Tüm alıştırma soruları

4581 soru

Soru 801Soru

What is the unit digit of the expression K=(23385×43794)16847K = (233^{85} \times 437^{94}) - 168^{47}?

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Cevap: 5

Cevap

The unit digit of the given expression is 5.
To find the unit digit of K=(23385×43794)16847K = (233^{85} \times 437^{94}) - 168^{47}, analyze each term using base cyclicity rules:
1. 23385233^{85}: Base digit 3 has cyclicity 4. 85÷4=2185 \div 4 = 21 remainder 1. 31=33^1 = 3.
2. 43794437^{94}: Base digit 7 has cyclicity 4. 94÷4=2394 \div 4 = 23 remainder 2. 72=4997^2 = 49 \rightarrow 9.
3. Product unit digit: 3×9=2773 \times 9 = 27 \rightarrow 7.
4. 16847168^{47}: Base digit 8 has cyclicity 4. 47÷4=1147 \div 4 = 11 remainder 3. 83=51228^3 = 512 \rightarrow 2.
5. Subtracting gives 72=57 - 2 = 5.

Adım Adım Çözüm

1
Find the unit digit of 23385233^{85}
Unit digit is 3
The unit digit of powers of 3 follows a cycle of 4: (3, 9, 7, 1). Since 851(mod4)85 \equiv 1 \pmod 4, the unit digit is 31=33^1 = 3.
2
Find the unit digit of 43794437^{94}
Unit digit is 9
The unit digit of powers of 7 follows a cycle of 4: (7, 9, 3, 1). Since 942(mod4)94 \equiv 2 \pmod 4, the unit digit is 72=49    97^2 = 49 \implies 9.
3
Find the unit digit of the product (23385×43794)(233^{85} \times 437^{94})
Unit digit is 7
Multiplying the unit digits of the two terms gives 3×9=273 \times 9 = 27, which has a unit digit of 7.
4
Find the unit digit of 16847168^{47}
Unit digit is 2
The unit digit of powers of 8 follows a cycle of 4: (8, 4, 2, 6). Since 473(mod4)47 \equiv 3 \pmod 4, the unit digit is 83=512    28^3 = 512 \implies 2.
5
Calculate the final unit digit of the composite expression
5
Subtracting the unit digit of the subtracted term from the product's unit digit yields 72=57 - 2 = 5.

Anahtar Kavram

Unit Digit and Cyclicity
Tahmini Süre:1m 30s
Soru 802Soru

Determine the unit digit of the finite series and exponent tower expression S=k=150(k!)k!+777S = \sum_{k=1}^{50} (k!)^{k!} + 7^{7^7}.

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Cevap: 0

Cevap

The unit digit of the expression is 0.
The sum of the factorial terms from k=1 to k=4 contributes unit digits of 1, 4, 6, and 6, totaling 17 (unit digit 7). Terms for k >= 5 end in 0. The power tower term 7^(7^7) has an exponent 7^7 which leaves a remainder of 3 when divided by 4. Since the cyclicity of 7 is 4, 7^3 gives a unit digit of 3. Adding 7 and 3 results in 10, giving a final unit digit of 0.

Adım Adım Çözüm

1
Calculate unit digits of factorial terms for k from 1 to 4
Unit digits are 1, 4, 6, and 6 respectively
1! = 1, 2! = 2, 3! = 6, 4! = 24 (with base ending in 4 raised to an even power 24 giving unit digit 6)
2
Analyze factorial terms for k >= 5
Unit digit is 0 for all k >= 5
Factorials for k >= 5 contain factors 2 and 5, making the trailing digit 0
3
Sum the unit digits of the series sum
Sum of unit digits is 1 + 4 + 6 + 6 = 17, giving unit digit 7
Only terms from k = 1 to 4 contribute to the unit digit of the factorial sum
4
Find the unit digit of the power tower 7^(7^7) using cyclicity modulo 4
7^7 mod 4 = 3, so unit digit is 7^3 mod 10 = 3
The base 7 has a cyclicity of 4, and 7^7 is congruent to 3 modulo 4
5
Add the unit digits of both components
7 + 3 = 10, unit digit is 0
Combining the unit digit of the factorial sum (7) and the tower exponent term (3)

Anahtar Kavram

Combining factorial unit digit termination properties with exponent tower cyclicity modulo 4.
Soru 803Soru

What value is obtained upon simplifying the mathematical expression given below using the correct order of operations (BODMAS)?

87.5% of 120[225×{24.5(4.5÷2.40.9×1.6+115)}]87.5\% \text{ of } 120 - \left[ 2 \frac{2}{5} \times \left\{ 24.5 - \left( 4.5 \div \overline{2.4 - 0.9} \times 1.6 + 1 \frac{1}{5} \right) \right\} \right]
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Cevap: 60.660.6

Cevap

60.660.6
The correct result 60.660.6 is achieved by systematically resolving operations from the innermost group outward: first the bar/vinculum, followed by division and multiplication inside the parentheses, subtraction in the curly brackets, multiplication in the square brackets, and finally subtracting this total from 87.5%87.5\% of 120120.

