Question

Difficulty: MediumWork Rate and Combined Work

An industrial facility uses two automated assembly units, Unit XX and Unit YY, to fabricate custom components. Working alone at its constant rate, Unit XX can complete a batch of components in 66 hours, while Unit YY can complete an identical batch working alone at its constant rate in 1212 hours. Unit XX begins working on a batch alone. After 22 hours, Unit YY joins Unit XX, and both units work together at their respective constant rates until the batch is complete. What is the total time, in hours, required to complete the batch from start to finish?

  1. A
    2232\frac{2}{3}
  2. B
    3123\frac{1}{2}
  3. 4234\frac{2}{3}Answer
  4. D
    66
  5. E
    88

Answer

4234\frac{2}{3} hours
The correct answer is 4234\frac{2}{3} hours. Unit XX works alone for 22 hours, completing 2×16=132 \times \frac{1}{6} = \frac{1}{3} of the job. This leaves 23\frac{2}{3} of the job remaining. Working together, Unit XX and Unit YY have a combined rate of 16+112=14\frac{1}{6} + \frac{1}{12} = \frac{1}{4} of the job per hour. The time spent working together is 2/31/4=83\frac{2/3}{1/4} = \frac{8}{3} hours. Adding the initial 22 hours gives a total duration of 2+83=4232 + \frac{8}{3} = 4\frac{2}{3} hours.

Step-by-Step Solution

1
Calculate the individual work rates of Unit XX and Unit YY.
Unit XX's rate is 16\frac{1}{6} batch per hour, and Unit YY's rate is 112\frac{1}{12} batch per hour.
Work rate is defined as Rate=1Time\text{Rate} = \frac{1}{\text{Time}} for completing one full job.
2
Determine the fraction of the batch completed by Unit XX during its 22 hours of solo work.
Unit XX completes 2×16=132 \times \frac{1}{6} = \frac{1}{3} of the batch.
Work done equals Rate×Time\text{Rate} \times \text{Time}.
3
Find the remaining fraction of work to be completed.
The remaining work is 113=231 - \frac{1}{3} = \frac{2}{3} of the batch.
Subtract the completed fraction from the total job (11).
4
Calculate the combined work rate when both units operate together.
Combined rate = 16+112=212+112=312=14\frac{1}{6} + \frac{1}{12} = \frac{2}{12} + \frac{1}{12} = \frac{3}{12} = \frac{1}{4} batch per hour.
Simultaneous work rates add linearly.
5
Calculate the time needed for both units to finish the remaining work.
Time together = 2/31/4=23×4=83=223\frac{2/3}{1/4} = \frac{2}{3} \times 4 = \frac{8}{3} = 2\frac{2}{3} hours.
Time equals Remaining WorkCombined Rate\frac{\text{Remaining Work}}{\text{Combined Rate}}.
6
Add the solo phase duration to the combined phase duration to get total elapsed time.
Total time = 2+83=143=4232 + \frac{8}{3} = \frac{14}{3} = 4\frac{2}{3} hours.
Total time is the sum of the times from each sequential stage.

Key Concept

Work Rate and Combined Work
Estimated Time:2m 0s
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