 dollars per mile, resulting in a rate of 1.80×(10.20)=1.441.80 \times (1 - 0.20) = 1.44 dollars per mile. The linear equation modeling the total cost for a delivery of mm miles during the promotion is 15.50+1.44m=27.0215.50 + 1.44m = 27.02. Subtracting 15.5015.50 from both sides gives 1.44m=11.521.44m = 11.52. Dividing both sides by 1.441.44 yields the distance m=8m = 8 miles.

Adım Adım Çözüm

1
Determine the discounted fuel surcharge per mile.
The discounted surcharge is 1.441.44 dollars per mile.
A 20%20\% discount is applied to the original 1.801.80 dollars per mile fuel surcharge: 1.80×(10.20)=1.441.80 \times (1 - 0.20) = 1.44.
2
Set up the linear equation representing the total promotional cost.
15.50+1.44m=27.0215.50 + 1.44m = 27.02, where mm represents the number of miles traveled.
The total cost is the sum of the flat rate of 15.5015.50 dollars and the promotional fuel surcharge of 1.441.44 dollars per mile multiplied by the number of miles.
3
Subtract the flat rate from both sides of the equation.
1.44m=11.521.44m = 11.52
To isolate the term with the variable mm, subtract the flat rate of 15.5015.50 from the total promotional cost of 27.0227.02.
4
Solve for the distance by division.
m=8m = 8
Divide both sides of the equation by the promotional rate per mile, 1.441.44, to find the number of miles.

Anahtar Kavram

Formulating and solving a multi-step linear equation in one variable with decimals and percentages to represent a real-world scenario.
Soru 88Soru

A local municipal water utility charges a flat monthly service fee plus a constant rate for each hundred cubic feet (HCF) of water consumed. During one month, a household that consumed 12 HCF of water was charged 46.00 dollars. Another household that consumed 18 HCF of water was charged 61.00 dollars. What is the flat monthly service fee, in dollars, charged by the utility?

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Cevap: 16

Cevap

The flat monthly service fee is 16 dollars.
By modeling the relationship as a linear function y=mx+by = mx + b, where xx is the consumption in HCF and yy is the total charge in dollars, we use the points (12,46)(12, 46) and (18,61)(18, 61) to find the slope m=61461812=2.5m = \frac{61 - 46}{18 - 12} = 2.5. Substituting m=2.5m = 2.5 and the point (12,46)(12, 46) back into the linear equation gives 46=2.5(12)+b46 = 2.5(12) + b, which simplifies to 46=30+b46 = 30 + b. Solving for bb gives 16, representing the flat service fee.

Adım Adım Çözüm

1
Set up a system of points representing the linear relationship between water consumed and monthly charge.
Two coordinate points are established: (12,46)(12, 46) and (18,61)(18, 61), where the first coordinate is the consumption in HCF and the second is the charge in dollars.
Since the utility charges a flat fee plus a constant rate, the relationship is linear and can be solved using coordinate points.
2
Find the constant rate per HCF (the slope of the line).
The slope mm is calculated as 61461812=156=2.5\frac{61 - 46}{18 - 12} = \frac{15}{6} = 2.5 dollars per HCF.
The slope represents the constant rate of change in total cost per HCF of water consumed.
3
Determine the flat monthly service fee (the y-intercept of the line).
Using the slope-intercept equation y=mx+by = mx + b with point (12,46)(12, 46) and m=2.5m = 2.5 yields 46=2.5(12)+b    46=30+b    b=1646 = 2.5(12) + b \implies 46 = 30 + b \implies b = 16.
The y-intercept represents the cost when consumption is zero, which is the flat monthly service fee.

Anahtar Kavram

Finding the y-intercept of a linear function from two points.
Tahmini Süre:1m 30s
Soru 89Soru

If 12(4x6)2(x+5)=3x1\frac{1}{2}(4x - 6) - 2(x + 5) = 3x - 1, what is the value of xx?

