Basic Numeracy

295 soru

Soru 241Soru

An arithmetic expression is given as 20×264020 \times 26 - 40. Which of the following represents the positive remainder when the final computed value of this expression is divided by 77?

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Cevap: 4

Cevap

The correct positive remainder is 4.
By following the order of operations, the expression evaluates to 480. When 480 is divided by 7, the quotient is 68, leaving a positive remainder of 4 (68×7=47668 \times 7 = 476, and 480476=4480 - 476 = 4). The same result is efficiently reached using modular arithmetic: (6×5)5=25(6 \times 5) - 5 = 25, and 254(mod7)25 \equiv 4 \pmod 7.

Adım Adım Çözüm

1
Calculate the exact numerical value of the expression.
20×2640=52040=48020 \times 26 - 40 = 520 - 40 = 480.
Applying standard order of operations (BODMAS), multiplication is performed before subtraction.
2
Divide the computed value by 7 to find the remainder.
480÷7=68480 \div 7 = 68 with a remainder of 44.
The remainder is the integer left over after dividing the total by the divisor.
3
Verify using modular arithmetic (optional).
201(mod7)20 \equiv -1 \pmod 7, 265(mod7)26 \equiv 5 \pmod 7, and 405(mod7)40 \equiv 5 \pmod 7. Thus, (1×5)5=10(-1 \times 5) - 5 = -10. Modulo 7, 1034-10 \equiv -3 \equiv 4.
Modular arithmetic provides a faster secondary method to confirm the remainder without computing large numbers.

Anahtar Kavram

Divisibility Rules and Remainder Theorem
Soru 242Soru

What is the remainder when the expression 4+9×11854 + 9 \times 11^{85} is divided by 1212?

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Cevap: 7

Cevap

The correct remainder is 7.
The correct answer is 7 because applying modular arithmetic rules simplifies 118511^{85} to 1-1 modulo 12. Substituting this back into the expression yields 4+9×(1)=54 + 9 \times (-1) = -5. To find the true positive remainder, the modulus 12 is added to 5-5, resulting in exactly 7.

Adım Adım Çözüm

1
Find the remainder of the base 11 when divided by the modulus 12.
111(mod12)11 \equiv -1 \pmod{12}
Using negative remainders simplifies calculations involving large exponents.
2
Evaluate the exponentiation term modulo 12.
1185(1)85=1(mod12)11^{85} \equiv (-1)^{85} = -1 \pmod{12}
A negative number raised to an odd power remains negative.
3
Substitute the evaluated power back into the expression following the standard order of operations (BODMAS).
4+9×(1)=49=5(mod12)4 + 9 \times (-1) = 4 - 9 = -5 \pmod{12}
Multiplication must be performed before addition.
4
Convert the negative remainder into a valid positive remainder.
5+12=7-5 + 12 = 7
The final remainder must be a positive integer between 0 and 11, achieved by adding the modulus.

Anahtar Kavram

Modular Arithmetic, Negative Remainders, and Order of Operations
Soru 243Soru

Consider the basic definitions and categories in the number system. Which of the following statements are mathematically correct? (Select all that apply)

Geçerli olan tümünü seçin

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Cevap: Every integer can be expressed as a rational number.; The number 22 is the only even prime number.

Cevap

The correct statements are that every integer is a rational number, and the number 2 is the only even prime number.
The valid statements accurately reflect mathematical definitions: integers are a subset of rational numbers because any integer can be expressed as a fraction with a denominator of 11, and 22 is structurally the only even number with exactly two divisors.

Adım Adım Çözüm

1
Analyze the relationship between integers and rational numbers.
Every integer nn can be written as n1\frac{n}{1}.
To verify if an integer fits the definition of a rational number.
2
Evaluate the classification of natural numbers into prime and composite.
The number 11 is an exception, being neither prime nor composite.
To check if the binary classification of non-prime implying composite holds true for all natural numbers.
3
Examine the properties of prime numbers and parity.
The number 22 is prime, while all other even numbers are divisible by 22 and thus composite.
To confirm whether 22 is uniquely the only even prime number.
4
Compare the fraction 227\frac{22}{7} with the mathematical constant π\pi.
227\frac{22}{7} is a rational approximation, whereas π\pi is strictly irrational.
To determine if an exact equality exists between these two commonly associated values.

Anahtar Kavram

Classification of numbers into rational, irrational, prime, and composite categories, along with their fundamental properties and exceptions.
Soru 244Soru

Evaluate the exact positive remainder that results from dividing 575455^{75} - 45 by 126126.

