Tüm alıştırma soruları

4581 soru

Soru 841Soru

Determine the exact numerical value of the following mathematical expression when evaluated strictly according to the VBODMAS rule:

45[15+{24÷(3+12 of (1682))}]45 - \left[ 15 + \left\{ 24 \div \left( 3 + \frac{1}{2} \text{ of } \left( 16 - \overline{8 - 2} \right) \right) \right\} \right]
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Cevap: 27

Cevap

The simplified numerical value of the given expression is 27.
Evaluating step-by-step using VBODMAS order of precedence (Vinculum -> Brackets -> Of -> Division -> Multiplication -> Addition -> Subtraction) yields the simplified result 27.

Adım Adım Çözüm

1
Evaluate the vinculum (bar) operation
\overline{8 - 2} = 6
According to VBODMAS, operations under a vinculum take precedence over standard bracket operations.
2
Simplify the innermost subtraction inside the round brackets
16 - 6 = 10
Subtracted the value obtained from the vinculum within the innermost parentheses.
3
Evaluate the 'of' operator
\frac{1}{2} \text{ of } 10 = 5
The 'of' operator represents multiplication with priority immediately following brackets.
4
Complete the addition in the round brackets
3 + 5 = 8
Evaluated the remaining addition within the round brackets.
5
Perform division inside the curly brackets
24÷8=324 \div 8 = 3
Divided 24 by the simplified result of the round brackets.
6
Perform addition inside the square brackets
15 + 3 = 18
Added 15 to the result from the curly brackets.
7
Perform final subtraction
45 - 18 = 27
Subtracted the square bracket result from 45 to obtain the final simplified value.

Anahtar Kavram

Order of Operations (VBODMAS Rule)
Tahmini Süre:1m 30s
Soru 842Soru

What is the unit digit of the expression S=284+497×354945S = 2^{84} + 4^{97} \times 3^{54} - 9^{45}?

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Cevap: 3

Cevap

The unit digit of the expression is 3.
The unit digit of 2842^{84} is 6 (since 84 is a multiple of 4, corresponding to the 4th position in cyclicity). The product 497×3544^{97} \times 3^{54} has a unit digit of (4×9)(mod10)=6(4 \times 9) \pmod{10} = 6. The unit digit of 9459^{45} is 9. Substituting these into the original expression yields 6+69=36 + 6 - 9 = 3.

Adım Adım Çözüm

1
Find the unit digit of 2842^{84}
Unit digit is 6
The cyclicity of 22 is 44 (2,4,8,62, 4, 8, 6). Since 84÷4=2184 \div 4 = 21 with remainder 00, we take the 4th term in the cyclicity pattern, which is 66.
2
Find the unit digit of 4974^{97} and 3543^{54}
Unit digit of 4974^{97} is 4; Unit digit of 3543^{54} is 9
The cyclicity of 44 is 22 (44 for odd powers, 66 for even powers). Since 9797 is odd, 4974^{97} ends in 44. The cyclicity of 33 is 44 (3,9,7,13, 9, 7, 1). Since 54=4×13+254 = 4 \times 13 + 2, remainder is 22, giving 32=93^2 = 9.
3
Find the unit digit of the product 497×3544^{97} \times 3^{54}
Unit digit of product is 6
Multiplying the unit digits: 4×9=364 \times 9 = 36, so the unit digit is 66.
4
Find the unit digit of 9459^{45}
Unit digit is 9
The cyclicity of 99 is 22 (99 for odd powers, 11 for even powers). Since 4545 is odd, 9459^{45} ends in 99.
5
Combine the unit digits following the algebraic operations
Unit digit is 3
Evaluating 6+69=129=36 + 6 - 9 = 12 - 9 = 3.

Anahtar Kavram

Unit Digit and Cyclicity of Exponential Numbers
Soru 843Soru

If x=11+461146x = \sqrt{11 + 4\sqrt{6}} - \sqrt{11 - 4\sqrt{6}} and (116)x215=64y+1\left(\frac{1}{16}\right)^{x^2 - 15} = 64^{y + 1}, what is the value of yy?

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Cevap: 1

Cevap

The value of yy is 11.
Simplifying 11±46\sqrt{11 \pm 4\sqrt{6}} as 8±3\sqrt{8} \pm \sqrt{3} yields x=23x = 2\sqrt{3} and x2=12x^2 = 12. Substituting x2x^2 gives (1/16)3=163=212(1/16)^{-3} = 16^3 = 2^{12}. Matching exponents with 64y+1=26y+664^{y+1} = 2^{6y+6} yields 12=6y+612 = 6y + 6, giving y=1y = 1.

Adım Adım Çözüm

1
Simplify the nested surds for xx
x=23x = 2\sqrt{3}
Express 11±4611 \pm 4\sqrt{6} as 11±224=(8±3)211 \pm 2\sqrt{24} = (\sqrt{8} \pm \sqrt{3})^2, giving 11+461146=(22+3)(223)=23\sqrt{11 + 4\sqrt{6}} - \sqrt{11 - 4\sqrt{6}} = (2\sqrt{2} + \sqrt{3}) - (2\sqrt{2} - \sqrt{3}) = 2\sqrt{3}.
2
Evaluate x2x^2
x2=12x^2 = 12
Squaring x=23x = 2\sqrt{3} yields x2=4×3=12x^2 = 4 \times 3 = 12.
3
Substitute x2=12x^2 = 12 into the exponent of the given equation
(116)3=64y+1\left(\frac{1}{16}\right)^{-3} = 64^{y + 1}
The exponent x215x^2 - 15 evaluates to 1215=312 - 15 = -3.
4
Convert both sides to a common prime base (base 2)
212=26y+62^{12} = 2^{6y + 6}
(116)3=163=(24)3=212\left(\frac{1}{16}\right)^{-3} = 16^3 = (2^4)^3 = 2^{12} and 64y+1=(26)y+1=26y+664^{y + 1} = (2^6)^{y + 1} = 2^{6y + 6}.
5
Equate powers and solve for yy
y=1y = 1
Since the bases are identical, 12=6y+6    6y=6    y=112 = 6y + 6 \implies 6y = 6 \implies y = 1.

