A technician measures a steady current of 50\text{ mA} flowing through a 120\ \Omega fixed… — Armed Services Vocational Aptitude Battery (ASVAB)

A technician measures a steady current of $50\text{ mA}$ flowing through a $120\ \Omega$ fixed resistor in a signal conditioning module. What is the voltage drop across the resistor?

A
$2.4\text{ V}$
$6\text{ V}$ Answer
C
$6{}000\text{ V}$
D
$0.6\text{ V}$

Answer

6\text{ V}

According to Ohm's law, the voltage drop across a component is determined by multiplying current by resistance (

V = I \times R

). Converting

50\text{ mA}

0.05\text{ A}

and multiplying by

120\ \Omega

gives

6\text{ V}

Step-by-Step Solution

Convert the current from milliamperes (mA) to amperes (A).

50\text{ mA} = 0.05\text{ A}

Standard electrical formulas require current in amperes.

Apply Ohm's law formula for voltage (

V = I \times R

V = 0.05\text{ A} \times 120\ \Omega = 6\text{ V}

Voltage across a resistor equals the product of current and resistance.

Key Concept

Ohm's Law states that voltage is equal to current multiplied by resistance (

V = I \times R

Estimated Time:45s

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