Adım Adım Çözüm

1
Evaluate the expression under the vinculum (bar)
2.40.9=1.5\overline{2.4 - 0.9} = 1.5
The vinculum has the highest priority among grouping symbols.
2
Evaluate the terms inside the parentheses (...)(...) using BODMAS
4.5÷1.5×1.6+115=3×1.6+1.2=4.8+1.2=6.04.5 \div 1.5 \times 1.6 + 1 \frac{1}{5} = 3 \times 1.6 + 1.2 = 4.8 + 1.2 = 6.0
Perform division first (4.5÷1.5=34.5 \div 1.5 = 3), then multiplication (3×1.6=4.83 \times 1.6 = 4.8), and finally addition (4.8+1.2=6.04.8 + 1.2 = 6.0).
3
Simplify the expression inside the curly brackets {...}\{...\}
24.56.0=18.524.5 - 6.0 = 18.5
Subtract the result of the parentheses from 24.524.5.
4
Simplify the expression inside the square brackets [...][...]
225×18.5=2.4×18.5=44.42 \frac{2}{5} \times 18.5 = 2.4 \times 18.5 = 44.4
Convert the mixed fraction 2252 \frac{2}{5} to decimal 2.42.4 and multiply by 18.518.5.
5
Calculate the percentage value
87.5% of 120=78×120=10587.5\% \text{ of } 120 = \frac{7}{8} \times 120 = 105
Convert 87.5%87.5\% to the equivalent fraction 78\frac{7}{8} and multiply by 120120.
6
Perform the final subtraction
10544.4=60.6105 - 44.4 = 60.6
Subtract the value of the square brackets from the percentage result.

Anahtar Kavram

Strict evaluation of nested brackets (vinculum, round, curly, square) and mixed operators (percentage, fraction, division, multiplication) using the BODMAS rule.
Soru 804Soru

What is the final numerical value of the following expression evaluated using the standard BODMAS rule?

50[18÷3×(4+2)]50 - [18 \div 3 \times (4 + 2)]
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Cevap: 14

Cevap

The final simplified value of the expression is 14.
Following the BODMAS order of operations: first simplify the inner bracket (4+2)=6(4 + 2) = 6. Next, evaluate inside the square bracket from left to right: 18÷3=618 \div 3 = 6, and then 6×6=366 \times 6 = 36. Finally, subtract from 50 to get 5036=1450 - 36 = 14.

Adım Adım Çözüm

1
Evaluate the innermost round brackets
4+2=64 + 2 = 6
According to BODMAS, operations inside brackets must be performed first.
2
Perform division inside the square brackets
18÷3=618 \div 3 = 6
Division and multiplication have equal priority and are performed from left to right.
3
Perform multiplication inside the square brackets
6×6=366 \times 6 = 36
Multiply the quotient obtained from division by the bracketed sum.
4
Subtract the result inside brackets from 50
5036=1450 - 36 = 14
Perform subtraction as the final operation.

Anahtar Kavram

BODMAS / Order of Operations
Soru 805Soru

What is the unit digit of the composite expression E=(1!+2!+3!++20!)2026+(31×32×33××320)E = (1! + 2! + 3! + \dots + 20!)^{2026} + (3^1 \times 3^2 \times 3^3 \times \dots \times 3^{20})?

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Cevap: 8

Cevap

The unit digit of the expression is 8.
Evaluating the expression requires breaking it down into two components. First, for the factorial sum 1!+2!+3!++20!1! + 2! + 3! + \dots + 20!, every term from 5!5! onward contains factors of both 2 and 5, so its unit digit is 0. The unit digit of the sum is determined solely by 1!+2!+3!+4!=331! + 2! + 3! + 4! = 33, which has a unit digit of 3. Raising 3 to the power 2026 gives 320263^{2026}. Since the unit digits of powers of 3 repeat in cycles of 4 (3, 9, 7, 1) and 20262(mod4)2026 \equiv 2 \pmod 4, the unit digit of 320263^{2026} is 32=93^2 = 9.

Second, the product 31×32××3203^1 \times 3^2 \times \dots \times 3^{20} simplifies using the exponent addition rule to 31+2++20=32103^{1+2+\dots+20} = 3^{210}. Dividing 210 by 4 leaves a remainder of 2, so 32103^{210} also has a unit digit of 32=93^2 = 9.

Adding the unit digits of both terms gives 9+9=189 + 9 = 18, resulting in a final unit digit of 8.

Adım Adım Çözüm

1
Find the unit digit of the inner factorial sum S=1!+2!+3!++20!S = 1! + 2! + 3! + \dots + 20!.
The unit digit of SS is 3.
For all k5k \ge 5, k!k! is divisible by 10 and ends in 0. Thus, only the sum of the first four terms 1!+2!+3!+4!=1+2+6+24=331! + 2! + 3! + 4! = 1 + 2 + 6 + 24 = 33 determines the unit digit.
2
Calculate the unit digit of the first term S202632026S^{2026} \equiv 3^{2026}.
The unit digit of the first term is 9.
The unit digits of powers of 3 repeat in a cycle of 4 (3, 9, 7, 1). Dividing the exponent 2026 by 4 gives a remainder of 2 (2026=4×506+22026 = 4 \times 506 + 2). Therefore, the unit digit is 32=93^2 = 9.
3
Simplify the exponential product P=31×32×33××320P = 3^1 \times 3^2 \times 3^3 \times \dots \times 3^{20}.
The product simplifies to 32103^{210}.
By exponent multiplication rules, 31×32××320=3i=120i3^1 \times 3^2 \times \dots \times 3^{20} = 3^{\sum_{i=1}^{20} i}. The sum of the first 20 positive integers is 20×212=210\frac{20 \times 21}{2} = 210.
4
Calculate the unit digit of 32103^{210}.
The unit digit of the second term is 9.
Dividing the exponent 210 by 4 gives a remainder of 2 (210=4×52+2210 = 4 \times 52 + 2). Therefore, the unit digit is 32=93^2 = 9.
5
Combine the unit digits of the two terms.
The unit digit of EE is 8.
Adding the unit digits gives 9+9=189 + 9 = 18. The unit digit of 18 is 8.