Anahtar Kavram

Nested surd evaluation via perfect square conversion combined with solving exponential equations using index rules.
Soru 844Soru

In a state public health drive conducted across three administrative zones—Zone X, Zone Y, and Zone Z—a total of 12,00012,000 vaccines were administered. Zone X received 35%35\% of the total vaccines administered. In Zone Y, the total number of vaccines administered was 800800 more than that in Zone X, and the ratio of vaccines administered to children versus adults was 2:32 : 3. The remaining vaccines were administered in Zone Z, where 60%60\% of the recipients were adults and the rest were children. If 40%40\% of the recipients in Zone X were children, what is the total number of children who received vaccines across all three zones combined?

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Cevap: 4,8004,800

Cevap

4,8004,800 children received vaccines across all three zones combined.
The total vaccines administered across the three zones equal 12,00012,000. Zone X accounts for 35%35\% (4,2004,200 vaccines), of which 40%40\% are children (1,6801,680). Zone Y receives 800800 more than Zone X (5,0005,000 vaccines), with children making up 2/52/5 of this amount (2,0002,000). Zone Z receives the remaining 2,8002,800 vaccines, where 40%40\% are children (1,1201,120). Adding these together (1,680+2,000+1,1201,680 + 2,000 + 1,120) yields 4,8004,800.

Adım Adım Çözüm

1
Calculate total vaccines and child recipients in Zone X
Total in Zone X = 0.35×12,000=4,2000.35 \times 12,000 = 4,200. Children in Zone X = 0.40×4,200=1,6800.40 \times 4,200 = 1,680.
Zone X receives 35%35\% of total vaccines, and 40%40\% of Zone X recipients are children.
2
Calculate total vaccines and child recipients in Zone Y
Total in Zone Y = 4,200+800=5,0004,200 + 800 = 5,000. Children in Zone Y = 22+3×5,000=25×5,000=2,000\frac{2}{2 + 3} \times 5,000 = \frac{2}{5} \times 5,000 = 2,000.
Zone Y receives 800800 more vaccines than Zone X, and children make up 22 parts out of 55 total parts.
3
Calculate total vaccines and child recipients in Zone Z
Total in Zone Z = 12,000(4,200+5,000)=2,80012,000 - (4,200 + 5,000) = 2,800. Children percentage in Zone Z = 100%60%=40%100\% - 60\% = 40\%. Children in Zone Z = 0.40×2,800=1,1200.40 \times 2,800 = 1,120.
Zone Z receives the remainder of total vaccines, and children constitute the remaining 40%40\% of Zone Z recipients.
4
Sum child recipients across all three zones
Total children = 1,680+2,000+1,120=4,8001,680 + 2,000 + 1,120 = 4,800.
Adding the child counts from Zone X, Zone Y, and Zone Z yields the final combined total.

Anahtar Kavram

Multi-step quantitative extraction, ratio division, and percentage base calculation from paragraph-based caselets.
Tahmini Süre:2m 30s
Soru 845Soru

If January 10, 1896, was a Friday, what day of the week was January 10, 1908?

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Cevap: Friday

Cevap

Friday
The correct day is Friday because evaluating the 12-year interval from January 10, 1896, to January 10, 1908, yields exactly 14 odd days. This breaks down into 12 baseline days (one for each year) plus 2 extra days for the leap years explicitly crossed (1896 and 1904). Importantly, the year 1900 is not a leap year, and the leap day of 1908 is not reached. Because 14 is perfectly divisible by 7 (remainder 0), the day of the week does not shift.

Adım Adım Çözüm

1
Calculate the total number of years between the two dates.
The total span from January 10, 1896, to January 10, 1908, is exactly 12 years.
Each standard year contributes 1 odd day (since 365 mod 7 = 1) to the day of the week progression.
2
Identify the number of leap years crossed within this specific time frame.
The leap days crossed belong to the years 1896 and 1904. Total = 2 additional leap days.
1896 is a leap year, and we cross its February 29th because we start on January 10th. The year 1900 is a century year not divisible by 400, so it is a standard year (no leap day). 1904 is a leap year. Although 1908 is a leap year, the period ends on January 10th, so its February 29th is not crossed.
3
Calculate the total number of odd days and determine the final day of the week.
12 standard odd days + 2 leap odd days = 14 odd days. 14 divided by 7 leaves a remainder of 0. Friday + 0 days = Friday.
Adding the accumulated odd days to the original day provides the target day of the week. A remainder of 0 indicates a complete cycle.

Anahtar Kavram

Century leap year rules and date boundary logic in calendars
Soru 846Soru

In a state disaster relief operation, a total of 1,2001,200 food packets were distributed among three relief camps: Camp A, Camp B, and Camp C. Camp A received 400400 packets, while Camp B received 150150 more packets than Camp A. The remaining food packets were distributed to Camp C. How many food packets were distributed to Camp C?

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Cevap: 250

Cevap

The total number of food packets distributed to Camp C is 250.
Camp A receives 400 packets. Camp B receives 150 more than Camp A, which equals 400 + 150 = 550 packets. Combined, Camp A and Camp B receive 400 + 550 = 950 packets. Subtracting 950 from the total allocation of 1,200 packets leaves 250 packets for Camp C.

Adım Adım Çözüm

1
Identify the number of packets given to Camp A and calculate the packets given to Camp B.
Camp A = 400 packets; Camp B = 400 + 150 = 550 packets.
The paragraph states Camp B received 150 more packets than Camp A.
2
Calculate the total number of packets distributed to Camp A and Camp B together.
Total for Camp A and Camp B = 400 + 550 = 950 packets.
Adding the individual allocations of Camp A and Camp B.
3
Subtract the combined allocation of Camp A and Camp B from the overall total packets.
Camp C = 1200 - 950 = 250 packets.
The remaining packets out of the total 1,200 were given to Camp C.

