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12 questions

Question 1Question

A network administrator is provisioning a hypervisor host server equipped with 128 GB128\text{ GB} of physical RAM. The host hypervisor requires 16 GB16\text{ GB} of RAM reserved strictly for host system operations and management overhead. If each guest virtual machine requires 12 GB12\text{ GB} of dedicated RAM, what is the maximum number of guest virtual machines that can run concurrently on this host without exceeding physical memory capacity?

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Answer: 9

Answer

9
To find the maximum number of concurrent guest virtual machines supported without memory overcommitment, first subtract the 16 GB16\text{ GB} reserved hypervisor overhead from the total 128 GB128\text{ GB} physical RAM, leaving 112 GB112\text{ GB}. Dividing 112 GB112\text{ GB} by the 12 GB12\text{ GB} required per VM yields approximately 9.339.33. Since partial virtual machines cannot be instantiated, the host supports a maximum of 9 fully provisioned VMs.

Step-by-Step Solution

1
Calculate RAM available for virtual machines
128 GB16 GB=112 GB128\text{ GB} - 16\text{ GB} = 112\text{ GB}
Deduct reserved hypervisor overhead from total physical RAM to ensure host operating system stability.
2
Calculate guest VM capacity
112 GB/12 GB=9.333...112\text{ GB} / 12\text{ GB} = 9.333... virtual machines
Determine how many 12 GB12\text{ GB} allocations fit into the remaining RAM pool.
3
Determine maximum concurrent VMs
9 virtual machines
Take the floor of the result because only complete virtual machines with full RAM allocations can run.

Key Concept

Virtual Machine RAM Capacity Planning and Hypervisor Overhead
Estimated Time:1m 30s
Question 2Question

A network administrator is assembling a virtualization host server containing multi-port network adapter expansion cards and high-speed storage accelerators. The host system components exhibit the following peak power requirements under full load:

- Processor (CPU): 190 W190\text{ W} peak draw
- Quad-port 10GbE PCIe expansion card: 35 W35\text{ W}
- PCIe NVMe storage accelerator card: 75 W75\text{ W}
- Motherboard, memory modules, and cooling system: 110 W110\text{ W} constant
- Solid-state drive array (4 drives total): 10 W10\text{ W} combined constant

To ensure operational stability and maintain peak efficiency, company guidelines require that the total peak power consumption does not exceed 75%75\% of the Power Supply Unit (PSU) maximum rated wattage output.

What is the minimum power supply capacity, in Watts (W\text{W}), required for this server configuration?

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Answer: 560

Answer

The minimum power supply capacity required is 560 W560\text{ W}.
The total peak power draw of all components is 190 W+35 W+75 W+110 W+10 W=420 W190\text{ W} + 35\text{ W} + 75\text{ W} + 110\text{ W} + 10\text{ W} = 420\text{ W}. Since the system must not exceed 75%75\% (0.750.75) of the PSU's total capacity, the required capacity is 420 W0.75=560 W\frac{420\text{ W}}{0.75} = 560\text{ W}.

Step-by-Step Solution

1
Sum the maximum peak wattage of all individual components to determine total peak system power draw.
Total peak draw = 190 W+35 W+75 W+110 W+10 W=420 W190\text{ W} + 35\text{ W} + 75\text{ W} + 110\text{ W} + 10\text{ W} = 420\text{ W}.
Accurate power sizing requires considering peak power consumption rather than average or idle draw.
2
Divide the total peak system draw by the maximum allowed load percentage (0.750.75).
Calculated minimum capacity = 420 W0.75=560 W\frac{420\text{ W}}{0.75} = 560\text{ W}.
Restricting continuous peak system draw to 75%75\% of rated PSU capacity leaves a 25%25\% operating headroom, maintaining power conversion efficiency and avoiding overload shutdowns.