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Cevap: 4-4

Cevap

4-4
The correct answer is 4-4. Distributing the terms on the left side of the equation 12(4x6)2(x+5)=3x1\frac{1}{2}(4x - 6) - 2(x + 5) = 3x - 1 gives 2x32x10=3x12x - 3 - 2x - 10 = 3x - 1. Simplifying the left side yields 13=3x1-13 = 3x - 1. Adding 11 to both sides results in 12=3x-12 = 3x. Finally, dividing both sides by 33 gives x=4x = -4.

Adım Adım Çözüm

1
Distribute the constants outside the parentheses on the left side of the equation.
2x32x10=3x12x - 3 - 2x - 10 = 3x - 1
Distributing 12\frac{1}{2} to (4x6)(4x - 6) yields 2x32x - 3, and distributing 2-2 to (x+5)(x + 5) yields 2x10-2x - 10.
2
Combine like terms on the left side of the equation.
13=3x1-13 = 3x - 1
Combining 2x2x and 2x-2x results in 00, and combining 3-3 and 10-10 results in 13-13.
3
Isolate the variable xx by adding 11 to both sides and dividing by 33.
x=4x = -4
Adding 11 to both sides gives 12=3x-12 = 3x. Dividing both sides by 33 yields x=4x = -4.

Anahtar Kavram

Solving linear equations in one variable by distributing constants and combining like terms.
Soru 90Soru

If 122(w1)=412 - 2(w - 1) = 4, what is the value of ww?

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Cevap: 5

Cevap

5
The correct answer is 5. We solve the equation by first distributing the coefficient 2-2 to (w1)(w - 1), which yields 122w+2=412 - 2w + 2 = 4. Combining the constant terms gives 142w=414 - 2w = 4. Subtracting 14 from both sides results in 2w=10-2w = -10. Finally, dividing by 2-2 isolates the variable, giving w=5w = 5.

Adım Adım Çözüm

1
Distribute the negative coefficient 2-2 to the terms inside the parentheses.
122w+2=412 - 2w + 2 = 4
To eliminate the parentheses and simplify the expression.
2
Combine the constant terms on the left side of the equation.
142w=414 - 2w = 4
To group like terms together.
3
Subtract 14 from both sides of the equation.
2w=10-2w = -10
To isolate the variable term on one side of the equation.
4
Divide both sides of the equation by 2-2.
w=5w = 5
To find the value of ww.

Anahtar Kavram

Solving linear equations in one variable using distributive properties and basic operations.
Soru 91Soru
A system of linear equations is shown below.
y=2x7y = 2x - 7
3x2y=113x - 2y = 11

What is the value of xx?

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Cevap: 3

Cevap

The correct value of xx is 3.
The correct value of xx is 3, which is found by substituting 2x72x - 7 for yy in the second equation and solving for xx.

Adım Adım Çözüm

1
Substitute the expression for yy from the first equation into the second equation.
3x2(2x7)=113x - 2(2x - 7) = 11
Since the first equation defines yy in terms of xx, substitution is a direct way to eliminate yy and solve for xx.
2
Distribute the 2-2 to both terms inside the parentheses.
3x4x+14=113x - 4x + 14 = 11
Applying the distributive property requires multiplying 2-2 by both 2x2x and 7-7, remembering that negative times negative is positive.
3
Combine the like terms on the left side of the equation.
x+14=11-x + 14 = 11
Simplifying the expression by combining the xx terms (3x4x=x3x - 4x = -x).
4
Isolate the variable term by subtracting 14 from both sides.
x=3-x = -3
Using the subtraction property of equality to move the constant term to the right side.
5
Solve for xx by multiplying or dividing both sides by 1-1.
x=3x = 3
Finding the positive value of xx.

