Basic Numeracy

295 soru

Soru 221Soru

What is the unit digit of the composite expression E=(648116×43785)32290E = (648^{116} \times 437^{85}) - 322^{90}?

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Cevap: 8

Cevap

The unit digit of the expression is 8.
The term 648116648^{116} has a unit digit of 6 (since 116(mod4)=0116 \pmod 4 = 0, giving 846(mod10)8^4 \equiv 6 \pmod{10}), and 43785437^{85} has a unit digit of 7 (since 85(mod4)=185 \pmod 4 = 1, giving 717(mod10)7^1 \equiv 7 \pmod{10}). The product of these two terms yields a unit digit of (6×7)(mod10)=2(6 \times 7) \pmod{10} = 2. The subtracted term 32290322^{90} has a unit digit of 4 (since 90(mod4)=290 \pmod 4 = 2, giving 224(mod10)2^2 \equiv 4 \pmod{10}). Subtracting gives 24=28(mod10)2 - 4 = -2 \equiv 8 \pmod{10}.

Adım Adım Çözüm

1
Find the unit digit of 648116648^{116}
Unit digit is 6
The base unit digit is 8, which follows a cyclicity of 4 (8, 4, 2, 6). Exponent 116÷4=29116 \div 4 = 29 with remainder 0. A remainder of 0 corresponds to the 4th position in the cyclicity cycle (84=40968^4 = 4096), giving a unit digit of 6.
2
Find the unit digit of 43785437^{85}
Unit digit is 7
The base unit digit is 7, which follows a cyclicity of 4 (7, 9, 3, 1). Exponent 85÷4=2185 \div 4 = 21 with remainder 1. A remainder of 1 corresponds to the 1st power (71=77^1 = 7), giving a unit digit of 7.
3
Calculate the unit digit of the product (648116×43785)(648^{116} \times 437^{85})
Unit digit is 2
Multiplying the unit digits from Step 1 and Step 2 gives 6×7=426 \times 7 = 42, which has a unit digit of 2.
4
Find the unit digit of 32290322^{90}
Unit digit is 4
The base unit digit is 2, which follows a cyclicity of 4 (2, 4, 8, 6). Exponent 90÷4=2290 \div 4 = 22 with remainder 2. A remainder of 2 corresponds to the 2nd power (22=42^2 = 4), giving a unit digit of 4.
5
Subtract to find the overall unit digit of EE
Unit digit is 8
Subtracting the unit digits gives 24=22 - 4 = -2. Converting to a positive unit digit in base 10 arithmetic gives 2+10=8-2 + 10 = 8.

Anahtar Kavram

Unit Digit and Cyclicity Rules for Exponential Expressions
Soru 222Soru

What is the simplified value of the following mathematical expression?

45÷5×3+[18{14(83)}]45 \div 5 \times 3 + [18 - \{14 - (8 - 3)\}]
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Cevap: 36

Cevap

36
Following the BODMAS rule step by step:
1. Innermost parenthesis: 83=58 - 3 = 5.
2. Curly braces: 145=914 - 5 = 9.
3. Square brackets: 189=918 - 9 = 9.
4. Left-to-right division and multiplication: 45÷5×3=9×3=2745 \div 5 \times 3 = 9 \times 3 = 27.
5. Addition: 27+9=3627 + 9 = 36.

Adım Adım Çözüm

1
Evaluate the innermost round brackets
8 - 3 = 5
According to the BODMAS rule, operations inside the innermost brackets must be solved first.
2
Evaluate the expression inside the curly braces
14 - 5 = 9
Substitute the result from the round brackets into the curly braces.
3
Evaluate the expression inside the square brackets
18 - 9 = 9
Substitute the result from the curly braces into the square brackets.
4
Perform Division and Multiplication from left to right
45 / 5 * 3 = 9 * 3 = 27
Division and multiplication have equal precedence and must be evaluated strictly from left to right.
5
Add the result of the bracket terms to the result of the arithmetic terms
27 + 9 = 36
Final addition yields the simplified result.

Anahtar Kavram

BODMAS Rule (Brackets, Orders, Division and Multiplication left-to-right, Addition and Subtraction left-to-right)
Soru 223Soru

What is the value of the following mathematical expression?