Key Concept

Power supply unit (PSU) wattage calculation and safety headroom planning
Estimated Time:2m 0s
Question 3Question

A system technician is calculating the minimum recommended power supply unit (PSU) wattage rating for a multimedia editing workstation. The workstation components have the following maximum continuous power requirements under full load:

- Central Processing Unit (CPU): 95 W95\text{ W}
- Dedicated Graphics Card (GPU): 210 W210\text{ W}
- Hardware Capture Expansion Card: 45 W45\text{ W}
- 10GbE Network Adapter Card: 35 W35\text{ W}
- Motherboard, System RAM, Storage Drives, and Cooling Fans: 65 W65\text{ W}

According to IT best practices, a power supply should be sized so that total maximum system power consumption does not exceed 75%75\% of the PSU's rated continuous output capacity. What is the minimum rated output wattage required for the replacement PSU?

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Answer: 600

Answer

600 W
To calculate the minimum required power supply wattage rating, first sum the continuous power draw of all components: 95 W (CPU)+210 W (GPU)+45 W (Capture Card)+35 W (NIC)+65 W (Motherboard/RAM/Storage/Cooling)=450 W95\text{ W}\text{ (CPU)} + 210\text{ W}\text{ (GPU)} + 45\text{ W}\text{ (Capture Card)} + 35\text{ W}\text{ (NIC)} + 65\text{ W}\text{ (Motherboard/RAM/Storage/Cooling)} = 450\text{ W}. To satisfy the guideline that total consumption must not exceed 75%75\% (0.750.75) of the rated PSU capacity, divide the total wattage draw by 0.75: 450 W0.75=600 W\frac{450\text{ W}}{0.75} = 600\text{ W}.

Step-by-Step Solution

1
Calculate the total power consumption of all workstation components under full load.
95 W+210 W+45 W+35 W+65 W=450 W95\text{ W} + 210\text{ W} + 45\text{ W} + 35\text{ W} + 65\text{ W} = 450\text{ W} total continuous power draw.
Proper PSU sizing requires accounting for all active internal hardware, including the CPU, GPU, all PCI Express expansion cards, drives, memory, motherboard, and cooling accessories.
2
Divide the total continuous power consumption by the targeted maximum load percentage (0.75).
450 W0.75=600 W\frac{450\text{ W}}{0.75} = 600\text{ W} minimum rated power supply output capacity.
Operating a power supply at or below 75% capacity ensures optimal energy conversion efficiency, reduces heat production, and provides essential safety headroom for transient power draw spikes.

Key Concept

Power supply wattage sizing calculations based on total system component power draw and target continuous load headroom guidelines.
Estimated Time:1m 30s
Question 4Question

A technician is sizing a power supply unit (PSU) for a dedicated video editing workstation. The workstation features the following components and estimated peak power requirements:
- Dual CPUs: 125 W125\text{ W} TDP each
- Dual PCIe Graphics Cards: 165 W165\text{ W} TDP each
- Motherboard, RAM, storage drives, and cooling fans combined: 120 W120\text{ W}

To ensure optimal efficiency and headroom, the technician specifies that total peak system draw must not exceed 70%70\% of the power supply's continuous wattage rating. What is the minimum continuous power supply output rating, in Watts, needed for this system?

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Answer: 1000

Answer

The minimum continuous power supply output rating required is 1000 W1000\text{ W}.
Summing component power requirements yields 250 W250\text{ W} for dual CPUs (2×125 W2 \times 125\text{ W}), 330 W330\text{ W} for dual GPUs (2×165 W2 \times 165\text{ W}), and 120 W120\text{ W} for additional peripherals, totaling 700 W700\text{ W}. To maintain peak system draw at or below 70%70\% of maximum PSU output, divide total draw by 0.700.70: 700 W0.70=1000 W\frac{700\text{ W}}{0.70} = 1000\text{ W}.

Step-by-Step Solution

1
Calculate total system peak power consumption
700 W700\text{ W}
Sum power draw across dual CPUs (250 W250\text{ W}), dual GPUs (330 W330\text{ W}), and system peripherals (120 W120\text{ W}).
2
Calculate minimum PSU rating based on the 70% headroom target
1000 W1000\text{ W}
Divide the total power draw of 700 W700\text{ W} by 0.700.70 so that peak draw represents no more than 70% of continuous output.