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Cevap: 80

Cevap

The positive remainder is 80.
The exact remainder is determined using modular arithmetic rules. By noting that 53=1255^3 = 125, we see that 1251(mod126)125 \equiv -1 \pmod{126}. The expression 5755^{75} can be rewritten as (53)25(5^3)^{25}, which evaluates to (1)25=1(-1)^{25} = -1. Subtracting the constant 4545 yields an intermediate remainder of 46-46. Because standard division requires a non-negative remainder, we must add the divisor (126126) to 46-46, which results in 8080.

Adım Adım Çözüm

1
Relate the base of the exponential term to the divisor
53=1251(mod126)5^3 = 125 \equiv -1 \pmod{126}
Finding a power of the base that equals 1 or -1 modulo the divisor significantly simplifies calculations with large exponents.
2
Express the given exponent in terms of the chosen power
575=(53)255^{75} = (5^3)^{25}
This allows for direct substitution of the modular equivalent.
3
Evaluate the remainder of the exponential portion
(1)25=1(mod126)(-1)^{25} = -1 \pmod{126}
Substituting 1-1 for 125125 makes evaluating the 25th25^{th} power trivial.
4
Incorporate the constant term into the expression
145=46(mod126)-1 - 45 = -46 \pmod{126}
The full expression is 575455^{75} - 45, so the constant must be subtracted from the remainder of the exponential part.
5
Convert the negative remainder into a standard positive remainder
46+126=80-46 + 126 = 80
Remainders must be non-negative. Adding the divisor to a negative remainder provides the correct equivalent positive remainder.

Anahtar Kavram

Modular Exponentiation and Negative Remainders

Alternatif Yöntem

You could apply the binomial theorem by rewriting 5755^{75} as 12525=(1261)25125^{25} = (126 - 1)^{25}. Expanding this yields a series of terms that are all multiples of 126126, plus a final term of (1)25(-1)^{25}. This clearly leaves a remainder of 1-1. Subtracting 4545 gives 46-46, which is then converted to 8080 by adding 126126.
Tahmini Süre:1m 0s
Soru 245Soru

The real number system is divided into rational and irrational numbers, with integers forming a subset of rational numbers. Which of the following numbers is classified as a rational number but is NOT an integer?

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Cevap: 154\frac{15}{4}

Cevap

154\frac{15}{4}
The number 154\frac{15}{4} is a rational number because it is expressed as a ratio of two integers. However, since 1515 is not evenly divisible by 44, it does not simplify to a whole number, meaning it falls strictly within the rational numbers but outside the subset of integers.

Adım Adım Çözüm

1
Analyze each number to determine if it is rational or irrational.
154\frac{15}{4}, 42-42, and 25\sqrt{25} can be expressed as ratios of integers, so they are rational. π\pi is known to be irrational.
The question requires finding a number that is first confirmed to be rational.
2
Identify which of the rational numbers are also integers.
42-42 is a negative integer. 25\sqrt{25} simplifies to 55, which is a positive integer.
Integers include whole numbers and their negatives. We need to eliminate these to find a number that is not an integer.
3
Select the remaining rational number.
154\frac{15}{4} is a rational number that cannot be simplified to a whole number.
It fulfills both conditions: being a rational number and not being an integer.

Anahtar Kavram

Classification of rational numbers and integers
Soru 246Soru

If PP is the smallest prime number and CC is the smallest positive composite number, what is the value of P+CP + C?

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Cevap: 6

Cevap

6
The smallest prime number is 2, as it is the first positive integer greater than 1 with exactly two distinct divisors. The smallest positive composite number is 4, as it is the first positive integer with more than two distinct divisors (1, 2, and 4). The number 1 is excluded from both categories. Therefore, their sum is 2 + 4 = 6.

Adım Adım Çözüm

1
Identify the smallest prime number.
P = 2
A prime number is a positive integer greater than 1 that has exactly two positive divisors. The smallest such number is 2.
2
Identify the smallest positive composite number.
C = 4
A composite number is a positive integer that has at least one divisor other than 1 and itself. The numbers 1, 2, and 3 are not composite. The number 4 has divisors 1, 2, and 4, making it the smallest positive composite number.
3
Calculate the sum of P and C.
2 + 4 = 6
The question asks for the sum of the two identified values.

Anahtar Kavram

Basic definitions and properties of prime and composite numbers
Soru 247Soru

What is the positive remainder when the product 54×8254 \times 82 is divided by 1111?

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Cevap: 6

Cevap

6
By finding the individual remainders of the factors (1-1 and 55) and multiplying them, we get 5-5. Adding the divisor (1111) to this negative remainder yields the correct positive remainder of 66.

