Tüm alıştırma soruları

4581 soru

Soru 861Soru

A logistics company assigns identification codes to container shipments based on a positive integer NN. The number NN has exactly 2424 positive factors, and its prime factorization contains only the prime factors 22, 33, and 77. If NN is a multiple of 1414 and the number of odd positive factors of NN is 66, what is the smallest possible value of NN?

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Cevap: 504504

Cevap

The smallest possible value of NN is 504504.
The number 504504 has prime factorization 23×32×712^3 \times 3^2 \times 7^1. Total positive factors = (3+1)(2+1)(1+1)=24(3+1)(2+1)(1+1) = 24, and odd positive factors = (2+1)(1+1)=6(2+1)(1+1) = 6. It is divisible by 1414 (504=14×36504 = 14 \times 36) and is the smaller of the two valid numbers (504504 and 11761176).

Adım Adım Çözüm

1
Express NN in terms of its prime factors.
N=2a×3b×7cN = 2^a \times 3^b \times 7^c, where a1,b1,c1a \ge 1, b \ge 1, c \ge 1 as NN contains prime factors 2,3,2, 3, and 77, and is a multiple of 14=2×714 = 2 \times 7.
The question specifies that NN is divisible by 1414 and contains prime factors 22, 33, and 77.
2
Formulate equations for total factors and odd factors.
Total positive factors T(N)=(a+1)(b+1)(c+1)=24T(N) = (a + 1)(b + 1)(c + 1) = 24. Odd positive factors depend only on odd prime powers (3b×7c3^b \times 7^c), so (b+1)(c+1)=6(b + 1)(c + 1) = 6.
Odd factors correspond to choosing 20=12^0 = 1 for the even prime factor.
3
Solve for exponent aa.
(a+1)×6=24    a+1=4    a=3(a + 1) \times 6 = 24 \implies a + 1 = 4 \implies a = 3.
Dividing total factors by odd factors isolates the term (a+1)(a + 1).
4
Find possible values for bb and cc.
Since (b+1)(c+1)=6(b + 1)(c + 1) = 6 with b,c1b, c \ge 1, the possible factor pairs for (b+1,c+1)(b+1, c+1) are (2,3)(2, 3) or (3,2)(3, 2). Case 1: b=1,c=2    N=23×31×72=1176b=1, c=2 \implies N = 2^3 \times 3^1 \times 7^2 = 1176. Case 2: b=2,c=1    N=23×32×71=504b=2, c=1 \implies N = 2^3 \times 3^2 \times 7^1 = 504.
Integer factorizations of 66 give two distinct exponent assignments.
5
Determine the minimum value.
Comparing 504504 and 11761176, the minimum value is 504504.
Assigning the larger exponent to the smaller prime base (33 instead of 77) minimizes the product.

Anahtar Kavram

Factors and Prime Factorization Constraints
Tahmini Süre:2m 0s
Soru 862Soru

What is the total number of positive even factors of the integer 180180?

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Cevap: 12

Cevap

The total number of positive even factors of 180180 is 1212.
The prime factorization of 180180 is 22×32×512^2 \times 3^2 \times 5^1. An even factor must be divisible by 22, so the power of 22 must be either 11 or 22 (22 choices). The power of 33 can be 0,1,0, 1, or 22 (33 choices), and the power of 55 can be 00 or 11 (22 choices). Total even factors = 2×3×2=122 \times 3 \times 2 = 12.

Adım Adım Çözüm

1
Express 180180 in terms of its prime factors.
180=22×32×51180 = 2^2 \times 3^2 \times 5^1
Prime factorization allows systematic calculation of factor counts using exponent combinations.
2
Determine the number of valid choices for each prime factor's exponent to form an even factor.
Choices for exponent of 22: 11 or 22 (22 choices). Choices for exponent of 33: 0,10, 1, or 22 (33 choices). Choices for exponent of 55: 00 or 11 (22 choices).
An even factor must contain at least one factor of 22, so the exponent of 22 cannot be 00.
3
Multiply the counts of choices together.
2×3×2=122 \times 3 \times 2 = 12
By the fundamental principle of counting, multiplying the available choices for each prime factor gives the total number of even factors.

Anahtar Kavram

Counting Even Factors using Prime Factorization
Soru 863Soru

Under a State Skill Development Mission, a total of 4,5004,500 candidates were enrolled across three vocational sectors: IT & Electronics, Healthcare & Allied Sciences, and Textile & Apparel. The IT & Electronics sector accounted for 40%40\% of the total enrolled candidates. The ratio of candidates enrolled in Healthcare & Allied Sciences to those in Textile & Apparel was 7:87 : 8. Upon completion of the training, 65%65\% of the enrolled candidates in IT & Electronics successfully obtained certification. The number of certified candidates in Healthcare & Allied Sciences was equal to 80%80\% of the certified candidates in IT & Electronics. If the total number of certified candidates across all three sectors combined was 2,8982,898, what percentage of the enrolled candidates in the Textile & Apparel sector successfully obtained certification?

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Cevap: 55

Cevap

The certification percentage of enrolled candidates in the Textile & Apparel sector is 55%55\%.
To find the certification percentage for the Textile & Apparel sector, first determine the enrollment figures: IT & Electronics has 1,8001,800 candidates (40%40\% of 4,5004,500), leaving 2,7002,700 candidates split in a 7:87 : 8 ratio between Healthcare (1,2601,260) and Textile (1,4401,440). Next, calculate certified candidates: IT & Electronics has 1,1701,170 certified (65%65\% of 1,8001,800), and Healthcare has 936936 certified (80%80\% of 1,1701,170). Subtracting these from the total 2,8982,898 certified candidates leaves 792792 certified candidates in Textile & Apparel. Finally, 7921,440×100%=55%\frac{792}{1,440} \times 100\% = 55\%.