Anahtar Kavram

Data extraction and step-by-step arithmetic computation from narrative caselets
Soru 847Soru

Two business partners, AA and BB, invested in a joint venture. What is the total profit earned by the business at the end of one year?

Statement I: Partner AA invested $6,000\$6,000 for the entire year, while Partner BB invested $9,000\$9,000 for 88 months.
Statement II: Partner AA's share of the annual profit is $2,400\$2,400.

Which of the following options correctly describes the sufficiency of the statements to answer the question?

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Cevap: Both Statement I and Statement II together are sufficient to answer the question, but neither statement alone is sufficient.

Cevap

Both Statement I and Statement II together are sufficient to answer the question, but neither statement alone is sufficient.
Evaluating Statement I alone gives the profit-sharing ratio between Partner A and Partner B as (6000×12):(9000×8)=1:1(6000 \times 12) : (9000 \times 8) = 1 : 1, which is insufficient by itself to find the monetary profit. Statement II alone gives Partner A's profit share as $2,400\$2,400, which is also insufficient without knowing the proportion. Combining both statements shows that both partners receive equal shares, so total profit is $2,400×2=$4,800\$2,400 \times 2 = \$4,800. Therefore, both statements together are necessary and sufficient.

Adım Adım Çözüm

1
Evaluate Statement I alone
Profit sharing ratio of A to B = (6000×12):(9000×8)=72,000:72,000=1:1(6000 \times 12) : (9000 \times 8) = 72,000 : 72,000 = 1 : 1.
Profit is distributed in proportion to the product of capital invested and time period. Since no dollar amounts of profit are given, total profit cannot be determined from Statement I alone.
2
Evaluate Statement II alone
Partner A's profit share = $2,400\$2,400.
Without knowing Partner B's share or the ratio between their shares, the total profit cannot be calculated from Statement II alone.
3
Evaluate Statement I and Statement II together
Since ratio of shares is 1:11:1 and A's share is $2,400\$2,400, B's share is also $2,400\$2,400. Total profit = $2,400+$2,400=$4,800\$2,400 + \$2,400 = \$4,800.
Combining the ratio from Statement I and the monetary value from Statement II gives a unique answer to the question.

Anahtar Kavram

Partnership profit distribution ratio and data sufficiency evaluation
Soru 848Soru
What is the simplified numerical value of the mathematical expression given below when evaluated strictly according to the VBODMAS rule?
15% of 200[36÷{18(2×74)}]×3.515\% \text{ of } 200 - \left[ 36 \div \left\{ 18 - \left( 2 \times \overline{7 - 4} \right) \right\} \right] \times 3.5
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Cevap: 19.519.5

Cevap

The simplified numerical value of the expression is 19.519.5.
Following the VBODMAS hierarchy, we first solve the bar term 74=3\overline{7-4} = 3, giving (2×3)=6(2 \times 3) = 6 inside the inner bracket. Next, the curly bracket simplifies to 186=1218 - 6 = 12. The square bracket simplifies to 36÷12=336 \div 12 = 3. Evaluating 15% of 200=3015\% \text{ of } 200 = 30 and the product 3×3.5=10.53 \times 3.5 = 10.5, we get 3010.5=19.530 - 10.5 = 19.5.

Adım Adım Çözüm

1
Evaluate the expression under the Vinculum (bar)
74=3\overline{7 - 4} = 3
According to VBODMAS, operations under the vinculum have the highest priority.
2
Evaluate the innermost round bracket ()( )
2×3=62 \times 3 = 6
Resolve the multiplication inside the round brackets.
3
Evaluate the curly bracket {}\{ \}
186=1218 - 6 = 12
Perform subtraction inside the curly brackets.
4
Evaluate the square bracket [][ ]
36÷12=336 \div 12 = 3
Perform division inside the square brackets.
5
Calculate the percentage portion
15% of 200=15100×200=3015\% \text{ of } 200 = \frac{15}{100} \times 200 = 30
'Of' represents multiplication in percentage evaluation.
6
Perform multiplication before final subtraction
3×3.5=10.53 \times 3.5 = 10.5
Multiplication takes precedence over final subtraction.
7
Perform final subtraction
3010.5=19.530 - 10.5 = 19.5
Subtract the result of the bracketed expression term from the percentage term.

Anahtar Kavram

Order of Operations (VBODMAS Rule)
Tahmini Süre:1m 30s
Soru 849Soru

What is the unit digit of the numerical expression M=3105×782+896M = 3^{105} \times 7^{82} + 8^{96}?

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Cevap: 3

Cevap

The unit digit of the given expression is 3.
The unit digit of an exponential term is determined by its base's cyclicity cycle and the exponent modulo 4. For 31053^{105}, 105(mod4)=1    31=3105 \pmod 4 = 1 \implies 3^1 = 3. For 7827^{82}, 82(mod4)=2    72=49    982 \pmod 4 = 2 \implies 7^2 = 49 \implies 9. The product of these terms has a unit digit of (3×9)(mod10)=7(3 \times 9) \pmod{10} = 7. For 8968^{96}, 96(mod4)=096 \pmod 4 = 0, which indicates the 4th position in the cyclicity pattern of 8 (8, 4, 2, 6), yielding a unit digit of 6. Finally, adding the unit digits gives (7+6)(mod10)=3(7 + 6) \pmod{10} = 3.