Key Concept

Power supply wattage sizing and efficiency headroom calculations
Question 5Question

A system administrator is configuring a hypervisor host that will run 4 identical virtual machines. Each virtual machine requires 4 GB of RAM to function properly. Additionally, the host hypervisor requires a minimum of 4 GB of dedicated host RAM for its own operation. What is the minimum total amount of host RAM, in gigabytes (GB), required to support this configuration?

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Answer: 20

Answer

The minimum total host RAM required is 20 GB.
The total host memory calculation must include both the RAM allocated to all guest virtual machines (4×4 GB=16 GB4 \times 4 \text{ GB} = 16 \text{ GB}) and the memory reserved for the host OS/hypervisor (4 GB4 \text{ GB}), resulting in a total of 20 GB20 \text{ GB}.

Step-by-Step Solution

1
Calculate total memory required for guest virtual machines
16 GB
Multiplying the 4 virtual machines by 4 GB of RAM per machine yields 16 GB total for guest workloads.
2
Add host hypervisor RAM overhead requirement
20 GB
The hypervisor itself requires 4 GB of system RAM to manage system resources and prevent host memory swapping.

Key Concept

Host RAM sizing and hypervisor overhead allocation
Question 6Question

A field technician is assembling a custom audio/video workstation. The system components have the following peak power requirements:

- Processor (CPU): 125 W125\text{ W}
- Dedicated Graphics Card (GPU): 285 W285\text{ W}
- PCIe Video Capture Card: 30 W30\text{ W}
- Motherboard, RAM, and cooling system: 70 W70\text{ W}
- Storage drives: 30 W30\text{ W}

To ensure stable operation and longevity, company policy specifies that the total power draw of all components must not exceed 80%80\% of the power supply unit's (PSU) rated continuous capacity.

What is the minimum rated capacity, in Watts (W\text{W}), required for the power supply unit?

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Answer: 675

Answer

The minimum rated capacity required for the power supply unit is 675 W675\text{ W}.
The total system power consumption is calculated by summing the requirements of all individual hardware components (125 W+285 W+30 W+70 W+30 W=540 W125\text{ W} + 285\text{ W} + 30\text{ W} + 70\text{ W} + 30\text{ W} = 540\text{ W}). To ensure the system power draw does not exceed 80%80\% of the PSU rating, the total draw is divided by 0.800.80, resulting in 5400.80=675 W\frac{540}{0.80} = 675\text{ W}.

Step-by-Step Solution

1
Calculate total peak power requirement of all workstation components.
125 W+285 W+30 W+70 W+30 W=540 W125\text{ W} + 285\text{ W} + 30\text{ W} + 70\text{ W} + 30\text{ W} = 540\text{ W} total power draw.
Before sizing a PSU, all component TDPs and peak power demands must be combined.
2
Calculate the minimum required PSU continuous wattage rating given the 80%80\% load limit.
540 W0.80=675 W\frac{540\text{ W}}{0.80} = 675\text{ W}.
Dividing the expected load by 0.800.80 ensures the power supply operates within its recommended continuous duty cycle without overloading.

Key Concept

Power supply sizing calculations including peak load headroom and maximum load percentages
Question 7Question

A virtualization administrator is sizing a bare-metal hypervisor host to accommodate 6 web server virtual machines (VMs) and 2 database server VMs running concurrently.

- Each web server VM requires 4 GB4\text{ GB} of dedicated RAM.
- Each database server VM requires 16 GB16\text{ GB} of dedicated RAM.
- The hypervisor OS itself requires a baseline memory allocation of 8 GB8\text{ GB} of RAM for kernel management.
- The hypervisor requires an additional operational memory overhead equal to 5%5\% of the total allocated guest VM RAM.
- Company policy mandates that total active host memory usage must not exceed 80%80\% of total physical installed RAM to prevent host starvation.

What is the minimum total physical RAM, in gigabytes (GB\text{GB}), that must be installed on the host server to satisfy all requirements?

