A DC cooling fan installed in an equipment enclosure has an internal resistance of 16\ \Om… — Armed Services Vocational Aptitude Battery (ASVAB)

A DC cooling fan installed in an equipment enclosure has an internal resistance of $16\ \Omega$ and draws a steady current of $1.5\text{ A}$ during normal operation. According to Ohm's law, what is the voltage drop across the fan in volts ( $\text{V}$ )?

Answer: 24 V

Answer

24 V

According to Ohm's law, voltage (

V

) is found by multiplying current (

I

) by resistance (

R

). With a current of

1.5\text{ A}

and a resistance of

16\ \Omega

, the voltage is

1.5 \times 16 = 24\text{ V}

Step-by-Step Solution

Identify the known electrical quantities from the problem statement.

I = 1.5\text{ A}

and

R = 16\ \Omega

Ohm's law requires current and resistance values to calculate voltage.

State Ohm's law formula arranged to solve for voltage (

V

V = I \times R

The potential difference across a resistive element is directly proportional to the product of current and resistance.

Multiply the current by the resistance to find the voltage.

V = 1.5\text{ A} \times 16\ \Omega = 24\text{ V}

Performing the multiplication yields the potential difference in volts.

Key Concept

Ohm's Law (

V = I \times R

)

Estimated Time:30s

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