Question

Difficulty: EasyArithmetic and Geometric Sequences and Series

The first term of a geometric sequence is 33, and the second term is 66. What is the 55 th term of this sequence?

  1. A
    1515
  2. B
    2424
  3. 4848Answer
  4. D
    9696
  5. E
    12961296

Answer

The fifth term of the sequence is 4848.
The first term of the geometric sequence is a1=3a_1 = 3, and the second term is a2=6a_2 = 6. The common ratio rr is 6÷3=26 \div 3 = 2. The nn th term of a geometric sequence is given by an=a1rn1a_n = a_1 \cdot r^{n-1}. For the fifth term (n=5n=5), the calculation is 3251=324=316=483 \cdot 2^{5-1} = 3 \cdot 2^4 = 3 \cdot 16 = 48. This matches the correct value.

Step-by-Step Solution

1
Find the common ratio (rr) of the geometric sequence.
r=63=2r = \frac{6}{3} = 2
The common ratio of a geometric sequence is found by dividing any term by the preceding term.
2
Apply the formula for the nn th term of a geometric sequence, an=a1rn1a_n = a_1 \cdot r^{n-1}, to find the fifth term.
a5=3251=324a_5 = 3 \cdot 2^{5-1} = 3 \cdot 2^4
We substitute a1=3a_1 = 3, r=2r = 2, and n=5n = 5 into the standard formula.
3
Evaluate the expression.
a5=316=48a_5 = 3 \cdot 16 = 48
Calculate 24=162^4 = 16 first, then multiply by 33 according to the order of operations.

Key Concept

Finding a specific term in a geometric sequence using the general formula
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