Adım Adım Çözüm

1
Calculate the number of candidates enrolled in IT & Electronics
Enrolled in IT & Electronics = 0.40×4,500=1,8000.40 \times 4,500 = 1,800 candidates.
IT & Electronics accounts for 40%40\% of the overall 4,5004,500 candidates.
2
Determine enrollment in Healthcare & Allied Sciences and Textile & Apparel
Remaining candidates = 4,5001,800=2,7004,500 - 1,800 = 2,700. Enrolled in Healthcare = 715×2,700=1,260\frac{7}{15} \times 2,700 = 1,260. Enrolled in Textile = 815×2,700=1,440\frac{8}{15} \times 2,700 = 1,440.
The remaining 2,7002,700 candidates are distributed between Healthcare and Textile in the ratio 7:87 : 8 (total 1515 parts).
3
Calculate certified candidates in IT & Electronics
Certified in IT & Electronics = 0.65×1,800=1,1700.65 \times 1,800 = 1,170 candidates.
65%65\% of the enrolled IT & Electronics candidates achieved certification.
4
Calculate certified candidates in Healthcare & Allied Sciences
Certified in Healthcare = 0.80×1,170=9360.80 \times 1,170 = 936 candidates.
Healthcare certified candidates equal 80%80\% of certified candidates in IT & Electronics.
5
Determine certified candidates in Textile & Apparel
Certified in Textile = 2,898(1,170+936)=2,8982,106=7922,898 - (1,170 + 936) = 2,898 - 2,106 = 792 candidates.
Total certified across all sectors is 2,8982,898.
6
Compute the certification rate for Textile & Apparel
Certification percentage = (7921,440)×100%=55%\left(\frac{792}{1,440}\right) \times 100\% = 55\%.
Divide certified Textile candidates by total enrolled Textile candidates and convert to percentage.

Anahtar Kavram

Data extraction, ratio partitioning, and sequential percentage calculation from unstructured text caselets.
Soru 864Soru

Is the integer xx odd?

Statement (I): x2+3xx^2 + 3x is an even integer.
Statement (II): x+5x + 5 is an even integer.

Which of the following options is correct?

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Cevap: Statement (II) alone is sufficient, but Statement (I) alone is not sufficient.

Cevap

Statement (II) alone is sufficient, but Statement (I) alone is not sufficient.
Evaluating Statement (I): x2+3x=x(x+3)x^2 + 3x = x(x+3). The product of any integer xx and (x+3)(x+3) is always even because one of the two numbers is always even. Thus, Statement (I) provides no specific information about whether xx is odd or even, making it insufficient. Evaluating Statement (II): x+5=evenx + 5 = \text{even}. Subtracting the odd integer 55 from an even integer yields an odd integer, so xx must be odd. Hence, Statement (II) alone is sufficient to answer the question definitively.

Adım Adım Çözüm

1
Evaluate Statement (I) individually.
Rewrite the expression as x2+3x=x(x+3)x^2 + 3x = x(x + 3). If xx is even, then x(x+3)=even×odd=evenx(x + 3) = \text{even} \times \text{odd} = \text{even}. If xx is odd, then x(x+3)=odd×even=evenx(x + 3) = \text{odd} \times \text{even} = \text{even}. Thus, x2+3xx^2 + 3x is always even regardless of whether xx is odd or even.
Since the statement holds true for all integers xx, it cannot determine whether xx is odd. Therefore, Statement (I) alone is NOT sufficient.
2
Evaluate Statement (II) individually.
The statement gives that x+5x + 5 is an even integer. Since 55 is an odd integer, Odd+Odd=Even\text{Odd} + \text{Odd} = \text{Even}, which implies xx must be an odd integer.
This yields a definitive 'Yes' answer to the question 'Is xx odd?'. Therefore, Statement (II) alone IS sufficient.
3
Conclude the data sufficiency evaluation.
Statement (II) alone is sufficient to answer the question, but Statement (I) alone is not sufficient.
Each statement was evaluated independently first, rendering statement combination unnecessary.

Anahtar Kavram

Data Sufficiency Parity Analysis
Tahmini Süre:1m 30s
Soru 865Soru

The table below presents the operational performance and energy distribution metrics of four regional power grids during FY 2025–26. Net available energy for distribution is determined by first deducting transmission and storage losses from total generation, and then subtracting auxiliary station consumption.

Regional GridTotal Energy Generated (GWh)Transmission & Storage Loss (%)Auxiliary Station Consumption (GWh)Commercial Sector Share of Net Available Energy (%)
Northern Grid12,00015%20040%
Southern Grid15,00012%40035%
Eastern Grid10,00020%30050%
Western Grid18,00010%20025%

Based on the data provided, what is the ratio of the total energy distributed to the commercial sector by the Southern Grid to the combined energy distributed to the commercial sector by the Northern and Western Grids?

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Cevap: 14 : 25

Cevap

The ratio of energy distributed to the commercial sector by the Southern Grid to the combined commercial distribution of the Northern and Western Grids is 14 : 25.
The correct option stating '14 : 25' accurately follows the prescribed two-stage deduction process. For the Southern Grid, subtracting 12% loss (1,800 GWh1,800\text{ GWh}) from 15,000 GWh15,000\text{ GWh} gives 13,200 GWh13,200\text{ GWh}, and subtracting 400 GWh400\text{ GWh} auxiliary consumption leaves 12,800 GWh12,800\text{ GWh}. Applying 35%35\% yields 4,480 GWh4,480\text{ GWh}. For the Northern Grid, net energy is (12,0001,800)200=10,000 GWh(12,000 - 1,800) - 200 = 10,000\text{ GWh}, giving 40%×10,000=4,000 GWh40\% \times 10,000 = 4,000\text{ GWh}. For the Western Grid, net energy is (18,0001,800)200=16,000 GWh(18,000 - 1,800) - 200 = 16,000\text{ GWh}, giving 25%×16,000=4,000 GWh25\% \times 16,000 = 4,000\text{ GWh}. Combining Northern and Western gives 8,000 GWh8,000\text{ GWh}. The ratio 4,4808,000\frac{4,480}{8,000} simplifies precisely to 14:2514 : 25.

