A field technician is testing a direct-current (DC) sensor module. What is the current flo… — Armed Services Vocational Aptitude Battery (ASVAB)

A field technician is testing a direct-current (DC) sensor module. What is the current flowing through the circuit when a potential difference of $90\text{ V}$ is applied across a total circuit resistance of $15\text{ k}\Omega$ ?

Answer:Under an applied potential difference of

90\text{ V}

, a circuit having a resistance of

15\text{ k}\Omega

conducts a current of 【6】 milliamperes.

Answer

6 milliamperes (6 mA)

According to Ohm's law (

I = \frac{V}{R}

), dividing the

90\text{ V}

source by the

15,000\ \Omega

(

15\text{ k}\Omega

) total resistance yields

0.006\text{ A}

, which converts directly to

6\text{ mA}

Step-by-Step Solution

Identify known circuit quantities and convert resistance from kilohms to ohms.

V = 90\text{ V}

and

R = 15\text{ k}\Omega = 15 \times 1,000\ \Omega = 15,000\ \Omega

Standard electrical formulas require resistance in base units of ohms (

\Omega

) to calculate current in amperes (

\text{A}

Apply Ohm's law (

I = \frac{V}{R}

) to solve for the current in amperes.

I = \frac{90\text{ V}}{15,000\ \Omega} = 0.006\text{ A}

Current is directly proportional to voltage and inversely proportional to resistance.

Convert current from amperes to milliamperes as requested by the statement.

0.006\text{ A} \times 1,000\text{ mA/A} = 6\text{ mA}

One milliampere equals one thousandth of an ampere (

1\text{ mA} = 10^{-3}\text{ A}

Key Concept

Ohm's Law (

I = \frac{V}{R}

) defines the proportional relationship between potential difference, current, and resistance in a direct-current circuit.

Estimated Time:45s

Question

Answer

Step-by-Step Solution

Key Concept

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