Anahtar Kavram

Unit Digit and Cyclicity of Factorial and Exponential Expressions
Tahmini Süre:2m 0s
Soru 806Soru
What exact numerical result is obtained when simplifying the following multi-bracket expression according to the BODMAS order of operations?
75% of 240[38.5+{1512(6.8×2.54.2+3.8)÷0.5}]75\% \text{ of } 240 - \left[ 38.5 + \left\{ 15\frac{1}{2} - \left( 6.8 \times 2.5 - \overline{4.2 + 3.8} \right) \div 0.5 \right\} \right]
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Cevap: 144

Cevap

The final simplified numerical value of the given expression is 144.
Following the BODMAS rule strictly: first evaluate the vinculum 4.2+3.8=8\overline{4.2 + 3.8} = 8; then resolve round brackets (6.8×2.58=9)(6.8 \times 2.5 - 8 = 9); next resolve curly brackets (15.59÷0.5=2.5)(15.5 - 9 \div 0.5 = -2.5); then square brackets (38.52.5=36)(38.5 - 2.5 = 36); and finally compute 75% of 240=18075\% \text{ of } 240 = 180. Subtracting 3636 from 180180 gives the correct result of 144.

Adım Adım Çözüm

1
Evaluate the vinculum (bar) operator first
\overline{4.2 + 3.8} = 8
According to BODMAS, the vinculum takes precedence over round brackets.
2
Simplify the terms inside the round brackets (parentheses)
6.8 \times 2.5 - 8 = 17 - 8 = 9
Multiplication precedes subtraction inside the innermost round brackets.
3
Simplify the terms inside the curly brackets (braces)
15.5 - (9 \div 0.5) = 15.5 - 18 = -2.5
Division (9÷0.5=189 \div 0.5 = 18) is performed before subtracting from 15.515.5 (151215\frac{1}{2}).
4
Simplify the terms inside the square brackets
38.5 + (-2.5) = 36
Adding the negative result from the curly brackets to 38.538.5 yields 3636.
5
Calculate the percentage 'Of' operation and perform final subtraction
75\% \text{ of } 240 - 36 = 180 - 36 = 144
'Of' operation (75%×240=18075\% \times 240 = 180) is calculated before subtracting the bracketed total.

Anahtar Kavram

BODMAS Rule with Vinculum and Nested Brackets
Tahmini Süre:2m 0s
Soru 807Soru
What is the result when the mathematical expression 45[12+(8÷2×3)]45 - [12 + (8 \div 2 \times 3)] is simplified strictly adhering to the standard BODMAS order of operations?
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Cevap: 21

Cevap

21
Following the BODMAS rule, operations inside the innermost parentheses are solved first from left to right: 8÷2=48 \div 2 = 4, then 4×3=124 \times 3 = 12. Next, addition inside the square brackets gives 12+12=2412 + 12 = 24. Finally, subtracting 24 from 45 yields 21.

Adım Adım Çözüm

1
Evaluate division inside the parentheses
8 ÷ 2 = 4
Division and multiplication have equal priority and are evaluated from left to right inside parentheses.
2
Evaluate multiplication inside the parentheses
4 × 3 = 12
Completing the operations within the parentheses.
3
Add the values inside the square brackets
12 + 12 = 24
Evaluating the bracketed addition.
4
Subtract from the outer term
45 - 24 = 21
Performing final subtraction outside the brackets.

Anahtar Kavram

BODMAS Rule (Order of Operations)
Tahmini Süre:45s
Soru 808Soru

What is the unit digit of the composite exponential expression E=43345+8188062575E = 433^{45} + 818^{80} - 625^{75}?

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Cevap: 4

Cevap

4
Evaluating each term individually: 43345433^{45} has unit digit 33 (since 45(mod4)=145 \pmod 4 = 1), 81880818^{80} has unit digit 66 (since 80(mod4)=080 \pmod 4 = 0, giving the 4th power unit digit 8468^4 \rightarrow 6), and 62575625^{75} has unit digit 55. Combining these gives 3+65=43 + 6 - 5 = 4.