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Answer: 83.5

Answer

83.5 GB
The correct calculated installed RAM is 83.5 GB83.5\text{ GB}. Total guest VM allocation is 56 GB56\text{ GB} (6×4 GB+2×16 GB6 \times 4\text{ GB} + 2 \times 16\text{ GB}). The hypervisor requires 8 GB8\text{ GB} baseline plus 2.8 GB2.8\text{ GB} (5%5\% of 56 GB56\text{ GB}) overhead, totaling 66.8 GB66.8\text{ GB} of active memory. To ensure this active memory represents no more than 80%80\% of physical capacity, the total physical RAM required is 66.8/0.80=83.5 GB66.8 / 0.80 = 83.5\text{ GB}.

Step-by-Step Solution

1
Calculate the total memory requested across all guest virtual machines.
56 GB56\text{ GB}
Multiplying 6 web server VMs by 4 GB4\text{ GB} (24 GB24\text{ GB}) and 2 database VMs by 16 GB16\text{ GB} (32 GB32\text{ GB}) gives a total guest RAM allocation of 56 GB56\text{ GB}.
2
Determine hypervisor baseline RAM and dynamic hypervisor overhead.
10.8 GB10.8\text{ GB}
The hypervisor baseline is 8 GB8\text{ GB}. The 5%5\% overhead on 56 GB56\text{ GB} guest RAM is 0.05×56 GB=2.8 GB0.05 \times 56\text{ GB} = 2.8\text{ GB}. Total hypervisor requirement is 8 GB+2.8 GB=10.8 GB8\text{ GB} + 2.8\text{ GB} = 10.8\text{ GB}.
3
Calculate total active memory workload.
66.8 GB66.8\text{ GB}
Combining total guest memory (56 GB56\text{ GB}) with hypervisor baseline and overhead (10.8 GB10.8\text{ GB}) yields 66.8 GB66.8\text{ GB} of required active memory.
4
Calculate total physical RAM needed to maintain an 80% maximum memory utilization threshold.
83.5 GB83.5\text{ GB}
Dividing total active memory by the maximum utilization factor (66.8 GB/0.8066.8\text{ GB} / 0.80) yields 83.5 GB83.5\text{ GB} of installed physical memory required.

Key Concept

Virtual Machine Memory Sizing and Hypervisor Overhead Calculation
Question 8Question

A systems technician is configuring a video editing workstation. The peak power requirements for the hardware components are as follows:

- Central Processing Unit (CPU): 105 W105\text{ W}
- Two dedicated PCI Express capture cards: 75 W75\text{ W} each
- Motherboard, system RAM, and active cooling fans combined: 85 W85\text{ W}

To prevent system instability and maintain PSU power efficiency, IT policy dictates incorporating a 25%25\% safety headroom buffer above the total peak component power draw. What is the minimum recommended power supply unit (PSU) output rating, in Watts (WW), required for this build?

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Answer: 425

Answer

The minimum recommended power supply unit rating is 425 W.
To determine the required power supply capacity, sum the peak power usage of all individual components: 105 W105\text{ W} for the CPU, 150 W150\text{ W} (2×75 W2 \times 75\text{ W}) for the capture cards, and 85 W85\text{ W} for the motherboard, memory, and fans, giving a total continuous load of 340 W340\text{ W}. Applying the required 25%25\% headroom (340 W×1.25340\text{ W} \times 1.25) yields 425 W425\text{ W}.

Step-by-Step Solution

1
Calculate the total baseline wattage requirement of all installed hardware components.
105 W+(2×75 W)+85 W=340 W105\text{ W} + (2 \times 75\text{ W}) + 85\text{ W} = 340\text{ W} total peak draw.
Both expansion cards must be accounted for alongside the CPU and core system components.
2
Apply the mandatory 25% safety headroom buffer to the total baseline wattage.
340 W×1.25=425 W340\text{ W} \times 1.25 = 425\text{ W}.
Adding a 25% margin ensures the PSU operates within its ideal efficiency curve and prevents thermal shutdown during power spikes.