Adım Adım Çözüm

1
Find the remainder of 5454 when divided by 1111.
Since 11×5=5511 \times 5 = 55, we can write 5454 as 55155 - 1. Thus, 541(mod11)54 \equiv -1 \pmod{11}.
Using a negative remainder simplifies the subsequent multiplication.
2
Find the remainder of 8282 when divided by 1111.
Since 11×7=7711 \times 7 = 77, we have 8277=582 - 77 = 5. Thus, 825(mod11)82 \equiv 5 \pmod{11}.
We need the remainder of the second factor to apply the remainder theorem for products.
3
Multiply the individual remainders.
(1)×5=5(-1) \times 5 = -5
According to modular arithmetic properties, the remainder of a product is the product of the individual remainders.
4
Convert the negative remainder to a positive remainder.
5+11=6-5 + 11 = 6
The question specifically asks for the positive remainder. Adding the divisor to a negative remainder gives the equivalent positive remainder.

Anahtar Kavram

Remainder Theorem and Modular Arithmetic
Soru 248Soru

Consider the three fractions 125\frac{12}{5}, 247\frac{24}{7}, and 3611\frac{36}{11}. What is the exact value of their Least Common Multiple (LCM)?

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Cevap: 72

Cevap

The Least Common Multiple (LCM) of the given fractions is 72.
To find the Least Common Multiple (LCM) of a set of fractions, we must divide the LCM of their numerators by the HCF of their denominators. The numerators (1212, 2424, and 3636) have an LCM of 7272. The denominators (55, 77, and 1111) share no common factors other than 11, making their HCF 11. Thus, the final LCM is 72/1=7272 / 1 = 72.

Adım Adım Çözüm

1
State the standard formula for finding the LCM of multiple fractions.
LCM = (LCM of numerators) / (HCF of denominators).
This mathematical property governs how multiples apply to rational numbers.
2
Calculate the LCM of the numerators.
The LCM of 1212, 2424, and 3636 is 7272.
7272 is the smallest integer perfectly divisible by all three numerators.
3
Calculate the HCF of the denominators.
The HCF of 55, 77, and 1111 is 11.
The numbers 55, 77, and 1111 are prime and share no common factors other than 11.
4
Compute the final fraction LCM.
72÷1=7272 \div 1 = 72.
Dividing the computed numerator LCM by the denominator HCF yields the answer.

Anahtar Kavram

Calculating the LCM of fractions using the specific formula relating numerators and denominators.
Soru 249Soru

If the 9-digit number 94x257y3694x257y36 is exactly divisible by 8888, what is the maximum possible value of the mathematical expression (5x3y)(5x - 3y)?

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Cevap: 27

Cevap

27
By applying the divisibility rules of 8 and 11, we isolate a finite set of possible digit combinations for x and y. Evaluating (5x3y)(5x - 3y) across all mathematically valid pairs proves that the pair x=6,y=1x=6, y=1 produces the highest numerical output of 27.

Adım Adım Çözüm

1
Determine the co-prime factors of the divisor.
The number must be divisible by 8 and 11, since 88 = 8 * 11 and GCD(8, 11) = 1.
Applying individual divisibility rules for co-prime factors is the standard method for composite divisors.
2
Apply the divisibility rule for 8 to the last three digits (y36y36).
The possible values for yy are 1, 3, 5, 7, and 9.
A number is divisible by 8 if its last three digits form a multiple of 8. 136, 336, 536, 736, and 936 all yield a remainder of 0 when divided by 8.
3
Apply the divisibility rule for 11 to the entire number.
The expression (x+y+4)(x + y + 4) must be a multiple of 11.
The rule for 11 requires the difference between the alternating sum of digits to be divisible by 11. Odd positions sum to (20+x+y)(20 + x + y) and even positions sum to 1616. Difference = (x+y+4)(x + y + 4).
4
Find all valid (x,y)(x, y) coordinate pairs.
The valid digit pairs are (6, 1), (4, 3), (2, 5), (0, 7), and (9, 9).
Since xx and yy are single digits between 0 and 9, (x+y+4)(x + y + 4) can only equal 11 or 22. This implies x+y=7x + y = 7 or x+y=18x + y = 18.
5
Evaluate the target expression (5x3y)(5x - 3y) for all valid pairs.
The values obtained are 27, 11, -5, -21, and 18 respectively. The absolute maximum is 27.
Testing all valid edge cases guarantees that the maximum possible value is correctly identified without assumptions.