Anahtar Kavram

Solving systems of linear equations using the substitution method.
Soru 92Soru
In the equation below, pp and qq are constants.
2p(6x9)3q(4x+2)=2x9\frac{2}{p}(6x - 9) - \frac{3}{q}(4x + 2) = -2x - 9
If the equation has infinitely many solutions for xx, what is the value of p+qp + q?
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Cevap: 5

Cevap

The value of p+qp+q is 55.
For the equation to have infinitely many solutions for xx, the coefficients of xx on both sides must be equal, and the constant terms on both sides must also be equal. Expanding the left side of the equation gives (12p12q)x(18p+6q)=2x9\left(\frac{12}{p} - \frac{12}{q}\right)x - \left(\frac{18}{p} + \frac{6}{q}\right) = -2x - 9. Equating the coefficients of xx yields 12p12q=2\frac{12}{p} - \frac{12}{q} = -2, which simplifies to 6p6q=1\frac{6}{p} - \frac{6}{q} = -1. Equating the constant terms yields 18p6q=9-\frac{18}{p} - \frac{6}{q} = -9, which simplifies to 18p+6q=9\frac{18}{p} + \frac{6}{q} = 9. Adding these two simplified equations eliminates the term with qq, giving 24p=8\frac{24}{p} = 8, which means p=3p = 3. Substituting p=3p = 3 back into the first equation yields 26q=12 - \frac{6}{q} = -1, which simplifies to 6q=3\frac{6}{q} = 3, meaning q=2q = 2. Thus, the value of p+qp + q is 3+2=53 + 2 = 5.

Adım Adım Çözüm

1
Expand and group the terms on the left side of the equation.
(12p12q)x(18p+6q)=2x9\left(\frac{12}{p} - \frac{12}{q}\right)x - \left(\frac{18}{p} + \frac{6}{q}\right) = -2x - 9
To analyze the linear equation, we must group the coefficients of the variable xx and the constant terms.
2
Set up a system of equations for pp and qq using the condition for infinitely many solutions.
12p12q=2\frac{12}{p} - \frac{12}{q} = -2 and 18p6q=9-\frac{18}{p} - \frac{6}{q} = -9
A linear equation in the form Ax+B=Cx+DAx + B = Cx + D has infinitely many solutions if and only if A=CA = C and B=DB = D.
3
Simplify the system of equations.
6p6q=1\frac{6}{p} - \frac{6}{q} = -1 (Equation 1) and 18p+6q=9\frac{18}{p} + \frac{6}{q} = 9 (Equation 2)
Dividing Equation 1 by 22 and Equation 2 by 1-1 simplifies the coefficients, making the system easier to solve.
4
Solve for pp by adding Equation 1 and Equation 2.
24p=8    p=3\frac{24}{p} = 8 \implies p = 3
Adding the two equations eliminates the term containing qq, allowing us to solve directly for pp.
5
Substitute p=3p = 3 back into Equation 1 to solve for qq.
636q=1    26q=1    6q=3    q=2\frac{6}{3} - \frac{6}{q} = -1 \implies 2 - \frac{6}{q} = -1 \implies \frac{6}{q} = 3 \implies q = 2
Using the value of pp allows us to isolate and solve for qq.
6
Calculate the sum of pp and qq.
p+q=3+2=5p + q = 3 + 2 = 5
The question asks for the value of p+qp + q.

Anahtar Kavram

Conditions for a linear equation in one variable to have infinitely many solutions, and solving systems of literal equations.
Soru 93Soru

A scientist is measuring the temperature of a sample that is being heated at a constant rate. At a starting time of 00 minutes, the temperature of the sample is 12C12^\circ\text{C}. After 88 minutes of heating, the temperature of the sample is 44C44^\circ\text{C}. If the temperature of the sample increases linearly with time, what is the temperature of the sample, in degrees Celsius, after 1515 minutes of heating?

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Cevap: 72

Cevap

72
The rate of temperature change is 441280=4C\frac{44 - 12}{8 - 0} = 4^\circ\text{C} per minute. Using the slope-intercept form, the temperature TT after tt minutes can be represented by the function T(t)=4t+12T(t) = 4t + 12. Substituting 1515 for tt yields T(15)=4(15)+12=60+12=72T(15) = 4(15) + 12 = 60 + 12 = 72.