Key Concept

Power supply unit (PSU) wattage sizing and safety headroom calculation
Question 9Question

A system administrator is configuring a bare-metal virtualization host equipped with 64 GB64\text{ GB} of physical RAM. The hypervisor requires a dedicated allocation of 8 GB8\text{ GB} of RAM for host management and system overhead. Each virtual machine (VM) deployed on the host requires 4 GB4\text{ GB} of RAM. Assuming memory overcommitment is not permitted, what is the maximum number of virtual machines that can be concurrently hosted on this server?

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Answer: 14

Answer

The maximum number of virtual machines that can be concurrently hosted is 14.
To determine the maximum number of virtual machines, host RAM overhead must first be subtracted from the total physical memory. 64 GB8 GB=56 GB64\text{ GB} - 8\text{ GB} = 56\text{ GB} of memory remains available for guest virtual machines. Dividing 56 GB56\text{ GB} by 4 GB4\text{ GB} per VM yields a maximum capacity of 14 VMs.

Step-by-Step Solution

1
Calculate the usable RAM available for guest virtual machines
56 GB56\text{ GB} of RAM available (64 GB8 GB64\text{ GB} - 8\text{ GB})
The hypervisor host requires 8 GB8\text{ GB} reserved for host management and operations, which cannot be assigned to guest VMs.
2
Calculate the maximum number of guest VMs supported
1414 virtual machines (56 GB/4 GB56\text{ GB} / 4\text{ GB})
Dividing the remaining 56 GB56\text{ GB} of RAM by the 4 GB4\text{ GB} required per VM yields the maximum VM capacity without overcommitment.

Key Concept

Virtual Machine Resource Allocation and Hypervisor Overhead
Question 10Question

A systems administrator is planning the hardware provisioning for a hypervisor host system that will run two distinct workloads: 55 database virtual machines (VMs) allocated 8 GB8\text{ GB} of RAM each, and 1010 web server VMs allocated 2 GB2\text{ GB} of RAM each. The host hypervisor operating system requires 4 GB4\text{ GB} of dedicated physical RAM to operate, and the virtualization platform requires an additional 5%5\% of the total allocated guest RAM for management overhead. What is the minimum total host RAM, in GB\text{GB}, required to provision all VMs without memory overcommitment?

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Answer: 67

Answer

The minimum total host RAM required is 67 GB67\text{ GB}.
To accurately provision a virtualization host without overcommitment, technicians must calculate the total memory assigned to guest VMs ((5×8 GB)+(10×2 GB)=60 GB(5 \times 8\text{ GB}) + (10 \times 2\text{ GB}) = 60\text{ GB}), calculate hypervisor overhead (5%5\% of 60 GB=3 GB60\text{ GB} = 3\text{ GB}), and include the host OS base requirement (4 GB4\text{ GB}). Adding these together (60 GB+3 GB+4 GB60\text{ GB} + 3\text{ GB} + 4\text{ GB}) yields a total of 67 GB67\text{ GB}.

Step-by-Step Solution

1
Calculate the total RAM allocated to all guest virtual machines.
5×8 GB+10×2 GB=40 GB+20 GB=60 GB5 \times 8\text{ GB} + 10 \times 2\text{ GB} = 40\text{ GB} + 20\text{ GB} = 60\text{ GB}
Each virtual machine requires its assigned memory dedicated from the host pool.
2
Calculate the hypervisor management overhead based on total guest RAM.
5% of 60 GB=0.05×60 GB=3 GB5\% \text{ of } 60\text{ GB} = 0.05 \times 60\text{ GB} = 3\text{ GB}
Hypervisors consume additional system memory to track state, manage virtual hardware tables, and handle guest processes.
3
Sum guest RAM, hypervisor overhead, and dedicated host operating system RAM.
60 GB+3 GB+4 GB=67 GB60\text{ GB} + 3\text{ GB} + 4\text{ GB} = 67\text{ GB}
Combining guest requirements, overhead, and base host OS usage determines total physical host RAM needed to prevent performance degradation or overcommitment.