Anahtar Kavram

Solving for unknown digits using combined co-prime divisibility rules and optimizing a linear algebraic expression based on finite digit constraints.
Tahmini Süre:2m 30s
Soru 250Soru

Determine the exact decimal value of the Least Common Multiple (LCM) for the two fractions 35\frac{3}{5} and 910\frac{9}{10}.

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Cevap: 1.8

Cevap

1.8
To find the LCM of fractions, we use the standard formula: LCM(numerators) / HCF(denominators). The numerators are 3 and 9, and their LCM is 9. The denominators are 5 and 10, and their HCF is 5. Dividing the LCM of the numerators by the HCF of the denominators gives 9/5. Converting this fraction to a decimal yields exactly 1.8.

Adım Adım Çözüm

1
Identify the correct formula for finding the LCM of fractions.
LCM of fractions = LCM(numerators) / HCF(denominators)
This is the fundamental rule for calculating the least common multiple when dealing with rational numbers.
2
Calculate the Least Common Multiple of the numerators.
The numerators are 3 and 9. Their LCM is 9.
9 is the smallest integer that is perfectly divisible by both 3 and 9.
3
Calculate the Highest Common Factor of the denominators.
The denominators are 5 and 10. Their HCF is 5.
5 is the largest integer that perfectly divides both 5 and 10 without leaving a remainder.
4
Apply the formula and convert the resulting fraction to a decimal.
LCM = 9 / 5 = 1.8
The question specifically asks for the exact decimal value, so the fraction 9/5 must be converted to 1.8.

Anahtar Kavram

The Least Common Multiple (LCM) of a set of fractions is found by dividing the LCM of their numerators by the HCF of their denominators.
Soru 251Soru

Consider the number P=4+7×3899P = 4 + 7 \times 38^{99}. What is the remainder when PP is divided by 1313?

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Cevap: 10

Cevap

10
The correct remainder is found by applying modular arithmetic step-by-step. First, 3838 modulo 1313 simplifies to 1-1. Because 9999 is an odd power, (1)99(-1)^{99} equals 1-1. Multiplying this by 77 yields 7-7. Adding 44 gives an intermediate remainder of 3-3. To find the true positive remainder, we add the divisor 1313 to 3-3, resulting in 1010.

Adım Adım Çözüm

1
Simplify the base of the exponentiated term modulo 13.
381(mod13)38 \equiv -1 \pmod{13}
Using a negative remainder that is close to zero makes evaluating large exponential powers mathematically manageable.
2
Evaluate the exponentiated term modulo 13.
(1)99=1(-1)^{99} = -1
A negative base raised to an odd power retains its negative sign.
3
Substitute the simplified term back into the original expression and apply the correct order of operations.
4+7×(1)=47=34 + 7 \times (-1) = 4 - 7 = -3
Standard order of operations requires multiplication to be performed before addition.
4
Convert the negative intermediate remainder into a valid positive remainder.
33+13=10(mod13)-3 \equiv -3 + 13 = 10 \pmod{13}
Remainders must be positive integers strictly less than the divisor.

Anahtar Kavram

Modular Arithmetic with Negative Bases and Order of Operations

Alternatif Yöntem

One could alternatively find the positive remainder of 38 modulo 13, which is 12, and then evaluate 4+7×1299(mod13)4 + 7 \times 12^{99} \pmod{13}. However, this requires observing the cyclicity pattern of powers of 12 modulo 13, making the negative base approach (-1) far more direct and efficient.
Tahmini Süre:1m 0s
Soru 252Soru

The product of two positive integers is 21602160 and their Highest Common Factor (HCF) is 1212. What is their Least Common Multiple (LCM)?

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Cevap: 180

Cevap

180
For any two positive integers, the product of their Highest Common Factor (HCF) and Least Common Multiple (LCM) is always equal to the product of the numbers themselves. Given that the product is 21602160 and the HCF is 1212, the LCM is calculated by rearranging the formula to LCM=ProductHCF\text{LCM} = \frac{\text{Product}}{\text{HCF}}. Substituting the values gives 2160÷12=1802160 \div 12 = 180.

Adım Adım Çözüm

1
Identify the fundamental formula connecting HCF, LCM, and the product of two positive integers.
HCF×LCM=Product\text{HCF} \times \text{LCM} = \text{Product}
This relationship allows you to find one missing value when the other two are known.
2
Substitute the known values from the problem into the equation.
12×LCM=216012 \times \text{LCM} = 2160
The problem explicitly states that the product is 21602160 and the HCF is 1212.
3
Solve for the LCM by dividing both sides of the equation by 1212.
LCM=180\text{LCM} = 180
Isolating the LCM variable provides the final requested value.