25[18{12(641)}]25 - [18 - \{12 - (6 - \overline{4 - 1})\}]
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Cevap: 16

Cevap

16
Following the BODMAS priority (Vinculum \rightarrow Round Brackets \rightarrow Curly Braces \rightarrow Square Brackets \rightarrow Outermost Subtraction):
1. Vinculum: 41=3\overline{4 - 1} = 3
2. Round brackets: 63=36 - 3 = 3
3. Curly braces: 123=912 - 3 = 9
4. Square brackets: 189=918 - 9 = 9
5. Outer subtraction: 259=1625 - 9 = 16.
Thus, 16 is the mathematically correct answer.

Adım Adım Çözüm

1
Evaluate the expression under the vinculum bar
41=3\overline{4 - 1} = 3
According to BODMAS, vinculum (bar bracket) has the highest priority.
2
Simplify the innermost round brackets (63)(6 - 3)
63=36 - 3 = 3
Evaluate terms inside round brackets next.
3
Simplify the curly braces {123}\{12 - 3\}
123=912 - 3 = 9
Evaluate terms inside curly braces next.
4
Simplify the square brackets [189][18 - 9]
189=918 - 9 = 9
Evaluate terms inside square brackets next.
5
Perform final subtraction from 25
259=1625 - 9 = 16
Complete the outermost operation.

Anahtar Kavram

BODMAS Rule with Vinculum (Bar Bracket)
Soru 224Soru

What is the unit digit of the expression 2442^{44}?

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Cevap: 6

Cevap

The unit digit of 2442^{44} is 6.
The unit digit of powers of 2 repeats in a pattern of 4 steps: 2, 4, 8, 6. Dividing the exponent 44 by 4 yields a remainder of 0. A remainder of 0 means the full 4th power in the cycle applies, so 24=162^4 = 16 yields a unit digit of 6.

Adım Adım Çözüm

1
Identify the base and its cyclicity pattern.
The base is 2. The powers of 2 follow a cyclic pattern of unit digits: 21=22^1 = 2, 22=42^2 = 4, 23=82^3 = 8, 24=162^4 = 16 (unit digit 6). The cyclicity of 2 is 4.
Unit digits repeat in a fixed pattern of length 4 for base 2.
2
Divide the exponent by the cyclicity period.
44÷4=1144 \div 4 = 11 with a remainder of 00.
Determining the remainder tells us which position in the 4-step cycle applies.
3
Apply the cyclicity rule for remainder 0.
A remainder of 0 corresponds to the 4th power in the cycle (24=162^4 = 16), giving a unit digit of 6.
When the exponent is exactly divisible by the cyclicity length, the unit digit is determined by the last element of the cycle (242^4), not 202^0.

Anahtar Kavram

Unit Digit Cyclicity for Base 2
Soru 225Soru
What is the simplified value of the following mathematical expression?
72÷[114+{21212×(2.514+16)}]×512\frac{7}{2} \div \left[ 1 \frac{1}{4} + \left\{ 2 \frac{1}{2} - \frac{1}{2} \times \left( 2.5 - \overline{\frac{1}{4} + \frac{1}{6}} \right) \right\} \right] \times \frac{5}{12}
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Cevap: 713\frac{7}{13}

Cevap

The simplified value of the expression is 713\frac{7}{13}.
Following strict BODMAS precedence: First, simplify the bar term 14+16=512\overline{\frac{1}{4} + \frac{1}{6}} = \frac{5}{12}. Next, resolve the round bracket 52512=2512\frac{5}{2} - \frac{5}{12} = \frac{25}{12}. Multiplying by 12\frac{1}{2} gives 2524\frac{25}{24}. The curly bracket simplifies to 522524=3524\frac{5}{2} - \frac{25}{24} = \frac{35}{24}. The square bracket yields 54+3524=6524\frac{5}{4} + \frac{35}{24} = \frac{65}{24}. Finally, evaluating left to right gives 72×2465×512=713\frac{7}{2} \times \frac{24}{65} \times \frac{5}{12} = \frac{7}{13}.