Adım Adım Çözüm

1
Determine the cyclicity and remainder for 31053^{105}
Unit digit is 3
The unit digits of powers of 3 repeat in a cycle of 4 (3, 9, 7, 1). Dividing the exponent by 4 gives 105(mod4)=1105 \pmod 4 = 1, corresponding to 31=33^1 = 3.
2
Determine the cyclicity and remainder for 7827^{82}
Unit digit is 9
The unit digits of powers of 7 repeat in a cycle of 4 (7, 9, 3, 1). Dividing the exponent by 4 gives 82(mod4)=282 \pmod 4 = 2, corresponding to 72=497^2 = 49 (unit digit 9).
3
Calculate the unit digit of the product 3105×7823^{105} \times 7^{82}
Unit digit is 7
Multiply the unit digits of the two factors: (3×9)=27(3 \times 9) = 27, which has a unit digit of 7.
4
Determine the cyclicity and remainder for 8968^{96}
Unit digit is 6
The unit digits of powers of 8 repeat in a cycle of 4 (8, 4, 2, 6). The exponent 96 is completely divisible by 4 (96(mod4)=096 \pmod 4 = 0). When remainder is 0, we use the 4th power in the cycle (84=40968^4 = 4096), which ends in 6.
5
Sum the unit digits of the two main terms
Unit digit is 3
Adding the unit digits gives (7+6)=13(7 + 6) = 13, which has a unit digit of 3.

Anahtar Kavram

Determining the unit digit of composite exponential expressions using power cyclicity.
Soru 850Soru

If p=12+12+12+p = \sqrt{12 + \sqrt{12 + \sqrt{12 + \dots}}} and q=121212q = \sqrt{12 - \sqrt{12 - \sqrt{12 - \dots}}}, such that 2p+qz=1642^{p+q-z} = \frac{1}{64}, what is the value of zz?

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Cevap: 1313

Cevap

The value of zz is 1313.
Solving p=12+pp = \sqrt{12 + p} yields the quadratic equation p2p12=0p^2 - p - 12 = 0, giving p=4p = 4. Solving q=12qq = \sqrt{12 - q} yields q2+q12=0q^2 + q - 12 = 0, giving q=3q = 3. Adding pp and qq gives p+q=7p + q = 7. Substituting this into 2p+qz=1642^{p+q-z} = \frac{1}{64} produces 27z=262^{7-z} = 2^{-6}. Equating the indices gives 7z=67 - z = -6, which solves to z=13z = 13.

Adım Adım Çözüm

1
Evaluate the first infinite nested surd pp
p=4p = 4
Let p=12+pp = \sqrt{12 + p}. Squaring both sides yields p2=12+p    p2p12=0p^2 = 12 + p \implies p^2 - p - 12 = 0. Factoring gives (p4)(p+3)=0(p-4)(p+3) = 0. Since p>0p > 0, p=4p = 4.
2
Evaluate the second infinite nested surd qq
q=3q = 3
Let q=12qq = \sqrt{12 - q}. Squaring both sides yields q2=12q    q2+q12=0q^2 = 12 - q \implies q^2 + q - 12 = 0. Factoring gives (q+4)(q3)=0(q+4)(q-3) = 0. Since q>0q > 0, q=3q = 3.
3
Substitute pp and qq into the exponent expression
p+q=7p + q = 7, giving 27z=1642^{7-z} = \frac{1}{64}
Summing pp and qq gives 4+3=74 + 3 = 7.
4
Solve the exponential equation for zz
z=13z = 13
Express 164\frac{1}{64} as a base 22 power: 164=26\frac{1}{64} = 2^{-6}. Equating exponents gives 7z=6    z=7+6=137 - z = -6 \implies z = 7 + 6 = 13.

Anahtar Kavram

Evaluation of infinite nested surds and solving exponential equations using laws of indices
Tahmini Süre:2m 0s
Soru 851Soru

What is the simplified value of the expression (64125)23\left(\frac{64}{125}\right)^{-\frac{2}{3}}?

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Cevap: 2516\frac{25}{16}

Cevap

2516\frac{25}{16}
The expression (64125)23\left(\frac{64}{125}\right)^{-\frac{2}{3}} is simplified by first converting the negative power to positive by inverting the fraction to (12564)23\left(\frac{125}{64}\right)^{\frac{2}{3}}. Taking the cube root yields 54\frac{5}{4}, and squaring that result gives 2516\frac{25}{16}.

Adım Adım Çözüm

1
Apply the negative exponent rule an=1ana^{-n} = \frac{1}{a^n} to invert the fraction
(64125)23=(12564)23\left(\frac{64}{125}\right)^{-\frac{2}{3}} = \left(\frac{125}{64}\right)^{\frac{2}{3}}
A negative exponent indicates taking the reciprocal of the base.
2
Express the base numbers as perfect cubes
125=53125 = 5^3 and 64=4364 = 4^3, so 12564=(54)3\frac{125}{64} = \left(\frac{5}{4}\right)^3
Rewriting bases into prime factors with power multiples simplifies fractional exponents.
3
Apply the power of a power rule (am)n=am×n(a^m)^n = a^{m \times n}
\left(\left(\frac{5}{4}\right)^3\right)^{\frac{2}{3}} = \left(\frac{5}{4}\right)^{3 \times \frac{2}{3}} = \left(\frac{5}{4}\right)^2
Multiplying the inner exponent 33 by the outer exponent 23\frac{2}{3} yields 22.
4
Square the fraction
(54)2=2516\left(\frac{5}{4}\right)^2 = \frac{25}{16}
Square both the numerator and the denominator to get the final numerical value.

Anahtar Kavram

Negative and Fractional Indices Rules
Soru 852Soru

Under a state renewable energy initiative, a total capacity of 15,000 kW15,000\text{ kW} of solar panels was installed across three districts: District Alpha, District Beta, and District Gamma. District Alpha was allocated 40%40\% of the total capacity. The capacity installed in District Beta was 34\frac{3}{4} of that in District Alpha, while the remaining capacity was installed in District Gamma. In District Alpha, 60%60\% of the installed capacity consists of rooftop solar panels, and the remainder consists of ground-mounted panels. In District Beta, the ratio of rooftop solar capacity to ground-mounted solar capacity is 2:32 : 3. In District Gamma, the ground-mounted solar capacity exceeds the rooftop solar capacity by 1,500 kW1,500\text{ kW}.