Anahtar Kavram

Relationship between the product of two numbers and their HCF and LCM
Soru 253Soru

Evaluate the mathematical validity of the three theoretical propositions listed below, which pertain to the fundamental properties of real numbers:

I. For two distinct irrational numbers xx and yy, it is mathematically possible for both their sum (x+y)(x + y) and their product (xy)(x \cdot y) to evaluate to rational numbers simultaneously.
II. If NN represents any natural number, its principal square root N\sqrt{N} must be either a natural number or an irrational number; it can never equate to a non-integer rational fraction.
III. The integer 00 is formally categorized as a positive even number, and the constant π\pi is categorized as a rational number because it represents the exact ratio of a circle's circumference to its diameter.

Which of the given propositions is/are correct?

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Cevap: Only I and II

Cevap

The correct answer is the option stating that only propositions I and II are correct.
Proposition I is mathematically accurate because using conjugate irrational numbers yields rational sums and products. Proposition II is accurate because the square root of a natural number cannot exist as a non-integer fraction; it must either be an integer or strictly irrational. Proposition III contains two definitive errors: zero is neither positive nor negative, and pi is an irrational number because it cannot be formed by the ratio of two integers.

Adım Adım Çözüm

1
Analyze the validity of Proposition I regarding the closure of irrational numbers.
Determined to be True. If x=5+3x = 5 + \sqrt{3} and y=53y = 5 - \sqrt{3} (both irrational), their sum is 1010 (rational) and their product is 253=2225 - 3 = 22 (rational). Thus, it is mathematically possible.
To test the understanding that the set of irrational numbers is not closed under addition or multiplication.
2
Analyze the validity of Proposition II regarding the square roots of natural numbers.
Determined to be True. A rational fraction in its simplest form p/qp/q (where q>1q > 1) squared is p2/q2p^2/q^2. This can never simplify to a whole number NN. Therefore, N\sqrt{N} is either a whole integer (if NN is a perfect square) or strictly irrational.
To verify the structural classification of square roots and rational fractions.
3
Analyze the validity of Proposition III regarding the classification of zero and pi.
Determined to be False. First, while zero (00) is an even integer, it separates positive and negative numbers and is definitively neither positive nor negative. Second, while π=C/d\pi = C/d, a rational number requires the ratio of two integers. In any true circle, circumference and diameter cannot both be integers simultaneously. Thus, π\pi is irrational.
To identify specific, common misconceptions regarding zero's sign parity and the rational geometric definition of pi.

Anahtar Kavram

Classification and structural properties of real numbers, including the irrationality of pi, the neutrality of zero, and arithmetic operations on irrational numbers.
Tahmini Süre:2m 0s
Soru 254Soru

Two automated watering sprinklers in a greenhouse operate on continuous cycles. Sprinkler X activates every 125\frac{12}{5} minutes, and Sprinkler Y activates every 1615\frac{16}{15} minutes. If both sprinklers activate simultaneously at a given moment, what is the minimum time interval, in minutes, before they activate together again?

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Cevap: 485\frac{48}{5}

Cevap

The minimum time interval is 485\frac{48}{5} minutes.
To find when two periodic events will happen together again, we must calculate the Least Common Multiple (LCM) of their periods. For fractions, the LCM is found by dividing the LCM of the numerators (12 and 16, which is 48) by the HCF of the denominators (5 and 15, which is 5). This results in 485\frac{48}{5}.

Adım Adım Çözüm

1
Identify that the problem requires finding the Least Common Multiple (LCM) of the two time intervals to determine when the periodic events will align again.
Calculate the LCM of 125\frac{12}{5} and 1615\frac{16}{15}.
Simultaneous events occurring at regular intervals coincide at the lowest common multiple of their respective periods.
2
Apply the formula for the LCM of fractions.
Formula: LCM of numeratorsHCF of denominators\frac{\text{LCM of numerators}}{\text{HCF of denominators}}.
This is the standard mathematical rule for finding the LCM of fractional values.
3
Find the LCM of the numerators (12 and 16) and the HCF of the denominators (5 and 15).
LCM(12, 16) = 48. HCF(5, 15) = 5.
The smallest positive number divisible by both 12 and 16 is 48. The largest positive number that divides both 5 and 15 is 5.
4
Substitute the calculated values back into the fraction formula.
485\frac{48}{5}
Combining the calculated numerator and denominator yields the final time interval.