Adım Adım Çözüm

1
Calculate the net available energy and commercial distribution for the Southern Grid.
Net Available = (15,0000.12×15,000)400=(15,0001,800)400=12,800 GWh(15,000 - 0.12 \times 15,000) - 400 = (15,000 - 1,800) - 400 = 12,800\text{ GWh}. Commercial Distribution = 35% of 12,800=4,480 GWh35\% \text{ of } 12,800 = 4,480\text{ GWh}.
Transmission loss must be deducted from total generation first, followed by auxiliary consumption.
2
Calculate the net available energy and commercial distribution for the Northern Grid.
Net Available = (12,0000.15×12,000)200=(12,0001,800)200=10,000 GWh(12,000 - 0.15 \times 12,000) - 200 = (12,000 - 1,800) - 200 = 10,000\text{ GWh}. Commercial Distribution = 40% of 10,000=4,000 GWh40\% \text{ of } 10,000 = 4,000\text{ GWh}.
Required to compute the combined baseline for Northern and Western grids.
3
Calculate the net available energy and commercial distribution for the Western Grid.
Net Available = (18,0000.10×18,000)200=(18,0001,800)200=16,000 GWh(18,000 - 0.10 \times 18,000) - 200 = (18,000 - 1,800) - 200 = 16,000\text{ GWh}. Commercial Distribution = 25% of 16,000=4,000 GWh25\% \text{ of } 16,000 = 4,000\text{ GWh}.
Required to complete the denominator sum of the target ratio.
4
Compute the target ratio of Southern Grid commercial distribution to Northern + Western Grid commercial distribution.
Combined Northern + Western = 4,000+4,000=8,000 GWh4,000 + 4,000 = 8,000\text{ GWh}. Ratio = 4,480:8,000=14:254,480 : 8,000 = 14 : 25.
Simplifying 4,4808,000\frac{4,480}{8,000} by dividing both terms by their greatest common divisor 160160 yields 14:2514 : 25.

Anahtar Kavram

Multi-step tabular data interpretation involving sequential percentage reduction, absolute deductions, and ratio simplification.
Soru 866Soru

What is the simplified numerical value of the mathematical expression given below when evaluated strictly according to the VBODMAS rule?

16.5+{4.5×[12(3.2+4.81.6÷0.8)]}16.5 + \left\{ 4.5 \times \left[ 12 - \left( 3.2 + \overline{4.8 - 1.6} \div 0.8 \right) \right] \right\}
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Cevap: 38.138.1

Cevap

The simplified numerical value of the expression is 38.138.1.
Following the VBODMAS priority sequence: resolving the vinculum gives 3.23.2; evaluating division inside the round bracket yields 3.2÷0.8=43.2 \div 0.8 = 4; finishing the round bracket yields 3.2+4=7.23.2 + 4 = 7.2; evaluating the square bracket gives 127.2=4.812 - 7.2 = 4.8; evaluating the curly bracket gives 4.5×4.8=21.64.5 \times 4.8 = 21.6; finally, adding 16.5+21.616.5 + 21.6 yields 38.138.1.

Adım Adım Çözüm

1
Evaluate the expression under the vinculum (bar)
4.81.6=3.2\overline{4.8 - 1.6} = 3.2
According to the VBODMAS rule, operations under a vinculum take highest priority.
2
Evaluate the division inside the innermost round bracket
3.2÷0.8=43.2 \div 0.8 = 4
Division takes precedence over addition within parentheses.
3
Complete the evaluation inside the round bracket
3.2+4=7.23.2 + 4 = 7.2
Add the remaining terms within the round bracket.
4
Evaluate the expression inside the square bracket
127.2=4.812 - 7.2 = 4.8
Subtract the result of the round bracket from 1212.
5
Evaluate the multiplication inside the curly bracket
4.5×4.8=21.64.5 \times 4.8 = 21.6
Multiply the term outside the square bracket by the simplified square bracket value.
6
Perform the final addition
16.5+21.6=38.116.5 + 21.6 = 38.1
Add the initial constant to the simplified curly bracket term.

Anahtar Kavram

Order of Operations (VBODMAS Rule)
Tahmini Süre:1m 30s
Soru 867Soru

A large water reservoir is equipped with two inlet pipes, Pipe PP and Pipe QQ, each filling the reservoir at its own constant rate. How many hours will it take to fill the empty reservoir if both pipes operate simultaneously from the start?

Statement (I): Pipe PP alone can fill the empty reservoir in 15 hours15\text{ hours}.
Statement (II): Pipe QQ fills the reservoir at a rate that is 50%50\% higher than the filling rate of Pipe PP.

Which of the following options correctly evaluates the sufficiency of the statements?

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Cevap: Both Statement (I) and Statement (II) together are sufficient to answer the question, but neither statement alone is sufficient.

Cevap

Both Statement (I) and Statement (II) together are sufficient to answer the question, but neither statement alone is sufficient.
Evaluating Statement (I) alone gives only the individual performance of Pipe P, which is insufficient to determine the combined time. Statement (II) alone provides only a relative ratio between the rates of Pipe P and Pipe Q without any concrete time metric, making it insufficient on its own. When both statements are combined, Statement (I) provides the base rate for Pipe P and Statement (II) allows calculation of Pipe Q's rate, leading to a unique answer of 6 hours for the combined operation.