Based on the provided information, which of the following statements regarding the solar panel capacity distribution are correct?

Geçerli olan tümünü seçin

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Cevap: The total rooftop solar capacity installed across all three districts is 6,900 kW6,900\text{ kW}.; The ground-mounted solar capacity in District Gamma is exactly twice its rooftop solar capacity.; The ratio of total ground-mounted solar capacity to total rooftop solar capacity across all three districts is 27:2327 : 23.

Cevap

The statements confirming that total rooftop solar capacity is 6,900 kW6,900\text{ kW}, ground-mounted capacity in District Gamma is twice its rooftop capacity, and the ratio of total ground-mounted to rooftop capacity is 27:2327 : 23 are all correct.
Evaluating the data step by step shows that District Alpha has 3,600 kW3,600\text{ kW} rooftop and 2,400 kW2,400\text{ kW} ground-mounted capacity; District Beta has 1,800 kW1,800\text{ kW} rooftop and 2,700 kW2,700\text{ kW} ground-mounted capacity; District Gamma has 1,500 kW1,500\text{ kW} rooftop and 3,000 kW3,000\text{ kW} ground-mounted capacity. This confirms that total rooftop capacity is 6,900 kW6,900\text{ kW}, District Gamma's ground-mounted capacity is twice its rooftop capacity (3,000 kW=2×1,500 kW3,000\text{ kW} = 2 \times 1,500\text{ kW}), and the overall ratio of ground-mounted to rooftop capacity is 8,100:6,900=27:238,100 : 6,900 = 27 : 23.

Adım Adım Çözüm

1
Calculate total capacity allocation for each district.
Alpha = 40% of 15,000=6,000 kW40\% \text{ of } 15,000 = 6,000\text{ kW}. Beta = 34×6,000=4,500 kW\frac{3}{4} \times 6,000 = 4,500\text{ kW}. Gamma = 15,000(6,000+4,500)=4,500 kW15,000 - (6,000 + 4,500) = 4,500\text{ kW}.
Determining individual district totals is necessary to break down capacity by panel type.
2
Determine rooftop and ground-mounted capacities for District Alpha and District Beta.
District Alpha: Rooftop = 60% of 6,000=3,600 kW60\% \text{ of } 6,000 = 3,600\text{ kW}, Ground = 2,400 kW2,400\text{ kW}. District Beta: Ratio 2:3    2:3 \implies Rooftop = 25×4,500=1,800 kW\frac{2}{5} \times 4,500 = 1,800\text{ kW}, Ground = 35×4,500=2,700 kW\frac{3}{5} \times 4,500 = 2,700\text{ kW}.
Applying given percentages and ratios yields the exact breakdown for Alpha and Beta.
3
Determine rooftop and ground-mounted capacities for District Gamma.
Let Rooftop = RR and Ground = GG. We have G+R=4,500G + R = 4,500 and GR=1,500G - R = 1,500. Solving gives 2G=6,000    G=3,000 kW2G = 6,000 \implies G = 3,000\text{ kW} and R=1,500 kWR = 1,500\text{ kW}.
Setting up simultaneous equations resolves the unknown components for Gamma.
4
Verify overall totals and evaluate each statement.
Total Rooftop = 3,600+1,800+1,500=6,900 kW3,600 + 1,800 + 1,500 = 6,900\text{ kW}. Total Ground = 2,400+2,700+3,000=8,100 kW2,400 + 2,700 + 3,000 = 8,100\text{ kW}. Gamma Ground/Rooftop ratio = 3,000/1,500=23,000 / 1,500 = 2. Beta percentage of total = 4,500/15,000=30%4,500 / 15,000 = 30\%. Ground to Rooftop ratio = 8,100/6,900=27/238,100 / 6,900 = 27 / 23.
Direct comparison evaluates which statements are factually supported by the paragraph data.

Anahtar Kavram

Data extraction and simultaneous calculation from unstructured paragraph-based quantitative scenarios.
Soru 853Soru

A vessel contains a mixture of milk and water. What is the initial total volume of the mixture in the vessel?

Statement I: The initial ratio of milk to water in the vessel is 3:23:2. When 10 liters10\text{ liters} of water is added to the mixture, the ratio of milk to water becomes 1:11:1.
Statement II: If 15 liters15\text{ liters} of the original mixture is removed and replaced with 15 liters15\text{ liters} of pure water, the quantity of milk remaining in the vessel is 27 liters27\text{ liters}.

Which of the following options correctly describes the sufficiency of the statements to answer the question?

Cevabı ve açıklamayı göster

Cevap: Statement I alone is sufficient, but Statement II alone is not sufficient.

Cevap

Statement I alone is sufficient to answer the question, but Statement II alone is not sufficient.
Statement I alone gives a complete quantitative relationship: with initial quantities 3x3x and 2x2x, adding 10 liters10\text{ liters} of water leads to 3x=2x+103x = 2x + 10, yielding x=10x = 10 and a unique total initial volume of 50 liters50\text{ liters}. Statement II alone leaves two unknown variables (initial milk fraction and total volume), so it is not sufficient.

Adım Adım Çözüm

1
Evaluate Statement I alone.
Initial volume is calculated as 50 liters50\text{ liters}.
Let the initial volume of milk be 3x3x liters and water be 2x2x liters, making the total initial volume 5x5x liters. Adding 10 liters10\text{ liters} of water gives the equation 3x2x+10=11\frac{3x}{2x + 10} = \frac{1}{1}, which simplifies to 3x=2x+10    x=103x = 2x + 10 \implies x = 10. Thus, total initial volume 5x=50 liters5x = 50\text{ liters}. Hence, Statement I alone is sufficient.
2
Evaluate Statement II alone.
Insufficient to find total initial volume.
Let the total initial volume be VV liters and the fraction of milk in the initial mixture be ff. Removing 15 liters15\text{ liters} of mixture removes 15f15f liters of milk. Replacing it with water adds no milk. The remaining milk equation is f(V15)=27f(V - 15) = 27. Since both ff and VV are unknown, VV cannot be uniquely determined. Hence, Statement II alone is not sufficient.