Anahtar Kavram

Calculating the Least Common Multiple (LCM) of fractions to solve simultaneous event problems.
Soru 255Soru

Let XX be the total number of positive factors of 120120, and let YY be the total number of positive factors of 150150. What is the value of the expression X+Y÷2×3X + Y \div 2 \times 3?

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Cevap: 34

Cevap

The value of the expression is 34.
The correct answer accurately determines the number of factors for 120 (which is 16) and 150 (which is 12). By substituting these values into the expression 16+12÷2×316 + 12 \div 2 \times 3 and strictly following the order of operations, division is performed first (12÷2=612 \div 2 = 6), followed by multiplication (6×3=186 \times 3 = 18), and finally addition (16+18=3416 + 18 = 34).

Adım Adım Çözüm

1
Determine the prime factorization of 120 and calculate its total number of positive factors, X.
120=23×31×51120 = 2^3 \times 3^1 \times 5^1. Thus, X=(3+1)(1+1)(1+1)=4×2×2=16X = (3+1)(1+1)(1+1) = 4 \times 2 \times 2 = 16.
The total number of factors of an integer is found by adding 1 to each exponent in its prime factorization and multiplying the results.
2
Determine the prime factorization of 150 and calculate its total number of positive factors, Y.
150=21×31×52150 = 2^1 \times 3^1 \times 5^2. Thus, Y=(1+1)(1+1)(2+1)=2×2×3=12Y = (1+1)(1+1)(2+1) = 2 \times 2 \times 3 = 12.
Applying the same factor counting formula to the prime factorization of 150.
3
Substitute the values of X and Y into the expression and evaluate according to the order of operations (BODMAS).
Expression: 16+12÷2×316 + 12 \div 2 \times 3. Step 3a (Division): 12÷2=612 \div 2 = 6. Step 3b (Multiplication): 6×3=186 \times 3 = 18. Step 3c (Addition): 16+18=3416 + 18 = 34.
BODMAS dictates that division and multiplication are evaluated from left to right before any addition is performed.

Anahtar Kavram

Calculating total number of factors using prime factorization combined with standard order of operations.
Tahmini Süre:1m 30s
Soru 256Soru

Consider the positive integer 21602160. How many of its positive factors are perfect squares?

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Cevap: 6

Cevap

6
The prime factorization of 21602160 is 24×33×512^4 \times 3^3 \times 5^1. For a factor to be a perfect square, all the exponents in its prime factorization must be even integers. Analyzing the bases: the base 22 can have an exponent of 0,2, or 40, 2, \text{ or } 4 (three options). The base 33 can have an exponent of 0 or 20 \text{ or } 2 (two options). The base 55 can only have an exponent of 00 to remain even (one option). Multiplying the number of possibilities for each base gives 3×2×1=63 \times 2 \times 1 = 6 total perfect square factors.

Adım Adım Çözüm

1
Find the prime factorization of 21602160.
2160=24×33×512160 = 2^4 \times 3^3 \times 5^1
Prime factorization is necessary to analyze the properties of the number's factors.
2
Identify the mathematical condition for a factor to be a perfect square.
Any perfect square factor must have the form 22x×32y×52z2^{2x} \times 3^{2y} \times 5^{2z} where the exponents are even.
Perfect squares require all prime factors to appear in pairs.
3
Count the number of valid even exponents for each prime factor.
For 22: exponents 0,2,40, 2, 4 (33 choices). For 33: exponents 0,20, 2 (22 choices). For 55: exponent 00 (11 choice).
The exponent of each prime in the factor cannot exceed its exponent in the original number.
4
Calculate the total number of perfect square factors.
3×2×1=63 \times 2 \times 1 = 6
The Fundamental Principle of Counting states we must multiply the independent choices to get the total number of combinations.

Anahtar Kavram

Using prime factorization to determine the properties and quantity of specific types of factors (perfect squares).
Soru 257Soru

What is the Highest Common Factor (HCF) of the fractions 34\frac{3}{4} and 910\frac{9}{10}?

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Cevap: 320\frac{3}{20}

Cevap

The correct Highest Common Factor is 320\frac{3}{20}.
To find the Highest Common Factor (HCF) of a set of fractions, the correct formula is to divide the HCF of their numerators by the LCM of their denominators. For the given fractions, the numerators are 3 and 9, and their HCF is 3. The denominators are 4 and 10, and their LCM is 20. Therefore, the HCF of the two fractions is 320\frac{3}{20}.