Adım Adım Çözüm

1
Find the unit digit of 43345433^{45}
Unit digit is 3
The unit digit of base 433 is 3. The cyclicity of 3 is 4 (31=3,32=9,33=7,34=13^1=3, 3^2=9, 3^3=7, 3^4=1). Dividing the exponent 45 by 4 gives 45=4×11+145 = 4 \times 11 + 1 (remainder 1). Thus, the unit digit is 31=33^1 = 3.
2
Find the unit digit of 81880818^{80}
Unit digit is 6
The unit digit of base 818 is 8. The cyclicity of 8 is 4 (81=8,82=4,83=2,84=68^1=8, 8^2=4, 8^3=2, 8^4=6). Dividing exponent 80 by 4 gives a remainder of 0. When remainder is 0, we take the 4th power, giving unit digit 66 (from 84=40968^4 = 4096).
3
Find the unit digit of 62575625^{75}
Unit digit is 5
The unit digit of base 625 is 5. Any positive integer power of a number ending in 5 always ends in 5 (cyclicity of 1).
4
Combine the unit digits of all terms
4
Substitute the individual unit digits into the expression: 3+65=43 + 6 - 5 = 4.

Anahtar Kavram

Unit Digit and Cyclicity Rules for Exponential Expressions
Soru 809Soru

Is the positive integer nn divisible by 3636?

Statement I: n2n^2 is divisible by 108108.
Statement II: n3n^3 is divisible by 576576.

Which of the following options correctly describes the sufficiency of the statements?

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Cevap: Both Statement I and Statement II together are sufficient to answer the question, but neither statement alone is sufficient.

Cevap

Both Statement I and Statement II together are sufficient to answer the question, but neither statement alone is sufficient.
Evaluating both statements together shows that Statement I requires nn to be a multiple of 1818 (21×322^1 \times 3^2) and Statement II requires nn to be a multiple of 1212 (22×312^2 \times 3^1). The least common multiple of 1818 and 1212 is 3636, which proves that nn is guaranteed to be divisible by 3636. Neither statement alone provides both prime factor requirements.

Adım Adım Çözüm

1
Analyze Statement I individually
Statement I states that n2n^2 is divisible by 108=22×33108 = 2^2 \times 3^3. In the prime factorization of a square n2n^2, all exponents must be even numbers. Thus, n2n^2 must contain at least 222^2 and 343^4. Taking square roots, nn must be a multiple of 21×32=182^1 \times 3^2 = 18. If n=18n = 18, nn is NOT divisible by 3636. If n=36n = 36, nn IS divisible by 3636. Because we get both 'No' and 'Yes' answers, Statement I alone is NOT sufficient.
We must test if Statement I uniquely determines whether nn is divisible by 3636.
2
Analyze Statement II individually
Statement II states that n3n^3 is divisible by 576=26×32576 = 2^6 \times 3^2. In the prime factorization of a cube n3n^3, all exponents must be multiples of 33. Thus, n3n^3 must contain at least 262^6 and 333^3. Taking cube roots, nn must be a multiple of 22×31=122^2 \times 3^1 = 12. If n=12n = 12, nn is NOT divisible by 3636. If n=36n = 36, nn IS divisible by 3636. Because we get both 'No' and 'Yes' answers, Statement II alone is NOT sufficient.
We must test if Statement II uniquely determines whether nn is divisible by 3636.
3
Combine Statement I and Statement II
From Statement I, nn contains at least 323^2 in its prime factorization. From Statement II, nn contains at least 222^2 in its prime factorization. Combining these requirements, nn must contain at least 22×32=362^2 \times 3^2 = 36. Therefore, nn is guaranteed to be divisible by 3636. Both statements together yield a definitive 'Yes'.
Evaluating both statements together combines the minimal necessary powers of each prime factor.

Anahtar Kavram

Data Sufficiency evaluation of prime factor exponents and divisibility rules
Tahmini Süre:2m 0s
Soru 810Soru

Determine the unit digit of the numerical expression N=(333444×444333)+(777888×888777)222555N = (333^{444} \times 444^{333}) + (777^{888} \times 888^{777}) - 222^{555}.

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Cevap: 4

Cevap

The unit digit of the given expression is 4.
By analyzing cyclicity of each base (3,4,7,8,23, 4, 7, 8, 2), we find that 3334441333^{444} \rightarrow 1, 4443334444^{333} \rightarrow 4, 7778881777^{888} \rightarrow 1, 8887778888^{777} \rightarrow 8, and 2225558222^{555} \rightarrow 8. Thus, the overall unit digit is (1×4)+(1×8)8=4+88=4(1 \times 4) + (1 \times 8) - 8 = 4 + 8 - 8 = 4.

Adım Adım Çözüm

1
Calculate unit digit of 333444×444333333^{444} \times 444^{333}
Unit digit is 4
Base 3 has cyclicity 4; 444(mod4)=0    341444 \pmod 4 = 0 \implies 3^4 \rightarrow 1. Base 4 has cyclicity 2; odd exponent 333    414333 \implies 4^1 \rightarrow 4. Total unit digit for term 1 = 1×4=41 \times 4 = 4.
2
Calculate unit digit of 777888×888777777^{888} \times 888^{777}
Unit digit is 8
Base 7 has cyclicity 4; 888(mod4)=0    741888 \pmod 4 = 0 \implies 7^4 \rightarrow 1. Base 8 has cyclicity 4; 777(mod4)=1    818777 \pmod 4 = 1 \implies 8^1 \rightarrow 8. Total unit digit for term 2 = 1×8=81 \times 8 = 8.
3
Calculate unit digit of 222555222^{555}
Unit digit is 8
Base 2 has cyclicity 4; 555(mod4)=3    238555 \pmod 4 = 3 \implies 2^3 \rightarrow 8.
4
Evaluate combined expression unit digit
4
Combine term unit digits: (4+88)=4(4 + 8 - 8) = 4.