Adım Adım Çözüm

1
Evaluate the expression under the vinculum (bar bracket)
14+16=3+212=512\overline{\frac{1}{4} + \frac{1}{6}} = \frac{3 + 2}{12} = \frac{5}{12}
According to BODMAS, the vinculum takes precedence over round brackets.
2
Evaluate the terms inside the round brackets
2.5512=52512=30512=25122.5 - \frac{5}{12} = \frac{5}{2} - \frac{5}{12} = \frac{30 - 5}{12} = \frac{25}{12}
Convert decimal 2.52.5 to fraction 52\frac{5}{2} and perform subtraction.
3
Perform multiplication inside the curly brackets
12×2512=2524\frac{1}{2} \times \frac{25}{12} = \frac{25}{24}
Multiplication inside brackets precedes subtraction.
4
Evaluate the terms inside the curly brackets
2122524=522524=602524=35242 \frac{1}{2} - \frac{25}{24} = \frac{5}{2} - \frac{25}{24} = \frac{60 - 25}{24} = \frac{35}{24}
Complete the subtraction inside the curly brackets.
5
Evaluate the terms inside the square brackets
114+3524=54+3524=30+3524=65241 \frac{1}{4} + \frac{35}{24} = \frac{5}{4} + \frac{35}{24} = \frac{30 + 35}{24} = \frac{65}{24}
Perform addition within the square brackets.
6
Perform division and multiplication from left to right
72÷6524×512=72×2465×512=8465×512=713\frac{7}{2} \div \frac{65}{24} \times \frac{5}{12} = \frac{7}{2} \times \frac{24}{65} \times \frac{5}{12} = \frac{84}{65} \times \frac{5}{12} = \frac{7}{13}
Division and multiplication have equal precedence and are executed strictly from left to right.

Anahtar Kavram

BODMAS Rule with Vinculum and Nested Brackets
Soru 226Soru

Let NN be the smallest positive integer that leaves remainders of 22, 44, and 66 when divided by 55, 77, and 99, respectively. What is the remainder when N2025N^{2025} is divided by 1717?

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Cevap: 11

Cevap

The remainder when N2025N^{2025} is divided by 1717 is 11.
The number NN satisfies N3(modlcm(5,7,9))N \equiv -3 \pmod{\text{lcm}(5,7,9)}, giving N=3153=312N = 315 - 3 = 312. Reducing 312(mod17)312 \pmod{17} gives 66. By Fermat's Little Theorem, 6161(mod17)6^{16} \equiv 1 \pmod{17}, so 6202569(mod17)6^{2025} \equiv 6^9 \pmod{17}. Calculating 69(mod17)6^9 \pmod{17} yields 6(mod17)-6 \pmod{17}, which converts to positive remainder 176=1117 - 6 = 11.

Adım Adım Çözüm

1
Determine the value of the smallest positive integer NN
N=312N = 312
From the problem statement: N23(mod5)N \equiv 2 \equiv -3 \pmod 5, N43(mod7)N \equiv 4 \equiv -3 \pmod 7, and N63(mod9)N \equiv 6 \equiv -3 \pmod 9. Therefore, N+3N + 3 must be divisible by lcm(5,7,9)=315\text{lcm}(5, 7, 9) = 315. The smallest positive integer is N=3153=312N = 315 - 3 = 312.
2
Reduce NN modulo 1717
N6(mod17)N \equiv 6 \pmod{17}
Dividing 312312 by 1717 gives 312=17×18+6312 = 17 \times 18 + 6, so 3126(mod17)312 \equiv 6 \pmod{17}.
3
Apply Fermat's Little Theorem to reduce the power
6202569(mod17)6^{2025} \equiv 6^9 \pmod{17}
Since 1717 is prime and gcd(6,17)=1\gcd(6, 17) = 1, 6161(mod17)6^{16} \equiv 1 \pmod{17}. Expressing the exponent as 2025=16×126+92025 = 16 \times 126 + 9 yields 62025(616)126×691126×6969(mod17)6^{2025} \equiv (6^{16})^{126} \times 6^9 \equiv 1^{126} \times 6^9 \equiv 6^9 \pmod{17}.
4
Evaluate 69(mod17)6^9 \pmod{17} and convert to positive remainder
Remainder is 1111
Computing successive powers modulo 1717: 62=362(mod17)6^2 = 36 \equiv 2 \pmod{17}, 6422=4(mod17)6^4 \equiv 2^2 = 4 \pmod{17}, and 6842=161(mod17)6^8 \equiv 4^2 = 16 \equiv -1 \pmod{17}. Thus, 69=68×6(1)×6=6(mod17)6^9 = 6^8 \times 6 \equiv (-1) \times 6 = -6 \pmod{17}. Converting to a positive remainder gives 6+17=11-6 + 17 = 11.

Anahtar Kavram

Chinese Remainder Theorem (Constant Difference Method), Fermat's Little Theorem, and Negative Remainder Conversion
Soru 227Soru

What is the unit digit of the expression N=240+431738N = 2^{40} + 4^{31} - 7^{38}?

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Cevap: 1

Cevap

The unit digit of the given expression is 1.
The unit digits of the individual terms are 6, 4, and 9 respectively. Adding the first two unit digits gives 6+4=106 + 4 = 10 (unit digit 0). Subtracting 9 from 10 yields 109=110 - 9 = 1. Therefore, the overall unit digit of the expression is 1.