Adım Adım Çözüm

1
Calculate the constant rate of temperature change (slope).
4 degrees Celsius per minute
To find how much the temperature increases each minute, divide the total change in temperature by the total change in time: 441280=328=4\frac{44 - 12}{8 - 0} = \frac{32}{8} = 4.
2
Set up the linear function for temperature T(t)T(t) over time tt.
T(t)=4t+12T(t) = 4t + 12
The initial temperature at t=0t = 0 is 12C12^\circ\text{C}, which represents the vertical intercept. The constant rate of change is 4C4^\circ\text{C} per minute.
3
Find the temperature at t=15t = 15 minutes.
72
Substitute 1515 for tt in the equation: T(15)=4(15)+12=60+12=72T(15) = 4(15) + 12 = 60 + 12 = 72.

Anahtar Kavram

Linear Functions and Rates of Change
Tahmini Süre:1m 0s
Soru 94Soru

A line in the xyxy-plane has a slope of 3-3. The line passes through the point (2,k)(2, k) and has an xx-intercept of (r,0)(r, 0), where kk and rr are constants. If r+k=10r + k = 10, what is the yy-intercept of the line?

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Cevap: (0,12)(0, 12)

Cevap

The y-intercept of the line is (0,12)(0, 12).
The correct answer is (0,12)(0, 12). By using the formula for slope m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} with the points (2,k)(2, k) and (r,0)(r, 0), we obtain 3=k02r-3 = \frac{k - 0}{2 - r}. Multiplying both sides by 2r2 - r gives k=3(2r)k = -3(2 - r), which simplifies to k=6+3rk = -6 + 3r, or 3rk=63r - k = 6. We can solve this alongside the given equation r+k=10r + k = 10 by adding the two equations: (3rk)+(r+k)=6+10    4r=16(3r - k) + (r + k) = 6 + 10 \implies 4r = 16, which yields r=4r = 4. Substituting r=4r = 4 back into the sum equation gives k=6k = 6. Now, using the x-intercept point (4,0)(4, 0) and the slope of 3-3, the equation of the line in point-slope form is y0=3(x4)y - 0 = -3(x - 4), which simplifies to y=3x+12y = -3x + 12. The y-intercept of this line is found by setting x=0x = 0, yielding (0,12)(0, 12).

Adım Adım Çözüm

1
Express the slope of the line using the coordinates of the two given points, (2,k)(2, k) and the x-intercept (r,0)(r, 0).
Using the slope formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}, we set up the equation: 3=k02r-3 = \frac{k - 0}{2 - r}.
This connects the geometric concept of slope to the algebraic coordinates of the points on the line.
2
Simplify the slope equation to relate kk and rr.
Multiplying both sides by 2r2 - r gives k=3(2r)    k=6+3rk = -3(2 - r) \implies k = -6 + 3r, which can be rewritten as 3rk=63r - k = 6.
Simplifying the equation makes it easier to solve as part of a system of linear equations.
3
Solve the system of equations consisting of 3rk=63r - k = 6 and the given equation r+k=10r + k = 10.
Adding the two equations together: (3rk)+(r+k)=6+10    4r=16    r=4(3r - k) + (r + k) = 6 + 10 \implies 4r = 16 \implies r = 4. Substituting r=4r = 4 into r+k=10r + k = 10 gives 4+k=10    k=64 + k = 10 \implies k = 6.
Solving the system of equations determines the numerical values of the constants rr and kk.
4
Find the equation of the line using the slope m=3m = -3 and the x-intercept (4,0)(4, 0), then determine the y-intercept.
Using point-slope form: y0=3(x4)    y=3x+12y - 0 = -3(x - 4) \implies y = -3x + 12. The y-intercept occurs when x=0x = 0, giving y=12y = 12, which corresponds to the point (0,12)(0, 12).
Writing the full linear equation allows us to find the y-intercept by evaluating the function at x=0x = 0.

Anahtar Kavram

Writing linear equations from given points and slope, and solving a system of linear equations to identify intercepts.
Tahmini Süre:2m 0s
Soru 95Soru

If 2x+7=152x + 7 = 15, what is the value of 4x34x - 3?