Anahtar Kavram

Unit Digit and Cyclicity of Numbers
Soru 811Soru

What is the simplified value of the following mathematical expression evaluated using the standard BODMAS rule?

24+16÷4×2(752)24 + 16 \div 4 \times 2 - (7 - \overline{5 - 2})
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Cevap: 28

Cevap

28
Following the standard order of operations (BODMAS), we first simplify the expression under the vinculum bar: 52=35 - 2 = 3. Next, we complete the subtraction inside the parentheses: 73=47 - 3 = 4. Then, we resolve division and multiplication from left to right: 16÷4=416 \div 4 = 4, and 4×2=84 \times 2 = 8. Finally, combining addition and subtraction gives 24+84=2824 + 8 - 4 = 28.

Adım Adım Çözüm

1
Evaluate the expression under the vinculum (bar)
\overline{5 - 2} = 3
The vinculum takes the highest priority in bracket operations.
2
Evaluate the round brackets
(7 - 3) = 4
Operations within brackets must be solved next.
3
Perform Division and Multiplication from left to right
16 \div 4 = 4; \quad 4 \times 2 = 8
Division and multiplication share equal precedence and are performed in order from left to right.
4
Perform Addition and Subtraction from left to right
24 + 8 - 4 = 28
Final addition and subtraction operations are executed left-to-right.

Anahtar Kavram

BODMAS Rule with Vinculum (Order of Operations)
Soru 812Soru

What is the unit digit of the numerical expression N=(137137×264102)+619199N = (137^{137} \times 264^{102}) + 619^{199}?

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Cevap: 1

Cevap

1
The unit digit of 137137137^{137} is derived from 137(mod4)=1137 \pmod 4 = 1, giving 71=77^1 = 7. The unit digit of 264102264^{102} is 6 because the exponent 102 is even. Multiplying these unit digits gives 7×6=427 \times 6 = 42, which contributes a unit digit of 2. The unit digit of 619199619^{199} is 9 because 199 is odd. Adding the unit digits yields 2+9=112 + 9 = 11, whose unit digit is 1.

Adım Adım Çözüm

1
Determine the unit digit of 137137137^{137} using the cyclicity of 7.
The exponent 137 leaves a remainder of 1 when divided by 4, giving a unit digit of 71=77^1 = 7.
The unit digit pattern for powers of 7 repeats every 4 powers (7, 9, 3, 1).
2
Determine the unit digit of 264102264^{102} using the cyclicity of 4.
Since 102 is an even exponent, 4even4^{\text{even}} yields a unit digit of 6.
Powers of 4 end in 4 for odd exponents and 6 for even exponents.
3
Calculate the unit digit of the product (137137×264102)(137^{137} \times 264^{102}).
(7×6)=42(7 \times 6) = 42, which has a unit digit of 2.
The unit digit of a product depends only on the product of the unit digits of its factors.
4
Determine the unit digit of 619199619^{199} using the cyclicity of 9.
Since 199 is an odd exponent, 9odd9^{\text{odd}} yields a unit digit of 9.
Powers of 9 end in 9 for odd exponents and 1 for even exponents.
5
Sum the unit digits to find the final unit digit of expression NN.
2+9=112 + 9 = 11, which has a unit digit of 1.
The unit digit of the sum of two terms is the unit digit of the sum of their individual unit digits.

Anahtar Kavram

Unit digit determination using exponent cyclicity rules for base digits 4, 7, and 9.
Tahmini Süre:1m 15s
Soru 813Soru

If M=7+210+7210M = \sqrt{7 + 2\sqrt{10}} + \sqrt{7 - 2\sqrt{10}} and xx satisfies the exponential equation (43)2x1=(116)x4\left(\sqrt[3]{4}\right)^{2x-1} = \left(\frac{1}{16}\right)^{x-4} with (43)2x1=2k\left(\sqrt[3]{4}\right)^{2x-1} = 2^k, what is the value of M2+kM^2 + k?

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Cevap: 23.5

Cevap

The value of M2+kM^2 + k is 23.5.
By writing 7±2107 \pm 2\sqrt{10} as (5±2)2(\sqrt{5} \pm \sqrt{2})^2, the radical simplifies cleanly to M=25M = 2\sqrt{5}, giving M2=20M^2 = 20. Rewriting the index equation in terms of base 2 yields 4x23=4x+16\frac{4x-2}{3} = -4x + 16, which gives x=258x = \frac{25}{8} and exponent k=3.5k = 3.5. Adding M2M^2 and kk results in 23.5.