Anahtar Kavram

Data Sufficiency evaluation of mixture ratios and algebraic equations
Tahmini Süre:1m 30s
Soru 854Soru

What is the unit digit of the numerical value of the expression N=528144+36389×2446517951N = 528^{144} + 363^{89} \times 244^{65} - 179^{51}?

Cevabı ve açıklamayı göster

Cevap: 9

Cevap

9
Evaluating each term's unit digit yields 6 for the first term, 3 for the second term, 4 for the third term, and 9 for the fourth term. Applying BODMAS rules: multiplication of 3 and 4 gives a unit digit of 2. Then adding 6 gives 8. Subtracting 9 from 8 gives a unit digit of 9 (since 18 - 9 = 9). Thus, the correct unit digit is 9.

Adım Adım Çözüm

1
Find the unit digit of 528144528^{144}
The unit digit of the base is 8. The cyclicity of 8 is 4. Dividing the exponent 144 by 4 gives a remainder of 0. When remainder is 0, we take the 4th power: 84=40968^4 = 4096, which has a unit digit of 6.
Exponents divisible by the cyclicity length correspond to the 4th power in the cycle.
2
Find the unit digit of 36389363^{89}
The unit digit of the base is 3. The cyclicity of 3 is 4. Dividing 89 by 4 gives a remainder of 1. Thus, the unit digit is 31=33^1 = 3.
The unit digit pattern for powers of 3 repeats every 4 powers.
3
Find the unit digit of 24465244^{65}
The unit digit of the base is 4. The cyclicity of 4 is 2 (powers alternate: 41=4,42=64^1 = 4, 4^2 = 6). Since the exponent 65 is odd, the unit digit is 4.
Powers of 4 with odd exponents always end in 4.
4
Find the unit digit of 17951179^{51}
The unit digit of the base is 9. The cyclicity of 9 is 2 (powers alternate: 91=9,92=19^1 = 9, 9^2 = 1). Since 51 is odd, the unit digit is 9.
Powers of 9 with odd exponents always end in 9.
5
Combine the unit digits using BODMAS rules
Unit digit of expression = [6+(3×4)9](mod10)=(6+29)(mod10)=(89)(mod10)=9[6 + (3 \times 4) - 9] \pmod{10} = (6 + 2 - 9) \pmod{10} = (8 - 9) \pmod{10} = 9.
Multiplication is performed before addition/subtraction, and a negative intermediate unit digit is adjusted by adding 10.

Anahtar Kavram

Unit digit calculation using cyclicity of digits and order of operations
Tahmini Süre:1m 30s
Soru 855Soru

Consider the positive integer N=60N = 60. Which of the following statements regarding the factors and prime factorization of NN is/are correct?

Geçerli olan tümünü seçin

Cevabı ve açıklamayı göster

Cevap: The total number of positive factors of 6060 is 1212.; The prime factorization of 6060 is 22×31×512^2 \times 3^1 \times 5^1.

Cevap

The total number of positive factors of 60 is 12, and the prime factorization of 60 is 22×31×512^2 \times 3^1 \times 5^1.
The statement declaring that the total number of positive factors is 1212 is correct because (2+1)(1+1)(1+1)=12(2+1)(1+1)(1+1) = 12. Furthermore, the statement giving prime factorization as 22×31×512^2 \times 3^1 \times 5^1 is correct as it accurately breaks down 6060 into prime bases.

Adım Adım Çözüm

1
Find the prime factorization of 6060
60=22×31×5160 = 2^2 \times 3^1 \times 5^1
Decomposing 6060 into its prime components provides the exponents needed for factor analysis.
2
Calculate the total number of positive factors
Total factors = (2+1)(1+1)(1+1)=3×2×2=12(2+1)(1+1)(1+1) = 3 \times 2 \times 2 = 12
Adding 11 to each prime exponent and multiplying gives the total count of positive factors.
3
Evaluate the distinct prime factors and their sum
Distinct prime factors are 2,3,52, 3, 5, and their sum is 2+3+5=102 + 3 + 5 = 10
Verifying distinct prime sum shows that claiming a sum of 1111 is incorrect.
4
Calculate the number of odd factors
Odd factors = (1+1)(1+1)=4(1+1)(1+1) = 4
Odd factors depend only on odd prime bases (31×513^1 \times 5^1), yielding 44 odd factors (1,3,5,151, 3, 5, 15).

Anahtar Kavram

Prime Factorization and Factor Counting Formula
Soru 856Soru

If x=10+22110221x = \sqrt{10 + 2\sqrt{21}} - \sqrt{10 - 2\sqrt{21}} and 9x2k=(1243)k69^{x^2 - k} = \left(\frac{1}{243}\right)^{k - 6}, find the value of kk.

Cevabı ve açıklamayı göster

Cevap: 2

Cevap

The value of kk is 2.
Simplifying xx yields x=(7+3)(73)=23x = (\sqrt{7} + \sqrt{3}) - (\sqrt{7} - \sqrt{3}) = 2\sqrt{3}, which gives x2=12x^2 = 12. Substituting x2=12x^2 = 12 into the exponential equation gives 912k=(1/243)k69^{12 - k} = (1/243)^{k - 6}. Expressing both sides with prime base 3 gives 32(12k)=35(k6)3^{2(12 - k)} = 3^{-5(k - 6)}, which simplifies to 3242k=3305k3^{24 - 2k} = 3^{30 - 5k}. Equating the exponents gives 242k=305k24 - 2k = 30 - 5k, which solves to k=2k = 2.

