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Zorluk: OrtaPharmacokinetic and Pharmacodynamic Principles

A 62-year-old man is admitted to the pulmonary care unit for management of a severe, refractory asthma exacerbation. The medical team initiates a continuous intravenous infusion of an adjunctive bronchodilator at a rate of 40 mg/hr40 \text{ mg/hr}. The medication exhibits first-order elimination kinetics. For this specific patient, the drug has a volume of distribution (VdV_d) of 40 L40 \text{ L} and an elimination half-life (t1/2t_{1/2}) of 6.93 hours6.93 \text{ hours} (note: ln⁡(2)≈0.693\ln(2) \approx 0.693). To rapidly achieve therapeutic levels, the physician orders an initial intravenous loading dose designed to immediately establish the exact steady-state plasma concentration that the continuous infusion will eventually maintain.

What is the required loading dose of the medication in milligrams?

Cevap: 400 mg

Cevap

400
To achieve the eventual steady-state concentration immediately, the administered loading dose must fill the patient's volume of distribution to that specific target concentration. First, find the target steady-state concentration (CssC_{ss}) that the infusion will achieve, which is defined as Css=Infusion RateClC_{ss} = \frac{\text{Infusion Rate}}{Cl}. The clearance (ClCl) is found using Cl=ke×VdCl = k_e \times V_d, where ke=0.693t1/2k_e = \frac{0.693}{t_{1/2}}. For this patient, ke=0.6936.93=0.1 hr−1k_e = \frac{0.693}{6.93} = 0.1 \text{ hr}^{-1}, and Cl=0.1 hr−1×40 L=4 L/hrCl = 0.1 \text{ hr}^{-1} \times 40 \text{ L} = 4 \text{ L/hr}. Consequently, Css=40 mg/hr4 L/hr=10 mg/LC_{ss} = \frac{40 \text{ mg/hr}}{4 \text{ L/hr}} = 10 \text{ mg/L}. The loading dose required is LD=Css×Vd=10 mg/L×40 L=400 mgLD = C_{ss} \times V_d = 10 \text{ mg/L} \times 40 \text{ L} = 400 \text{ mg}. Alternatively, this calculation algebraically simplifies to LD=Infusion Rateke=400.1=400 mgLD = \frac{\text{Infusion Rate}}{k_e} = \frac{40}{0.1} = 400 \text{ mg}.

Adım Adım Çözüm

1
Calculate the elimination rate constant (kek_e).
ke=0.1 hr−1k_e = 0.1 \text{ hr}^{-1}
The elimination rate constant is inversely proportional to the half-life: ke=0.693t1/2=0.6936.93 hrk_e = \frac{0.693}{t_{1/2}} = \frac{0.693}{6.93 \text{ hr}}.
2
Calculate the drug clearance (ClCl).
Cl=4 L/hrCl = 4 \text{ L/hr}
Clearance is the product of the elimination rate constant and the volume of distribution: Cl=ke×Vd=0.1 hr−1×40 LCl = k_e \times V_d = 0.1 \text{ hr}^{-1} \times 40 \text{ L}.
3
Calculate the target steady-state plasma concentration (CssC_{ss}).
Css=10 mg/LC_{ss} = 10 \text{ mg/L}
At steady state, the continuous infusion rate equals the elimination rate. Css=Infusion RateCl=40 mg/hr4 L/hrC_{ss} = \frac{\text{Infusion Rate}}{Cl} = \frac{40 \text{ mg/hr}}{4 \text{ L/hr}}.
4
Calculate the required loading dose (LDLD).
LD=400 mgLD = 400 \text{ mg}
The loading dose required to achieve a specific target concentration immediately is the product of that target concentration and the volume of distribution: LD=Css×Vd=10 mg/L×40 LLD = C_{ss} \times V_d = 10 \text{ mg/L} \times 40 \text{ L}.

Anahtar Kavram

Calculating a loading dose designed to immediately achieve the steady-state concentration of a planned continuous infusion.
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