Adım Adım Çözüm

1
Simplify the nested surd expression for M
M = 2\sqrt{5}, so M^2 = 20
Recognize that 7±210=(5±2)27 \pm 2\sqrt{10} = (\sqrt{5} \pm \sqrt{2})^2.
2
Convert both sides of the exponential equation to base 2
24x23=24x+162^{\frac{4x-2}{3}} = 2^{-4x+16}
Apply laws of indices: 43=22/3\sqrt[3]{4} = 2^{2/3} and 116=24\frac{1}{16} = 2^{-4}.
3
Solve for x by equating the powers of 2
x=258=3.125x = \frac{25}{8} = 3.125
Since bases are equal, the powers must be equal.
4
Determine the exponent value k
k = 3.5
Substitute x into the exponent expression k=4x+16k = -4x + 16.
5
Calculate the final combined expression M^2 + k
23.5
Add M2=20M^2 = 20 and k=3.5k = 3.5.

Anahtar Kavram

Nested radical simplification using binomial square expansion combined with solving exponential equations via prime base unification.
Soru 814Soru

The Highest Common Factor (HCF) and Least Common Multiple (LCM) of two positive three-digit integers PP and QQ (where P>QP > Q) are 2424 and 10801080, respectively. If the difference between the two numbers is 9696, what is the sum of the two numbers (P+QP + Q)?

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Cevap: 336

Cevap

The sum of the two numbers P and Q is 336.
By representing P=24aP = 24a and Q=24bQ = 24b with gcd(a,b)=1\gcd(a, b) = 1, the relation HCF×LCM=P×Q\text{HCF} \times \text{LCM} = P \times Q yields a×b=45a \times b = 45. The coprime factor pairs of 4545 are (45,1)(45, 1) and (9,5)(9, 5). The pair (45,1)(45, 1) gives 10801080 and 2424, which are not both three-digit numbers. The pair (9,5)(9, 5) gives P=216P = 216 and Q=120Q = 120, both of which are three-digit numbers with a difference of 9696. The sum of these two numbers is 216+120=336216 + 120 = 336.

Adım Adım Çözüm

1
Express the two numbers in terms of their HCF and coprime factors
Let P=24aP = 24a and Q=24bQ = 24b where gcd(a,b)=1\gcd(a, b) = 1 and a>ba > b.
Any two numbers sharing an HCF of hh can be represented as hah \cdot a and hbh \cdot b where aa and bb have no common prime factors.
2
Relate the product of the coprime factors to the LCM and HCF
a×b=LCMHCF=108024=45a \times b = \frac{\text{LCM}}{\text{HCF}} = \frac{1080}{24} = 45.
The product of two numbers equals the product of their HCF and LCM: (24a)(24b)=24×1080(24a)(24b) = 24 \times 1080.
3
Identify all coprime factor pairs of 45
The coprime factor pairs (a,b)(a, b) with a>ba > b are (45,1)(45, 1) and (9,5)(9, 5).
Factor pairs such as (15,3)(15, 3) are invalid because gcd(15,3)=31\gcd(15, 3) = 3 \neq 1.
4
Apply the three-digit integer and difference constraints to select the valid pair
For (a,b)=(9,5)(a, b) = (9, 5), P=24×9=216P = 24 \times 9 = 216 and Q=24×5=120Q = 24 \times 5 = 120. Difference = 216120=96216 - 120 = 96.
The pair (45,1)(45, 1) yields P=1080P = 1080 (four digits) and Q=24Q = 24 (two digits), failing the three-digit criteria.
5
Calculate the sum of PP and QQ
P+Q=216+120=336P + Q = 216 + 120 = 336.
The question asks specifically for the sum P+QP + Q.

Anahtar Kavram

Properties of HCF and LCM including HCF x LCM = Product of Numbers and Prime Factor Coprimality
Soru 815Soru
What is the simplified numerical value of the following mathematical expression when evaluated strictly according to the BODMAS rule?
45[3×{12÷(1.5+2.71.2)}+2.5]×245 - \left[ 3 \times \left\{ 12 \div \left( 1.5 + \overline{2.7 - 1.2} \right) \right\} + 2.5 \right] \times 2
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Cevap: 16

Cevap

16
Evaluating the expression according to VBODMAS rules step-by-step: first the vinculum gives 1.5; adding inside round brackets gives 3; dividing inside curly braces gives 4; multiplying and adding inside square brackets gives 14.5; finally multiplying by 2 gives 29, and subtracting from 45 yields 16.

Adım Adım Çözüm

1
Evaluate the expression under the vinculum (bar)
\overline{2.7 - 1.2} = 1.5
According to VBODMAS, operations under a vinculum must be simplified first.
2
Simplify the expression inside the round brackets (parentheses)
1.5 + 1.5 = 3
Parentheses have priority after the vinculum is resolved.
3
Evaluate the division inside the curly braces
12÷3=412 \div 3 = 4
Operations within braces are evaluated next.
4
Simplify the expression inside the square brackets
3 \times 4 + 2.5 = 12 + 2.5 = 14.5
Inside brackets, multiplication takes precedence over addition.
5
Perform final operations outside brackets using standard operator precedence
45 - 14.5 \times 2 = 45 - 29 = 16
Multiplication must be executed before subtraction.

Anahtar Kavram

Hierarchy of operations in VBODMAS (Vinculum, Brackets, Orders, Division, Multiplication, Addition, Subtraction)
Soru 816Soru

A standard analog clock indicates the time is exactly 4:10. Calculate the smaller angle, in degrees, formed between the hour hand and the minute hand.