Adım Adım Çözüm

1
Identify the formula for finding the HCF of fractions.
HCF of fractions = (HCF of Numerators) / (LCM of Denominators)
This is the mathematical rule required to find the greatest common divisor for fractional numbers.
2
Calculate the HCF of the numerators (3 and 9).
The HCF of 3 and 9 is 3.
3 is the largest integer that divides both 3 and 9 without leaving a remainder.
3
Calculate the LCM of the denominators (4 and 10).
The LCM of 4 and 10 is 20.
The multiples of 4 are 4, 8, 12, 16, 20... and the multiples of 10 are 10, 20... The lowest common multiple they share is 20.
4
Divide the result of the numerators' HCF by the denominators' LCM.
320\frac{3}{20}
Applying the values to the formula gives the final fractional answer.

Anahtar Kavram

HCF and LCM of Fractions
Soru 258Soru

Three different wooden boards have lengths of 34\frac{3}{4} meters, 910\frac{9}{10} meters, and 158\frac{15}{8} meters, respectively. A carpenter wants to cut them into smaller pieces of equal length such that no material is wasted. What is the maximum possible length of each smaller piece?

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Cevap: 340\frac{3}{40} meters

Cevap

The correct answer is 340\frac{3}{40} meters.
To find the maximum equal length that can be cut from all three boards, we must find the Highest Common Factor (HCF) of their lengths. The formula for the HCF of fractions is the HCF of the numerators divided by the LCM of the denominators. The numerators are 3,9,3, 9, and 1515, yielding an HCF of 33. The denominators are 4,10,4, 10, and 88, yielding an LCM of 4040. Thus, the maximum length is 340\frac{3}{40} meters.

Adım Adım Çözüm

1
Identify the mathematical operation required.
The problem asks for the 'maximum possible length' that can evenly divide all three board lengths without remainders. This requires finding the Highest Common Factor (HCF) of the three fractions.
Cutting multiple items into the largest possible equal smaller pieces is a classic application of HCF.
2
Recall the formula for finding the HCF of fractions.
HCF of fractions=HCF of NumeratorsLCM of Denominators\text{HCF of fractions} = \frac{\text{HCF of Numerators}}{\text{LCM of Denominators}}
This is the standard rule for finding the greatest common divisor of a set of rational numbers.
3
Calculate the HCF of the numerators (3,9,153, 9, 15).
The factors of 33 are 1,31, 3. The factors of 99 are 1,3,91, 3, 9. The factors of 1515 are 1,3,5,151, 3, 5, 15. The highest common factor is 33.
The numerator of our final fraction must be the HCF of the given numerators.
4
Calculate the LCM of the denominators (4,10,84, 10, 8).
The prime factorization of 44 is 222^2. For 88, it is 232^3. For 1010, it is 2×52 \times 5. The LCM takes the highest power of each prime present: 23×5=8×5=402^3 \times 5 = 8 \times 5 = 40.
The denominator of our final fraction must be the LCM of the given denominators.
5
Combine the results to find the final HCF.
340\frac{3}{40} meters.
Applying the formula from Step 2 with the values found in Step 3 and Step 4.

Anahtar Kavram

HCF and LCM of Fractions
Soru 259Soru

Consider the following 88 mathematical expressions:

I. π227\pi - \frac{22}{7}
II. 273\frac{\sqrt{27}}{\sqrt{3}}
III. (32)2(\sqrt{3} - \sqrt{2})^2
IV. The infinite decimal 0.1011011100.101101110\dots (where the number of consecutive 11 s increases by one each time)
V. 1.4141.414
VI. 10×2.5\sqrt{10} \times \sqrt{2.5}
VII. e0e^0
VIII. 2+8\sqrt{2} + \sqrt{8}

How many of the above expressions evaluate to a rational number?

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Cevap: 4

Cevap

Exactly 4 of the expressions evaluate to a rational number.
Out of the 8 expressions provided, exactly 4 result in rational numbers: Expression II (simplifies to 3), Expression V (terminating decimal 1414/1000), Expression VI (simplifies to sqrt(25) = 5), and Expression VII (simplifies to 1). The remaining 4 expressions yield irrational results.