Adım Adım Çözüm

1
Find the unit digit of 2402^{40} using cyclicity.
The cyclicity of 2 is 4 (2, 4, 8, 6). Divide the exponent 40 by 4: 40(mod4)=040 \pmod 4 = 0. When the remainder is 0, take the 4th power: 24=162^4 = 16, so the unit digit is 6.
Powers of 2 repeat their unit digits in cycles of 4.
2
Find the unit digit of 4314^{31}.
The cyclicity of 4 is 2 (4 for odd exponents, 6 for even exponents). Since 31 is odd, the unit digit is 4.
Odd powers of 4 always end in 4.
3
Find the unit digit of 7387^{38}.
The cyclicity of 7 is 4 (7, 9, 3, 1). Divide the exponent 38 by 4: 38(mod4)=238 \pmod 4 = 2. 72=497^2 = 49, so the unit digit is 9.
A remainder of 2 corresponds to the second term in the cyclicity sequence of 7.
4
Combine the unit digits according to the expression N=240+431738N = 2^{40} + 4^{31} - 7^{38}.
Unit digit = (6+4)9=109=1(6 + 4) - 9 = 10 - 9 = 1.
Perform modular arithmetic modulo 10 to find the final unit digit.

Anahtar Kavram

Unit Digit Cyclicity and Modular Addition/Subtraction
Soru 228Soru

What is the unit digit of 7827^{82}?

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Cevap: 9

Cevap

The unit digit of 7827^{82} is 9.
The unit digits of powers of 7 repeat in a pattern of 4 (7, 9, 3, 1). Dividing the exponent 82 by 4 yields a remainder of 2. The second number in the cyclic pattern is 9, making 9 the unit digit of 7827^{82}.

Adım Adım Çözüm

1
Find the cyclicity of the base number 7
The unit digits follow a repeating 4-step sequence: 7, 9, 3, 1.
Powers of 7 cycle every 4 powers because 71=77^1=7, 72=497^2=49, 73=3437^3=343, and 74=24017^4=2401.
2
Divide the exponent by the cyclicity period
82÷4=2082 \div 4 = 20 with a remainder of 2.
The remainder determines the equivalent power position within the 4-step cycle.
3
Determine the unit digit from the remainder
The unit digit of 727^2 is 9.
A remainder of 2 corresponds to 727^2, giving 9.

Anahtar Kavram

Unit Digit Cyclicity
Soru 229Soru

Let N=75x38y2N = 75x38y2 be a seven-digit number that is completely divisible by 7272, where xx and yy are single-digit natural numbers such that x>yx > y. What is the remainder when 2xy+12^{x \cdot y + 1} is divided by 1313?

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Cevap: 22

Cevap

The remainder when 2xy+12^{x \cdot y + 1} is divided by 1313 is 22.
The seven-digit number 75x38y275x38y2 is divisible by 7272, which means it must satisfy divisibility by both 88 and 99. The last three digits 8y28y2 are divisible by 88 only when y=3y = 3 or y=7y = 7. The sum of digits 25+x+y25 + x + y is divisible by 99 when x+y=2x + y = 2 or x+y=11x + y = 11. Testing y=3y = 3 gives x=8x = 8, which satisfies x>yx > y. Testing y=7y = 7 gives x=4x = 4, which violates x>yx > y. Thus, x=8x = 8 and y=3y = 3, giving xy+1=25x \cdot y + 1 = 25. By Fermat's Little Theorem, 2121(mod13)2^{12} \equiv 1 \pmod{13}, so 225=(212)2212(mod13)2^{25} = (2^{12})^2 \cdot 2^1 \equiv 2 \pmod{13}.

