Examkin

Question

Difficulty: MediumOhm's Law

An avionics technician is analyzing a direct-current (DC) subassembly with an applied voltage of 36 V36\text{ V} across a load resistor rated at 1.8 kΩ1.8\text{ k}\Omega. What is the resistance in ohms and the resulting current in milliamperes? Fill in the blanks below to complete the circuit analysis.

Answer:The total resistance of the load is 【1800】 Ω\Omega, and the steady current flowing through the circuit is 【20】 mA\text{mA}.

Answer

The resistance is 1800 Ω and the current is 20 mA.
Converting 1.8 kΩ1.8\text{ k}\Omega to base units gives 1800 Ω1800\ \Omega. Dividing the applied voltage of 36 V36\text{ V} by 1800 Ω1800\ \Omega yields 0.02 A0.02\text{ A}, which corresponds to 20 mA20\text{ mA}.

Step-by-Step Solution

1
Convert the load resistance from kilohms (kΩ) to ohms (Ω)
R=1.8 kΩ=1.8×1000 Ω=1800 ΩR = 1.8\text{ k}\Omega = 1.8 \times 1000\ \Omega = 1800\ \Omega
Standard electrical calculations using Ohm's Law require base units of ohms, volts, and amperes.
2
Apply Ohm's Law (I=VRI = \frac{V}{R}) to calculate the circuit current in amperes
I=36 V1800 Ω=0.02 AI = \frac{36\text{ V}}{1800\ \Omega} = 0.02\text{ A}
Current is directly proportional to voltage and inversely proportional to resistance.
3
Convert the current from amperes (A) to milliamperes (mA)
I=0.02 A×1000 mA/A=20 mAI = 0.02\text{ A} \times 1000\text{ mA/A} = 20\text{ mA}
The required unit for the current blank is milliamperes.

Key Concept

Ohm's Law (I=VRI = \frac{V}{R}) and metric prefix conversions (kilo- and milli-).
Estimated Time:45s
Rate this question

Topics

Ohm's Law

More questions from this topic