Adım Adım Çözüm

1
Evaluate Statement (I) alone
Pipe PP's rate is 115\frac{1}{15} of the reservoir per hour. However, no information is given regarding Pipe QQ's rate.
Statement (I) alone is insufficient to calculate the combined time.
2
Evaluate Statement (II) alone
Pipe QQ's rate is 1.51.5 times Pipe PP's rate, meaning Rate(QQ) =1.5×= 1.5 \times Rate(PP).
Statement (II) alone gives only a relative ratio of work rates, with no numerical time value given, so it is insufficient.
3
Evaluate Statements (I) and (II) together
From Statement (I), Rate(PP) =115= \frac{1}{15} reservoir/hour. From Statement (II), Rate(QQ) =1.5×115=110= 1.5 \times \frac{1}{15} = \frac{1}{10} reservoir/hour. Combined rate =115+110=16= \frac{1}{15} + \frac{1}{10} = \frac{1}{6} reservoir/hour. Thus, total combined time =6 hours= 6\text{ hours}.
Combining both statements yields a unique and definitive answer.

Anahtar Kavram

Data Sufficiency in Work and Time / Rate Problems
Soru 868Soru

A teacher wants to divide 8484 students into equal groups such that the number of students in each group is a prime factor of 8484. What is the sum of all distinct prime numbers that can represent the size of these groups?

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Cevap: 1212

Cevap

The sum of all distinct prime group sizes is 1212.
The prime factorization of 8484 is 22×3×72^2 \times 3 \times 7. The distinct prime factors are 22, 33, and 77. Summing these distinct prime numbers yields 2+3+7=122 + 3 + 7 = 12.

Adım Adım Çözüm

1
Find the prime factorization of 8484.
84=22×31×7184 = 2^2 \times 3^1 \times 7^1.
Decomposing 8484 into prime factors reveals all prime numbers that divide 8484 exactly.
2
Identify the distinct prime factors of 8484.
The distinct prime factors are 22, 33, and 77.
The question specifies distinct prime factors, so each prime base is listed once regardless of its exponent.
3
Calculate the sum of these distinct prime factors.
2+3+7=122 + 3 + 7 = 12.
Adding the distinct prime factors gives the sum of all possible prime group sizes.

Anahtar Kavram

Prime Factorization and Distinct Prime Factors
Soru 869Soru

Let NN be a positive integer with the prime factorization N=24×32×53N = 2^4 \times 3^2 \times 5^3. Which of the following statements regarding the positive factors of NN are correct?

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Cevap: The total number of positive factors of NN that are perfect squares is 1212.; The number of positive factors of NN that are divisible by 1515 is 3030.

Cevap

The correct statements are that the total number of positive factors of NN that are perfect squares is 1212, and the number of positive factors of NN that are divisible by 1515 is 3030.
The statement asserting that NN has 1212 factors that are perfect squares is correct because choosing even powers (0,2,40, 2, 4 for 22; 0,20, 2 for 33; and 0,20, 2 for 55) yields 3×2×2=123 \times 2 \times 2 = 12 factors. The statement asserting that 3030 factors are divisible by 1515 is also correct because forcing exponents of 33 and 55 to be at least 11 yields 5×2×3=305 \times 2 \times 3 = 30 factors.

Adım Adım Çözüm

1
Analyze the prime factorization N=24×32×53N = 2^4 \times 3^2 \times 5^3
Any positive factor of NN is of the form 2a×3b×5c2^a \times 3^b \times 5^c, where 0a40 \le a \le 4, 0b20 \le b \le 2, and 0c30 \le c \le 3.
By the Fundamental Theorem of Arithmetic, factors inherit prime bases with constrained exponents.
2
Count the number of factors that are perfect squares
For a perfect square, a{0,2,4}a \in \{0, 2, 4\} (3 choices), b{0,2}b \in \{0, 2\} (2 choices), and c{0,2}c \in \{0, 2\} (2 choices). Total square factors =3×2×2=12= 3 \times 2 \times 2 = 12.
All prime exponents in a perfect square must be even non-negative integers.
3
Count the number of factors divisible by 1515
Since 15=31×5115 = 3^1 \times 5^1, a{0,1,2,3,4}a \in \{0, 1, 2, 3, 4\} (5 choices), b{1,2}b \in \{1, 2\} (2 choices), and c{1,2,3}c \in \{1, 2, 3\} (3 choices). Total factors divisible by 15=5×2×3=3015 = 5 \times 2 \times 3 = 30.
Divisibility by 1515 mandates at least one factor of 33 and at least one factor of 55.
4
Verify even and odd factor counts to evaluate the remaining claims
Even factors require a1a \ge 1, giving 4×3×4=484 \times 3 \times 4 = 48 even factors. Odd factors require a=0a = 0, giving 1×3×4=121 \times 3 \times 4 = 12 odd factors.
Evaluating a1a \ge 1 vs a=0a = 0 confirms that claims specifying 5050 even factors and 1515 odd factors are incorrect.

Anahtar Kavram

Counting factors with constrained exponents in prime factorizations
Soru 870Soru
What is the final numerical value of the following expression when evaluated strictly according to the VBODMAS rule?
12.5×4[16+{25÷(3.5+2.81.3)}]12.5 \times 4 - \left[ 16 + \left\{ 25 \div \left( 3.5 + \overline{2.8 - 1.3} \right) \right\} \right]
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Cevap: 29

Cevap

The simplified numerical value of the expression is 29.
Applying VBODMAS step-by-step resolves the vinculum first (2.8 - 1.3 = 1.5), then the round brackets (3.5 + 1.5 = 5), curly brackets (25 / 5 = 5), square brackets (16 + 5 = 21), and finally the multiplication and subtraction (50 - 21 = 29).