Adım Adım Çözüm

1
Apply divisibility rule by 8 to find possible values of y
yy can be either 33 or 77
A number is divisible by 7272 if it is divisible by both 88 and 99. For divisibility by 88, the last three digits 8y28y2 must be divisible by 88. Testing single digits gives 832/8=104832 / 8 = 104 and 872/8=109872 / 8 = 109.
2
Apply divisibility rule by 9 to find corresponding x values and enforce x > y
x=8x = 8 and y=3y = 3
For divisibility by 99, the sum of digits (7+5+x+3+8+y+2=25+x+y)(7 + 5 + x + 3 + 8 + y + 2 = 25 + x + y) must be a multiple of 99. If y=3y = 3, 28+x=36    x=828 + x = 36 \implies x = 8, satisfying x>yx > y. If y=7y = 7, 32+x=36    x=432 + x = 36 \implies x = 4, which violates x>yx > y.
3
Evaluate the exponent x * y + 1
Exponent = 25
Substituting x=8x = 8 and y=3y = 3 gives 83+1=258 \cdot 3 + 1 = 25.
4
Calculate 2^25 mod 13 using Fermat's Little Theorem
Remainder is 2
Since 1313 is prime, Fermat's Little Theorem states 2121(mod13)2^{12} \equiv 1 \pmod{13}. Therefore, 225=(212)2211222(mod13)2^{25} = (2^{12})^2 \cdot 2^1 \equiv 1^2 \cdot 2 \equiv 2 \pmod{13}.

Anahtar Kavram

Combining composite divisibility rules (8 and 9) with Fermat's Little Theorem for large power remainder evaluation.
Soru 230Soru

Calculate the exact numerical value of the following mathematical expression by applying the standard order of operations (BODMAS):

36.4[12.8+{6.5×(4.42.6+0.8)}÷1.3]36.4 - \left[ 12.8 + \left\{ 6.5 \times \left( 4.4 - \overline{2.6 + 0.8} \right) \right\} \div 1.3 \right]
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Cevap: 18.6

Cevap

The simplified value of the mathematical expression is 18.6.
Strict application of BODMAS requires simplifying grouping symbols from the innermost vinculum outward, followed by resolving division prior to addition within brackets, yielding an exact answer of 18.6.

Adım Adım Çözüm

1
Evaluate the expression underneath the vinculum (bar line)
\overline{2.6 + 0.8} = 3.4
The vinculum functions as an innermost bracket with highest evaluation priority.
2
Evaluate the terms inside the round brackets
4.4 - 3.4 = 1.0
Process operations inside round brackets next.
3
Perform multiplication within the curly braces
6.5×1.0=6.56.5 \times 1.0 = 6.5
Complete operations within the curly braces.
4
Execute division inside the square brackets
6.5÷1.3=5.06.5 \div 1.3 = 5.0
Division takes precedence over addition according to BODMAS rules.
5
Perform addition within the square brackets
12.8 + 5.0 = 17.8
Finish evaluating all operations contained within the square brackets.
6
Perform final subtraction from left to right
36.4 - 17.8 = 18.6
Complete the outermost subtraction to arrive at the final simplified value.

Anahtar Kavram

BODMAS Rule with Vinculum and Decimals
Soru 231Soru

What is the simplified value of 7+433\sqrt{7 + 4\sqrt{3}} - \sqrt{3}?

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Cevap: 2

Cevap

The simplified value is 2.
Expressing 7+437 + 4\sqrt{3} as (2+3)2(2 + \sqrt{3})^2 allows the square root to simplify directly to 2+32 + \sqrt{3}. Subtracting 3\sqrt{3} leaves the exact numerical answer 2.

Adım Adım Çözüm

1
Rewrite the expression under the square root as a perfect square of a binomial.
7+43=22+(3)2+2(2)(3)=(2+3)27 + 4\sqrt{3} = 2^2 + (\sqrt{3})^2 + 2(2)(\sqrt{3}) = (2 + \sqrt{3})^2
Using the identity (a+b)2=a2+b2+2ab(a+b)^2 = a^2 + b^2 + 2ab, setting a=2a = 2 and b=3b = \sqrt{3} yields a2+b2=4+3=7a^2 + b^2 = 4 + 3 = 7 and 2ab=432ab = 4\sqrt{3}.
2
Evaluate the square root of the perfect square.
(2+3)2=2+3\sqrt{(2 + \sqrt{3})^2} = 2 + \sqrt{3}
The principal square root of a positive squared expression x2\sqrt{x^2} is xx.
3
Perform the subtraction indicated in the stem.
(2+3)3=2(2 + \sqrt{3}) - \sqrt{3} = 2
The radical terms 3\sqrt{3} and 3-\sqrt{3} cancel out, leaving the integer 2.