Key Concept

Virtual Machine Resource Requirements and Host RAM Capacity Planning
Question 11Question

A server administrator is planning a hypervisor deployment on a physical host workstation configured with 64 GB64\text{ GB} of RAM. The host operating system and hypervisor core require a baseline allocation of 8 GB8\text{ GB} of RAM, and organizational compliance requires reserving an additional 10%10\% of the total physical RAM for hypervisor dynamic overhead and host stability. If each planned guest virtual machine requires 5 GB5\text{ GB} of dedicated RAM, what is the maximum number of virtual machines that can be concurrently deployed on this host?

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Answer: 9

Answer

The maximum number of virtual machines that can be hosted concurrently without exceeding host resource limits is 9.
Subtracting both host core memory (8 GB8\text{ GB}) and dynamic safety overhead (10%10\% of 64 GB=6.4 GB64\text{ GB} = 6.4\text{ GB}) leaves 49.6 GB49.6\text{ GB} of usable RAM for guest workloads. Dividing 49.6 GB49.6\text{ GB} by 5 GB5\text{ GB} per VM yields 9.929.92, which rounds down to 9 fully provisioned virtual machines.

Step-by-Step Solution

1
Calculate the host dynamic overhead buffer
10%×64 GB=6.4 GB10\% \times 64\text{ GB} = 6.4\text{ GB}
Hypervisors require reserved memory overhead beyond the base operating system requirements to manage VM states safely.
2
Calculate total host RAM requirements
8 GB+6.4 GB=14.4 GB8\text{ GB} + 6.4\text{ GB} = 14.4\text{ GB}
Combines base host OS requirement with the mandatory dynamic buffer overhead.
3
Determine total remaining RAM available for guest virtual machines
64 GB14.4 GB=49.6 GB64\text{ GB} - 14.4\text{ GB} = 49.6\text{ GB}
Deduct host host dependencies from physical RAM capacity.
4
Calculate maximum VM count and floor to whole unit
49.6 GB/5 GB=9.92=9\lfloor 49.6\text{ GB} / 5\text{ GB} \rfloor = \lfloor 9.92 \rfloor = 9
Virtual machines cannot be provisioned partially; total memory allocation must be fully satisfied per instance.

Key Concept

Virtual Machine Memory Allocation & Host Overhead Capacity Planning
Estimated Time:1m 30s
Question 12Question

An IT technician is assembling a custom multimedia workstation. The system components have the following peak power draws:

- Central Processing Unit (CPU): 105 W105\text{ W}
- Motherboard and RAM combined: 45 W45\text{ W}
- Storage drives: 30 W30\text{ W}
- PCIe Expansion Video Card: 220 W220\text{ W}

To ensure system stability, the technician requires a power supply unit (PSU) rated for 25%25\% higher wattage than the calculated total peak power consumption. What is the minimum recommended power supply rating in Watts?

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Answer: 500

Answer

The minimum recommended power supply unit rating is 500 Watts.
The total peak consumption of the workstation components is 105 W+45 W+30 W+220 W=400 W105\text{ W} + 45\text{ W} + 30\text{ W} + 220\text{ W} = 400\text{ W}. Applying a 25%25\% safety margin (400 W×1.25400\text{ W} \times 1.25) yields a minimum recommended power supply capacity of 500 W500\text{ W}.

Step-by-Step Solution

1
Sum the power consumption of all individual hardware components.
105 W+45 W+30 W+220 W=400 W105\text{ W} + 45\text{ W} + 30\text{ W} + 220\text{ W} = 400\text{ W} total peak power draw.
Determining the total combined baseline wattage is required before applying safety margins.
2
Apply the 25% safety buffer multiplier to the total peak wattage.
400 W×1.25=500 W400\text{ W} \times 1.25 = 500\text{ W}.
Adding a 20% to 30% headroom margin prevents PSU strain, power spikes, and overheating under maximum thermal loads.

Key Concept

Power supply unit (PSU) wattage calculation and safety headroom buffer.
Estimated Time:45s
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