In an auxiliary radio circuit, a direct-current source applies 24\text{ V} across a fixed … — Armed Services Vocational Aptitude Battery (ASVAB)

In an auxiliary radio circuit, a direct-current source applies $24\text{ V}$ across a fixed resistor, producing a measured current flow of $8\text{ mA}$ . What is the resistance of the component?

A
$3\ \Omega$
B
$192\ \Omega$
C
$300\ \Omega$
$3{}000\ \Omega$ Answer

Answer

3{}000\ \Omega

Applying Ohm's Law (

R = \frac{V}{I}

) with the current converted to amperes (

8\text{ mA} = 0.008\text{ A}

) gives

\frac{24\text{ V}}{0.008\text{ A}} = 3{}000\ \Omega

Step-by-Step Solution

Convert the current from milliamperes (mA) to base amperes (A)

8\text{ mA} = 8 \times 10^{-3}\text{ A} = 0.008\text{ A}

Ohm's Law calculations require current in base units of amperes.

Apply Ohm's Law to solve for resistance (

R

)

R = \frac{V}{I} = \frac{24\text{ V}}{0.008\text{ A}} = 3{}000\ \Omega

Resistance equals voltage divided by current.

Key Concept

Ohm's Law defines the direct relationship between voltage, current, and resistance in a DC circuit (

R = \frac{V}{I}

Estimated Time:45s

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