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Cevap: 65; 65°; 65 degrees

Cevap

65 degrees
At exactly 4:10, the minute hand has moved 6060^\circ from the top of the clock, and the hour hand has moved 120120^\circ for the four hours plus an extra 55^\circ for the ten minutes passed. The difference between their specific positions (125125^\circ and 6060^\circ) is exactly 6565^\circ.

Adım Adım Çözüm

1
Calculate the angular position of the minute hand relative to the 12 o'clock mark.
The minute hand is at 10 minutes, which corresponds to an angle of 10×6=6010 \times 6^\circ = 60^\circ.
The minute hand moves 360360^\circ in 60 minutes, which equals a speed of 66^\circ per minute.
2
Calculate the angular position of the hour hand relative to the 12 o'clock mark.
The hour hand has moved past the 4 o'clock mark. Its position is 4×30+10×0.5=120+5=1254 \times 30^\circ + 10 \times 0.5^\circ = 120^\circ + 5^\circ = 125^\circ.
The hour hand moves 3030^\circ per hour and an additional 0.50.5^\circ per minute due to continuous drift.
3
Find the absolute difference between the two angular positions to determine the angle between the hands.
12560=65|125^\circ - 60^\circ| = 65^\circ.
The angle between the two hands is simply the absolute difference of their individual positions from the 12 o'clock reference point.

Anahtar Kavram

Clock hand angular positioning and the calculation of hour-hand drift.
Soru 817Soru

As the Municipal Commissioner overseeing a high-value infrastructure tender, you are informed that the technical evaluation committee has shortlisted three firms. Just two days before the final financial bids are to be opened, you receive a credible anonymous email with documentary evidence showing that the Chief Engineer, who heads the evaluation committee, has a spouse holding significant undisclosed shares in the highest-rated firm. The project is already delayed by a year, and the allocated central funds will irrevocably lapse in 15 days if the contract is not awarded. What is the most administratively sound and ethically appropriate course of action?

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Cevap: Pause the financial bid opening, immediately constitute an independent fact-finding committee to verify the evidence within a strict timeframe, and officially apprise the funding agency of the situation to seek a provisional extension.

Cevap

Pause the financial bid opening, immediately constitute an independent fact-finding committee to verify the evidence within a strict timeframe, and officially apprise the funding agency of the situation to seek a provisional extension.
The correct course of action prioritizes institutional integrity and transparency. By pausing the process and initiating a time-bound inquiry, the administrator ensures due process is followed. By officially communicating with the funding agency, they handle the timeline pressure professionally without compromising ethical standards.

Adım Adım Çözüm

1
Analyze the core conflict presented in the scenario.
The tension is between upholding procedural integrity (addressing the conflict of interest) and meeting strict administrative deadlines (preventing the lapse of funds).
Identifying the competing values is essential for evaluating which course of action respects the hierarchy of administrative ethics.
2
Evaluate the legality and proportionality of immediate punitive actions.
Taking drastic measures like immediate suspension or blacklisting without formal verification violates natural justice.
Administrative decisions must be backed by formal inquiries, not just initial allegations or anonymous tips.
3
Assess the transparency and formal correctness of the proposed solutions.
The correct action must involve a formal halt, a time-bound objective investigation, and transparent communication with stakeholders (the funding agency).
Transparency and adherence to due process are paramount in public administration, taking precedence over informal compromises or rushed expediency.

Anahtar Kavram

Conflict of Interest Management and Due Process in Public Procurement
Tahmini Süre:2m 0s
Soru 818Soru

Let N=25×34×52N = 2^5 \times 3^4 \times 5^2. How many positive integer factors of NN are divisible by 1212 but not divisible by 1515?

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Cevap: 16

Cevap

16 positive factors
The number NN is given by 25×34×522^5 \times 3^4 \times 5^2. A factor 2a×3b×5c2^a \times 3^b \times 5^c is divisible by 12=22×3112 = 2^2 \times 3^1 if a{2,3,4,5}a \in \{2,3,4,5\} (4 choices), b{1,2,3,4}b \in \{1,2,3,4\} (4 choices), and c{0,1,2}c \in \{0,1,2\} (3 choices), giving 4×4×3=484 \times 4 \times 3 = 48 factors. Among these, those also divisible by 15=31×5115 = 3^1 \times 5^1 must be divisible by LCM(12,15)=60=22×31×51\text{LCM}(12,15) = 60 = 2^2 \times 3^1 \times 5^1, which restricts c{1,2}c \in \{1,2\} (2 choices), yielding 4×4×2=324 \times 4 \times 2 = 32 factors. Subtracting these gives 4832=1648 - 32 = 16 factors.