Adım Adım Çözüm

1
Evaluate the vinculum (bar) operation first
\overline{2.8 - 1.3} = 1.5
According to VBODMAS, the vinculum takes top priority over all other operations.
2
Simplify the expression inside the innermost round brackets
3.5 + 1.5 = 5
Next in hierarchy are the round brackets (parentheses).
3
Simplify the expression inside the curly brackets
25÷5=525 \div 5 = 5
Evaluate operations inside curly braces next.
4
Simplify the expression inside the square brackets
16 + 5 = 21
Complete the evaluation of the outer square brackets.
5
Perform the multiplication and final subtraction outside the brackets
12.5 \times 4 = 50 \text{ and then } 50 - 21 = 29
Perform multiplication before final subtraction following standard operator precedence.

Anahtar Kavram

VBODMAS Rule (Vinculum, Brackets, Orders, Division, Multiplication, Addition, Subtraction)
Tahmini Süre:1m 30s
Soru 871Soru

A positive integer NN has the prime factorization N=2a×3b×5cN = 2^a \times 3^b \times 5^c, where aa, bb, and cc are positive integers. It is known that NN has exactly 4848 positive factors, N/2N/2 has 3636 positive factors, and N/5N/5 has 4040 positive factors. What is the total number of positive factors of N/3N/3?

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Cevap: 24

Cevap

The total number of positive factors of N/3N/3 is 24.
By writing the factor formula (a+1)(b+1)(c+1)=48(a+1)(b+1)(c+1) = 48 and comparing it with d(N/2)=a(b+1)(c+1)=36d(N/2) = a(b+1)(c+1) = 36 and d(N/5)=(a+1)(b+1)c=40d(N/5) = (a+1)(b+1)c = 40, we uniquely determine the exponents a=3a = 3, b=1b = 1, and c=5c = 5. Dividing NN by 33 changes the prime exponent of 33 to 00. Applying the factor count formula to 23×30×552^3 \times 3^0 \times 5^5 yields (3+1)(0+1)(5+1)=24(3+1)(0+1)(5+1) = 24.

Adım Adım Çözüm

1
Express the total number of factors of NN using its prime factorization
d(N)=(a+1)(b+1)(c+1)=48d(N) = (a+1)(b+1)(c+1) = 48
The number of positive factors of a number p1e1p2e2pkekp_1^{e_1} p_2^{e_2} \dots p_k^{e_k} is given by (e1+1)(e2+1)(ek+1)(e_1+1)(e_2+1)\dots(e_k+1).
2
Use the factor counts of N/2N/2 and N/5N/5 to determine the exponents aa and cc
a=3a = 3 and c=5c = 5
Since d(N/2)=a(b+1)(c+1)=36d(N/2) = a(b+1)(c+1) = 36, taking the ratio d(N/2)/d(N)d(N/2)/d(N) yields a/(a+1)=36/48=3/4a/(a+1) = 36/48 = 3/4, which gives a=3a = 3. Similarly, d(N/5)=(a+1)(b+1)c=40d(N/5) = (a+1)(b+1)c = 40, so d(N/5)/d(N)=c/(c+1)=40/48=5/6d(N/5)/d(N) = c/(c+1) = 40/48 = 5/6, giving c=5c = 5.
3
Solve for the remaining exponent bb
b=1b = 1
Substituting a=3a = 3 and c=5c = 5 into d(N)=48d(N) = 48 gives (3+1)(b+1)(5+1)=48    24(b+1)=48    b+1=2    b=1(3+1)(b+1)(5+1) = 48 \implies 24(b+1) = 48 \implies b+1 = 2 \implies b = 1.
4
Calculate the number of positive factors of N/3N/3
d(N/3)=(3+1)(0+1)(5+1)=4×1×6=24d(N/3) = (3+1)(0+1)(5+1) = 4 \times 1 \times 6 = 24
Dividing NN by 33 reduces the exponent of 33 from b=1b = 1 to b1=0b-1 = 0, so N/3=23×30×55N/3 = 2^3 \times 3^0 \times 5^5.

Anahtar Kavram

Prime Factorization and Number of Factors
Tahmini Süre:2m 0s
Soru 872Soru

Consider the positive integer 9090. Which of the following statements regarding the factors and prime factorization of 9090 are correct?

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Cevap: The prime factorization of 9090 is 21×32×512^1 \times 3^2 \times 5^1.; The total number of positive factors of 9090 is 1212.

Cevap

The prime factorization of 90 is 2^1 × 3^2 × 5^1, and the total number of positive factors of 90 is 12.
The prime factorization of 90 is indeed 2^1 × 3^2 × 5^1. The total number of positive factors is calculated as (1+1)(2+1)(1+1) = 12, making both statement options correct.

Adım Adım Çözüm

1
Find the prime factorization of 90.
90 = 2 × 45 = 2 × 3^2 × 5 = 2^1 × 3^2 × 5^1.
Decomposing 90 into prime base powers establishes the prime factorization.
2
Calculate the total number of positive factors using exponents.
Total factors = (1 + 1)(2 + 1)(1 + 1) = 2 × 3 × 2 = 12.
Adding 1 to each prime exponent and multiplying gives the total factor count.
3
Verify even factors and prime factor sum.
Even factors = 1 × (2 + 1)(1 + 1) = 6. Distinct prime sum = 2 + 3 + 5 = 10.
Confirming additional properties disproves the incorrect statements.