Anahtar Kavram

Simplification of Nested Surds
Soru 232Soru
Find the exact numerical value of the following mathematical expression evaluated strictly according to the VBODMAS rule:
75% of 160[3.5×8+{48÷(145×2)}]75\% \text{ of } 160 - \left[ 3.5 \times 8 + \left\{ 48 \div \left( 14 - \overline{5 \times 2} \right) \right\} \right]
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Cevap: 80

Cevap

The simplified numerical value of the expression is 8080.
Evaluating the expression following strict VBODMAS hierarchy: bar expression 5×2=10\overline{5 \times 2} = 10, round brackets 1410=414 - 10 = 4, curly brackets 48÷4=1248 \div 4 = 12, square brackets 3.5×8+12=403.5 \times 8 + 12 = 40, and percentage 'of' term 75% of 160=12075\% \text{ of } 160 = 120. Finally, 12040=80120 - 40 = 80.

Adım Adım Çözüm

1
Evaluate the expression under the vinculum (bar)
5×2=10\overline{5 \times 2} = 10
According to VBODMAS, operations grouped under a bar take highest priority.
2
Evaluate inside the innermost round brackets (1410)(14 - 10)
1410=414 - 10 = 4
Perform subtraction inside the parentheses.
3
Evaluate inside the curly brackets {48÷4}\{48 \div 4\}
48÷4=1248 \div 4 = 12
Divide the number outside the round bracket by the result of the round bracket.
4
Evaluate inside the square brackets [3.5×8+12][3.5 \times 8 + 12]
28+12=4028 + 12 = 40
Perform multiplication (3.5×8=283.5 \times 8 = 28) before adding 1212.
5
Calculate the percentage term 75% of 16075\% \text{ of } 160
75100×160=120\frac{75}{100} \times 160 = 120
Evaluate the 'of' operation before final subtraction.
6
Perform final subtraction 12040120 - 40
80
Subtract the total result of the bracketed expression from the percentage term.

Anahtar Kavram

Order of Operations (VBODMAS Rule)
Soru 233Soru
Evaluate the following numerical expression strictly according to the VBODMAS rule:
2.5×12[8+{15÷(4.52.1+0.9)}]2.5 \times 12 - \left[ 8 + \left\{ 15 \div \left( 4.5 - \overline{2.1 + 0.9} \right) \right\} \right]
What is the final calculated value?
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Cevap: 12

Cevap

12
Evaluating the expression following strict VBODMAS priority yields: Vinculum (2.1 + 0.9 = 3) -> Round brackets (4.5 - 3 = 1.5) -> Curly brackets (15 / 1.5 = 10) -> Square brackets (8 + 10 = 18) -> Multiplication (2.5 * 12 = 30) -> Subtraction (30 - 18 = 12).

Adım Adım Çözüm

1
Evaluate the expression under the vinculum bar
2.1 + 0.9 = 3
According to the VBODMAS rule, operations under a vinculum take highest priority.
2
Evaluate the innermost round brackets
4.5 - 3 = 1.5
Perform subtraction inside the round brackets after resolving the vinculum.
3
Perform division within the curly brackets
15 / 1.5 = 10
Division inside curly brackets must be calculated before simplifying the outer bracket.
4
Perform addition within the square brackets
8 + 10 = 18
Complete the evaluation of the square bracket section.
5
Perform multiplication outside the brackets
2.5 * 12 = 30
Multiplication takes precedence over final subtraction.
6
Perform final subtraction
30 - 18 = 12
Complete the expression by subtracting the bracket result from the product.

Anahtar Kavram

VBODMAS Rule (Vinculum, Brackets, Orders, Division, Multiplication, Addition, Subtraction)
Soru 234Soru

Find the total number of positive factors of the integer 7575.

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Cevap: 6

Cevap

The total number of positive factors of 75 is 6.
The prime factorization of 75 is 31×523^1 \times 5^2. The number of positive factors is obtained by adding 1 to each exponent in the prime factorization and multiplying the results: (1+1)×(2+1)=2×3=6(1 + 1) \times (2 + 1) = 2 \times 3 = 6. The complete list of positive factors is 1, 3, 5, 15, 25, and 75.

Adım Adım Çözüm

1
Express 75 in terms of its prime factors.
75=31×5275 = 3^1 \times 5^2
Prime factorization breaks down the number into prime components essential for counting factors.
2
Apply the standard formula for total positive factors of a number N=pa×qbN = p^a \times q^b.
Total factors =(1+1)×(2+1)=2×3=6= (1 + 1) \times (2 + 1) = 2 \times 3 = 6
Each factor is formed by choosing a power of 3 (2 choices: 30,313^0, 3^1) and a power of 5 (3 choices: 50,51,525^0, 5^1, 5^2).

Anahtar Kavram

Total Number of Positive Factors from Prime Factorization
Soru 235Soru

What is the total number of positive integer factors of 120120?

