Question

Difficulty: MediumWork Rate and Combined Work

Machine X and Machine Y, operating independently at their respective constant rates, can complete a bottling order together in 66 hours. If Machine X works alone for 22 hours and is then joined by Machine Y, both machines work together for an additional 4.84.8 hours to finish the remaining part of the order. How many hours would it take Machine Y, operating alone at its constant rate, to complete the entire bottling order?

  1. A
    1010
  2. B
    1212
  3. 1515Answer
  4. D
    1616
  5. E
    1818

Answer

1515 hours
The correct answer is 1515 hours. Using the work equation Work=Rate×Time\text{Work} = \text{Rate} \times \text{Time}, the combined rate of Machine X and Machine Y is 16\frac{1}{6}. The work completed by both machines in the 4.84.8-hour period is 4.8×16=0.84.8 \times \frac{1}{6} = 0.8 of the job. Since the remaining 0.20.2 of the job was completed by Machine X in 22 hours, Machine X's rate is 0.22=0.1=110\frac{0.2}{2} = 0.1 = \frac{1}{10} per hour. Subtracting Machine X's rate from the combined rate yields Machine Y's rate: 16110=115\frac{1}{6} - \frac{1}{10} = \frac{1}{15} per hour. Therefore, Machine Y takes 1515 hours operating alone to finish the entire bottling order.

Step-by-Step Solution

1
Define rates for Machine X and Machine Y
Let Machine X's rate be rxr_x orders per hour and Machine Y's rate be ryr_y orders per hour. Their combined rate is rx+ry=16r_x + r_y = \frac{1}{6} orders per hour.
Combined work rate is the reciprocal of the combined completion time of 66 hours.
2
Express the total work completed in two stages
Machine X works alone for 22 hours completing 2rx2 r_x of the order. Then both work together for 4.84.8 hours completing 4.8(rx+ry)4.8(r_x + r_y) of the order. Thus, 2rx+4.8(rx+ry)=12 r_x + 4.8(r_x + r_y) = 1.
The sum of work completed in the two stages equals 11 full job.
3
Substitute the combined rate into the equation to find rxr_x
Since rx+ry=16r_x + r_y = \frac{1}{6}, we substitute: 2rx+4.8(16)=1    2rx+0.8=1    2rx=0.2    rx=0.1=1102 r_x + 4.8\left(\frac{1}{6}\right) = 1 \implies 2 r_x + 0.8 = 1 \implies 2 r_x = 0.2 \implies r_x = 0.1 = \frac{1}{10}.
Substituting the combined rate simplifies the equation to a single variable, rxr_x.
4
Calculate ryr_y and the time needed for Machine Y working alone
ry=16110=5330=230=115r_y = \frac{1}{6} - \frac{1}{10} = \frac{5 - 3}{30} = \frac{2}{30} = \frac{1}{15} orders per hour. Time taken by Machine Y alone =1ry=15= \frac{1}{r_y} = 15 hours.
Subtracting Machine X's rate from the combined rate yields Machine Y's rate, whose reciprocal gives the time to complete the job alone.

Key Concept

Work Rate and Combined Work
Estimated Time:2m 0s
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