Anahtar Kavram

Prime factorization and formulas for determining total and specific factor counts of an integer
Soru 873Soru

The table below details raw material procurement, fabric output, and sales revenues across four regional textile development clusters for FY 2024–25:

Textile ClusterRaw Cotton Procured ('000 MT)Fabric Produced ('000 metres)Export Value (₹ Crores)Domestic Sales (₹ Crores)
Cluster A40320160240
Cluster B50500300200
Cluster C60480240360
Cluster D30240180120

What is the absolute difference (in ₹ Crores) between the average domestic sales across all four clusters and the domestic sales of the cluster that achieved the highest fabric production efficiency per unit of raw cotton procured?

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Cevap: ₹30 Crores

Cevap

The absolute difference is ₹30 Crores.
The correct answer is ₹30 Crores. Fabric production efficiency per unit of raw cotton is calculated as Fabric Produced ('000 metres) divided by Raw Cotton Procured ('000 MT). Cluster B yields 500 / 50 = 10 metres/MT, which is the highest among all clusters (others yield 8 metres/MT). Cluster B's domestic sales are ₹200 Crores. The average domestic sales across all clusters is (240 + 200 + 360 + 120) / 4 = ₹230 Crores. The absolute difference between ₹230 Crores and ₹200 Crores is ₹30 Crores.

Adım Adım Çözüm

1
Calculate fabric production efficiency per unit of raw cotton procured for each cluster
Cluster A: 320 / 40 = 8 metres/MT; Cluster B: 500 / 50 = 10 metres/MT; Cluster C: 480 / 60 = 8 metres/MT; Cluster D: 240 / 30 = 8 metres/MT.
To identify which cluster achieved the highest fabric production per unit of raw cotton procured.
2
Identify the domestic sales of the most efficient cluster
Cluster B achieved the highest efficiency (10 metres/MT). Its domestic sales volume is ₹200 Crores.
This provides the targeted cluster's metric for comparison.
3
Calculate the average domestic sales across all four clusters
Total Domestic Sales = 240 + 200 + 360 + 120 = ₹920 Crores. Average Domestic Sales = 920 / 4 = ₹230 Crores.
To determine the benchmark average domestic sales across the dataset.
4
Compute the absolute difference
| ₹230 Crores - ₹200 Crores | = ₹30 Crores.
To answer the final question requirement.

Anahtar Kavram

Data grid ratio comparison and benchmark deviation analysis
Soru 874Soru

A rectangular courtyard measuring 105 cm105\text{ cm} in length and 135 cm135\text{ cm} in width is to be completely paved with identical square tiles without cutting any tile. What is the maximum possible side length of each square tile?

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Cevap: 15 cm15\text{ cm}

Cevap

The maximum possible side length of each square tile is 15 cm15\text{ cm}.
The maximum side length of a square tile that fits exact integer counts along both length and width is given by HCF(105,135)\text{HCF}(105, 135). By prime factorization, 105=3×5×7105 = 3 \times 5 \times 7 and 135=33×5135 = 3^3 \times 5. The common prime factors are 33 and 55, each with lowest power 11. Therefore, HCF=3×5=15 cm\text{HCF} = 3 \times 5 = 15\text{ cm}.

Adım Adım Çözüm

1
Identify the required mathematical operation
To find the maximum side length of identical square tiles that fit whole dimensions of 105 cm105\text{ cm} and 135 cm135\text{ cm}, find the Highest Common Factor (HCF) of 105105 and 135135.
The side of each square tile must divide both the length and the width completely, and to maximize tile size, we need the largest such divisor.
2
Perform prime factorization of both numbers
105=3×5×7105 = 3 \times 5 \times 7
135=33×5=3×3×3×5135 = 3^3 \times 5 = 3 \times 3 \times 3 \times 5
Expressing numbers as products of prime factors allows easy identification of common factors.
3
Calculate the HCF using prime powers
HCF(105,135)=31×51=15\text{HCF}(105, 135) = 3^1 \times 5^1 = 15
HCF is obtained by taking the product of the smallest powers of all common prime factors.

Anahtar Kavram

Application of HCF and Prime Factorization in Spatial Tiling Problems
Tahmini Süre:45s
Soru 875Soru

Let N=25×34×52N = 2^5 \times 3^4 \times 5^2. How many positive integer factors of NN are divisible by 1212 but not divisible by 7272?

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Cevap: 21

Cevap

21
The correct answer is 21. By analyzing the exponent bounds of 2a×3b×5c2^a \times 3^b \times 5^c, there are 48 factors of NN divisible by 1212 (a2,b1a \ge 2, b \ge 1). Among these, 27 factors are also divisible by 7272 (a3,b2a \ge 3, b \ge 2). Subtracting the two counts gives 4827=2148 - 27 = 21 factors divisible by 12 but not by 72.