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Cevap: 16

Cevap

The total number of positive integer factors of 120120 is 1616.
By prime factorizing 120120, we get 23×31×512^3 \times 3^1 \times 5^1. Applying the factor count formula (a+1)(b+1)(c+1)(a+1)(b+1)(c+1), we obtain (3+1)(1+1)(1+1)=4×2×2=16(3+1)(1+1)(1+1) = 4 \times 2 \times 2 = 16.

Adım Adım Çözüm

1
Find the prime factorization of 120120
120=23×31×51120 = 2^3 \times 3^1 \times 5^1
To calculate the total number of factors systematically, express the number as a product of prime factors.
2
Apply the total factor count formula
Number of factors = (3+1)(1+1)(1+1)(3 + 1)(1 + 1)(1 + 1)
If a number N=pa×qb×rcN = p^a \times q^b \times r^c, the total number of positive factors is (a+1)(b+1)(c+1)(a+1)(b+1)(c+1).
3
Compute the product
4×2×2=164 \times 2 \times 2 = 16
Multiplying the incremented prime exponents gives the total count of factors.

Anahtar Kavram

Number of Positive Factors from Prime Factorization
Soru 236Soru

If 2x+342x18x+1=64\frac{2^{x+3} \cdot 4^{2x-1}}{8^{x+1}} = 64, what is the value of (x+2)2(x + 2)^2?

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Cevap: 36

Cevap

The value of (x+2)2(x + 2)^2 is 36.
Converting all terms to base 2 simplifies the equation to 22x2=262^{2x-2} = 2^6. Equating the powers gives 2x2=62x - 2 = 6, so x=4x = 4. Substituting x=4x = 4 into (x+2)2(x + 2)^2 yields (4+2)2=36(4 + 2)^2 = 36.

Adım Adım Çözüm

1
Convert all exponential terms to base 2
Numerator term 42x1=24x24^{2x-1} = 2^{4x-2}, denominator term 8x+1=23x+38^{x+1} = 2^{3x+3}, and right-hand side 64=2664 = 2^6.
To combine powers using index laws, all expressions must share a common base.
2
Simplify the left-hand side expression using exponent laws
2x+324x223x+3=25x+123x+3=2(5x+1)(3x+3)=22x2\frac{2^{x+3} \cdot 2^{4x-2}}{2^{3x+3}} = \frac{2^{5x+1}}{2^{3x+3}} = 2^{(5x+1)-(3x+3)} = 2^{2x-2}.
Apply product law aman=am+na^m \cdot a^n = a^{m+n} and quotient law aman=amn\frac{a^m}{a^n} = a^{m-n}.
3
Solve for the variable x
22x2=26    2x2=6    x=42^{2x-2} = 2^6 \implies 2x - 2 = 6 \implies x = 4.
When bases are equal, exponents must be equal.
4
Evaluate the requested target expression
(4+2)2=62=36(4 + 2)^2 = 6^2 = 36.
Substitute the calculated value of x=4x = 4 into (x+2)2(x + 2)^2.

Anahtar Kavram

Laws of Indices and Exponential Equations
Tahmini Süre:1m 30s
Soru 237Soru

What is the remainder when 62×5362 \times 53 is divided by 6060?

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Cevap: 46

Cevap

46
To find the remainder of a product, we can multiply the remainders of each individual number. When divided by 60, 62 leaves a remainder of 2. So, we multiply 2 by 53 to get 106. Finally, we divide 106 by 60, which leaves a remainder of 46.

Adım Adım Çözüm

1
Find the remainder of each factor when divided by 60.
622(mod60)62 \equiv 2 \pmod{60} and 5353(mod60)53 \equiv 53 \pmod{60} (or 7(mod60)-7 \pmod{60}).
By the properties of modular arithmetic, we can simplify large multiplications by replacing numbers with their remainders.
2
Multiply the remainders together.
2×53=1062 \times 53 = 106. Alternatively, using negative remainders: 2×(7)=142 \times (-7) = -14.
The remainder of a product is equal to the product of the individual remainders.
3
Find the final remainder by dividing the product from Step 2 by 60.
106=60×1+46106 = 60 \times 1 + 46, so the remainder is 4646. (If using 14-14, add 6060 to get 4646).
The intermediate product must be reduced modulo 60 to find the final positive remainder.

Anahtar Kavram

Properties of Remainders in Multiplication
Soru 238Soru

Consider the number obtained by multiplying 4848 and 5353. If this product is divided by 5050, what is the resulting positive remainder?