Adım Adım Çözüm

1
Simplify the nested surds for xx
10+221=7+3\sqrt{10 + 2\sqrt{21}} = \sqrt{7} + \sqrt{3} and 10221=73\sqrt{10 - 2\sqrt{21}} = \sqrt{7} - \sqrt{3}
Nested surds of the form a±2b\sqrt{a \pm 2\sqrt{b}} simplify to m±n\sqrt{m} \pm \sqrt{n} where m+n=am + n = a and mn=bm \cdot n = b.
2
Evaluate xx and calculate x2x^2
x=23x = 2\sqrt{3} and x2=12x^2 = 12
Subtracting the two surds gives (7+3)(73)=23(\sqrt{7} + \sqrt{3}) - (\sqrt{7} - \sqrt{3}) = 2\sqrt{3}. Squaring 232\sqrt{3} gives (2)2×3=12(2)^2 \times 3 = 12.
3
Express both sides of the exponential equation with base 3
3242k=3305k3^{24 - 2k} = 3^{30 - 5k}
Since 9=329 = 3^2 and 243=35243 = 3^5, 912k=(32)12k=3242k9^{12 - k} = (3^2)^{12 - k} = 3^{24 - 2k} and (1/243)k6=(35)k6=3305k(1/243)^{k - 6} = (3^{-5})^{k - 6} = 3^{30 - 5k}.
4
Equate the powers and solve for kk
k=2k = 2
Since bases are equal (3>0,313 > 0, 3 \neq 1), setting exponents equal gives 242k=305k    3k=6    k=224 - 2k = 30 - 5k \implies 3k = 6 \implies k = 2.

Anahtar Kavram

Simplification of nested square root surds a±2b\sqrt{a \pm 2\sqrt{b}} combined with equating exponents using prime base factorization.
Soru 857Soru

What is the exact value of the two-digit positive integer NN?

Statement (I): The sum of the tens digit and the units digit of NN is equal to 1212.
Statement (II): Reversing the digits of NN yields a new two-digit integer that is 3636 greater than NN.

Which of the following statements correctly describes the sufficiency of the given data to answer the question?

Cevabı ve açıklamayı göster

Cevap: Both Statement (I) and Statement (II) together are sufficient, but neither statement alone is sufficient.

Cevap

Both Statement (I) and Statement (II) together are sufficient to answer the question, but neither statement alone is sufficient.
Evaluating each statement independently reveals that neither statement alone narrows NN down to a single value. Combining both equations (x+y=12x + y = 12 and yx=4y - x = 4) yields a single unique pair x=4x = 4 and y=8y = 8, giving N=48N = 48. Therefore, both statements together are required and sufficient.

Adım Adım Çözüm

1
Represent the two-digit integer algebraically.
Let N=10x+yN = 10x + y, where xx is the tens digit (1x91 \leq x \leq 9) and yy is the units digit (0y90 \leq y \leq 9).
Setting up standard place-value variables allows formal analysis of both statements.
2
Evaluate Statement (I) alone.
From Statement (I), x+y=12x + y = 12. Possible pairs (x,y)(x,y) are (3,9),(4,8),(5,7),(6,6),(7,5),(8,4),(9,3)(3,9), (4,8), (5,7), (6,6), (7,5), (8,4), (9,3). Thus, NN could be 39,48,57,66,75,84,39, 48, 57, 66, 75, 84, or 9393.
Since multiple valid values of NN exist, Statement (I) alone is NOT sufficient.
3
Evaluate Statement (II) alone.
The reversed number is 10y+x10y + x. Given (10y+x)(10x+y)=36    9(yx)=36    yx=4(10y + x) - (10x + y) = 36 \implies 9(y - x) = 36 \implies y - x = 4. Possible pairs (x,y)(x,y) are (1,5),(2,6),(3,7),(4,8),(5,9)(1,5), (2,6), (3,7), (4,8), (5,9), giving N=15,26,37,48,N = 15, 26, 37, 48, or 5959.
Since multiple valid values of NN exist, Statement (II) alone is NOT sufficient.
4
Evaluate Statement (I) and Statement (II) together.
System of linear equations: x+y=12x + y = 12 and yx=4y - x = 4. Adding the two equations gives 2y=16    y=82y = 16 \implies y = 8. Substituting y=8y = 8 gives x=4x = 4. Thus, N=48N = 48 uniquely.
Both statements combined provide a unique value for NN, making them together sufficient.

Anahtar Kavram

Data Sufficiency in Digit-Based Integer Problems
Tahmini Süre:1m 30s
Soru 858Soru

In a state sericulture development drive, three agricultural districts—District R, District S, and District T—produced a cumulative total of 3,000 kg3,000\text{ kg} of raw silk, consisting exclusively of Mulberry silk and Eri silk. Across all three districts combined, Mulberry silk accounted for 60%60\% of the total raw silk production. In District R, total raw silk production was 1,000 kg1,000\text{ kg}, of which 65%65\% was Mulberry silk. District S produced a total of 1,200 kg1,200\text{ kg} of raw silk with a Mulberry silk to Eri silk production ratio of 7:57 : 5. The remaining raw silk was produced in District T. What is the absolute difference between the quantity of Mulberry silk and the quantity of Eri silk produced in District T?

Cevabı ve açıklamayı göster

Cevap: 100 kg100\text{ kg}

Cevap

The absolute difference between Mulberry silk and Eri silk produced in District T is 100 kg100\text{ kg}.
Total raw silk produced is 3,000 kg3,000\text{ kg}, making total Mulberry silk 1,800 kg1,800\text{ kg} (60%60\%) and total Eri silk 1,200 kg1,200\text{ kg}. District R produces 650 kg650\text{ kg} Mulberry and 350 kg350\text{ kg} Eri silk. District S produces 700 kg700\text{ kg} Mulberry and 500 kg500\text{ kg} Eri silk. Consequently, District T produces 450 kg450\text{ kg} Mulberry silk (1,8001,3501,800 - 1,350) and 350 kg350\text{ kg} Eri silk (1,2008501,200 - 850). The difference between Mulberry and Eri silk in District T is 450350=100 kg450 - 350 = 100\text{ kg}.