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Cevap: 13

Cevap

13
To find the value of the expression, first solve the linear equation for the variable. Subtracting 7 from both sides of the equation yields 2x=82x = 8. Dividing both sides of the equation by 2 yields x=4x = 4. Substituting this value back into the expression yields 4(4)3=163=134(4) - 3 = 16 - 3 = 13. Alternatively, since 2x=82x = 8, multiplying both sides by 2 gives 4x=164x = 16. Subtracting 3 from both sides of this relation yields 4x3=163=134x - 3 = 16 - 3 = 13.

Adım Adım Çözüm

1
Subtract 7 from both sides of the equation
2x=82x = 8
To isolate the variable term on one side of the equation
2
Divide both sides by 2
x=4x = 4
To solve for the variable
3
Substitute the value of the variable into the target expression
1313
To find the final evaluated value requested by the question

Anahtar Kavram

Solving a linear equation in one variable and evaluating an expression
Soru 96Soru

A chemist mixes two saline solutions. Solution A is 12%12\% salt by mass, and Solution B is 30%30\% salt by mass. The mass of Solution B used in the mixture is 20 grams more than 13\frac{1}{3} of the mass of Solution A used. If the resulting mixture is 18%18\% salt by mass, what is the mass, in grams, of Solution A used?

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Cevap: 120

Cevap

The mass of Solution A used is 120 grams.
The correct answer is 120. By setting the mass of Solution A to xx, the mass of Solution B is 13x+20\frac{1}{3}x + 20. Equating the total salt content from both individual solutions to the total salt content of the final mixture gives the linear equation 0.12x+0.30(13x+20)=0.18(x+13x+20)0.12x + 0.30\left(\frac{1}{3}x + 20\right) = 0.18\left(x + \frac{1}{3}x + 20\right). Simplifying both sides yields 0.22x+6=0.24x+3.60.22x + 6 = 0.24x + 3.6. Solving this equation gives 0.02x=2.40.02x = 2.4, which simplifies to x=120x = 120.

Adım Adım Çözüm

1
Define the variable xx as the mass, in grams, of Solution A used in the mixture, and express the mass of Solution B in terms of xx.
Mass of Solution A = xx grams; Mass of Solution B = 13x+20\frac{1}{3}x + 20 grams.
To set up expressions representing the mass of each solution in the mixture.
2
Calculate the mass of salt contributed by each solution and write an expression for the total mass of salt.
Salt from Solution A = 0.12x0.12x grams; Salt from Solution B = 0.30(13x+20)=0.10x+60.30\left(\frac{1}{3}x + 20\right) = 0.10x + 6 grams; Total salt = 0.22x+60.22x + 6 grams.
To find the total amount of salt before mixing.
3
Express the total mass of the mixture and the total salt content using the final mixture's percentage.
Total mass of mixture = 43x+20\frac{4}{3}x + 20 grams; Total salt in final mixture = 0.18(43x+20)=0.24x+3.60.18\left(\frac{4}{3}x + 20\right) = 0.24x + 3.6 grams.
To write the total salt content in terms of the final mixture's concentration.
4
Equate the two expressions for the total mass of salt and solve the linear equation for xx.
0.22x+6=0.24x+3.6    2.4=0.02x    x=1200.22x + 6 = 0.24x + 3.6 \implies 2.4 = 0.02x \implies x = 120.
To find the mass of Solution A that satisfies the mixture conditions.

Anahtar Kavram

Setting up and solving a linear equation in one variable from a mixture word problem.
Soru 97Soru

For the linear function ff, the table below displays selected values of xx and their corresponding function values f(x)f(x).

xxf(x)f(x)
2-211
2299
441313

What is the value of f(10)f(10)?

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Cevap: 25

Cevap

The value of f(10)f(10) is 25.
The correct answer is 25. By using the points (2,1)(-2, 1) and (2,9)(2, 9), the slope of the linear function is calculated as m=912(2)=2m = \frac{9 - 1}{2 - (-2)} = 2. Substituting this slope and the point (2,9)(2, 9) into the slope-intercept form, f(x)=2x+bf(x) = 2x + b, gives 9=2(2)+b9 = 2(2) + b, which resolves to b=5b = 5. Thus, the linear function is defined by f(x)=2x+5f(x) = 2x + 5. Evaluating the function at x=10x = 10 yields f(10)=2(10)+5=25f(10) = 2(10) + 5 = 25.

