Question

Difficulty: HardWork Rate and Combined Work

Three automated server clusters—Cluster XX, Cluster YY, and Cluster ZZ—process large-scale data analytics tasks. Working alone at their respective constant rates, Cluster XX can complete a standard workload in 1212 hours, Cluster YY can complete it in 2020 hours, and Cluster ZZ can complete it in 3030 hours. Cluster XX and Cluster YY begin processing a standard workload together. After 44 hours, Cluster XX goes offline due to maintenance while Cluster YY continues working alone. Exactly 22 hours after Cluster XX goes offline, Cluster ZZ is brought online to assist Cluster YY. How many additional hours will it take Cluster YY and Cluster ZZ working together to complete the remaining portion of the workload?

  1. 4.44.4 hoursAnswer
  2. B
    5.65.6 hours
  3. C
    2.82.8 hours
  4. D
    18.3318.33 hours
  5. E
    6.26.2 hours

Answer

The additional time required for Cluster Y and Cluster Z to finish the remaining workload is 4.44.4 hours.
The combined rate of Cluster X and Cluster Y is 112+120=215\frac{1}{12} + \frac{1}{20} = \frac{2}{15} job/hr. In 44 hours, they complete 4×215=8154 \times \frac{2}{15} = \frac{8}{15} of the job, leaving 715\frac{7}{15}. Cluster Y then works alone for 22 hours, completing 2×120=1102 \times \frac{1}{20} = \frac{1}{10} of the job. The remaining work is 715110=1130\frac{7}{15} - \frac{1}{10} = \frac{11}{30}. Finally, Cluster Y and Cluster Z work together at a combined rate of 120+130=112\frac{1}{20} + \frac{1}{30} = \frac{1}{12} job/hr. The time needed to finish is 11/301/12=4.4\frac{11/30}{1/12} = 4.4 hours.

Step-by-Step Solution

1
Calculate individual work rates for each cluster per hour.
rX=112r_X = \frac{1}{12}, rY=120r_Y = \frac{1}{20}, and rZ=130r_Z = \frac{1}{30} of the total workload per hour.
Work rate is the reciprocal of the total time required to complete one full workload.
2
Calculate the work completed in Stage 1 when Cluster X and Cluster Y work together for 4 hours.
Combined rate rX+Y=112+120=5+360=860=215r_{X+Y} = \frac{1}{12} + \frac{1}{20} = \frac{5 + 3}{60} = \frac{8}{60} = \frac{2}{15}. Work done in 4 hours = 4×215=8154 \times \frac{2}{15} = \frac{8}{15}. Remaining work = 1815=7151 - \frac{8}{15} = \frac{7}{15}.
Multiply the combined rate of Clusters X and Y by 4 hours to find the fraction of work completed.
3
Calculate the work completed in Stage 2 when Cluster Y works alone for 2 hours.
Work done by Y in 2 hours = 2×120=110=3302 \times \frac{1}{20} = \frac{1}{10} = \frac{3}{30}. Remaining work = 715110=1430330=1130\frac{7}{15} - \frac{1}{10} = \frac{14}{30} - \frac{3}{30} = \frac{11}{30}.
Subtract the work done by Cluster Y during its solo 2-hour interval from the remaining work.
4
Calculate the time required for Cluster Y and Cluster Z working together to complete the remaining 11/3011/30 of the work.
Combined rate rY+Z=120+130=3+260=560=112r_{Y+Z} = \frac{1}{20} + \frac{1}{30} = \frac{3 + 2}{60} = \frac{5}{60} = \frac{1}{12}. Time t=11/301/12=1130×12=13230=4.4t = \frac{11/30}{1/12} = \frac{11}{30} \times 12 = \frac{132}{30} = 4.4 hours.
Divide the remaining workload fraction by the combined hourly work rate of Clusters Y and Z.

Key Concept

Combined Work Rate in Multi-Stage Problems
Estimated Time:2m 0s
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