Adım Adım Çözüm

1
Evaluate expression I (pi minus 22/7)
The expression evaluates to an irrational number.
The number pi is irrational, while 22/7 is a rational approximation. The difference between an irrational number and a rational number is always irrational.
2
Evaluate expression II (sqrt(27) / sqrt(3))
The expression simplifies to 3, which is a rational number.
Using the properties of radicals, sqrt(27) / sqrt(3) = sqrt(27/3) = sqrt(9) = 3.
3
Evaluate expression III (square of (sqrt(3) - sqrt(2)))
The expression expands to 5 - 2*sqrt(6), which is an irrational number.
Applying the binomial square formula (a-b)^2 = a^2 - 2ab + b^2 yields 3 - 2*sqrt(6) + 2. Since sqrt(6) is irrational, the entire expression is irrational.
4
Evaluate expression IV (the pattern decimal 0.101101110...)
The expression is an irrational number.
The decimal is non-terminating and non-periodic (the pattern changes constantly by adding an extra 1), which is the definition of an irrational decimal.
5
Evaluate expression V (1.414)
The expression is a rational number.
1.414 is a terminating decimal. Any terminating decimal can be written as a fraction of integers (1414/1000), making it rational.
6
Evaluate expression VI (sqrt(10) * sqrt(2.5))
The expression simplifies to 5, which is a rational number.
Multiplying the terms inside the radicals gives sqrt(10 * 2.5) = sqrt(25) = 5.
7
Evaluate expression VII (e^0)
The expression simplifies to 1, which is a rational number.
Any non-zero real number raised to the power of 0 equals 1.
8
Evaluate expression VIII (sqrt(2) + sqrt(8))
The expression simplifies to 3*sqrt(2), which is an irrational number.
sqrt(8) can be simplified to 2*sqrt(2). Adding sqrt(2) gives 3*sqrt(2), which remains an irrational product.
9
Count the total number of rational expressions
Expressions II, V, VI, and VII are rational. Total count is 4.
Identifying the rational outcomes from the previous steps.

Anahtar Kavram

Properties and Definitions of Rational and Irrational Numbers
Tahmini Süre:2m 30s
Soru 260Soru

Analyze the following three mathematical assertions concerning the classification and properties of numbers:

Assertion I: The expression 3216÷4×2\sqrt{32} - 16 \div 4 \times \sqrt{2} evaluates to an irrational number.
Assertion II: For any prime number pp that is strictly greater than 22, the value of p21p^2 - 1 is always a multiple of 88.
Assertion III: The number 00 is classified as a rational number and an even integer, but it is neither a prime nor a composite number.

Which of the assertions provided above are logically correct?

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Cevap: Assertions II and III are the only correct statements.

Cevap

Assertions II and III are the only correct statements.
Assertion II is mathematically accurate because the square of any odd prime minus one always factors into 4k(k+1)4k(k+1), which is a multiple of 88. Assertion III is also accurate as zero strictly fits the definitions of a rational number (0/10/1) and an even integer (0=2×00 = 2 \times 0), while being neither prime nor composite. Assertion I is false because correctly evaluating the expression from left-to-right yields 00, which is a rational number.

Adım Adım Çözüm

1
Evaluate Assertion I using the correct order of operations (BODMAS/PEMDAS).
3216÷4×2=424×2=4242=0\sqrt{32} - 16 \div 4 \times \sqrt{2} = 4\sqrt{2} - 4 \times \sqrt{2} = 4\sqrt{2} - 4\sqrt{2} = 0.
Division and multiplication have equal precedence and are evaluated from left to right. The result, 00, is a rational number, making Assertion I false.
2
Analyze Assertion II for primes p>2p > 2.
All primes p>2p > 2 are odd, so p=2k+1p = 2k + 1 for some integer kk. Then p21=(2k+1)21=4k2+4k=4k(k+1)p^2 - 1 = (2k+1)^2 - 1 = 4k^2 + 4k = 4k(k+1).
Since kk and k+1k+1 are consecutive integers, one must be even. Thus, k(k+1)k(k+1) is an even integer, making 4k(k+1)4k(k+1) a multiple of 88. Assertion II is strictly true.
3
Verify the classifications of the number 00 in Assertion III.
00 can be written as 0/10/1 (rational), is divisible by 22 without remainder (even), and has no strictly positive divisors that satisfy the definition of primes or composites.
By standard mathematical definitions, 00 is rational, even, and neither prime nor composite. Assertion III is true.

Anahtar Kavram

Classification of numbers involving rational/irrational properties, algebraic properties of prime numbers, and the precise classification of zero.

Alternatif Yöntem

For Assertion II, students under time pressure can test the first few qualifying prime numbers (e.g., p=3321=8p=3 \Rightarrow 3^2-1=8; p=5521=24p=5 \Rightarrow 5^2-1=24) to quickly establish confidence in the truth of the statement without a formal algebraic proof.
Tahmini Süre:2m 0s
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Basic Numeracy Alıştırma Soruları — State PSC Exam — Sayfa 13 | Examkin