Adım Adım Çözüm

1
Express NN in prime factorized form and define the general structure of its factors.
Any positive factor of N=25×34×52N = 2^5 \times 3^4 \times 5^2 has the form k=2a×3b×5ck = 2^a \times 3^b \times 5^c, where 0a50 \le a \le 5, 0b40 \le b \le 4, and 0c20 \le c \le 2.
Prime factorization determines all possible divisors of a composite number.
2
Calculate the total number of factors divisible by 12=22×3112 = 2^2 \times 3^1.
For kk to be divisible by 12, we require a2a \ge 2 (a{2,3,4,5}a \in \{2,3,4,5\}, 4 choices), b1b \ge 1 (b{1,2,3,4}b \in \{1,2,3,4\}, 4 choices), and c0c \ge 0 (c{0,1,2}c \in \{0,1,2\}, 3 choices). Total factors = 4×4×3=484 \times 4 \times 3 = 48.
A factor contains another number as a divisor if all prime exponent lower bounds of the divisor are satisfied.
3
Calculate the number of factors divisible by both 1212 and 1515, which is equivalent to being divisible by LCM(12,15)=60=22×31×51\text{LCM}(12, 15) = 60 = 2^2 \times 3^1 \times 5^1.
For kk to be divisible by 60, we require a2a \ge 2 (4 choices), b1b \ge 1 (4 choices), and c1c \ge 1 (c{1,2}c \in \{1,2\}, 2 choices). Total factors = 4×4×2=324 \times 4 \times 2 = 32.
To exclude factors divisible by 15, we must find the intersection of multiples of 12 and multiples of 15.
4
Subtract the factors divisible by 60 from the factors divisible by 12.
Factors divisible by 12 but not by 15 = 4832=1648 - 32 = 16.
Applying the principle of set difference yields the exact count satisfying both conditions.

Anahtar Kavram

Counting Factors with Prime Factorization Constraints
Tahmini Süre:2m 0s
Soru 819Soru

For the composite numerical expression E=(412120+317201)814102E = (412^{120} + 317^{201}) - 814^{102}, which of the following represents its unit digit?

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Cevap: 7

Cevap

7
Evaluating each term by cyclicity yields unit digits of 6 for 412120412^{120}, 7 for 317201317^{201}, and 6 for 814102814^{102}. Combining these according to the operations gives (6+7)6=7(6 + 7) - 6 = 7, resulting in a unit digit of 7.

Adım Adım Çözüm

1
Determine the unit digit of 412120412^{120}
Unit digit is 6
The unit digit of base 412 is 2, which has a cyclicity of 4 (2, 4, 8, 6). The exponent 120 is divisible by 4 (120(mod4)=0120 \pmod 4 = 0), so we take the 4th power in the cycle: 24=162^4 = 16, giving a unit digit of 6.
2
Determine the unit digit of 317201317^{201}
Unit digit is 7
The unit digit of base 317 is 7, which has a cyclicity of 4 (7, 9, 3, 1). The exponent remainder is 201(mod4)=1201 \pmod 4 = 1, corresponding to 71=77^1 = 7.
3
Determine the unit digit of 814102814^{102}
Unit digit is 6
The unit digit of base 814 is 4, which has a cyclicity of 2 (4 for odd powers, 6 for even powers). Since 102 is an even exponent, the unit digit is 6.
4
Combine the unit digits according to the expression E=(412120+317201)814102E = (412^{120} + 317^{201}) - 814^{102}
Unit digit is 7
Adding the unit digits of the first two terms gives 6+7=136 + 7 = 13, which has a unit digit of 3. Subtracting 6 gives 36=33 - 6 = -3, which in modulo 10 arithmetic yields 136=713 - 6 = 7.

Anahtar Kavram

Cyclicity of numbers and modular arithmetic for unit digit determination
Tahmini Süre:1m 30s
Soru 820Soru

The table below shows the annual wheat production (in metric tonnes) across four agricultural zones from 2021 to 2023:

Agricultural Zone202120222023
Zone A150180210
Zone B200250300
Zone C100120150
Zone D300330360

Which of the following statements regarding the data given in the table are correct?

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Cevap: Zone A registered a 20%20\% growth in wheat production from 2021 to 2022.; In 2023, the wheat production of Zone B was exactly double that of Zone C.

Cevap

The correct statements are that Zone A registered a 20%20\% growth in wheat production from 2021 to 2022, and in 2023, the wheat production of Zone B was exactly double that of Zone C.
Zone A's production grew from 150150 to 180180 tonnes, which is a growth of 30150×100%=20%\frac{30}{150} \times 100\% = 20\%. In 2023, Zone B produced 300300 tonnes while Zone C produced 150150 tonnes, making Zone B's production exactly double that of Zone C.

Adım Adım Çözüm

1
Calculate the percentage growth for Zone A from 2021 to 2022.
Percentage increase = 180150150×100%=20%\frac{180 - 150}{150} \times 100\% = 20\%. Statement is correct.
To verify the growth statement for Zone A using the base year 2021 value (150150).
2
Compare Zone B and Zone C production figures for the year 2023.
Zone B produced 300300 tonnes and Zone C produced 150150 tonnes. Ratio = 300150=2\frac{300}{150} = 2. Statement is correct.
To check if Zone B production was double that of Zone C in 2023.
3
Calculate the percentage increase for Zone D from 2021 to 2022.
Percentage increase = 330300300×100%=10%15%\frac{330 - 300}{300} \times 100\% = 10\% \neq 15\%. Statement is incorrect.
To evaluate the claim regarding Zone D's percentage growth.
4
Calculate the total wheat production of Zone C across 2021, 2022, and 2023.
Total = 100+120+150=370100 + 120 + 150 = 370 tonnes 400\neq 400 tonnes. Statement is incorrect.
To verify the three-year total production claim for Zone C.

Anahtar Kavram

Tabular Data Interpretation and Percentage Growth Analysis
ÖncekiSayfa 41 / 230Sonraki
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