Adım Adım Çözüm

1
Calculate overall production totals for Mulberry and Eri silk
Total Mulberry silk = 60% of 3,000 kg=1,800 kg60\% \text{ of } 3,000\text{ kg} = 1,800\text{ kg}. Total Eri silk = 3,000 kg1,800 kg=1,200 kg3,000\text{ kg} - 1,800\text{ kg} = 1,200\text{ kg}.
Establishing aggregate category totals provides the basis to determine missing District T values.
2
Determine breakdown for District R and District S
District R: Total = 1,000 kg1,000\text{ kg}, Mulberry = 65%×1,000=650 kg65\% \times 1,000 = 650\text{ kg}, Eri = 350 kg350\text{ kg}. District S: Total = 1,200 kg1,200\text{ kg}, Mulberry = 712×1,200=700 kg\frac{7}{12} \times 1,200 = 700\text{ kg}, Eri = 512×1,200=500 kg\frac{5}{12} \times 1,200 = 500\text{ kg}.
Extract specific entity values from given percentage and ratio conditions.
3
Derive Mulberry and Eri silk quantities for District T
District T Mulberry = 1,800(650+700)=450 kg1,800 - (650 + 700) = 450\text{ kg}. District T Eri = 1,200(350+500)=350 kg1,200 - (350 + 500) = 350\text{ kg}.
Subtracting known district totals from overall state totals yields District T quantities.
4
Calculate the absolute difference for District T
Difference = 450 kg350 kg=100 kg450\text{ kg} - 350\text{ kg} = 100\text{ kg}.
Directly answers the final prompt query.

Anahtar Kavram

Data extraction, multi-entity category balance, and multi-step quantitative calculation from unstructured paragraph data.
Soru 859Soru

What is the numerical value of the mathematical expression given below when evaluated strictly according to the VBODMAS rule?

18% of 250+[34{12×2.5(14÷2+83)}]18\% \text{ of } 250 + \left[ 34 - \left\{ 12 \times 2.5 - \left( 14 \div 2 + \overline{8 - 3} \right) \right\} \right]
Cevabı ve açıklamayı göster

Cevap: 61

Cevap

61
Following the VBODMAS priority rule, we first clear the vinculum 83=5\overline{8-3}=5. Next, within the round brackets, division precedes addition: 14÷2+5=7+5=1214 \div 2 + 5 = 7 + 5 = 12. Inside the curly brackets, multiplication precedes subtraction: 12×2.512=3012=1812 \times 2.5 - 12 = 30 - 12 = 18. The square bracket reduces to 3418=1634 - 18 = 16. Evaluating 18%18\% of 250250 gives 4545. Adding 45+1645 + 16 yields the correct final result of 61.

Adım Adım Çözüm

1
Evaluate the vinculum bar term
\overline{8 - 3} = 5
According to VBODMAS, operations under a vinculum (bar) must be simplified first.
2
Simplify the innermost round brackets
(14 \div 2 + 5) = 7 + 5 = 12
Division takes precedence over addition inside the parentheses.
3
Simplify the curly brackets
\{ 12 \times 2.5 - 12 \} = 30 - 12 = 18
Multiplication is performed before subtraction inside the brace group.
4
Simplify the square brackets
[ 34 - 18 ] = 16
Complete the bracket hierarchy by evaluating the outer square brackets.
5
Evaluate the 'of' percentage term
18\% \text{ of } 250 = \frac{18}{100} \times 250 = 45
The percentage 'of' operator is calculated as multiplication.
6
Perform the final addition
45 + 16 = 61
Combine the percentage term with the simplified bracket result.

Anahtar Kavram

VBODMAS Rule (Vinculum, Brackets, Of, Division, Multiplication, Addition, Subtraction)
Soru 860Soru

Find the unit digit of the numerical expression N=(1!+2!+3!++50!)25+888N = (1! + 2! + 3! + \dots + 50!)^{25} + 8^{88}.

Cevabı ve açıklamayı göster

Cevap: 9

Cevap

The unit digit of the given expression is 9.
All factorials from 5!5! to 50!50! end in 0, so the sum (1!+2!+3!++50!)(1! + 2! + 3! + \dots + 50!) ends in 1+2+6+24=331 + 2 + 6 + 24 = 33, which has a unit digit of 3. Raising 3 to the power 25 yields a unit digit of 3 because 25(mod4)=125 \pmod 4 = 1. For 8888^{88}, since 88 is divisible by 4 (88(mod4)=088 \pmod 4 = 0), we take the 4th term of the cyclicity of 8, which is 6. Summing the unit digits yields 3+6=93 + 6 = 9.

Adım Adım Çözüm

1
Determine the unit digit of the base sum (1!+2!+3!++50!)(1! + 2! + 3! + \dots + 50!).
Unit digit of base is 3.
Factorials 5!5! and above all end in 0 (5!=1205! = 120), so only 1!+2!+3!+4!=331! + 2! + 3! + 4! = 33 contributes to the unit digit.
2
Calculate the unit digit of 3253^{25}.
Unit digit is 3.
The cyclicity pattern of 3 has period 4 (3, 9, 7, 1). Exponent 25(mod4)=125 \pmod 4 = 1, giving 31=33^1 = 3.
3
Calculate the unit digit of 8888^{88}.
Unit digit is 6.
The cyclicity pattern of 8 has period 4 (8, 4, 2, 6). Exponent 88(mod4)=088 \pmod 4 = 0, so we take the 4th position in the cycle, which is 6.
4
Add the unit digits of both terms.
Final unit digit is 9.
3+6=93 + 6 = 9, which gives a unit digit of 9.

Anahtar Kavram

Cyclicity of numbers and factorial unit digit properties
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