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Cevap: 44

Cevap

44
Applying the properties of modular arithmetic, 4848 is congruent to 2(mod50)-2 \pmod{50} and 5353 is congruent to 3(mod50)3 \pmod{50}. Multiplying these gives a remainder of 6(mod50)-6 \pmod{50}. To find the standard positive remainder, we add the divisor 5050 to 6-6, resulting in 4444. Alternatively, direct calculation gives 48×53=254448 \times 53 = 2544, and 25442544 divided by 5050 yields a quotient of 5050 with a remainder of 4444.

Adım Adım Çözüm

1
Find the remainder of 48 divided by 50.
-2
Using a negative remainder simplifies the multiplication step.
2
Find the remainder of 53 divided by 50.
3
Individual remainders are needed to apply the product rule of modular arithmetic.
3
Multiply the individual remainders.
2×3=6-2 \times 3 = -6
The remainder of a product is congruent to the product of the individual remainders.
4
Convert the negative remainder to a positive remainder.
50 - 6 = 44
A standard remainder must be a non-negative integer strictly less than the divisor.

Anahtar Kavram

Remainder Theorem and Negative Modulus
Soru 239Soru

If the equation x+x9=9\sqrt{x} + \sqrt{x - 9} = 9 holds true, what is the exact value of xx?

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Cevap: 25

Cevap

25
The exact value of xx is 25. By moving one radical to the right side and squaring both sides, we eliminate one square root. Simplifying and isolating the remaining square root allows us to square both sides a second time, revealing the final value. Alternatively, using the conjugate property of surds: multiplying both sides of the identity (x)2(x9)2=9(\sqrt{x})^2 - (\sqrt{x-9})^2 = 9 by their difference gives (xx9)(x+x9)=9(\sqrt{x} - \sqrt{x-9})(\sqrt{x} + \sqrt{x-9}) = 9. Since the sum is 9, the difference must be 1 (i.e., xx9=1\sqrt{x} - \sqrt{x-9} = 1). Adding this back to the original equation yields 2x=102\sqrt{x} = 10, so x=5\sqrt{x} = 5 and x=25x = 25.

Adım Adım Çözüm

1
Isolate one of the square root terms on one side of the equation.
x=9x9\sqrt{x} = 9 - \sqrt{x - 9}
Isolating a radical makes it easier to eliminate it by squaring both sides.
2
Square both sides of the equation and expand the right side.
x=8118x9+(x9)x = 81 - 18\sqrt{x - 9} + (x - 9)
Squaring eliminates the isolated radical. The right side is expanded using the algebraic identity (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2.
3
Simplify the equation by canceling xx from both sides and combining constant terms.
x=x+7218x918x9=72x = x + 72 - 18\sqrt{x - 9} \Rightarrow 18\sqrt{x - 9} = 72
Combining like terms simplifies the equation, leaving only a single radical expression.
4
Divide by 18 and square both sides one final time to solve for xx.
x9=4x9=16x=25\sqrt{x - 9} = 4 \Rightarrow x - 9 = 16 \Rightarrow x = 25
Isolating the final radical and squaring removes the remaining root, yielding a simple linear equation for xx.

Anahtar Kavram

Solving radical equations and applying algebraic identities with surds.
Soru 240Soru

Suppose a certain positive integer xx yields a remainder of 44 upon division by 1717. What is the remainder obtained when the quantity 5x385x - 38 is divided by 1717?

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Cevap: 1616

Cevap

The correct answer is 1616.
By substituting the initial remainder 44 into the expression, we evaluate 5(4)38=185(4) - 38 = -18. To find the valid positive remainder modulo 1717, we add multiples of 1717 until the number becomes non-negative: 18+34=16-18 + 34 = 16.

Adım Adım Çözüm

1
Identify the modular relationship for xx
x4(mod17)x \equiv 4 \pmod{17}
The problem states that xx leaves a remainder of 44 when divided by 1717.
2
Substitute this remainder into the given expression 5x385x - 38
5(4)38=2038=185(4) - 38 = 20 - 38 = -18
Using the properties of modular arithmetic, we can substitute the remainder directly into polynomial expressions.
3
Find the equivalent positive remainder for 18-18 modulo 1717
18+17+17=16-18 + 17 + 17 = 16
Remainders must be non-negative integers strictly less than the divisor. Adding multiples of 1717 to 18-18 gives the valid positive equivalent.

Anahtar Kavram

Modular Arithmetic and Negative Remainders
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Basic Numeracy Alıştırma Soruları — State PSC Exam — Sayfa 12 | Examkin