Adım Adım Çözüm

1
Calculate the slope of the linear function using two coordinate pairs.
Slope m=2m = 2
The slope of a linear function can be determined by the formula m=f(x2)f(x1)x2x1m = \frac{f(x_2) - f(x_1)}{x_2 - x_1}. Substituting (2,1)(-2, 1) and (2,9)(2, 9) yields m=912(2)=84=2m = \frac{9 - 1}{2 - (-2)} = \frac{8}{4} = 2.
2
Find the y-intercept of the function to write its equation.
f(x)=2x+5f(x) = 2x + 5
Substituting the slope m=2m = 2 and the point (2,9)(2, 9) into the slope-intercept form f(x)=mx+bf(x) = mx + b gives 9=2(2)+b9 = 2(2) + b, which simplifies to b=5b = 5.
3
Evaluate the function for the input value 10.
f(10)=25f(10) = 25
Substituting x=10x = 10 into the linear function equation f(x)=2x+5f(x) = 2x + 5 yields f(10)=2(10)+5=25f(10) = 2(10) + 5 = 25.

Anahtar Kavram

Determining a linear function from a table of values and using it to find specific outputs.
Tahmini Süre:1m 30s
Soru 98Soru

If 56(y2)13(2y5)=32\frac{5}{6}(y - 2) - \frac{1}{3}(2y - 5) = \frac{3}{2}, what is the value of 4y4y?

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Cevap: 36

Cevap

The correct answer is 36.
To solve the equation 56(y2)13(2y5)=32\frac{5}{6}(y - 2) - \frac{1}{3}(2y - 5) = \frac{3}{2}, we first clear the fractions by multiplying the entire equation by the least common denominator, 6, which yields 5(y2)2(2y5)=95(y - 2) - 2(2y - 5) = 9. Distributing the terms on the left side gives 5y104y+10=95y - 10 - 4y + 10 = 9. Combining like terms simplifies this to y=9y = 9. The question asks for the value of 4y4y, so we multiply 99 by 44 to get the final answer of 3636.

Adım Adım Çözüm

1
Multiply both sides of the equation by the least common denominator, which is 6.
5(y2)2(2y5)=95(y - 2) - 2(2y - 5) = 9
Multiplying by 6 eliminates the fractions, simplifying the equation.
2
Distribute the coefficients across the parentheses.
5y104y+10=95y - 10 - 4y + 10 = 9
Expanding the terms allows like terms to be combined in the next step.
3
Combine the variable terms and constant terms on the left side of the equation.
y=9y = 9
Combining 5y4y5y - 4y yields yy, and combining 10+10-10 + 10 yields 00, isolating the variable.
4
Multiply the value of yy by 4.
4y=364y = 36
The question asks for the value of 4y4y rather than just yy.

Anahtar Kavram

Solving a linear equation in one variable by clearing fractions and combining like terms.
Soru 99Soru

A line in the xyxy-plane is defined by the equation 5y2x=155y - 2x = 15. What is the slope of the line?

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Cevap: 25\frac{2}{5}

Cevap

The slope of the line is 25\frac{2}{5}.
To find the slope of the line, convert the equation 5y2x=155y - 2x = 15 into slope-intercept form, y=mx+by = mx + b, where mm represents the slope. First, add 2x2x to both sides to get 5y=2x+155y = 2x + 15. Next, divide both sides by 55 to isolate yy, yielding y=25x+3y = \frac{2}{5}x + 3. In this form, the coefficient of xx is the slope, which is 25\frac{2}{5}.