Adım Adım Çözüm

1
Represent the general form of a factor of NN
Every positive factor of N=25×34×52N = 2^5 \times 3^4 \times 5^2 can be uniquely written as f=2a×3b×5cf = 2^a \times 3^b \times 5^c, where a{0,1,2,3,4,5}a \in \{0, 1, 2, 3, 4, 5\}, b{0,1,2,3,4}b \in \{0, 1, 2, 3, 4\}, and c{0,1,2}c \in \{0, 1, 2\}.
By the Fundamental Theorem of Arithmetic, any factor of a number in prime-factored form takes exponents bounded by the original number's exponents.
2
Identify exponent constraints for divisibility by 12
Since 12=22×3112 = 2^2 \times 3^1, for ff to be divisible by 1212, we must have a2a \ge 2 and b1b \ge 1.
Divisibility requires prime factor exponents in the factor to be at least as large as those in the divisor.
3
Calculate the total number of factors divisible by 12
Number of choices for aa: 52+1=45 - 2 + 1 = 4 (values 2,3,4,52, 3, 4, 5). Number of choices for bb: 41+1=44 - 1 + 1 = 4 (values 1,2,3,41, 2, 3, 4). Number of choices for cc: 20+1=32 - 0 + 1 = 3 (values 0,1,20, 1, 2). Total count = 4×4×3=484 \times 4 \times 3 = 48.
By the multiplication principle of counting, independent choices for each exponent are multiplied.
4
Identify exponent constraints and count factors divisible by 72
Since 72=23×3272 = 2^3 \times 3^2, a factor is divisible by 7272 if a3a \ge 3 and b2b \ge 2. Number of choices: a{3,4,5}a \in \{3, 4, 5\} (3 choices), b{2,3,4}b \in \{2, 3, 4\} (3 choices), c{0,1,2}c \in \{0, 1, 2\} (3 choices). Total count = 3×3×3=273 \times 3 \times 3 = 27.
Every factor of NN that is divisible by 72 is inherently also a factor divisible by 12, forming a strict subset.
5
Apply the principle of subtraction to find the required count
Required count = (Factors divisible by 12) - (Factors divisible by 72) = 4827=2148 - 27 = 21.
The set of factors divisible by 12 but not by 72 is the set difference between factors divisible by 12 and factors divisible by 72.

Anahtar Kavram

Counting Factors with Divisibility Constraints using Prime Factorization
Tahmini Süre:2m 0s
Soru 876Soru
Calculate the exact numerical value of the given mathematical expression using the VBODMAS rule:
35 of 250[42+{24÷(7.54.2+0.3)}]\frac{3}{5} \text{ of } 250 - \left[ 42 + \left\{ 24 \div \left( 7.5 - \overline{4.2 + 0.3} \right) \right\} \right]
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Cevap: 100

Cevap

100
Evaluating strictly according to VBODMAS order of operations yields 100: Vinculum gives 4.5, round brackets give 3, division in curly brackets gives 8, addition in square brackets gives 50, 'of' operation gives 150, and 150 - 50 = 100.

Adım Adım Çözüm

1
Evaluate the expression under the vinculum (bar line)
4.2 + 0.3 = 4.5
According to the VBODMAS rule, the vinculum takes precedence over standard brackets and operations.
2
Simplify the innermost round brackets
7.5 - 4.5 = 3
Operations inside round parentheses ( ) are resolved next.
3
Evaluate the expression inside the curly brackets
24 / 3 = 8
Perform the division operation inside curly braces { }.
4
Evaluate the expression inside the square brackets
42 + 8 = 50
Perform addition within the outer square brackets [ ].
5
Calculate the 'of' operation
(3/5) * 250 = 150
The 'of' operation takes priority over standard addition and subtraction outside brackets.
6
Perform final subtraction
150 - 50 = 100
Subtract the total evaluated bracketed quantity from the 'of' calculation result.

Anahtar Kavram

Hierarchical priority of operations in VBODMAS involving vinculum, nested brackets, and fractional 'of' operations
Soru 877Soru

A positive integer NN has exactly 1515 positive factors and is divisible by 66. If NN has exactly two distinct prime factors, what is the sum of all possible values of NN that are less than 500500?

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Cevap: 468

Cevap

The sum of all possible values of N less than 500 is 468.
For a number N=pa×qbN = p^a \times q^b to have 15 factors, (a+1)(b+1)=15(a+1)(b+1) = 15. The factor pairs of 15 for two prime factors are (5,3)(5, 3) and (3,5)(3, 5), which correspond to exponent pairs (4,2)(4, 2) and (2,4)(2, 4). Since NN is divisible by 6, its prime factors are 2 and 3. Computing both cases gives 24×32=1442^4 \times 3^2 = 144 and 22×34=3242^2 \times 3^4 = 324. Both are less than 500, making their sum 144+324=468144 + 324 = 468.

Adım Adım Çözüm

1
Determine the prime factors of N
N has prime factors 2 and 3
Since N is divisible by 6, it must have at least 2 and 3 as prime factors. The problem states N has exactly two distinct prime factors, so its prime factorization is of the form N=2a×3bN = 2^a \times 3^b.
2
Apply the total factors formula
(a+1)(b+1)=15(a + 1)(b + 1) = 15
The total number of positive factors of N=pa×qbN = p^a \times q^b is given by (a+1)(b+1)=15(a + 1)(b + 1) = 15.
3
Find valid non-negative integer pairs (a, b)
Either (a=4,b=2)(a=4, b=2) or (a=2,b=4)(a=2, b=4)
Since 15 factors into 5×35 \times 3 or 3×53 \times 5 (note that 15×115 \times 1 would imply only one prime factor, which contradicts having two distinct prime factors), the possible exponent pairs are (4,2)(4, 2) and (2,4)(2, 4).
4
Calculate the values of N and check bounds
N1=24×32=144N_1 = 2^4 \times 3^2 = 144 and N2=22×34=324N_2 = 2^2 \times 3^4 = 324
Both 144<500144 < 500 and 324<500324 < 500 meet all conditions.
5
Sum the valid values of N
144+324=468144 + 324 = 468
Adding the two valid integers yields the total sum.

Anahtar Kavram

Factors and Prime Factorization Exponent Rule
Soru 878Soru

Three church bells toll together at intervals of 99 minutes, 1212 minutes, and 1515 minutes respectively. If they all toll together at 8:00 AM8:00\text{ AM}, at what time will they next toll together?

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Cevap: 11:00 AM

Cevap

11:00 AM
The bells will toll together after a duration equal to the Least Common Multiple (LCM) of their individual tolling intervals. The prime factorizations are 9=329 = 3^2, 12=22×312 = 2^2 \times 3, and 15=3×515 = 3 \times 5. Taking the highest power of each prime factor yields LCM(9,12,15)=22×32×5=180\text{LCM}(9, 12, 15) = 2^2 \times 3^2 \times 5 = 180 minutes, which is equal to 33 hours. Adding 33 hours to 8:00 AM8:00\text{ AM} gives 11:00 AM11:00\text{ AM}.

Adım Adım Çözüm

1
Find prime factorizations of each interval
9=329 = 3^2, 12=22×312 = 2^2 \times 3, and 15=3×515 = 3 \times 5
To compute the Least Common Multiple (LCM), express each number in prime factor form.
2
Calculate the LCM
LCM(9,12,15)=22×32×5=4×9×5=180 minutes\text{LCM}(9, 12, 15) = 2^2 \times 3^2 \times 5 = 4 \times 9 \times 5 = 180\text{ minutes}
Take the highest power of each prime factor involved.
3
Convert minutes to hours and add to the initial time
180 minutes=3 hours180\text{ minutes} = 3\text{ hours}; 8:00 AM+3 hours=11:00 AM8:00\text{ AM} + 3\text{ hours} = 11:00\text{ AM}
Determine the exact time the bells will next chime together.

Anahtar Kavram

Application of Least Common Multiple (LCM) in Simultaneous Periodic Events
Soru 879Soru
What is the simplified numerical value of the following mathematical expression when evaluated strictly according to the VBODMAS rule?
40% of 150[16+{20÷(8.53.1+1.4)}]40\% \text{ of } 150 - \left[ 16 + \left\{ 20 \div \left( 8.5 - \overline{3.1 + 1.4} \right) \right\} \right]
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Cevap: 39

Cevap

39
Evaluating strictly by VBODMAS priority: first the vinculum yields 4.5, then the round bracket gives 8.5 - 4.5 = 4, then division yields 20 ÷ 4 = 5, followed by square bracket addition 16 + 5 = 21. Finally, subtracting 21 from 40% of 150 (which is 60) gives 60 - 21 = 39.

Adım Adım Çözüm

1
Evaluate the expression under the vinculum (bar)
\overline{3.1 + 1.4} = 4.5
The vinculum has the highest priority and must be evaluated first.
2
Evaluate the terms inside the round brackets
8.5 - 4.5 = 4
The next priority is resolving the innermost parentheses.
3
Perform division inside the curly brackets
20÷4=520 \div 4 = 5
Inside curly brackets, division takes precedence over addition.
4
Evaluate the terms inside the square brackets
16 + 5 = 21
Resolve the outer square bracket by adding the terms.
5
Calculate the percentage term
40\% \text{ of } 150 = \frac{40}{100} \times 150 = 60
'Of' represents multiplication in percentage operations.
6
Perform final subtraction
60 - 21 = 39
Subtract the total bracket value from the percentage calculation.

Anahtar Kavram

VBODMAS Rule (Vinculum, Brackets, Orders, Division, Multiplication, Addition, Subtraction)
Soru 880Soru

Consider the positive integer N=720N = 720, which has a prime factorization of 24×32×512^4 \times 3^2 \times 5^1. Which of the following statements regarding the positive factors of NN are correct?

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Cevap: The number of positive factors of NN that are perfect squares is 66.; The sum of all positive even factors of NN is 23402340.; The product of all positive factors of NN is equal to 72015720^{15}.

Cevap

The correct statements are those asserting that NN has 6 perfect square factors, that the sum of all positive even factors of NN is 2340, and that the product of all positive factors of NN is 72015720^{15}.
The statements confirming 6 perfect square factors, a sum of 2340 for even factors, and a factor product of 72015720^{15} are all mathematically correct applications of prime factorization principles.

Adım Adım Çözüm

1
Determine perfect square factors of N=24×32×51N = 2^4 \times 3^2 \times 5^1
For a factor 2a×3b×5c2^a \times 3^b \times 5^c to be a square, exponents a,b,ca, b, c must be even. Possible values: a{0,2,4}a \in \{0, 2, 4\} (3 options), b{0,2}b \in \{0, 2\} (2 options), c{0}c \in \{0\} (1 option). Number of square factors =3×2×1=6= 3 \times 2 \times 1 = 6.
Perfect squares require all prime factors to have even exponents.
2
Calculate the sum of all positive even factors
Sum of all factors =(20+21+22+23+24)(30+31+32)(50+51)=31×13×6=2418= (2^0+2^1+2^2+2^3+2^4)(3^0+3^1+3^2)(5^0+5^1) = 31 \times 13 \times 6 = 2418. Sum of odd factors (only 202^0) =1×13×6=78= 1 \times 13 \times 6 = 78. Sum of even factors =241878=2340= 2418 - 78 = 2340.
Even factors are obtained by subtracting odd factor sum from total factor sum.
3
Count factors divisible by 15
Since 15=31×5115 = 3^1 \times 5^1, factors of 720 divisible by 15 require a{0,1,2,3,4}a \in \{0, 1, 2, 3, 4\} (5 choices), b{1,2}b \in \{1, 2\} (2 choices), and c{1}c \in \{1\} (1 choice). Total factors =5×2×1=10= 5 \times 2 \times 1 = 10.
Divisibility by 15 requires at least power 1 for both prime factors 3 and 5.
4
Compute the product of all positive factors
Total factors T=(4+1)(2+1)(1+1)=30T = (4+1)(2+1)(1+1) = 30. Product of factors =NT/2=72030/2=72015= N^{T/2} = 720^{30/2} = 720^{15}.
Factors pair up such that fi×fT+1i=Nf_i \times f_{T+1-i} = N, giving T/2T/2 pairs.

Anahtar Kavram

Properties of positive factors derived from prime factorization: square factor counts, even factor sums, constrained divisibility factor counts, and total factor product formula.
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