Adım Adım Çözüm

1
Write the given equation of the line.
5y2x=155y - 2x = 15
To identify the slope, we need to manipulate the given equation.
2
Isolate the yy term on one side by adding 2x2x to both sides.
5y=2x+155y = 2x + 15
This is the first step in converting the equation to slope-intercept form (y=mx+by = mx + b).
3
Divide both sides of the equation by 55 to solve for yy.
y=25x+3y = \frac{2}{5}x + 3
Dividing isolates yy completely, putting the equation in the form y=mx+by = mx + b, where mm is the slope and bb is the yy-intercept.
4
Identify the slope mm from the equation.
The slope mm is 25\frac{2}{5}.
In the equation y=25x+3y = \frac{2}{5}x + 3, the coefficient of xx represents the slope of the line.

Anahtar Kavram

Slope of a line from its equation
Soru 100Soru

A linear equation models the total cost, in dollars, of purchasing xx pounds of almonds and yy pounds of walnuts. Under the original pricing, purchasing 88 pounds of almonds and 1515 pounds of walnuts costs cc dollars. If the price per pound of almonds is increased by 25%25\% and the price per pound of walnuts is decreased by 10%10\%, the cost of purchasing 88 pounds of almonds and 1515 pounds of walnuts is still cc dollars. Under the original pricing, a customer can purchase exactly 2222 pounds of almonds and no walnuts for cc dollars. How many pounds of walnuts and no almonds can the customer purchase for cc dollars under the original pricing?

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Cevap: 16.5

Cevap

16.5
Under the original pricing, the cost of 88 pounds of almonds at aa dollars per pound and 1515 pounds of walnuts at bb dollars per pound is represented by the linear equation 8a+15b=c8a + 15b = c. Under promotional pricing, the cost of almonds increases by 25%25\% to 1.25a1.25a, and the cost of walnuts decreases by 10%10\% to 0.90b0.90b. The new cost for the same amounts of nuts is 8(1.25a)+15(0.90b)=10a+13.5b=c8(1.25a) + 15(0.90b) = 10a + 13.5b = c. Setting the two cost equations equal to each other gives 8a+15b=10a+13.5b8a + 15b = 10a + 13.5b, which simplifies to 1.5b=2a1.5b = 2a, or a=0.75ba = 0.75b. Since 2222 pounds of almonds can be purchased for cc dollars, we have 22a=c22a = c. Substituting a=0.75ba = 0.75b yields 22(0.75b)=c22(0.75b) = c, which simplifies to 16.5b=c16.5b = c. Thus, exactly 16.516.5 pounds of walnuts can be purchased for cc dollars.

Adım Adım Çözüm

1
Set up the equation representing the total cost of the initial purchase under the original pricing.
8a+15b=c8a + 15b = c, where aa is the original price per pound of almonds and bb is the original price per pound of walnuts.
To represent the cost relation using the original individual prices of almonds and walnuts.
2
Modify the individual prices for the promotional rates and write the new total cost equation.
8(1.25a)+15(0.90b)=c    10a+13.5b=c8(1.25a) + 15(0.90b) = c \implies 10a + 13.5b = c.
The price per pound of almonds increases by 25%25\% (multiplied by 1.251.25) and the price per pound of walnuts decreases by 10%10\% (multiplied by 0.900.90).
3
Equate the two expressions representing cc to find the ratio between the prices aa and bb.
8a+15b=10a+13.5b    2a=1.5b    a=0.75b8a + 15b = 10a + 13.5b \implies 2a = 1.5b \implies a = 0.75b.
Since both purchasing combinations yield the same total budget cc, their cost equations are equal.
4
Use the budget equation for purchasing only almonds to determine the equivalent purchase in walnuts.
22a=c    22(0.75b)=c    16.5b=c22a = c \implies 22(0.75b) = c \implies 16.5b = c. Therefore, 16.516.5 pounds of walnuts can be bought for cc dollars.
Substituting the price relationship a=0.75ba = 0.75b allows expressing the budget cc purely in terms of the price of walnuts bb.

Anahtar Kavram

Modeling linear relationships in two variables and analyzing changes in coefficients.
ÖncekiSayfa 5 / 22Sonraki
Algebra Alıştırma Soruları — SAT — Sayfa 5 | Examkin